I want to copy only 20180721 files from Outgoing to Incoming folder. I also want to remove the first numbers from the file name and want to rename from -1 to -3. I want to keep my commands to minimum so I am using pax command below.
Filename:
216118105741_MOM-09330-20180721_102408-1.jar
Output expected:
MOM-09330-20180721_102408-3.jar
I have tried this command and it's doing most of the work apart from removing the number coming in front of the file name. Can anyone help?
Command used:
pax -rw -pe -s/-1/-3/ ./*20180721*.jar ../Incoming/
Try this simple script using just parameter expansion:
for file in *20180721*.jar; do
new=${file#*_}
cp -- "$file" "/path/to/destination/${new%-*}-3.jar"
done
You can try this
In general
for i in `ls files-to-copy-*`; do
cp $i `echo $i | sed "s/rename-from/rename-to/g"`;
done;
In your case
for i in `ls *_MOM*`; do
cp $i `echo $i | sed "s/_MOM/MOM/g" | sed "s/-1/-3/g"`;
done;
pax only applies the first successful substitution even if the -s option is specified more than once. You can pipe the output to a second pax instance, though.
pax -w -s ':^[^_]*_::p' *20180721*.jar | (builtin cd ../Incoming; pax -r -s ':1[.]jar$:3.jar:p')
Related
I try to search for files and seperate path and version as variable because each will be needed later for creating a directory and to unzip a .jar in desired path.
file=$(find /home/user/Documents/test/ -path *.jar)
version=$(echo "$file" | grep -P -o '[0-9].[0-9].[0-9].[0-9]')
path=$(echo "$file" | sed 's/\(.*\)[/].*/\1/')
newpath=$(echo "${path}/${version}")
echo "$newpath"
result
> /home/user/Documents/test/gb0500
> /home/user/Documents/test/gb0500 /home/user/Documents/test/gb0500
> /home/user/Documents/test /home/user/Documents/test/1.3.2.0
> 1.3.2.1
> 1.3.2.2
> 1.2.0.0
> 1.3.0.0
It's hilarious that it's only working at one line.
what else I tried:
file=$(find /home/v990549/Dokumente/test/ -path *.jar)
version=$(grep -P -o '[0-9].[0-9].[0-9].[0-9]')
path=$(sed 's/\(.*\)[/].*/\1/')
while read $file
do
echo "$path$version"
done
I have no experience in scripting. Thats what I figured out some days ago. I am just practicing and trying to make life easier.
find output:
/home/user/Documents/test/gb0500/gb0500-koetlin-log4j2-web-1.3.2.0-javadoc.jar
/home/user/Documents/test/gb0500/gb0500-koetlin-log4j2-web-1.3.2.1-javadoc.jar
/home/user/Documents/test/gb0500/gb0500-koetlin-log4j2-web-1.3.2.2-javadoc.jar
/home/user/Documents/test/gb0500-co-log4j2-web-1.2.0.0-javadoc.jar
/home/user/Documents/test/gb0500-commons-log4j2-web-1.3.0.0-javadoc.jar
As the both variables version and path are newline-separated, how about:
file=$(find /home/user/Documents/test/ -path *.jar)
version=$(echo "$file" | grep -P -o '[0-9].[0-9].[0-9].[0-9]')
path=$(echo "$file" | sed 's/\(.*\)[/].*/\1/')
paste -d "/" <(echo "$path") <(echo "$version")
Result:
/home/user/Documents/test/gb0500/1.3.2.0
/home/user/Documents/test/gb0500/1.3.2.1
/home/user/Documents/test/gb0500/1.3.2.2
/home/user/Documents/test/1.2.0.0
/home/user/Documents/test/1.3.0.0
BTW I do not recommend to store multiple filenames in a single variable
as a newline-separated variable due to several reasons:
Filenames may contain a newline character.
It is not easy to manipulate the values of each line.
For instance you could simply say
the third line as path=${file%/*} if file contains just one.
Hope this helps.
This question already has answers here:
Run script on multiple files
(3 answers)
Closed 3 years ago.
I'm very new to bash. I have ten text files that I want to edit with the same line of code.
#!/bin/bash
sed -i -e 's/.\{6\}/&\n/g' -e 's/edit/edit2/g' | tr -d "\n" | sed 's/edit2/edit/g'| grep -o "here.*there" | sed -r '/^.{,100}$/d'
< files 1-10
I know I could use sed -f sed.sh <file1 >file1 but that only works with sed commands and it only works one file at a time?
Do I have to run a loop?
There's some great existing answers on the Unix stack exchange that help deal with your problem. Specifically, from this post, they use a loop to recursively loop through all the files in a particular directory, as follows:
( shopt -s globstar dotglob;
for file in **; do
if [[ -f $file ]] && [[ -w $file ]]; then
sed -i -- 's/foo/bar/g' "$file"
fi
done
)
Note the line, shopt -s globstar dotglob;, which allows us to use globbing patterns in the for loop. We also enclose the code in brackets, to prevent the shopt -s globstar dotglob; line option from becoming a global setting.
If you would like to apply this example to your file, you can just place your files in the current directory, and the code would probably look something like this:
( shopt -s globstar dotglob;
for file in **; do
if [[ -f $file ]] && [[ -w $file ]]; then
sed -i -e 's/.\{6\}/&\n/g' -e 's/edit/edit2/g' | tr -d "\n" | sed 's/edit2/edit/g' | grep -o "here.*there" | sed -r '/^.{,100}$/d' "$file"
fi
done
)
Note that we have placed a "$file" variable beside each of the seds that you used in your code, this replaces the name of the file for each command.
There is another example given in the code that allows you to pick which files to run on, rather than all the files in a directory, which you can also re-purpose for your code, as given here:
( shopt -s globstar dotglob
sed -i -- 's/foo/bar/g' **baz*
sed -i -- 's/foo/bar/g' **.baz
)
To answer your question of doing a loop on each line, you will need to put a loop for each line inside your for loop, like so:
while read line ; do
: sed -i -e 's/.\{6\}/&\n/g' -e 's/edit/edit2/g' | tr -d "\n" | sed 's/edit2/edit/g' | grep -o "here.*there" | sed -r '/^.{,100}$/d' "$line”
done
)
Although the for loop can be useful for dealing with files in recursive directories, I would recommend against also using another loop to grab lines, since it muddies your code, and it’s possible there is a better way to do it without parsing line by line.
The linked question is a fairly complete guide to many of the cases you may come across, and is also worth a read if you want to learn more.
Hope that helps!
You could use a for loop.
You could use the tool parallel.
Example
Create a set of test files using a for-loop
mkdir -p /tmp/so58333536
cd /tmp/so58333536
for i in 1.txt 2.txt 3.txt 4.txt 5.txt;do echo "The answer is 41" > $i;done
cat /tmp/so58333536/*
Now correct your mistake using parallel [1].
mkdir /tmp/so58333536.new
ls /tmp/so58333536/* |parallel "sed 's/41/42/' {} > /tmp/so58333536.new/{/}"
cat /tmp/so58333536.new/*
{}:: refers to the current file
{/}:: refers to name of the current file (path is removed)
Reads: List all files in so58333536 and apply the following sed command to each file and write the output to so58333536.new.
[1] Another option is to use sed -i for in-place editing.
Be very carefull with this!! Mistakes can cause serious damages!
# !! Do not use -i option regularly !!
ls /tmp/so58333536/* |parallel "sed -i 's/41/42/'"
I have a bash script which needs to go through files in a directory in an iOS device and remove files one by one.
To list files from command line I use the following command:
ios-deploy --id UUID --bundle_id BUNDLE -l | grep Documents
and to go one by one on each file I use the following for loop in my script
for line in $(ios-deploy --id UUID --bundle_id BUNDLE -l | grep Documents); do
echo "${line}"
done
Now the problem is that there are files which names have spaces in them, and in such cases the for loop treats them as 2 separate lines.
How can I escape that whitespace in for loop definition so that I get one line per each file?
This might solve your issue:
while IFS= read -r -d $'\n'
do
echo "${REPLY}"
done < <(ios-deploy --id UUID --bundle_id BUNDLE -l | grep Documents)
Edit per Charles Duffy recommendation:
while IFS= read -r line
do
echo "${line}"
done < <(ios-deploy --id UUID --bundle_id BUNDLE -l | grep Documents)
I want to make UNIX script, which will automatically move my working directory files to newly created directories.
Example: In you dir you got files:
001-file.html,
001-file.rb,
002-file.html,
002-file.rb
And 2 files will be moved to ./NewDir/001-file and another 2 to ./NewDir/002-file
My problem is that after I get correct string from Unix commands I cannot assign it to variable.
Here is my code:
clear
echo "Starting script"
echo "Dir = "$(pwd)
read -p "Please enter count(max '999') of different file groups:" max_i
read -p "Enter new dir name:" outer_dir_name
for ((i=0; i<=$max_i;i++)) do
a1=$(($i/100))
a2=$((($i-$a1*100)/10))
a3=$(($i-($a2*10)-($a1*100)))
inner_dir_name=$((ls *[$a1][$a2][$a3]* 2>/dev/null | head -n 1 | cut -f1 -d"."))
echo $inner_dir_name
echo "--------------"
done
One pair of round parentheses is enough for command substitution.
inner_dir_name=$(ls *[$a1][$a2][$a3]* 2>/dev/null | head -n 1 | cut -f1 -d".")
It looks like you're going about the operation the hard way. I would probably do something like this, assuming that there are no spaces in the file names:
ls | sed 's/\..*$//' | sort -u |
while read prefix
do
mkdir -p $outer_dir_name/$prefix
mv $prefix.* $outer_dir_name/$prefix
done
The ls could be made more precise with:
ls [0-9][0-9][0-9]-file.*
If I was worried about blanks and other odd-ball characters in the file names, I'd have to use something more careful:
for file in [0-9][0-9][0-9]-file.*
do
prefix=${file%%.*}
[ -d "$outer_dir_name/$prefix" ] || mkdir -p "$outer_dir_name/$prefix"
mv "$file" "$outer_dir_name/$prefix"
done
This executes more mv commands, in general.
Hi guys i've a problem with grep . I don't know if there is another search code in shell script.
I'm trying to backup a folder AhmetsFiles which is stored in my Flash Disk , but at the same time I've to group them by their extensions and save them into [extensionName] Folder.
AhmetsFiles
An example : /media/FlashDisk/AhmetsFiles/lecture.pdf must be stored in /home/$(whoami)/Desktop/backups/pdf
Problem is i cant copy a file which name contains spaces.(lecture 2.pptx)
After this introduction here my code.
filename="/media/FlashDisk/extensions"
count=0
exec 3<&0
exec 0< $filename
mkdir "/home/$(whoami)/Desktop/backups"
while read extension
do
cd "/home/$(whoami)/Desktop/backups"
rm -rf "$extension"
mkdir "$extension"
cd "/media/FlashDisk/AhmetsFiles"
files=( `ls | grep -i "$extension"` )
fCount=( `ls | grep -c -i "$extension"` )
for (( i=0 ; $i<$fCount ; i++ ))
do
cp -f "/media/FlashDisk/AhmetsFiles/${files[$i]}" "/home/$(whoami)/Desktop/backups/$extension"
done
let count++
done
exec 0<&3
exit 0
Your looping is way more complicated than it needs to be, no need for either ls or grep or the files and fCount variables:
for file in *.$extension
do
cp -f "/media/FlashDisk/AhmetsFiles/$file" "$HOME/Desktop/backups/$extension"
done
This works correctly with spaces.
I'm assuming that you actually wanted to interpret $extension as a file extension, not some random string in the middle of the filename like your original code does.
Why don't you
grep -i "$extension" | while IFS=: read x ; do
cp ..
done
instead?
Also, I believe you may prefer something like grep -i ".$extension$" instead (anchor it to the end of line).
On the other hand, the most optimal way is probably
cp -f /media/FlashDisk/AhmetsFiles/*.$extension "$HOME/Desktop/backups/$extension/"