How to use CDI into JAX-RS client - jersey

I have searched a while on SO and official documentation but I cannot found a way to use directly CDI injection into a JAX-RS client.
I retrieve a client using the builder method and I want to register a WriterInterceptor (or any filter like component) which uses injection to retrieve another bean.
I want to use CDI injection and avoid registering each bean with HK2.
ClientBuilder.newBuilder()
.register(MyWriter.class)
.build();
And MyWriter with the injected class.
#Provider
public class MyWriter implements WriterInterceptor {
private final MyRepo repo;
#Inject
public MyWriter(MyRepo repo) {
this.repo = repo;
}
#Override
public void aroundWriteTo(WriterInterceptorContext context) throws IOException, WebApplicationException {
context.proceed();
}
}
public class MyRepo {
}
I am running in an embedded jetty with Jersey 2 and Weld SE.

Its possible to inject in java se application using wield .
#Singleton
public class Application {
private static Logger logger = LoggerFactory.getLogger(Application.class);
#inject
private SomeOtherBean injectedBean;
public void run() {
logger.debug("application initialized");
injectedBean.doSomething();
}
}
inside main initialize weild
import java.io.IOException;
import org.jboss.weld.environment.se.Weld;
import org.jboss.weld.environment.se.WeldContainer;
public class EntryPoint {
public static void main(String[] args) throws IOException {
Weld weld = new Weld();
WeldContainer container = weld.initialize();
Application application = container.instance().select(Application.class).get();
application.run();
weld.shutdown();
}
}
Have a look at below doc
https://docs.jboss.org/weld/reference/latest/en-US/html/environments.html#_java_se
also below tutorial
https://randling.wordpress.com/2011/08/15/cdi-in-java-se/

If I understand everything correctly, this has already been asked and answered. In a nutshell: you have to override the default behaviour of the H2K Binder, so it reaches for the Weld Bean Manager. You don't have to register every Bean with H2K later on.
Edit: to contain everything in the post, so you don't have to read the comments:
The linked answer is for the server-side, not the client.
With standard tools (Jersey Client-side injection providers and the Weld bridge), it seems to be a too big overhead/impossible to do
Apparently in the Dropwizard project they managed to do custom client-side injection.

Related

Grpc Spring Boot Starter

I am trying to integrate a grpcService to my spring boot application. In this service class i have a jpaRepository which is #Autowired. When i run the server this repository is not injected( is null when i'm trying to use it).
#Service
public class MedicationPlanService extends medicationPlanGrpc.medicationPlanImplBase {
#Autowired
private MedicationPlanRepository medicationPlanRepository;
#Override
public void hello(MedicationPlan.HelloRequest request, StreamObserver<MedicationPlan.HelloResponse> responseObserver) {
List<MedicationPlan> medicationPlans = medicationPlanRepository.findAll();
MedicationPlan.HelloResponse.Builder response = MedicationPlan.HelloResponse.newBuilder();
response.setResponseMessage("hello");
responseObserver.onNext(response.build());
responseObserver.onCompleted();
}
}
#Component
public class GrpcServerStartConfiguration {
#PostConstruct
public void startGrpcServer() throws IOException, InterruptedException {
Server server = ServerBuilder.forPort(9091).addService(new MedicationPlanService()).build();
server.start();
System.out.println("gRPC server started");
server.awaitTermination();
}
}
When i try to use the medicationPlanRepository i realized that it is null.
Thanks in advance :).
Because you're creating MedicationPlanService with "new", it becomes a simple object, not a bean. And things such as DI don't work in this way.
Initialize these 2 classes correctly (via #ComponentScan or #Bean in #Configuration class). Then inject MedicationPlanService into GrpcServerStartConfiguration. The latter you can mark as #Configuration for better understaning btw.

Alfresco Process Services with TaskListener #Autowired issue

I am using Alfresco Process Services and have created a created a spring boot project for custom logic like TaskListeners and Delegations. I am creating the jar file from this maven project and copying it into webapps/activiti-app/WEB-INF/lib folder.
I have a simple TaskListener as below which is getting called on Task start. But the #Autowired variables are always null.
package com.activiti.extension.bean;
#Component("myTaskListener")
public class MyTaskListener implements TaskListener {
#Autowired
UserService userService;
#Override
public void notify(DelegateTask task) {
logger.info("userService: " +userService); // Always prints null
}
Finally I was able to make it work. I was putting the task listener in the class field of the Task properties with full package name. Now I am putting Delegate expression like ${myTaskListener} and it worked...
Thank you all for your time and help
This is because your your MyTaskListener is annotated as #Component or at least being ignored by spring during init. for auto-wiring capabilities spring requires this annotation (or similar to this) under the provided #ComponentScan packages to consider the class as a bean otherwise it will take as a normal java class and hence the #autowired is of no use in your case.
This below code is worked for me
#Component
public class MyTaskListener implements TaskListener {
public static UserService getUserServiceObject() {
return SpringApplicationContextHolder.getApplicationContext().getBean(UserService.class);
}
#Override
public void notify(DelegateTask delegateTask) {
//UserService Object, It is not null now
getUserServiceObject();
}
}
#Component
public class SpringApplicationContextHolder implements ApplicationContextAware {
private static ApplicationContext applicationContext = null;
public static ApplicationContext getApplicationContext() {
return applicationContext;
}
#Override
public void setApplicationContext(ApplicationContext applicationContext) throws BeansException {
this.applicationContext = applicationContext;
}
}
There is also one more way to get to your custom service "UserService" using Alfresco Spring Application context.
First access ServiceRegistry (registry used for accessing Alfresco Services but also any other custom service):
ServiceRegistry serviceRegistry = (ServiceRegistry) Context.getProcessEngineConfiguration().getBeans().get(ActivitiConstants.SERVICE_REGISTRY_BEAN_KEY);
Then get custom service UserService:
QName qname = QName.createQName("UserService");
UserService userService = (UserService) serviceRegistry.getService(qname);

ClassBridge with DAO class injected

I have a Hibernate Search ClassBridge where I want to use #Inject to inject a Spring 4.1 managed DAO/Service class. I have annotated the ClassBridge with #Configurable. I noticed that Spring 4.2 adds some additional lifecycle methods that might do the trick, but I'm on Spring 4.1
The goal of this is to store a custom field into the index document based on a query result.
However, since the DAO, depends on the SessionFactory getting initialized, it doesn't get injected because it doesn't exist yet when the #Configurable bean gets processed.
Any suggestions on how to achieve this?
You might try to create a custom field bridge provider, which could get hold of the Spring application context through some static method. When provideFieldBridge() is called you may return a Spring-ified instance of that from the application context, assuming the timing is better and the DAO bean is available by then.
Not sure whether it'd fly, but it may be worth trying.
Hibernate Search 5.8.0 includes support for bean injection. You can see the issue https://hibernate.atlassian.net/browse/HSEARCH-1316.
However I couldn't make it work in my application and I had implemented a workaround.
I have created an application context provider to obtain the Spring application context.
public class ApplicationContextProvider implements ApplicationContextAware {
private static ApplicationContext context;
public static ApplicationContext getApplicationContext() {
return context;
}
#Override
public void setApplicationContext(ApplicationContext context) throws BeansException {
ApplicationContextProvider.context = context;
}
}
I have added it to the configuration class.
#Configuration
public class RootConfig {
#Bean
public ApplicationContextProvider applicationContextProvider() {
return new ApplicationContextProvider();
}
}
Finally I have used it in a bridge to retrieve the spring beans.
public class AttachmentTikaBridge extends TikaBridge {
#Override
public void set(String name, Object value, Document document, LuceneOptions luceneOptions) {
// get service bean from the application context provider (to be replaced when HS bridges support beans injection)
ApplicationContext applicationContext = ApplicationContextProvider.getApplicationContext();
ExampleService exampleService = applicationContext.getBean(ExampleService .class);
// use exampleService ...
super.set(name, content, document, luceneOptions);
}
}
I think this workaround it's quite simple in comparision with other solutions and it doesn't have any big side effect except the bean injection happens in runtime.

Java 8 and Spring 4 : Use autowiring in interface

Java 8 added a new feature by which we can provide method implementation in interfaces.
Is there any way in Spring 4 by which we can inject beans in the interface which can be used inside the method body?
Below is the sample code
public interface TestWiring{
#Autowired
public Service service;// this is not possible as it would be static.
//Is there any way I can inject any service bean which can be used inside testWiringMethod.
default void testWiringMethod(){
// Call method of service
service.testService();
}
}
This is a bit tricky but it works if you need the dependency inside the interface for whatever requirement.
The idea would be to declare a method that will force the implemented class to provide that dependency you want to autowire.
The bad side of this approach is that if you want to provide too many dependencies the code won't be pretty since you will need one getter for each dependency.
public interface TestWiring {
public Service getService();
default void testWiringMethod(){
getService().testService();
}
}
public class TestClass implements TestWiring {
#Autowire private Service service;
#Override
public Service getService() {
return service;
}
}
You can created Class utils of application context and use it everywhere even not bean class .
you can have code somethins this :
public class ApplicationContextUtil implements ApplicationContextAware {
private static ApplicationContext applicationContext;
#Override
public void setApplicationContext(ApplicationContext context) {
ApplicationContextUtil.applicationContext = context;
}
public static ApplicationContext getApplicationContext() {
return applicationContext;
}
}
and add this to your spring configuration
<bean class="com.example.ApplicationContextUtil" id="applicationContextUtil"/>
now simple to use when you need :
ApplicationContextUtil.getApplicationContext().getBean(SampleBean.class)
this word in web and simple spring app.

How to Initialize Jersey Application (ResourceConfig) With Spring?

I'm using Jersey 2 and Spring, and I'm trying to initialize my Jersey application (i.e. the class derived from ResourceConfig) with parameters from the Spring context.
Background: I have a single Jersey application that I build (i.e. a single WAR) and I deploy it across a server cluster with different Spring configurations on different servers to enable or disable different parts of the server, e.g. some of the servers have /search resources turned on, etc. This was really easy in Jersey 1.0: I just put,
<context:component-scan base-package="com.mycompany.resources.search"/>
in a Spring config to have Jersey scan that particular package and enable the JAX-RS resource providers in it.
Now in Jersey 2.0 the Spring <context:component-scan ... /> doesn't work, so resources have to be programmatically registered in a startup class derived from ResourceConfig:
public class MyApplication extends ResourceConfig {
public MyApplication() {
packages("com.mycompany.resources.search");
}
}
So far so good, but I need to conditionally scan that package, and I can't figure out how to get any Spring configuration into the MyApplication class. I thought that constructor injection might work:
public class MyApplication extends ResourceConfig {
#Autowired
public MyApplication(#Qualifier("my-config") MyConfiguration myConfiguration) {
if (myConfiguration.isEnabled()) {
packages("com.mycompany.resources.search");
}
}
}
However HK2 complains that it can't find a default constructor to use... so this indicates to me that DI is in play in the construction of this class, but that the DI isn't using Spring.
Similarly, using the the Spring bean lifecycle doesn't work:
public class MyApplication extends ResourceConfig implements InitializingBean {
#Autowired
private MyConfiguration myConfiguration;
public MyApplication() {
}
#Override
public void afterPropertiesSet() throws Exception {
if (myConfiguration.isEnabled()) {
packages("com.mycompany.resources.search");
}
}
}
(The afterPropertiesSet method isn't called.)
So now I'm stuck: is there any way to configure a Jersey ResourceConfig application object using Spring?
UPDATE:
I accepted #JohnR's answer below but I'll also include my eventual solution which I think is a bit cleaner. #JohnR's answer was to have the object initialized twice: first by Spring and then by Jersey/HK2. When Spring initializes the object you cache the dependencies in a static member, and then when Jersey/HK2 initializes it later you can retrieve the dependencies.
I ended up doing this:
public class MyApplication extends ResourceConfig {
public MyApplication() {
ApplicationContext rootCtx = ContextLoader.getCurrentWebApplicationContext();
MyConfiguration myConfiguration = rootCtx.getBean(MyConfiguration.class);
if (myConfiguration.isEnabled()) {
packages("com.mycompany.resources.whatever");
}
}
}
Rather than having the object initialized twice, we let Jersey/HK2 initialize it but then we retrieve the dependencies from Spring.
Both solutions are vulnerable to timing: they both assume that Spring is initialized before Jersey/HK2.
Expanding on my previous comment:
Trying to extend ResourceConfig is dangerous if you don't know what you're doing. Jersey becomes unpredictable, and if you try to subclass it into an Abstract class, Jersey crashes.
Instead, the JAX-RS specification provides us with a very useful interface called Feature: It allows you to register any classes you want as if you were configuring your own application. Furthermore, you don't need to use the awkward AbstractBinder, you just specify what contracts you register your classes with.
import org.springframework.context.ApplicationContext;
import org.springframework.web.context.support.WebApplicationContextUtils;
import javax.ws.rs.container.DynamicFeature;
import javax.ws.rs.container.ContainerRequestFilter;
import javax.ws.rs.container.ContainerResponseFilter;
import javax.ws.rs.core.Context;
import javax.ws.rs.core.Feature;
import javax.ws.rs.core.FeatureContext;
// Don't use #Component here, we need to inject the Spring context manually.
public class MySpringFeature implements Feature {
#Context
private ServletContext servletContext;
private ApplicationContext applicationContext;
#Autowired
private MySecurityDAO mySecurityDAO;
#Autowired
private MySpringResponseFilter myResponseFilter;
#Override
public boolean configure(FeatureContext context) {
if(this.servletContext == null) {
return false; // ERROR!
}
this.applicationContext = WebApplicationContextUtils.getWebApplicationContext(servletContext);
if(this.applicationContext == null) {
return false; // ERROR!
}
// This is where the magic happens!
AutowireCapableBeanFactory bf = applicationContext.getAutowireCapableBeanFactory();
bf.autowireBean(this);
// From here you can get all the beans you need
// Now we take a Spring bean instance,
// and register it with its appropriate JAX-RS contract
context.register(myResponseFilter, ContainerResponseFilter.class);
// Or, we could do this instead:
SomeSecurityFilter mySecurityFilter = new SomeSecurityFilter();
mySecurityFilter.setSecurityDAO(mySecurityDAO);
context.register(mySegurityFilter, ContainerRequestFilter.class);
// Or even this:
SomeOtherSpringBean someOtherBean = applicationContext.getBean(SomeOtherSpringBean.class);
context.register(someOtherBean, SomeOtherJerseyContract.class);
// Success!
return true;
}
}
And in your ResourceConfig:
public class MyApplication extends ResourceConfig() {
public MyApplication() {
register(MySpringFeature.class);
}
}
Ta-da!
So now I'm stuck: is there any way to configure a Jersey
ResourceConfig application object using Spring?
I don't think you can configure Jersey to obtain your ResourceConfig from Spring as a Spring managed bean. It's a bit hackish, but you could do something like this. Note that you'll end up with two instance of your ResourceConfig: one managed by Spring and another by Jersey:
public class MyApplication extends ResourceConfig {
// static, available to all instances
private static MyConfiguration myConfiguration;
public MyApplication() {
// when Spring creates the first instance of MyApplication, myConfiguration
// will be null because the setter wasn't called yet
if (myConfiguration != null)
{
// second instance created by jersey... Spring will have autowired
// the first instance, and myConfiguration is static
if (myConfiguration.isEnabled())
packages("com.mycompany.resources.search");
}
}
#Autowired
public void setMyConfiguration(MyConfiguration config)
{
// instance level setter saves to a static variable to make it available for
// future instances (i.e. the one created by jersey)
MyApplication.myConfiguration = config;
}
}
Again, this is fairly hackish. You'll want to make sure Spring is initialized before Jersey and look closely at any threading issues that could occur during initialization.

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