number = 100010001111111
for (int i=0; number.length(); i++) {
while number[i] == 1 {
k++;
}
}
I would like to implement a while-loop as a replacement for the for-loop as shown above.
How could I convert this to a while-loop?
Here's a solution for the problem you mentioned in your comment (Problem - 96A)
#include <iostream>
using namespace std;
int main()
{
cout << "Please enter your players situation" << endl;
std::string str;
cin >> str;
std::string::size_type i = 0;
int NumbersofAppearances = 0;
int ConsectiveNumberSequence = 7; //You can change that to whatever sequence you like
bool IsDangerous=false;
while (i < str.size())
{
if(str[i]=='1' )
{
++NumbersofAppearances;
//We need to check if we reached the consecutive number or not and save it on a different bool variable
if(NumbersofAppearances>=ConsectiveNumberSequence)
IsDangerous=true;
}
else
{
NumbersofAppearances=0;
}
++i;
}
//print out the end result
if (IsDangerous)
cout <<"YES , this is dangerous"<< endl;
else
cout <<"No, this is not dangerous"<< endl;
return 0;
}
And here's a link to Coding ground
Related
#include <iostream>
using namespace std;
//prints the board with labels for options.
void print(const char board[3][3]) //function prototype
{
for(int Row = 0; Row < 3; ++Row)
{
for(int Col =0; Col < 3; ++Col)
{
cout << board[Row][Col],;
cout << " | ";
}
}
}
int main()
{
int MaxiBoardGrid = 9;
char board[3][3];
board[0][0]='A';
board[0][1]='B';
board[0][2]='C';
board[1][0]='D';
board[1][1]='E';
board[1][2]='F';
board[2][0]='G';
board[2][1]='H';
board[2][2]='I';
print(board);
return 0;
}
DESIRED OUTPUT;
A|B|C|
------
D|E|F
------
G|H|I
I am stuck with having the lines printed and the rows in the format above.
language is C++.
I am new to 2D array and I am trying to use the basic codes I am conversant with to get the board printed. then assign player for my proposed game.
Thanks.
I am new and learning C++ using the Programming Principles ... book by Bjarne Stroustrup. I am working on one problem and can't figure out how to make my code work. I know the issue is with if (words[i]==bad[0, bad.size() - 1]) in particular bad.size() - 1])
I am trying to out put all words in the words vector except display a bleep instead of any words from the words vector that match any of the words in the bad vector. So I need to know if words[i] matches any of the values in the bad vector.
#include "../std_lib_facilities.h"
using namespace std;
int main()
{
vector<string> words; //declare Vector
vector<string> bad = {"idiot", "stupid"};
//Read words into Vector
for(string temp; cin >> temp;)
words.push_back(temp);
cout << "Number of words currently entered "
<< words.size() << '\n';
//sort the words
sort(words);
//read out words
for(int i = 0; i < words.size(); ++i)
if (i==0 || words[i-1]!= words[i])
if (words[i]==bad[0, bad.size() - 1])
cout << "Bleep!\n";
else
cout << words[i] << '\n';
return 0;
}
You need to go through all of the entries in the bad vector for each entry in the words vector. Something like this:
for(const string& word : words)
{
bool foundBadWord = false;
for(const string& badWord : bad)
{
if(0 == word.compare(badWord))
{
foundBadWord = true;
break;
}
}
if(foundBadWord)
{
cout << "Bleep!\n";
}
else
{
cout << word << "\n";
}
}
int main()
{
string sentence;
int length;
cout << "Enter the sentence now." << endl;
getline(cin, sentence);
for(int i = 0; i < sentence[i]; i++)
{
if(sentence[i]==';')
cout<<" ";
else if(sentence[i] != ' ')
{
cout << sentence[i];
}
else if(sentence[i] == ' ')
{
cout << endl;
}
}
}
I need help in this code to change into stack coding method. At least you can show me some clue how to change this code into simple stack code.
cin>>a>>b>>c>>d>>e>>f>>g;
myStack.push(g);
myStack.push(f);
myStack.push(e);
myStack.push(d);
myStack.push(c);
myStack.push(b);
myStack.push(a);
while(!myStack.empty()){
cout<<myStack.top()<<endl;
myStack.pop();
}
return 0;
}
This is an example, but its not flexible. User only can enter 7 words or maybe we can do it in array?
I am trying to use a number randomly selected between 1 and 2 and use that to display a random cout. I can't quite get this to work. Any suggestions? Thanks!
#include <iostream>
#include <string>
#include <cstdlib>
#include <ctime>
using namespace std;
int main()
{
srand(time(0));
for (int i = 1; i <= 1; i++)
{
int d1 = rand() % 2 + 1;
cout << d1 << endl;
cout << endl;
system("pause");
if (d1 == "1");
{
cout << "hello";
}
if (d1 == "2")
{
cout << "goodbye";
}
return 0;
}
First i recommend you make sure that you are not comparing an int to a string. Also remove the semicolon from after the first if statement.
if (d1 == 1)
{
cout << "hello";
}
Next make an else if statement instead of a new if statement.
else if (d1 == 2)
{
cout << "goodbye";
}
This should fix just about everything. Hope this helps. Goobyebye!
You're comparing an int to a string. change to, e.g. d1 == 1
That should get you going...
Compare the int to an int, then use the else clause.
Also, your if statement doesn't need a semicolon.
if (d1 == 1)
{
cout << "hello";
}
else
{
cout << "goodbye";
}
When you make a statement like:
if (d1 == "1")
You are comparing a string and an integer. Try:
if(d1 == 1)
#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;
int main()
{
string token = "000000:::AAAA:::000011:::Hello 8:::::::D Jay!";
string * stringArray = new string[token.size()];
string interim;
int r = 0;
int arrayCounter = 0;
for(int x = 0; x < token.length(); x++)
{
if(token[x] != ':')
{
interim[r] = token[x];
r++;
}
}
for (int x = 0; x < r; x++)
{
cout << interim[x] << endl;
}
system("pause");
return 0;
}
I am new and learning, and have narrowed it down to the line:
interim[r] = token[x];
..But i don't know why it crashes. Advice? I am coding in Visual C++ VSE2012
The string interim has a size of zero. Setting interim[r] = token[x] modifies the string at location r without changing its size. With a size of zero this is undefined behavior.
interim += token[x] is probably what you want.
Example:
#include <iostream>
#include <string>
using namespace std;
int main()
{
string token = "000000:::AAAA:::000011:::Hello 8:::::::D Jay!";
string interim;
for(int x = 0; x < token.length(); x++)
{
if(token[x] != ':')
{
interim += token[x];
}
}
cout << interim << endl;
system("pause");
return 0;
}
Output:
000000AAAA000011Hello 8D Jay!
Press any key to continue . . .