I've following query:
$visible = array(1,2,3);
$views = DB::table('ims_view')
->Where(function($query) {
$query->where('iv_status', 1)->whereIn('id', $visible);
})->orderBy('iv_name', 'asc')->get();
Error: Undefined variable: visible
How to pass the variabnle to inner where?
you have to use the variable you want passed into the scope like so:
use ($visible)
`$views = DB::table('ims_view')
->Where(function($query) use ($visible){
$query->where('iv_status', 1)
->whereIn('id', $visible);
})->orderBy('iv_name', 'asc')->get();`
Related
In laravel, I can use many where rules as an array a run one query to the database using laravel eloquent where method to get needed result.
Code:
$where = [];
$where[] = ['user_id', '!=', null];
$where[] = ['updated_at', '>=', date('Y-m-d H:i:s')];
if($request->searchTerm) {
$where[] = ['title', 'like', '%' . $request->searchTerm . '%'];
}
Model::where($where)->get();
Question part:
Now I need to use Laravel Eloquent method whereIn with array params to get needed result with one query.
I tried by looping method but with many queries to the database.
Code:
$model = new Model;
$whereIn = [];
$whereIn[] = ['date', '>=', Carbon::now()->subDays(10)];
$whereIn[] = ['user_role', 'candidate'];
if (!empty($scope) && is_array($scope)) {
$whereIn[] = ['user_id', $scope];
}
if(is_array($employment) && !empty($employment)) {
$whereIn[] = ['employment', $employment];
}
if(is_array($experience) && !empty($experience)) {
$whereIn[] = ['experience', $experience];
}
foreach ($whereIn as $v) {
$model = $model->whereIn($v[0], $v[1]);
}
dump($model->get());
First I tired $model->whereIn($whereIn)->get() but it's return error. It's possible get results with one query using whereIn without looping?
Note: My $whereIn array will be dynamic array!
whereIn is a query builder function so you can't use it on the model directly. Instead you should create a query builder instance. I also suggest you use when instead of the if statements:
$models = Model::when(!empty($scope) && is_array($scope), function ($query) use ($scope) {
$query->whereIn('user_id', $scope);
})->when(!empty($employment) && is_array($employment), function ($query) use ($employment) {
$query->whereIn('employment', $employment);
})->when(!empty($experience) && is_array($experience), function ($query) use ($experience) {
$query->whereIn('experience', $experience);
})->get();
dump($models);
when essentially runs the function when the first parameter is true. There's more detail in the documentation under conditional clauses.
Since your $whereIn variable is an array of arrays it will work like :
$model->whereIn($whereIn[0][0], $whereIn[0][1])->get();
If it just a simple array then you can use :
$model->whereIn($whereIn[0], $whereIn[1])->get();
Do in Eloquent
$model = Model::whereIn('id', array(1, 2, 3))->get();
Or using Query builder then :
$model = DB::table('table')->whereIn('id', array(1, 2, 3))->get();
I have a database query as below:
$data = DB::table('settings')->select('value')->where('name', '=', $name)->get();
echo $data["value"];
but it gives error:
Undefined index: value
if I echo $data; then I get below result:
[{"value":"theme_default"}]
get() returns a Laravel Collection object, which has magic methods to turn itself into a string when you try to use it as such (like with an echo statement). As you can see in the JSON that you've printed, $data is an array or collection of objects, so you want the first one in the collection before trying to get the value:
$row = $data->first();
echo $row->value;
Try this:
$data = DB::table('settings')->select('value')->where('name', '=', $name)->first();
echo $data["value"];
//or
echo $data->value;
You can turn the result into an array like this:
$data = DB::table('settings')
->select('value')
->where('name', '=', $name)
->get()
->toArray();
//then use the value of the first element
dd(#$data[0]['value']);
, but I strongly suggest that you use the Laravel Collection in order to make use of its powerful methods.
I'm getting the error of undefined when() method in laravel 5 when use Database: Query Builder Conditional Statements
https://laravel.com/docs/5.2/queries#conditional-statements
Call to undefined method Illuminate\Database\Query\Builder::when()
$job = $request->input('Job');
$EmpDetails = DB::table('EMPLOYEES')->when($job, function ($query) {
return $query->where('Job', '=', $job);
})->get();
print_r($EmpDetails);
$EmpDetails = DB::table('EMPLOYEES')->where('JOB',$job)->get();
I think this should work.
Edit: You might want to use advance where. In that case:
$EmpDetails = DB::table('EMPLOYEES')->where(function($query) use ($job)
{
$query->where('JOB',$job);
})->get()
I have a code:
$response = $this->posts
->where('author_id', '=', 1)
->with(array('postComments' => function($query) {
$query->where('comment_type', '=', 1);
}))
->orderBy('created_at', 'DESC')
->limit($itemno)
->get();
And when I logged this query with:
$queries = \DB::getQueryLog();
$last_query = end($queries);
\Log::info($last_query);
In log file I see follow:
"select * from `post_comments` where `post_comments`.`post_id` in (?, ?, ?, ?) and `comment_type` <> ?"
Why is the question mark for comment_type in the query?
Update #1:
I replaced current code with following and I get what I want. But I'm not sure it is OK. Maybe exists many better, nicer solution.
$response = $this->posts
->where('author_id', '=', 1)
->join('post_comments', 'post_comments.post_id', '=', 'posts.id')
->where('comment_type', '=', 1)
->orderBy('created_at', 'DESC')
->limit($itemno)
->get();
Behind the scene the PDO is being used and it's the way that PDO does as a prepared query, for example check this:
$title = 'Laravel%';
$author = 'John%';
$sql = "SELECT * FROM books WHERE title like ? AND author like ? ";
$q = $conn->prepare($sql);
$q->execute(array($title,$author));
In the run time during the execution of the query by execute() the ? marks will be replaced with value passed execute(array(...)). Laravel/Eloquent uses PDO and it's normal behavior in PDO (PHP Data Objects). There is another way that used in PDO, which is named parameter/placeholder like :totle is used instead of ?. Read more about it in the given link, it's another topic. Also check this answer.
Update: On the run time the ? marks will be replaced with value you supplied, so ? will be replaced with 1. Also this query is the relational query, the second part after the first query has done loading the ids from the posts table. To see all the query logs, try this instead:
$queries = \DB::getQueryLog();
dd($queries);
You may check the last two queries to debug the queries for the following call:
$response = $this->posts
->where('author_id', '=', 1)
->with(array('postComments' => function($query) {
$query->where('comment_type', '=', 1);
}))
->orderBy('created_at', 'DESC')
->limit($itemno)
->get();
Update after clarification:
You may use something like this if you have setup relation in your Posts model:
// $this->posts->with(...) is similar to Posts::with(...)
// if you are calling it directly without repository class
$this->posts->with(array('comments' =. function($q) {
$q->where('comment_type', 1);
}))
->orderBy('created_at', 'DESC')->limit($itemno)->get();
To make it working you need to declare the relationship in your Posts (Try to use singular name Post if possible) model:
public function comments()
{
return $this->hasmany('Comment');
}
Your Comment model should be like this:
class Comment extends Eloquent {
protected $table = 'post_comments';
}
Laravel Advance Query Builder not seeing parent method variable
public function read($status=null,$skip=0,$take=10,$orderby=array())
{
$table = DB::table('users')
->skip($skip)
->take($take)
->where(function($query) {
if($status)
$query->where('status','!=',$status);
});
}
This returns an error which $status variable undefined inside the advance where query. Is there anything to extend?
If you want to use variables in your closure, you must include them.
Change
->where(function($query) {
to
->where(function($query) use ($status) {