I want to make a mailgun curl call using windows batch file. Since windows shell doesn't support multiple lines, how can I execute the below curl function in windows batch file?
curl -s --user 'api:key-xxxxxxxxxx' \
https://api.mailgun.net/v3/sandboxbxxxxxxxxxxxxx.mailgun.org/messages \
-F from='user <email#gmail.com>' \
-F to='user <email#live.com>' \
-F subject='Hello' \
-F text='body!' \
-F attachment=#test.txt \
Update
When I tried to execute the command after removing the multiple lines it returned this error:
curl -s --user 'api:key-xxxxxxxxxx' https://api.mailgun.net/v3/sandboxbxxxxxxxxxxxxx.mailgun.org/messages -F from='user -F to='user -F subject='Hello' -F text='body!' -F attachment=#test.txt 0<email#live.com 1>'
The system cannot find the file specified.
PS: The attachment file is in the same directory
Thanks!
simply on one line and put the <> redirection char between " or escape it with ^:
curl -s --user 'api:key-xxxxxxxxxx' https://api.mailgun.net/v3/sandboxbxxxxxxxxxxxxx.mailgun.org/messages -F from="user <email#gmail.com>" -F to="user <email#live.com>" -F subject='Hello' -F text='body!' -F attachment=#test.txt
You can also create variable for each element :
set "$ApiKey=api:key-xxxxxxxxxx"
set "$Url=https://api.mailgun.net/v3/sandboxbxxxxxxxxxxxxx.mailgun.org/messages"
set "$From=email#gmail.com"
....
and then
curl -s --user '%$ApiKey%' %$Url% -F from="user <%$From%>" -F to= ....
Related
Need to write some status checker at bash-script:
Have file with strings like that:
domain.com; 111.111.111.111,222.222.222.222; /link/to/somefile.js,/link/to/somefile2.js
domain2.com; 122.122.111.111,211.211.222.222; /link/to/somefile2.js,/link/to/somefile3.js
Need to execute such commands at total:
curl -s -I -H 'Host: domain.com' http://111.111.111.111/link/to/somefile.js
curl -s -I -H 'Host: domain.com' http://222.222.222.222/link/to/somefile.js
curl -s -I -H 'Host: domain.com' http://111.111.111.111/link/to/somefile2.js
curl -s -I -H 'Host: domain.com' http://222.222.222.222/link/to/somefile2.js
curl -s -I -H 'Host: domain2.com' http://122.122.111.111/link/to/somefile2.js
curl -s -I -H 'Host: domain2.com' http://211.211.222.222/link/to/somefile2.js
curl -s -I -H 'Host: domain2.com' http://122.122.111.111/link/to/somefile3.js
curl -s -I -H 'Host: domain2.com' http://211.211.222.222/link/to/somefile3.js
The question is:
what tool do I need to use to have such result at total?
Maybe xargs with some arguments/flags can do that or gnu parallel?
Can you, please, show examples?
I can to separate lines and set result to different variables that's isn't problem at all:
domain=$(cut -d';' -f1 file| xargs -I N -d "," echo curl -H) \'N\'
ip=$(cut -d';' -f2 file| xargs -I N -d "," echo curl -H) \'N\'
and else
But question at other :) :
how after delimiting and separating strings to variables, I can execute curl with different variables at that case - the number of arguments for different variables will be different ?
The answer's that get Barmar doesn't cover task problem at all, cause it has greater than two list's. The problem is not at ignorance of bash, but of way I can resolve issue
#!/usr/bin/env bash
# ^^^^- IMPORTANT: not /bin/sh
# print command instead of running it, so people can test their answers without real URLs
log_command() { printf '%q ' "$#"; printf '\n'; }
while IFS='; ' read -r domain addrs_str files_str; do
IFS=, read -a addrs <<<"$addrs_str"
IFS=, read -a files <<<"$files_str"
for file in "${files[#]}"; do
for addr in "${addrs[#]}"; do
log_command curl -s -I -H "Host: $domain" "http://$addr/$file"
done
done
done
...emits as output (as the list of commands if it would run if the log_command prefix were removed):
curl -s -I -H Host:\ domain.com http://111.111.111.111//link/to/somefile.js
curl -s -I -H Host:\ domain.com http://222.222.222.222//link/to/somefile.js
curl -s -I -H Host:\ domain.com http://111.111.111.111//link/to/somefile2.js
curl -s -I -H Host:\ domain.com http://222.222.222.222//link/to/somefile2.js
curl -s -I -H Host:\ domain2.com http://122.122.111.111//link/to/somefile2.js
curl -s -I -H Host:\ domain2.com http://211.211.222.222//link/to/somefile2.js
curl -s -I -H Host:\ domain2.com http://122.122.111.111//link/to/somefile3.js
curl -s -I -H Host:\ domain2.com http://211.211.222.222//link/to/somefile3.js
...as you can see at https://ideone.com/dTC8q8
Now how does this work?
Step 1: Read each line into domain, addrs_str and files_str, split on semicolons and spaces.
That's what's done by the line IFS='; ' read -r domain addrs_str files_str, which operates as described in BashFAQ #1, and in How to read variables from file, with multiple variables per line?
Step 2: For addrs_str and files_str, split them on commas into separate arrays. This is described in How do I split a string on a delimiter in Bash?
Step 3: Iterate over those arrays, and call curl for each combination. If you wanted to call the first IP with only the first file, and the second IP with the second file, you could use Iterate over two arrays simultaneously in bash; otherwise, it's a plain nested loop.
With GNU Parallel it would look like this
doit() {
domain="$1"
ips="$2"
paths="$3"
parallel --dry-run -d ',' -q curl -s -I -H Host:\ "$domain" http://{1}/{2} ::: "$ips" ::: "$paths"
}
export -f doit
parallel --colsep ';' doit :::: input.file
Remove --dry-run when you are convinced it works.
I have this bash script code:
#!/bin/bash
FILES=/home/user/Downloads/asd/
for f in $FILES
do
curl -F dir="#/home/user/Downloads/asd;$f" -F Match=3 -F "Name=DrKla" \
-F countNo=1 -F outputFormat=json "http://somelink.com"
done
Inside the asd folder there are 6 files and I want them to be uploaded 1 by 1 with this code as an argument of -F "dir=#...."
When I run my code I get the error:
Warning: skip unknown form field: /home/user/Downloads/asd/
curl: (43) A libcurl function was given a bad argument
Here is a working version of the code for a single file:
curl -F dir="#/home/user/Downloads/asd/count.txt" -F Match=3 -F "Name=DrKla" \
-F countNo=1 -F outputFormat=json "http://somelink.com"
So I want to have all the files in asd folder to be read and uploaded like this. I don't see what's wrong with my do loop.
The issues appear to be that you only give a path, not a reference to all files in the path * and there is a strange semi-colon ; in your path:
#!/bin/bash
FILES=/home/user/Downloads/asd/*
for f in $FILES
do
curl -F dir="#$f" -F Match=3 -F "Name=DrKla" \
-F countNo=1 -F outputFormat=json "http://somelink.com"
done
I'm not sure what the # is for or if it is needed, but $f should already contain the path.
I'm working with installr API.
I'm trying to do the following curl request via a script :
curl -H "X-InstallrAppToken: mytoken" https://www.installrapp.com/apps.json/ \
-F 'qqfile=#'$APKPATH \
-F 'releaseNotes=These are my release notes' \
-F 'notify=true'
and it works perfectly.
However, when I try to get my release notes from a file with a variable like this :
RELEASENOTES=`cat "release_notes/test.md"`
curl -H "X-InstallrAppToken: mytoken" https://www.installrapp.com/apps.json/ \
-F 'qqfile=#'$APKPATH \
-F 'releaseNotes='$RELEASENOTES \
-F 'notify=true' > /dev/null
it doesn't work at all, only the first word is sent. For the others, I have the error Could not resolve host: xxx.
I did a echo on these two curl request and the exact same thing is printed.
is that the catcommand which return a specific format ?
Probably an issue with the quotes and spaces. You can use double-quotes around a variable to allow variable expansion in the shell.
RELEASENOTES=$(cat "release_notes/test.md")
curl -H "X-InstallrAppToken: mytoken" https://www.installrapp.com/apps.json/ \
-F "qqfile=#${APKPATH}" \
-F "releaseNotes=${RELEASENOTES}" \
-F 'notify=true' > /dev/null
I'm trying to use Xcode 5 bots for my Continuos Integration. I need to create a zip-file of my app-file.
In my scheme under Archive I use this script:
LATESTBUILD=$(ls -1rt /Library/Server/Xcode/Data/BotRuns | tail -1)
APP="/Library/Server/Xcode/Data/BotRuns/${LATESTBUILD}/output/Archive.xcarchive/Products/Applications/${PRODUCT_NAME}.app"
echo "Zipping .app for ${PRODUCT_NAME}"
/usr/bin/zip -r "${APP}.zip" "${APP}"
echo "Sending to *HockeyApp*"
curl \
-F "status=2" \
-F "notify=0" \
-F "notes=Testing CI" \
-F "notes_type=0" \
-F "ipa=${APP}.zip" \
-H "X-HockeyAppToken: myToken \
https://rink.hockeyapp.net/api/2/apps/myAppID/app_versions/upload
This will create a .zip-file. However, not the actual app but the whole folder structure for ${app}.
How can I create a zip-file that only contains the actual app?
To specify a file parameter with curl, you have to prefix the filename with #. Correct would be:
echo "Sending to *HockeyApp*"
curl \
-F "status=2" \
-F "notify=0" \
-F "notes=Testing CI" \
-F "notes_type=0" \
-F "ipa=#${APP}.zip" \
-H "X-HockeyAppToken: myToken \
https://rink.hockeyapp.net/api/2/apps/myAppID/app_versions/upload
Fixed this by stepping in to the directory before zipping it.
cd "/tmp/Archive.xcarchive/Products/Applications/"
when i use bash to upload files to dropbox, it works fine but when i manually use command line it does not work.
I'm thinking it might be the & in the url.. im not sure..
Bash code:
CURL_BIN="/usr/bin/curl"
#Note: This option explicitly allows curl to perform "insecure" SSL connections and transfers.
#CURL_ACCEPT_CERTIFICATES="-k"
CURL_PARAMETERS="--progress-bar"
APPKEY="zrwv8z3bycfk3m8"
OAUTH_ACCESS_TOKEN="aaaaaaaa"
APPSECRET="aaaaaaaaaa"
OAUTH_ACCESS_TOKEN_SECRET="aaaaaaaaa"
ACCESS_LEVEL="dropbox"
API_UPLOAD_URL="https://api-content.dropbox.com/1/files_put"
RESPONSE_FILE="temp2.txt"
FILE_SRC="temp.txt"
$CURL_BIN $CURL_ACCEPT_CERTIFICATES $CURL_PARAMETERS -v -i -o "$RESPONSE_FILE" --upload-file "$FILE_SRC" "$API_UPLOAD_URL/$ACCESS_LEVEL/$FILE_DST?oauth_consumer_key=$APPKEY&oauth_token=$OAUTH_ACCESS_TOKEN&oauth_signature_method=PLAINTEXT&oauth_signature=$APPSECRET%26$OAUTH_ACCESS_TOKEN_SECRET"
Manual code:
curl --insecure --progress-bar -v -i -o temp2.txt --upload-file temp.txt https://api-content.dropbox.com/1/files_put/dropbox/attachments/temp.txt?oauth_consumer_key=aaaaaaaaaa&oauth_token=aaaaaaaaa&oauth_signature_method=PLAINTEXT&oauth_signature=aaaaaaaaa%26aaaaaaaaaa
curl --insecure --progress-bar -v -i -o temp2.txt --upload-file temp.txt "https://api-content.dropbox.com/1/files_put/dropbox/attachments/temp.txt?oauth_consumer_key=aaaaaaaaaa&oauth_token=aaaaaaaaa&oauth_signature_method=PLAINTEXT&oauth_signature=aaaaaaaaa%26aaaaaaaaaa"
The solution is to add in the inverted commas "