what to do with an inverted polymorphic relation? - laravel

I have been trying to get my head around these polymorphic relationships all day. I might be over complicating/thinking it but. Can Laravel handle inverse polymorphic relationships? I have a registration flow that can have two types of field Models- normal field and customField.
When I loop through all the fields available it could pull the attributes from either NormalField or CustomField.
<?php
foreach($registrationFlow->fields->get() as $field)
{
echo $field->name; // could be custom field or could be normal field
}
?>
My difficulty is that, the example given in the docs works if you want to assign a photo to either staff or orders, but i want to assign either a customField or a normalField to a registrationFlow
*Edit
If you follow the example for the polymorphic many to many relationship, The tag class contains posts and videos- while i would want just a simple fields() method that relates to customField or normalField dependent on the type

First of all, you should take a look at the updated docs for Laravel 5.1: https://laravel.com/docs/5.1/eloquent-relationships#polymorphic-relations.
I think the difficulty with the example they provide is that the relationship between Photo and Staff/Product are "has-a" relationships, whereas you are trying to model an "is-a" relationship. However, you can model "is-a" essentially the same way. Take a look at this article: http://richardbagshaw.co.uk/laravel-user-types-and-polymorphic-relationships/.
Basically, the strategy is to define a generic model (and a generic table), perhaps in your case Field, that relates to your RegistrationFlow. You then have two subtype models, NormalField and CustomField, that have one-to-one relationships with Field. (there's your "is-a"). Thus, RegistrationFlow is indirectly related to your field subtypes.
Polymorphism comes in when you want to access the specific subtypes:
class Field extends Model {
public function fieldable()
{
return $this->morphTo();
}
}
Your base field table should have fieldable_id and fieldable_type columns defined (see the Eloquent docs).
You can then add methods to NormalField and CustomField that let you access the base model (your "inverse relationship"):
class NormalField {
public function field()
{
return $this->morphOne('Field', 'fieldable');
}
}
class CustomField {
public function field()
{
return $this->morphOne('Field', 'fieldable');
}
}
Usage:
$field = Field::find(1);
// Gets the specific subtype
$fieldable = $field->fieldable;

Related

Laravel polymorphic hasMany relationship

From Laravel's docs, the model polymorphism is defined as follows:
Polymorphic relations allow a model to belong to more than one other model on a single association
Sounds like it's designed to work with belongsTo instead of hasMany side. Here's a scenario that I want to achieve:
In my system, there are many project types, each projec type will have its own invoice field layout. Let's say we have a Project model that has a type field, whose value could be contract or part-time. We have another two tables called ContractInvoice and PartTimeInvoice to define their respective field layout, both of these invoice tables have a project_id referencing a project record. What I want to do is I want a universal interface to retrieve all invoices given a project, something like $project->invoices.
Current solution
I can't figure out how to achieve this via polymorphism. So what I am currently doing is kind silly, using a switch statement in my invoice() method on Project model class:
switch ($this->type) {
case 'contract':
$model = 'App\ContractInvoice';
break;
case 'part-time':
$model = 'App\PartTimeInvoice';
break;
}
return $this->hasMany($model);
I feel like there must be a better way to do this. Can someone please shed some light?
I don't see how a polymorphic relationship would be beneficial in this case. If you had different project type models and a single invoices table, then the invoices could morphTo the projects. But as you've described it, the switch statement sounds like it is adequate. You could achieve the same means using when conditionals like:
public function invoices()
{
return $this->when($this->type === 'contract', function () {
return $this->hasMany(ContractInvoice::class);
})->when($this->type === 'part-time', function () {
return $this->hasMany(PartTimeInvoice::class);
});
}
The type attribute on the Project model and the separate invoice tables are defining a rigid relationship between them, which goes against the idea of polymorphism. Think likes for comments and posts.

Laravel 5.5 retrieving null by nested relation

I have 3 databases:
Routes:
id
name
Rates:
Id
Route_id
Car_id
Cars:
id
name
My model for routes
public function rates()
{
return $this->hasMany('App\Rate', 'route_id');
}
My model for rates
public function car() {
return $this->belongsTo('App\Car','car_id');
}
Now I need to access the car relation, but when I do
return $this->route->with('from','to','rates.car')->paginate(74);
I get null for the car relation
{"id":1,"from_id":1,"to_id":2,"distance":400,"created_at":null,"updated_at":null,"from":{"id":1,"name":"\u0410\u043a\u043a\u043e","created_at":null,"updated_at":null,"lat":32.93310000000000314912540488876402378082275390625,"long":35.0827000000000026602720026858150959014892578125},"to":{"id":2,"name":"\u0410\u0440\u0430\u0434","created_at":null,"updated_at":null,"lat":31.261399999999998300381776061840355396270751953125,"long":35.21490000000000009094947017729282379150390625},"rates":[{"id":1,"route_id":1,"car_id":1,"rate":1123,"night_rate":1391,"car":null},{"id":5551,"route_id":1,"car_id":2,"rate":1123,"night_rate":1391,"car":null},{"id":11101,"route_id":1,"car_id":3,"rate":1123,"night_rate":1391,"car":null},{"id":16651,"route_id":1,"car_id":4,"rate":1123,"night_rate":1391,"car":null},{"id":22201,"route_id":1,"car_id":5,"rate":1123,"night_rate":1391,"car":null},{"id":27751,"route_id":1,"car_id":6,"rate":1123,"night_rate":1391,"car":null},{"id":33301,"route_id":1,"car_id":7,"rate":1123,"night_rate":1391,"car":null},{"id":38851,"route_id":1,"car_id":8,"rate":1123,"night_rate":1391,"car":null}]},
From my understanding you are trying to access a Car model through a Route model.
A couple of things I noticed that should help you find a solution.
First off I think the inverse relation you are supposed to use the belongToMany() function instead.
public function car() {
return $this->belongsToMany('App\Car','Rates'); // Perhaps call the table something like routes_cars to more clearly define it's a pivot table
}
Next I see you are trying to use model functions within the context of $this(). I assume you are doing this in your model? That logic should be in a controller, that might cause some undesired results but I'm not entirely sure. Also it looks like your parameters are incorrect when using with(). You use the function name that you defined in belongsToMany()
App/Route::with('car')->paginate(74);
With the correct relationships setup you rarely need to worry about the pivot table. If you are going to add extra information in the pivot table there are laravel functions to help you do that in the documentation.

getting all attributes for nested relationships in laravel in one JSON

I am trying to get all attributes in one JSON.
Eg:
Consider I have a table "place" with "id","name","description" as attributes.
Now,
I have another table "region" with "id","name","place_id","description" as attributes(or) schema.
There is one to many relationship between place and region.
And now,I define another table "street" with "id","name","region_id" as its schema.
There is again One to Many relationship between "region" and "street".
I want to get all details which comes in one place.If there is some place "1,banglore,garden city" and there are two regions with that place_id as
"{"1,r.t.nagar,1,region in banglore"},{"2,ashok nagar,1,region in banglore"}".Here "1" is foreign key referring id of "banglore's id(1)".
Now,similarly if each region has 3 streets in street table.I want to get all the values in one JSON. I know that we can get this with foreach .But,i want an efficient solution to get all nested relationship to my Place model from Region,Street in JSON.
Thanks.
You first need to define one to many relations like:
class Places extends Eloquent{
....
public function regions()
{
return $this->hasMany('App\Region');
}
...
}
And the same to streets:
class Regions extends Eloquent{
....
public function streets()
{
return $this->hasMany('App\Street');
}
....
}
Note that I have assumed that your models stay within App folder and have corresponding namespaces.
After that you can get you model like:
Place::with('regions.streets')->get();
Which will automatically nest all relations and cast to JSON if you send a json response.

Relationship mapping with NeoEloquent

I'm tinkering with Neo4j 2.3.0 and Laravel 5.1 using NeoEloquent. I've set up a couple of dummy nodes and some relationships between them:
image of Neo4j model - apologies, I cannot insert images directly yet :)
So articles can use a template. The inverse of this relationship is that a template is used by an article.
I've set up the classes like so:
Class Template extends Model
{
public function articles()
{
return $this->hasMany('App\Article', 'USED_BY');
}
}
And:
Class Article extends Model
{
public function template()
{
return $this->belongsTo('App\Template', 'USES');
}
}
So far, so good, I think.
I have a page where I am wanting to eventually list all of the articles in the system, along with some useful metadata, like the template each ones uses. For this, I have set something up in the controller:
$articles = array();
foreach (Article::with('template')->get() as $article) {
array_push($articles, $article);
}
return $articles;
Not the most elegant, but it should return the data for both the article and it's associated template. However:
[{"content":"Some test content","title":"Test Article","id":28,"template":null},{"content":"Some flibble content","title":"Flibble","id":31,"template":null}]
So the question is - why is this returning null?
More interestingly, if I set up the relationship to the same thing in BOTH directions, it returns the values. i.e. if I change the USED_BY to USES, then the data is returned, but this doesn't make sense from an architectural point of view - a template does not 'use' an article.
So what am I missing?
More interestingly, if I set up the relationship to the same thing in BOTH directions, it returns the values.
That's correct, because this is how it operates. It is worth knowing that the relationship methods you have defined represent the relationship itself, which means for both models Template and Article to target the USED_BY relationship from any side it has to be the same in articles() and template.
The solution would be to use something like USES (or any notion you like) on both sides. This reference should help you make good decisions regarding your relationships.
On the other hand, if you still wish to have different relations on the sides then kindly note that in your model (image) both relationships are in outgoing direction. i.e. Fibble-[:USES]->Template and Template-[:USED_BY]->Fibble which means template() should be an outgoing relationship such as hasOne instead of belongsTo which is incoming.

'Method' vs 'Dynamic Property' in Eloquent ORM with Laravel?

I want to count the number of posts belongs to a tag. Should I use method or dynamic property?
<?php
class Tag extends Eloquent {
public function posts()
{
return $this->belongsToMany('Post');
}
public function postsCount()
{
return count($this->posts);
}
public function getPostsCountAttribute()
{
return count($this->posts);
}
}
So in template should I use dynamic property:
{{ $tag->postCount }}
or method:
{{ $tag->postCount() }}
Excerpt from the documentation of Laravel 4 regarding Eloquent's Dynamic Properties (accessor) in relationships (bold are mine):
Eloquent allows you to access your relations via dynamic properties. Eloquent will automatically load the relationship for you, and is even smart enough to know whether to call the get (for one-to-many relationships) or first (for one-to-one relationships) method. It will then be accessible via a dynamic property by the same name as the relation.
That said, using the method defined for the database relationship or the dynamic property (accessor) will behave differently.
If you issue the post count using the method as follows:
$count = $tag->posts()->count();
That will generate the proper SQL with the COUNT aggregate function.
In the other hand, if you issue the post count using the dynamic property (accessor) as follows:
$count = count($tag->posts);
That will fetch all the posts, convert them to an array of objects, then counting the number of element of the array.
In your case, the choice should depend of the usage of the posts related to a tag. If you just want to count, then use the method and the aggregate function. But, if apart from counting you will be doing something else with those posts, then use the dynamic property (accessor).

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