How Hive reads data even after dropping from hdfs? - hadoop

I have an external table in hive and pointing to HDFS location. By mistake I have ran the job to load the data into HDFS two times.
Even after deleting the duplicate file from HDFS hive is showing the data count two times(i.e. including deleted duplicate data file count).
select count(*) from tbl_name -- returns double time
But ,
select count(col_name) from tbl_name -- returns actual count.
Same table when I tried from Impala after
INVALIDATE METADATA
I could see only data count which is available in HDFS(not duplicate).
How can hive give count as double even after deleting from physical location(hdfs) , does it read from statistics?

Hive is using statistics for computing cont(*). You deleted files manually (not using Hive) that is why the stats is wrong.
The solution is:
to switch-off statistics usage in such cases:
set hive.compute.query.using.stats=false;
to analyze table as you mention in your comment:
analyze table tbl_name partition(a,b,c) compute statistics;

Related

Unable to partition hive table backed by HDFS

Maybe this is an easy question but, I am having a difficult time resolving the issue. At this time, I have an pseudo-distributed HDFS that contains recordings that are encoded using protobuf 3.0.0. Then, using Elephant-Bird/Hive I am able to put that data into Hive tables to query. The problem that I am having is partitioning the data.
This is the table create statement that I am using
CREATE EXTERNAL TABLE IF NOT EXISTS test_messages
PARTITIONED BY (dt string)
ROW FORMAT SERDE
"com.twitter.elephantbird.hive.serde.ProtobufDeserializer"
WITH serdeproperties (
"serialization.class"="path.to.my.java.class.ProtoClass")
STORED AS SEQUENCEFILE;
The table is created and I do not receive any runtime errors when I query the table.
When I attempt to load data as follows:
ALTER TABLE test_messages_20180116_20180116 ADD PARTITION (dt = '20171117') LOCATION '/test/20171117'
I receive an "OK" statement. However, when I query the table:
select * from test_messages limit 1;
I receive the following error:
Failed with exception java.io.IOException:java.lang.IllegalArgumentException: FieldDescriptor does not match message type.
I have been reading up on Hive table and have seen that the partition columns do not need to be part of the data being loaded. The reason I am trying to partition the date is both for performance but, more so, because the "LOAD DATA ... " statements move the files between directories in HDFS.
P.S. I have proven that I am able to run queries against hive table without partitioning.
Any thoughts ?
I see that you have created EXTERNAL TABLE. So you cannot add or drop partition using hive. you need to create a folder using hdfs or MR or SPARK. EXTERNAL table can only be read by hive but not managed by HDFS. You can check the hdfs location '/test/dt=20171117' and you will see that folder has not been created.
My suggestion is create the folder(partition) using "hadoop fs -mkdir '/test/20171117'" then try to query the table. although it will give 0 row. but you can add the data to that folder and read from Hive.
You need to specify a LOCATION for an EXTERNAL TABLE
CREATE EXTERNAL TABLE
...
LOCATION '/test';
Then, is the data actually a sequence file? All you've said is that it's protobuf data. I'm not sure how the elephantbird library works, but you'll want to double check that.
Then, your table locations need to look like /test/dt=value in order for Hive to read them.
After you create an external table over HDFS location, you must run MSCK REPAIR TABLE table_name for the partitions to be added to the Hive metastore

Set ORC file name

I'm currently implementing ETL (Talend) of monitoring data to HDFS, and Hive table.
I am now facing concerns about duplicates. More in details, if we need to run one ETL Job 2 times with the same input, we will end up with duplicates in our Hive table.
The solution to that in RDMS would have been to store the input file name and to "DELETE WHERE file name=..." before sending the data. But Hive is not a RDBMS, and does not support deletes.
I would like to have your advice on how to handle this. I envisage two solutions :
Actually, the ETL is putting CSV files to the HDFS, which are used to feed an ORC table with a "INSERT INTO TABLE ... SELECT ..." The problem is that, with this operation, I'm losing the file name, and the ORC file is named 00000. Is it possible to specify the file name of this created ORC file ? If yes, I would be able to search the data by it's file name and delete it before launching the ETL.
I'm not used to Hive's ACID capability (feature on Hive 0.14+). Would you recommend to enable ACID with Hive ? Will I be able to "DELETE WHERE" with it ?
Feel free to propose should you have any other solution to that.
Bests,
Orlando
If the data volume in target table is not too large, I would advise
INSERT INTO TABLE trg
SELECT ... FROM src
WHERE NOT EXISTS
(SELECT 1
FROM trg x
WHERE x.key =src.key
AND <<additional filter on target to reduce data volume>>
)
Hive will automatically rewrite the correlated sub-query into a MapJoin, extracting all candidate keys in target table into a Java HashMap, and filtering source rows on-the-fly. As long as the HashMap can fit in the RAM available for Mappers heap size (check your default conf files, increase with a set command in Hive script if necessary) the performance will be sub-optimal, but you can be pretty sure that you will not have any duplicate.
And in your actual use case you don't have to check each key but only a "batch ID", more precisely the original file name; the way I've done it in my previous job was
INSERT INTO TABLE trg
SELECT ..., INPUT__FILE__NAME as original_file_name
FROM src
WHERE NOT EXISTS
(SELECT DISTINCT 1
FROM trg x
WHERE x.INPUT__FILE__NAME =src.original_file_name
AND <<additional filter on target to reduce data volume>>
)
That implies an extra column in your target table, but since ORC is a columnar format, it's the number of distinct values that matter -- so that the overhead would stay low.
Note the explicit "DISTINCT" in the sub-query; a mature DBMS optimizer would automatically do it at execution time, but Hive does not (not yet) so you have to force it. Note also the "1" is just a dummy value required because of "SELECT" semantics; again, a mature DBMS would allow a dummy "null" but some versions of Hive would crash (e.g. with Tez in V0.14) so "1" or "'A'" are safer.
Reference:
https://cwiki.apache.org/confluence/display/Hive/LanguageManual+SubQueries#LanguageManualSubQueries-SubqueriesintheWHEREClause
https://cwiki.apache.org/confluence/display/Hive/LanguageManual+VirtualColumns
I'm answering myself. I found a solution :
I partitionned my table with (date,input_file_name) (note, I can get the input_file_name with SELECT INPUT__FILE__NAME in Hive.
Once I did this, before running the ETL, I can send to Hive an ALTER TABLE DROP IF EXISTS PARTITION (file_name=...) so that the folder containing the input data is deleted if this INPUT_FILE has already been sent to the ORC table.
Thank you everyone for your help.
Cheers,
Orlando

Hive count(*) query is not invoking mapreduce

I have external tables in hive, I am trying to run select count(*) from table_name query but the query returns instantaneously and gives result which is i think already stored. The result returned by query is not correct. Is there a way to force a map reduce job and make the query execute each time.
Note: This behavior is not followed for all external tables but some of them.
Versions used : Hive 0.14.0.2.2.6.0-2800, Hadoop 2.6.0.2.2.6.0-2800 (Hortonworks)
After some finding I have got a method that kicks off MR for counting number of records on orc table.
ANALYZE TABLE 'table name' PARTITION('partition columns') COMPUTE STATISTICS;
--OR
ANALYZE TABLE 'table name' COMPUTE STATISTICS;
This is not a direct alternative for count(*) but provides latest count of records in the table.
Doing a wc -l on ORC data won't give you an accurate result, since the data is encoded. This would work if the data was stored in a simple text file format with one row per line.
Hive does not need to launch a MapReduce for count(*) of an ORC file since it can use the ORC metadata to determine the total count.
Use the orcfiledump command to analyse ORC data from the command line
https://cwiki.apache.org/confluence/display/Hive/LanguageManual+ORC#LanguageManualORC-ORCFileDumpUtility
From personal experience, COUNT(*) on an ORC table usually returns wrong figures -- i.e. it returns the number of rows on the first data file only. If the table was fed by multiple INSERTs then you are stuck.
With V0.13 you could fool the optimizer into running a dummy M/R job by adding a dummy "where 1=1" clause -- takes much longer, but actually counts the rows.
With 0.14 the optimizer got smarter, you must add a non-deterministic clause e.g. "where MYKEY is null". Assuming that MYKEY is a String, otherwise the "is null" clause may crash your query -- another ugly ORC bug.
By the way, a SELECT DISTINCT on partition key(s) will also return wrong results -- all existing partitions will be shown, even the empty ones. Not specific to ORC this time.
please try the below :
hive>set hive.fetch.task.conversion=none in your hive session and then trigger select count(*) operation in your hive session to mandate mapreduce

How Load distributed data in Hive works?

My target is to perform a SELECT query using Hive
When I have a small data on a single machine (namenode), I start by:
1-Creating a table that contains this data: create table table1 (int col1, string col2)
2-Loading the data from a file path: load data local inpath 'path' into table table1;
3-Perform my SELECT query: select * from table1 where col1>0
I have huge data, of 10 millions rows that doesn't fit into a single machine. Lets assume Hadoop divided my data into for example 10 datanodes and each datanode contains 1 million row.
Retrieving the data to a single computer is impossible due to its huge size or would take alot of time in case it is possible.
Will Hive create a table at each datanode and perform the SELECT query
or will Hive move all the data a one location (datanode) and create one table? (which is inefficient)
Ok, so I will walk through what happens when you load data into Hive.
The 10 million line file will be cut into 64MB/128MB blocks.
Hadoop, not Hive, will distribute the blocks to the different slave nodes on the cluster.
These blocks will be replicated several times. Default is 3.
Each slave node will contain different blocks that make up the original file, but no machine will contain every block. However, since Hadoop replicates the blocks there must be at least enough empty space on the cluster to accommodate 3x the file size.
When the data is in the cluster Hive will project the table onto the data. The query will be run on the machines Hadoop chooses to work on the blocks that make up the file.
10 million rows isn't that large though. Unless the table has 100 columns you should be fine in any case. However, if you were to do a select * in your query just remember that all that data needs to be sent to the machine that ran the query. That could take a long time depending on file size.
I hope I covered your question. If not please let me know and I'll try to help further.
The query
select * from table1 where col1>0
is just a map side job. So the data block is processed locally at every node. There is no need to collect data centrally.

updating Hive external table with HDFS changes

lets say, I created Hive external table "myTable" from file myFile.csv ( located in HDFS ).
myFile.csv is changed every day, then I'm interested to update "myTable" once a day too.
Is there any HiveQL query that tells to update the table every day?
Thank you.
P.S.
I would like to know if it works the same way with directories: lets say, I create Hive partition from HDFS directory "myDir", when "myDir" contains 10 files. next day "myDIr" contains 20 files (10 files were added). Should I update Hive partition?
There are two types of tables in Hive basically.
One is Managed table managed by hive warehouse whenever you create a table data will be copied to internal warehouse.
You can not have latest data in the query output.
Other is external table in which hive will not copy its data to internal warehouse.
So whenever you fire query on table then it retrieves data from the file.
SO you can even have the latest data in the query output.
That is one of the goals of external table.
You can even drop the table and the data is not lost.
If you add a LOCATION '/path/to/myFile.csv' clause to your table create statement, you shouldn't have to update anything in Hive. It will always use the latest version of the file in queries.

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