#include <iostream>
using namespace std;
//prints the board with labels for options.
void print(const char board[3][3]) //function prototype
{
for(int Row = 0; Row < 3; ++Row)
{
for(int Col =0; Col < 3; ++Col)
{
cout << board[Row][Col],;
cout << " | ";
}
}
}
int main()
{
int MaxiBoardGrid = 9;
char board[3][3];
board[0][0]='A';
board[0][1]='B';
board[0][2]='C';
board[1][0]='D';
board[1][1]='E';
board[1][2]='F';
board[2][0]='G';
board[2][1]='H';
board[2][2]='I';
print(board);
return 0;
}
DESIRED OUTPUT;
A|B|C|
------
D|E|F
------
G|H|I
I am stuck with having the lines printed and the rows in the format above.
language is C++.
I am new to 2D array and I am trying to use the basic codes I am conversant with to get the board printed. then assign player for my proposed game.
Thanks.
Related
I am supposed to write a program with three files (mysource.c, myMain.c, and mysource.h) to create a randomly generated string of characters. The length of the string is decided by the user. After the string is generated, the program will bump all letters in the string to the next letter in the alphabet to create a new offset string. I have most of the code sorted out, but my output is printing "╠╠╠╠". It prints the correct amount of characters but it is only printing those symbols. What do I need to do so that the characters print as actual letters rather than these symbols?
Here is my header file:
void generateChars(char *myarr, int len);
void offsetChars(char *myarr, int len);
void printChars(char *myarr, int len);
Here is my source code:
#include <stdio.h>
#include <stdlib.h>
#include "mysource.h"
void generateChars(char* myarr, int len)
{
int i = 0;
char letters[26] ={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o'
,'p','q','r','s','t','u','v','w','x','y','z' };
for (i = 0; i < len; i++);
{
myarr[i] = letters[rand() % 26];
}
}
//end generate function
void offsetChars(char *myarr, int len)
{
char i;
int j;
for (j = 0; j < len; j++)
{
for (i = 'a'; i <= 'z'; i++)
{
if (myarr[j] == i)
{
myarr[j] = i + 1;
break;
}
if (myarr[j] == 'z')
{
myarr[j] = 'a';
break;
}
}
}
}
//end offset function
void printChars(char *myarr, int len)
{
int i;
for (i = 0; i < len; i++)
{
printf("%c",myarr[i]);
}
}//end of print function
Here is my main code:
#include <stdio.h>
#include <stdlib.h>
#include "mysource.h"
int main()
{
int n;
printf("How many random characters do you want to
generate?: ");
scanf_s("%i", &n);
char myarr[1024];
printf("\nOriginal Combo:\n");
generateChars(&myarr, n);
printChars(&myarr, n);
printf("\nOffset Combo:\n");
offsetChars(&myarr, n);
printChars(&myarr, n);
return 0;
}
Here is the output I get:
I don't have enough reputation so this is the picture of the output
Yes there are two source codes, the objective is to make this assignment work with both source codes. Any help is appreciated!
#include <string>
#include <iostream>
#include <vector>
#include <map>
using std::map;
using std::vector;
using std::string;
typedef map<char, int> edges;
typedef vector<edges> trie;
trie build_trie(vector<string> & patterns) {
trie t;
// write your code here
for(int j=0;j<patterns.size();j++){
//current NOde = root;
int currNI=0;
for(int i=0;i<patterns[j].size();i++){
char currS = patterns[j][i];
auto it = t[currNI].begin();
//auto mit = it->edges.begin();
if(t[currNI].edges.find(currS)!=t[currNI].edges.end()){
currNI = t[currNI].edges.find(currS)->second;
}else{
t.push_back(edges.insert(currS,t.size()));
t[currNI].edges.insert(currS,t.size());
currNI = t.size();
}
}
}
return t;
}
int main() {
size_t n;
std::cin >> n;
vector<string> patterns;
for (size_t i = 0; i < n; i++) {
string s;
std::cin >> s;
patterns.push_back(s);
}
trie t = build_trie(patterns);
for (size_t i = 0; i < t.size(); ++i) {
for (const auto & j : t[i]) {
std::cout << i << "->" << j.second << ":" << j.first << "\n";
}
}
return 0;
}
Hi I was trying to build trie using vector and map but I am not able to access elements of map.
I have also added image of pseudo code for better clarity.
I have used iterators and many other tricks that are already present on stackoverflow and on other platform but somehow I am not able to access what I want.
Thank You
To answer your questions: in your code, edges is a type, not an object.
t[currNI] is of type edges, thus is a map<char, int>.
You should try t[currNI].find(currS) and t[currNI].end() directly.
NB: after you fix this, there are still other errors in your code.
I' did this program what suppose save pairs of string ,int on one vector and print the strings of the maximum number on vector
but when i try to find this strings don't appears nothing so I try print all values of int's on vector and although was finding the maximum of 10 all values in the vector was printing as 0. Someone can explain was it occurred and how I can access the values , please.
#include <iostream>
#include <utility>
#include <vector>
#include <string>
#include <algorithm>
using namespace std;
typedef vector<pair<string,int>> vsi;
bool paircmp(const pair<string,int>& firste,const pair<string,int>& seconde );
int main(int argc, char const *argv[]) {
vsi v(10);
string s;
int n,t;
cin>>t;
for (size_t i = 0;i < t;i++) {
for (size_t j = 0; j < 10; j++) {
cin>>s>>n;
v.push_back(make_pair(s,n));
}
sort(v.begin(),v.end(),paircmp);
int ma=v[v.size()-1].second;
cout<<ma<<endl;
for (size_t j = 0; j < 10; j++) {
cout << v.at(j).second <<endl;
if(v[j].second == ma)
cout<<v[j].first<<endl;
}
}
return 0;
}
bool paircmp(const pair<string,int>& firste,const pair<string,int>& seconde ){
return firste.second < seconde.second;
}
This line
vsi v(10);
creates you a std::vector filled with 10 default-constructed std::pair<std::string, int>s. That is, an empty string and zero.
You then push_back other values to your vector but they happen to be sorted after those ten initial elements, probably because they all have positive ints in them.
Therefore, printing the first member of the first ten elements prints ten empty strings.
This is all I can guess from what you have provided. I don't know what you are trying to accomplish with this code.
Try something like
for (const auto& item : v)
{
std::cout << "{ first: '" << item.first << "', "
<< "second: " << item.second << " }\n";
}
to print all elements of the vector v.
number = 100010001111111
for (int i=0; number.length(); i++) {
while number[i] == 1 {
k++;
}
}
I would like to implement a while-loop as a replacement for the for-loop as shown above.
How could I convert this to a while-loop?
Here's a solution for the problem you mentioned in your comment (Problem - 96A)
#include <iostream>
using namespace std;
int main()
{
cout << "Please enter your players situation" << endl;
std::string str;
cin >> str;
std::string::size_type i = 0;
int NumbersofAppearances = 0;
int ConsectiveNumberSequence = 7; //You can change that to whatever sequence you like
bool IsDangerous=false;
while (i < str.size())
{
if(str[i]=='1' )
{
++NumbersofAppearances;
//We need to check if we reached the consecutive number or not and save it on a different bool variable
if(NumbersofAppearances>=ConsectiveNumberSequence)
IsDangerous=true;
}
else
{
NumbersofAppearances=0;
}
++i;
}
//print out the end result
if (IsDangerous)
cout <<"YES , this is dangerous"<< endl;
else
cout <<"No, this is not dangerous"<< endl;
return 0;
}
And here's a link to Coding ground
#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;
int main()
{
string token = "000000:::AAAA:::000011:::Hello 8:::::::D Jay!";
string * stringArray = new string[token.size()];
string interim;
int r = 0;
int arrayCounter = 0;
for(int x = 0; x < token.length(); x++)
{
if(token[x] != ':')
{
interim[r] = token[x];
r++;
}
}
for (int x = 0; x < r; x++)
{
cout << interim[x] << endl;
}
system("pause");
return 0;
}
I am new and learning, and have narrowed it down to the line:
interim[r] = token[x];
..But i don't know why it crashes. Advice? I am coding in Visual C++ VSE2012
The string interim has a size of zero. Setting interim[r] = token[x] modifies the string at location r without changing its size. With a size of zero this is undefined behavior.
interim += token[x] is probably what you want.
Example:
#include <iostream>
#include <string>
using namespace std;
int main()
{
string token = "000000:::AAAA:::000011:::Hello 8:::::::D Jay!";
string interim;
for(int x = 0; x < token.length(); x++)
{
if(token[x] != ':')
{
interim += token[x];
}
}
cout << interim << endl;
system("pause");
return 0;
}
Output:
000000AAAA000011Hello 8D Jay!
Press any key to continue . . .