End program after breaking from loop - c++11

Question

while (1)
{
cout << "Enter number and unit: ";
cin >> number;
cin >> unit;
if (unit == "in")
{
result = 2.54f * number;
cout << number << " Inches are " << result << " centimeters!" << endl;
}
else if (unit == "ft")
{
result = 0.3f * number;
cout << number << " Feet are " << result << " meters!" << endl;
}
else if (unit == "yd")
{
result = 0.9f * number;
cout << number << " Yards are " << result << " meters!" << endl;
}
else if (unit == "mi")
{
result = 1.6f * number;
cout << number << " Miles are " << result << " kilometers!" << endl;
}
else
{
cout << "\tINVALID!!!\n...the program will now exit...\n";
cin.clear();
cin >> unit;
cin >> number;
break;
}
}
cout << "Thank you for using English to Metric!\n" << endl;
return 0;}
What am I missing in order to get the last cout and exit the program without having to input anything after break?

Answer 1

The break in the else clause will exit the loop, but immediately before it you perform
cin.clear();
cin >> unit;
cin >> number;
break;
The cin >>s are why the program is waiting for additional input.
Without them, the cin.clear() is unnecessary, unless you plan to do additional cin operations later.
else
{
std::cin.clear(); // optional
break;
}
} // end while
std::cout << "Thank you\n";
Will work.