In laravel, I can use many where rules as an array a run one query to the database using laravel eloquent where method to get needed result.
Code:
$where = [];
$where[] = ['user_id', '!=', null];
$where[] = ['updated_at', '>=', date('Y-m-d H:i:s')];
if($request->searchTerm) {
$where[] = ['title', 'like', '%' . $request->searchTerm . '%'];
}
Model::where($where)->get();
Question part:
Now I need to use Laravel Eloquent method whereIn with array params to get needed result with one query.
I tried by looping method but with many queries to the database.
Code:
$model = new Model;
$whereIn = [];
$whereIn[] = ['date', '>=', Carbon::now()->subDays(10)];
$whereIn[] = ['user_role', 'candidate'];
if (!empty($scope) && is_array($scope)) {
$whereIn[] = ['user_id', $scope];
}
if(is_array($employment) && !empty($employment)) {
$whereIn[] = ['employment', $employment];
}
if(is_array($experience) && !empty($experience)) {
$whereIn[] = ['experience', $experience];
}
foreach ($whereIn as $v) {
$model = $model->whereIn($v[0], $v[1]);
}
dump($model->get());
First I tired $model->whereIn($whereIn)->get() but it's return error. It's possible get results with one query using whereIn without looping?
Note: My $whereIn array will be dynamic array!
whereIn is a query builder function so you can't use it on the model directly. Instead you should create a query builder instance. I also suggest you use when instead of the if statements:
$models = Model::when(!empty($scope) && is_array($scope), function ($query) use ($scope) {
$query->whereIn('user_id', $scope);
})->when(!empty($employment) && is_array($employment), function ($query) use ($employment) {
$query->whereIn('employment', $employment);
})->when(!empty($experience) && is_array($experience), function ($query) use ($experience) {
$query->whereIn('experience', $experience);
})->get();
dump($models);
when essentially runs the function when the first parameter is true. There's more detail in the documentation under conditional clauses.
Since your $whereIn variable is an array of arrays it will work like :
$model->whereIn($whereIn[0][0], $whereIn[0][1])->get();
If it just a simple array then you can use :
$model->whereIn($whereIn[0], $whereIn[1])->get();
Do in Eloquent
$model = Model::whereIn('id', array(1, 2, 3))->get();
Or using Query builder then :
$model = DB::table('table')->whereIn('id', array(1, 2, 3))->get();
Related
I have have 3 tables in my projects they are:
products(can have Multiple Variants)
variants (belongsto product)
product_attributes (this have product_id,attribute_id,value_id)
I want to filter variants from a product by value ids thats comes from form request as example (1,2,6)
I have tried like this:
$poruduct_id = $request->product_id;
$value_ids = $request->value_ids;
$searched_variants = Variant::whereHas('product.attributeValues', function ($query) use ($value_ids, $product_id) {
$query->whereIn('value_id', [$value_ids]);
})->where('product_id', $product_id)->get();
dd($searched_variants);
But the problem is the query returns all records from the product. What is the solution to filter exactly the values that the product Variants have?
Thank you.
-UPDATED-
I have tried like this but nothing changed
$searched_variants = Variant::select('product_id')->whereHas('product.attributeValues', function ($query) use ($value_ids, $product_id) {
$query->whereIn('value_id', [$value_ids]);
})->groupBy('product_id')
->havingRaw('COUNT(*) = ?', [count((array) $value_ids)])
->get();
-**FİNALLY SOLUTİON**-
I made it like this : I get the value code that is in for example Large the code is L
get all the codes to controller and executed this query ı hope this helps someone
1.$value_codes=$request->value_codes;
2.$value_codes_array=explode(',',$value_codes);
3.$product_id=$request->product_id;
4.$searchValues = preg_split('/,/', $value_codes_array, -1, PREG_SPLIT_NO_EMPTY);
$searchValues = preg_split('/,/', $value_idss, -1, PREG_SPLIT_NO_EMPTY);
$variants= Variant::where(function ($q) use ($searchValues) {
foreach ($searchValues as $value) {
$q->orWhere('sku', 'like', "%-{$value}")
->orWhere('sku', 'like', "%-{$value}-%")
->orWhere('sku', 'like', "{$value}-%");
}
})->where('product_id',$product_id)->get();
dd($variants);
If you have n variants to one product, you query should be like:
Product Model
public function variants: HasMany relationships
//usage
$produtc->variants->and here the query function
You need to use it in this way, it should work:
$productId = $request->product_id;
$valueIds = $request->value_ids;
$searchedVariants = Variant::whereHas('product.attributeValues', function ($query) use ($valueIds) {
$query->distinct()->whereIn('value_id', $valueIds);
}, '=', count($valueIds))->where('product_id', $productId)->get();
I am making an app that filters products
I want to add this query chunk to my $products = $products-> newQuery();
I'm using $products = $products-> newQuery(); Because I am querying with filters. Example:
$products = $products->newQuery();
if ($request->has('brand') && !empty($brand)) {
$products->where('brand', '=', $brand);
}
if ($request->has('size') && !empty($size)) {
$products->whereHas('stocks', function($query) use ($size) {
$query->where('size', '=', $size);
});
}
I want to add this query
$best_sellers = OrderItem::select('product_id')->groupBy('product_id')->orderByRaw('SUM(quantity) DESC')->limit(2)->get();
I have previously used it in another method and it works but I don't know how to integrate it
I tried:
$products->whereHas('order_items', function($query) {
$query->select('product_id')->groupBy('product_id')->orderByRaw('SUM(quantity) DESC');
});
But it hasn't worked
Any idea? thanks
Updated with Error:
you need to use with() to add relationship data whereHas() it just for filter it does not add new key
example
$products->with(['order_items'=> function ($q) {
$q->select('product_id')->groupBy('product_id')->orderByRaw('SUM(quantity) DESC')->limit(2)->get();
}]);
I am trying to get all rows and distinct column from single query. but paginate method is only giving result but not pagination option like total prev next etc..
$offers = Offer::whereHas('users', function ($q) use ($authUser) {
$q->where('user_id', $authUser->parent_id);
$q->where('publisher_id', '=', $authUser->id);
});
and distinct column
$websites = $offers->distinct()->get(['website']);
with pivot columns (just wanted to show my full query)
$offers->orderBy($sortBy, $orderBy)->paginate($perPage)->map(function ($offer) {
if (!empty($offer->users)) {
$manager = $publisher = '';
foreach ($offer->users as $user) {
$manager = $user->pivot->user_id;
$publisher = $user->pivot->publisher_id;
}
$offer->manager = $manager;
$offer->publisher = $publisher;
}
return $offer;
});
Return
return response()->json([
'offers' => $offers,
'websites' => $websites
], 200);
hope my question will make sense.
Thanks.
You should run getCollection() before mapping to get the paginator's underlying collection.
(https://laravel.com/api/7.x/Illuminate/Pagination/LengthAwarePaginator.html#method_getCollection)
$offers->orderBy($sortBy, $orderBy)->paginate($perPage)
->getCollection()
->map(function ($offer) {
// ...
return $offer;
});
I'm answering based on it being $offers:
Your usage of map() is copying the modified results of your paginate() call to a new collection and that collection does not include the pagination information. That's why you no longer have pagination information.
Since there result of paginate() is already a usable collection, you can use each() instead of map() which will alter the objects in-place.
i have a simple question as i do not know which line i should add into to get laravel pagination. (->paginate(5).
public function index(Request $request)
{
$codeSearch = $request->get('code');
$descriptionSearch = $request->get('description');
//$tmp = Category::all()->toArray();
$tmp = Category::where('code','like','%' .$codeSearch. '%')->where('description','like','%' .$codeSearch. '%')->get()->toArray();
$category = array();
foreach ($tmp as $key => $row) {
$policy = Category::find($row['parent_id']);
$tmpResult = new Category();
$tmpResult->id = $row['id'];
$tmpResult->code = $row['code'];
$tmpResult->description = $row['description'];
$tmpResult->parent_id = $policy['description'];
$tmpResult->status = $row['status'];
array_push($category, $tmpResult);
}
return view('category.index', compact('category'));
}
Paginate can't be called on the collection, so you have to run it on the query, by simply replace ->get() with ->paginate(5) like this
$tmp = Category::where('code','like','%' .$codeSearch. '%')
->where('description','like','%' .$codeSearch. '%')
->paginate(5)
->toArray();
Try
$tmp = Category::where('code','like','%' .$codeSearch. '%')->where('description','like','%' .$codeSearch. '%')->paginate(5);
In view
#foreach($tmp as $tm)
//whatever operation you like to do
#endforeach
{{$tmp->links()}}
The following ->get(), ->first(), all() get the results from the database and so does ->paginate(5), so I would suggest that you replace ->get() with paginate(5) an you can get rid of toArray() because the result will be a collection with which you can use foreach() or get a value by index.
As you need an array in your condition, then you can simply convert the final array into a collection object and use the pagination concept.
$items = [
'item1',
'item2',
'item3',
'item4',
'item5',
'item6',
'item7',
'item8',
'item9',
'item10'
];
// Get current page form url e.x. &page=1
$currentPage = LengthAwarePaginator::resolveCurrentPage();
// Create a new Laravel collection from the array data
$itemCollection = collect($items);
// Define how many items we want to be visible in each page
$perPage = 1;
// Slice the collection to get the items to display in current page
$currentPageItems = $itemCollection->slice(($currentPage * $perPage) - $perPage, $perPage)->all();
// Create our paginator and pass it to the view
$paginatedItems= new LengthAwarePaginator($currentPageItems , count($itemCollection), $perPage);
// set url path for generted links
$paginatedItems->setPath($request->url());
return view('items_view', ['items' => $paginatedItems]);
It would probably be easier to have a relationship setup for a Category's parent. Then you can load the parent when you retrieve the categories.
class Category extends Model
{
...
public function parent()
{
return $this->belongsTo(self::class);
}
}
I feel like your search is probably trying to do an OR WHERE, search the code field for this value or the description:
$categories = Category::with('parent')
->where('code', 'like', '%' .$codeSearch. '%')
->orWhere('description', 'like', '%' .$codeSearch. '%')
->paginate(5);
Then in your view if you want the parent category's description you can get it through the relationship:
#foreach ($categories as $category)
parent description: {{ $category->parent->description }}
#endforeach
I have the following relationship functions in my Job model:
public function resourceTypes(){
return $this->belongsToMany('ResourceType', 'job_requests');
}
public function resources(){
return $this->belongsToMany('Resource', 'jobs_resources')->withPivot('flow_type', 'resource_type_id');
}
I am able to get an object with data from both of the above relationships using:
$job = Job::findorfail($projectId);
$result = $job->with('resources.resourceTypes')->get();
I would like to put a where clause on the jobs_resources pivot table - specifically on the column flow_type.
How would I do this?
Try something like this:
$job = Job::with('resources' => function($q) {
$q->with('resourceTypes')->where('flow_type',2);
})->findorfail($projectId);
In above you will get only those resources with flow_type = 2
I ended up using the following statement:
Job::with(['resources' => function ($query){
$query->wherePivot('flow_type', '=', '1' );
}, 'resources.resourceTypes'])->where('id', $projectId)->firstOrFail();
$result = DB::table('job')
->join('job_resources', 'job.id', '=', 'job_resources.job_id')
->join('job_requests', 'job_resources.request_id', '=', 'job_requests.id')
->where('job_resources.flow_type', '=', CONDITION)
->get();
Your table data is not clear from your input, but this method (query builder) should work