Capturing multiple line output into a Bash variable - bash

I've got a script 'myscript' that outputs the following:
abc
def
ghi
in another script, I call:
declare RESULT=$(./myscript)
and $RESULT gets the value
abc def ghi
Is there a way to store the result either with the newlines, or with '\n' character so I can output it with 'echo -e'?

Actually, RESULT contains what you want — to demonstrate:
echo "$RESULT"
What you show is what you get from:
echo $RESULT
As noted in the comments, the difference is that (1) the double-quoted version of the variable (echo "$RESULT") preserves internal spacing of the value exactly as it is represented in the variable — newlines, tabs, multiple blanks and all — whereas (2) the unquoted version (echo $RESULT) replaces each sequence of one or more blanks, tabs and newlines with a single space. Thus (1) preserves the shape of the input variable, whereas (2) creates a potentially very long single line of output with 'words' separated by single spaces (where a 'word' is a sequence of non-whitespace characters; there needn't be any alphanumerics in any of the words).

Another pitfall with this is that command substitution — $() — strips trailing newlines. Probably not always important, but if you really want to preserve exactly what was output, you'll have to use another line and some quoting:
RESULTX="$(./myscript; echo x)"
RESULT="${RESULTX%x}"
This is especially important if you want to handle all possible filenames (to avoid undefined behavior like operating on the wrong file).

In case that you're interested in specific lines, use a result-array:
declare RESULT=($(./myscript)) # (..) = array
echo "First line: ${RESULT[0]}"
echo "Second line: ${RESULT[1]}"
echo "N-th line: ${RESULT[N]}"

In addition to the answer given by #l0b0 I just had the situation where I needed to both keep any trailing newlines output by the script and check the script's return code.
And the problem with l0b0's answer is that the 'echo x' was resetting $? back to zero... so I managed to come up with this very cunning solution:
RESULTX="$(./myscript; echo x$?)"
RETURNCODE=${RESULTX##*x}
RESULT="${RESULTX%x*}"

Parsing multiple output
Introduction
So your myscript output 3 lines, could look like:
myscript() { echo $'abc\ndef\nghi'; }
or
myscript() { local i; for i in abc def ghi ;do echo $i; done ;}
Ok this is a function, not a script (no need of path ./), but output is same
myscript
abc
def
ghi
Considering result code
To check for result code, test function will become:
myscript() { local i;for i in abc def ghi ;do echo $i;done;return $((RANDOM%128));}
1. Storing multiple output in one single variable, showing newlines
Your operation is correct:
RESULT=$(myscript)
About result code, you could add:
RCODE=$?
even in same line:
RESULT=$(myscript) RCODE=$?
Then
echo $RESULT $RCODE
abc def ghi 66
echo "$RESULT"
abc
def
ghi
echo ${RESULT#Q}
$'abc\ndef\nghi'
printf '%q\n' "$RESULT"
$'abc\ndef\nghi'
but for showing variable definition, use declare -p:
declare -p RESULT RCODE
declare -- RESULT="abc
def
ghi"
declare -- RCODE="66"
2. Parsing multiple output in array, using mapfile
Storing answer into myvar variable:
mapfile -t myvar < <(myscript)
echo ${myvar[2]}
ghi
Showing $myvar:
declare -p myvar
declare -a myvar=([0]="abc" [1]="def" [2]="ghi")
Considering result code
In case you have to check for result code, you could:
RESULT=$(myscript) RCODE=$?
mapfile -t myvar <<<"$RESULT"
declare -p myvar RCODE
declare -a myvar=([0]="abc" [1]="def" [2]="ghi")
declare -- RCODE="40"
3. Parsing multiple output by consecutives read in command group
{ read firstline; read secondline; read thirdline;} < <(myscript)
echo $secondline
def
Showing variables:
declare -p firstline secondline thirdline
declare -- firstline="abc"
declare -- secondline="def"
declare -- thirdline="ghi"
I often use:
{ read foo;read foo total use free foo ;} < <(df -k /)
Then
declare -p use free total
declare -- use="843476"
declare -- free="582128"
declare -- total="1515376"
Considering result code
Same prepended step:
RESULT=$(myscript) RCODE=$?
{ read firstline; read secondline; read thirdline;} <<<"$RESULT"
declare -p firstline secondline thirdline RCODE
declare -- firstline="abc"
declare -- secondline="def"
declare -- thirdline="ghi"
declare -- RCODE="50"

After trying most of the solutions here, the easiest thing I found was the obvious - using a temp file. I'm not sure what you want to do with your multiple line output, but you can then deal with it line by line using read. About the only thing you can't really do is easily stick it all in the same variable, but for most practical purposes this is way easier to deal with.
./myscript.sh > /tmp/foo
while read line ; do
echo 'whatever you want to do with $line'
done < /tmp/foo
Quick hack to make it do the requested action:
result=""
./myscript.sh > /tmp/foo
while read line ; do
result="$result$line\n"
done < /tmp/foo
echo -e $result
Note this adds an extra line. If you work on it you can code around it, I'm just too lazy.
EDIT: While this case works perfectly well, people reading this should be aware that you can easily squash your stdin inside the while loop, thus giving you a script that will run one line, clear stdin, and exit. Like ssh will do that I think? I just saw it recently, other code examples here: https://unix.stackexchange.com/questions/24260/reading-lines-from-a-file-with-bash-for-vs-while
One more time! This time with a different filehandle (stdin, stdout, stderr are 0-2, so we can use &3 or higher in bash).
result=""
./test>/tmp/foo
while read line <&3; do
result="$result$line\n"
done 3</tmp/foo
echo -e $result
you can also use mktemp, but this is just a quick code example. Usage for mktemp looks like:
filenamevar=`mktemp /tmp/tempXXXXXX`
./test > $filenamevar
Then use $filenamevar like you would the actual name of a file. Probably doesn't need to be explained here but someone complained in the comments.

How about this, it will read each line to a variable and that can be used subsequently !
say myscript output is redirected to a file called myscript_output
awk '{while ( (getline var < "myscript_output") >0){print var;} close ("myscript_output");}'

Related

how to assign each of multiple lines in a file as different variable?

this is probably a very simple question. I looked at other answers but couldn't come up with a solution. I have a 365 line date file. file as below,
01-01-2000
02-01-2000
I need to read this file line by line and assign each day to a separate variable. like this,
d001=01-01-2000
d002=02-01-2000
I tried while read commands but couldn't get them to work.It takes a lot of time to shoot one by one. How can I do it quickly?
Trying to create named variable out of an associative array, is time waste and not supported de-facto. Better use this, using an associative array:
#!/bin/bash
declare -A array
while read -r line; do
printf -v key 'd%03d' $((++c))
array[$key]=$line
done < file
Output
for i in "${!array[#]}"; do echo "key=$i value=${array[$i]}"; done
key=d001 value=01-01-2000
key=d002 value=02-01-2000
Assumptions:
an array is acceptable
array index should start with 1
Sample input:
$ cat sample.dat
01-01-2000
02-01-2000
03-01-2000
04-01-2000
05-01-2000
One bash/mapfile option:
unset d # make sure variable is not currently in use
mapfile -t -O1 d < sample.dat # load each line from file into separate array location
This generates:
$ typeset -p d
declare -a d=([1]="01-01-2000" [2]="02-01-2000" [3]="03-01-2000" [4]="04-01-2000" [5]="05-01-2000")
$ for i in "${!d[#]}"; do echo "d[$i] = ${d[i]}"; done
d[1] = 01-01-2000
d[2] = 02-01-2000
d[3] = 03-01-2000
d[4] = 04-01-2000
d[5] = 05-01-2000
In OP's code, references to $d001 now become ${d[1]}.
A quick one-liner would be:
eval $(awk 'BEGIN{cnt=0}{printf "d%3.3d=\"%s\"\n",cnt,$0; cnt++}' your_file)
eval makes the shell variables known inside your script or shell. Use echo $d000 to show the first one of the newly defined variables. There should be no shell special characters (like * and $) inside your_file. Remove eval $() to see the result of the awk command. The \" quoted %s is to allow spaces in the variable values. If you don't have any spaces in your_file you can remove the \" before and after %s.

Open file with two columns and dynamically create variables

I'm wondering if anyone can help. I've not managed to find much in the way of examples and I'm not sure where to start coding wise either.
I have a file with the following contents...
VarA=/path/to/a
VarB=/path/to/b
VarC=/path/to/c
VarD=description of program
...
The columns are delimited by the '=' and some of the items in the 2nd column may contain gaps as they aren't just paths.
Ideally I'd love to open this in my script once and store the first column as the variable and the second as the value, for example...
echo $VarA
...
/path/to/a
echo $VarB
...
/path/to/a
Is this possible or am I living in a fairy land?
Thanks
You might be able to use the following loop:
while IFS== read -r name value; do
declare "$name=$value"
done < file.txt
Note, though, that a line like foo="3 5" would include the quotes in the value of the variable foo.
A minus sign or a special character isn't allowed in a variable name in Unix.
You may consider using BASH associative array for storing key and value together:
# declare an associative array
declare -A arr
# read file and populate the associative array
while IFS== read -r k v; do
arr["$k"]="$v"
done < file
# check output of our array
declare -p arr
declare -A arr='([VarA]="/path/to/a" [VarC]="/path/to/c" [VarB]="/path/to/b" [VarD]="description of program" )'
What about source my-file? It won't work with spaces though, but will work for what you've shared. This is an example:
reut#reut-home:~$ cat src
test=123
test2=abc/def
reut#reut-home:~$ echo $test $test2
reut#reut-home:~$ source src
reut#reut-home:~$ echo $test $test2
123 abc/def

Is there a way to loop variables from another file into my bash script?

Sorry to be a pain, but I'm not sure how I can loop values from an outside file, into my bash script as variables. I have three variable names in my bash script:
$TAGBEGIN
$TAGEND
$MYCODE
In a separate varSrc.txt file, I have several variables:
# a - Some marker
tagBegin_a='/<!-- Begin A -->/'
tagEnd_a='/<!-- End A -->/'
code_a=' [ some code to replace in between tags ] '
# b - Some marker
tagBegin_b='/<!-- Begin B -->/'
tagEnd_b='/<!-- End B -->/'
code_b=' [ some code to replace in between tags ] '
# c - Some marker
...
I need my bash script to be able to loop through each "# marker"* section and perform a function:
source varSrc.txt
$TAGBEGIN
$TAGEND
$MYCODE
...
sed '
'"$TAGEND"' R '"$MYCODE"'
'"$TAGBEGIN"','"$TAGEND"' d
' -i $TARGETDIR
Note: sed code logic (not quoting mess) courtesy of Glenn J.
I need some kind of looping logic like:
for (var i = 0; i <= markers in varSrc.txt ; i++) {
// set bash vars equal to varSrc values
$TAGBEGIN= $tagBegin_i
$TAGEND= $tagEnd_i
$MYCODE= $code_i
// run the 'sed' replace command
sed '
'"$TAGEND"' R '"$MYCODE"'
'"$TAGBEGIN"','"$TAGEND"' d
' -i $TARGETDIR
}
Is this something that can be feasibly done in a bash script and is this a good approach? Any suggestions, pointers or guidance is very, very appreciated!
*(which I don't think is a real marker I can use)
[Answering the question as amended]
There's no need use use, iterate over, or think about markers at all. Leave them out.
source varSrc.txt
for beginVar in "${!tagBegin_#}"; do # Iterate over defined begin variable names
endVar=tagEnd_${var#tagBegin_} # Generate the name of the end variable
codeVar=code_${var#tagBegin_} # Generate the name of the code variable
begin=${!beginVar} # Look up the contents of the begin variable
end=${!endVar} # Look up the contents of the end variable
code=${!codeVar} # Look up the contents of the code variable
sed -e "$end R $code" -e "$begin,$end d" -i "$file"
done
[Answers original, pre-amended question]
source only works if your input file is valid bash syntax; it isn't. Thus, you'll need to parse it yourself, something like the following:
begin= end= code=
while IFS= read -r; do
case $REPLY in
#*)
# we saw a marker; process all vars seen so far
[[ $begin && $end && $code ]] || continue # do nothing if we have no vars seen
sed -e "$end R $code" -e "$begin,$end d" -i "$file"
;;
'$TAGBEGIN='*) begin=${REPLY#'$TAGBEGIN='} ;;
'$TAGEND='*) end=${REPLY#'$TAGEND='} ;;
'$MYCODE='*) code=${REPLY#'$MYCODE='} ;;
esac
done <varSrc.txt
What you can do is export your variables in your second file an the execute the script within your current environment (with a dot before the script) to get the variable names/markers you can parse the file and search for an $ or #

How can I set a variable = null in for loop?

I have this code in Elastix2.5 (CentOS):
for variable in $(while read line; do myarray[ $index]="$line"; index=$(($index+1)); echo "$line"; done < prueba);
This extract the values for each line from "prueba" file.
Prueba file contents passwords like this:
Admin1234
Hello543
Chicken5444
Dino6759
3434Cars4
Adminis5555
But, $variable only get values from lines where there are letters, I need that it get NULL values from blank lines. How can I do it?
Your problem is use of a for loop with a command substitution ($(...)); let's look at this simple example:
$ for v in $(echo 'line_1'; echo ''; echo 'line_3'); do echo "$v"; done
line_1
line_3
Note how the empty string produced by the 2nd echo command is effectively discarded.
Analogously, any empty lines produced by your while loop are discarded.
The solution is to avoid for loops altogether for parsing command output:
In your case, simply use only the while loop for iterating over the input file:
while read -r line; do
myarray[index++]="$line"
done < prueba
printf '%s\n' "${myarray[#]}"
-r was added to ensure that read doesn't modify the input (doesn't try to interpret \-prefixed sequences) - this is good practice in general.
Note how incrementing the index was moved directly into the array subscript (index++).
printf '%s\n' "${myarray[#]}" prints all array elements after the file's been read, demonstrating that empty lines were read as well.
You can use is_null function.
is_null($a)
http://php.net/manual/en/function.is-null.php

Variable assignment when reading from file using cat

I have a txt file that is in the format below:
name1 path/to/some/directory
name2 path/to/some/other/directory
name3 path/to/some/directory
name4 path/to/some/other/directory
...
Here is the code I have written to read this file line by line:
NUM=1
for line in $(cat /path/to/my/file.txt); do
if [ $((NUM%2)) -eq 1 ]
then
name= $line #this line does not work
echo $line #while this line works just fine
else
sudo tar -cf /desired/path/$name.tar $line
fi
NUM=$((NUM+1))
done
This code actually reads file word by word, and it alternates between then and else of if statement. Once it assigns a value it has read to variable name (then part inside if), then it uses that variable in command that is performed in else part of if. (This is how I expect it to work.)
The problem that arises is that variable assignment in then part of if seems not to work, it sees word it has just read as command, and doesn't assign its value to variable. I tried to echo it and it works just fine.
Why name= $line variable assignment is not working?
Thank you for any suggestions, comments or answers.
The assignments in bash require no space around =.
Hence, you need to say:
name="$line"
^ ^
quotes!
This happens because anything happening after the declaration is considered a command. See for example this, that tries to define r to 2 and then echo 1 is executed:
$ r=2 echo 1
1
This is why it is also a good thing to quote the declaration: name="$line".
Regarding the parsing and definition of variables of the file, you can maybe use this approach:
declare $('s/\s\+/="/; s/$/"/' a)
This replaces the spaces in between the first and second word by =" and the end of line with ". This way, name /path/ gets converted into name="/path/". By using declare, this command gets executed and makes variables be ready for use.
$ cat a
name1 aa
name2 rr
name5 hello
$ sed 's/\s\+/="/; s/$/"/' a
name1="aa"
name2="rr"
name5="hello"
$ declare $('s/\s\+/="/; s/$/"/' a)
So now you have the variables ready to use:
$ echo "$name5"
hello
And finally, note that this is equivalent (and better) than for line in $(cat /path/to/my/file.txt):
while IFS= read -r val1 val2 ...
do
... things ...
done < /path/to/my/file.txt

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