Replace printf with cout statements - shell

Question

I'm trying to write a script which could inline replace a printf statement with the cout statement. It could be either in sed or awk.
For example, if printf statement is
printf("int=%d, str=%s", i, s) ;
Then it should be replaced with :
cout << "int=" << i << ", str=" << s;
printf statement could have any no. of arguments. Accordingly, cout statement should be generated and replaced inline.
Other such examples could be:
printf("Statement2: %d %d %s %f", i, j, s ,f);
printf("statement3: %d %f",
i,
f);
CString failedMsg;
failedMsg.Format(_T("FAILED Triggered=%d expected=%d in %s"),
(int)i,
(int)j,
static_cast<LPCTSTR>(__TFUNCTION__));
Output:
cout << "Statement2: " << i << " " << j << " " << s << " " << f;
cout << "statement3: " << i << " " << f;
std::stringstream failedMsg;
failedMsg << "FAILED Triggered=" << (int)i
<< " expected=" << (int)i
<< " in " << __TFUNCTION__;
Yes, I'm new to StackOverflow. I'll learn the way how it works and how to ask for help. But for right now I'll just request for your gracious support to solve this.
Thanks.

Answer 1

───▄██▄─██▄───▄
─▄██████████▄███▄
─▌████████████▌
▐▐█░█▌░▀████▀░░
░▐▄▐▄░░░▐▄▐▄░░░░
using Perl if your printf function is on a single line not separate line; otherwise I think you cannot
for something like:
printf("int=%d, str=%s", i, s) ;
std::cout << "one" << '\n'; // just for sure
printf("one=%d, two=%d, three=%d, four=%d, five=%d", a, b , c, d , e);
for( int i = 0; i < 10; ++i ){
std::cout << i << '\n';
}
you can:
perl -ne '$T=0;/printf/ && s/printf|[ ",;()]+|%[a-z]/ /g && (#A=split) && ($T=1);if($T){$s=($#A+1)/2;$n=0;print "std::cout << ";print "\"$A[$n] \" << $A[$n+++$s] << " for 1..$s;print q("\n":),"\n";}else{print}' file
the output:
std::cout << "int= " << i << "str= " << s << "\n":
std::cout << "one" << '\n'; // just for sure
std::cout << "one= " << a << "two= " << b << "three= " << c << "four= " << d << "five= " << e << "\n":
for( int i = 0; i < 10; ++i ){
std::cout << i << '\n';
}
For something like:
printf("Statement2: %d %d %s %f", i, j, s ,f);
std::cout << "one" << '\n'; // just for sure
printf("Statement2: %d %d %s %f", i, j, s ,f);
for( int i = 0; i < 10; ++i ){
std::cout << i << '\n';
}
You can use: ( as script.sh )
perl -ne '$T=0;/printf/ && s/printf|[ ",;()]+|%[a-z]/ /g && (#A=split) && ($T=1);if($T){$n=0;print "std::cout << \"$A[0] \" << ";print " $A[++$n] <<" for 1..$#A-1;print q( "\n"),"\n"; }else{print}' file
the output:
std::cout << "Statement2: " << i << j << s << "\n"
std::cout << "one" << '\n'; // just for sure
std::cout << "Statement2: " << i << j << s << "\n"
for( int i = 0; i < 10; ++i ){
std::cout << i << '\n';
}