Creating a loop with curl -F argument - bash

Question

I have this bash script code:
#!/bin/bash
FILES=/home/user/Downloads/asd/
for f in $FILES
do
curl -F dir="#/home/user/Downloads/asd;$f" -F Match=3 -F "Name=DrKla" \
-F countNo=1 -F outputFormat=json "http://somelink.com"
done
Inside the asd folder there are 6 files and I want them to be uploaded 1 by 1 with this code as an argument of -F "dir=#...."
When I run my code I get the error:
Warning: skip unknown form field: /home/user/Downloads/asd/
curl: (43) A libcurl function was given a bad argument
Here is a working version of the code for a single file:
curl -F dir="#/home/user/Downloads/asd/count.txt" -F Match=3 -F "Name=DrKla" \
-F countNo=1 -F outputFormat=json "http://somelink.com"
So I want to have all the files in asd folder to be read and uploaded like this. I don't see what's wrong with my do loop.

Answer 1

The issues appear to be that you only give a path, not a reference to all files in the path * and there is a strange semi-colon ; in your path:
#!/bin/bash
FILES=/home/user/Downloads/asd/*
for f in $FILES
do
curl -F dir="#$f" -F Match=3 -F "Name=DrKla" \
-F countNo=1 -F outputFormat=json "http://somelink.com"
done
I'm not sure what the # is for or if it is needed, but $f should already contain the path.