get only a part of text() with xpath - xpath

I'm trying to get the array of authors of this website:
http://www.intechopen.com/books/latest/1/list
with this xpath:
response.xpath("//div[#id='sizer']/div[#id='content']/div[#class='grid']/div[#class='main-content']/div[#id='tc']/div/ul[#class='book-listing entity-listing']/li/dl/dd[#class='meta']/text()[count(preceding-sibling::br) = 0]").extract()
but i want only the names, without the "editor", how can I do it?

After selecting the text, use the regular expression function re() with a capture group in order to exclude the text you do not want:
response.xpath("//div[#id='sizer']/div[#id='content']/div[#class='grid']/div[#class='main-content']/div[#id='tc']/div/ul[#class='book-listing entity-listing']/li/dl/dd[#class='meta']/text()[count(preceding-sibling::br) = 0]")
.re(r'Editor\s*(.*)')

Related

How to take xpath to Get Text from class inside th

I have the following XPath :
//table[#class='ui-jqgrid-htable']/thead/tr/th//text()
And I'm trying to get the text from it with the following command :
String LabelName = driver.findElement(By.xpath("//table[#class='ui-jqgrid htable']/thead/tr/th//text()")).getText()
But it's not printing text, the result is blank. Could you help me please ?
The text() in your xpath does not qualify as an element. Your element ends at //table[#class='ui-jqgrid-htable']/thead/tr/th. Try using getText() for this XPath.
Also, a table would have many headers. Using findElement will only return the first one.
If you want to get all headers use
driver.findElements(By.xpath("//table[#class='ui-jqgrid-htable']/thead/tr/th"))
and loop through the list to getText of individual element.

Conditional XPath on multiple elements

I am trying to use xpath to set an exchange property from the value of one element, depending on what the value is in another element...
So in my case i want an xpath to identify the PartyID where the RoleCode = 60. And another xpath expression to find the PartyID for where the RoleCode = Z60.
I would have used [1] etc but the send cannot guarantee the order the segments will be in.
Help is much appreciated!
<RegisteredProductCollection>
<RegisteredProduct>
<Status>1</Status>
<AddressLine2>test</AddressLine2>
<AddressLine1>37</AddressLine1>
<RegisteredProductPartyInformation>
<RegisteredProductPartyInformation>
<PartyID>9000028253</PartyID>
<RoleCode>60</RoleCode>
</RegisteredProductPartyInformation>
<RegisteredProductPartyInformation>
<PartyID>1288219</PartyID>
<RoleCode>Z60</RoleCode>
</RegisteredProductPartyInformation>
</RegisteredProductPartyInformation>
<PostalCode>3200</PostalCode>
<Country>NZ</Country>
<ProductID>G02411</ProductID>
<SerialID>1234124124</SerialID>
<City>test</City>
<ReferenceDate>20200514000000</ReferenceDate>
<District>wai</District>
</RegisteredProduct>
</RegisteredProductCollection>
You can use these XPath-1.0 expressions:
//RegisteredProductPartyInformation[RoleCode='60']/PartyID
and
//RegisteredProductPartyInformation[RoleCode='Z60']/PartyID
Change the ' to " if necessary.

XPath Get value inside query string

I use this XPath
//#getparam
to get this list of URL
/blabla/bla.php?id=100001&target=lala&new=lulu
/blabla/bla.php?id=100002&target=lala&new=lulu
/blabla/bla.php?id=100003&target=lala&new=lulu
I want to get list of IDs, and try this XPath
substring-before(substring-after(//#getparam, "?id="), "&")
but it only returns first ID. How to get all IDs only using XPath?
If you're using XPath 2.0, the following will do the trick:
//#getparam/substring-before(substring-after(., "?id="), "&")
If you're using XPath 1.0, there is no single expression to return the desired result set. You can iterate over each result of //#getParam and apply the functions.

How to use like in XPath?

I have a page that searches with filters. I have this code for example,
xmlTempResultSearch = xmlResidentListDisplay.selectNodes("//PeopleList/Row[#LastName != '"+txtSearch.value+"']");
xmlTempResultSearch.removeAll();
This selects the data that is not equal to the LastName inputted on the txtSearch textbox and then removes them from the result set so that its filtered to equal the last name on the txtSearch textbox.
My problem with this code is that it should be equal (=) to the txtSearch.value, what I want is that I want the result set LIKE the txtSearch.value. What happens on my page is that when I type 'santos' on the txtSearch textbox, its result set is all those last names with 'santos'. But when I type 'sant', nothing appears. I want the same result set with 'santos' because it all contains 'sant'
You can use all of the XPath (1.0) string functions. If you have XPath 2.0 available, then you can even use RegEx.
contains()
starts-with()
substring()
substring-before()
substring-after()
concat()
translate()
string-length()
There is no **ends-with() in XPath 1.0, but it can easily be expressed with this XPath 1.0 expression**:
substring($s, string-length($s) - string-length($t) +1) = $t
is true() exactly when the string $s ends with the string $t.
You can use start-with function and not function. Reference:
http://www.w3schools.com/xpath/xpath_functions.asp
xmlTempResultSearch = xmlResidentListDisplay.selectNodes("//PeopleList/Row[not(starts-with(#LastName,'"+ txtSearch.value +"'))]");
you can use contains() function of XPath:
xmlTempResultSearch = xmlResidentListDisplay.selectNodes("//PeopleList/Row[not(contains(#LastName,'"+txtSearch.value+"'))]");

Selenium Webdriver + Ruby regex: Can I use regex with find_element?

I am trying to click an element that changes per each order like so
edit_div_123
edit_div_124
edit_div_xxx
xxx = any three numbers
I have tried using regex like so:
#driver.find_element(:css, "#edit_order_#{\d*} > div.submit > button[name=\"commit\"]").click
#driver.find_element(:xpath, "//*[(#id = "edit_order_#{\d*}")]//button").click
Is this possible? Any other ways of doing this?
You cannot use Regexp, like the other answers have indicated.
Instead, you can use a nifty CSS Selector trick:
#driver.find_element(:css, "[id^=\"edit_order_\"] > div.submit > button[name=\"commit\"]").click
Using:
^= indicates to find the element with the value beginning with your criteria.
*= says the criteria should be found anywhere within the element's value
$= indicates to find the element with with your criteria at the end of the value.
~= allows you to find the element based on a single criteria when the actual value has multiple space-seperated list of values.
Take a look at http://net.tutsplus.com/tutorials/html-css-techniques/the-30-css-selectors-you-must-memorize/ for some more info on other neat CSS tricks you should add to your utility belt!
You have no provided any html fragment that you are working on. Hence my answer is just based on the limited inputs provided your question.
I don't think WebDriver APIs support regex for locating elements. However, you can achieve what you want using just plain XPath as follows:
//*[starts-with(#id, 'edit_div_')]//button
Explanation: Above xpath will try to search all <button> nodes present under all elements whose id attribute starts with string edit_div_
In short, you can use starts-with() xpath function in order to match element with id format as edit_div_ followed by any number of characters
No, you can not.
But you should do something like this:
function hasClass(element, className) {
var re = new RegExp('(?:^|\\s+)' + className + '(?:\\s+|$)');
return re.test(element.className);
}
This worked for me
#driver.find_element(:xpath, "//a[contains(#href, 'person')]").click

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