I try to search for files and seperate path and version as variable because each will be needed later for creating a directory and to unzip a .jar in desired path.
file=$(find /home/user/Documents/test/ -path *.jar)
version=$(echo "$file" | grep -P -o '[0-9].[0-9].[0-9].[0-9]')
path=$(echo "$file" | sed 's/\(.*\)[/].*/\1/')
newpath=$(echo "${path}/${version}")
echo "$newpath"
result
> /home/user/Documents/test/gb0500
> /home/user/Documents/test/gb0500 /home/user/Documents/test/gb0500
> /home/user/Documents/test /home/user/Documents/test/1.3.2.0
> 1.3.2.1
> 1.3.2.2
> 1.2.0.0
> 1.3.0.0
It's hilarious that it's only working at one line.
what else I tried:
file=$(find /home/v990549/Dokumente/test/ -path *.jar)
version=$(grep -P -o '[0-9].[0-9].[0-9].[0-9]')
path=$(sed 's/\(.*\)[/].*/\1/')
while read $file
do
echo "$path$version"
done
I have no experience in scripting. Thats what I figured out some days ago. I am just practicing and trying to make life easier.
find output:
/home/user/Documents/test/gb0500/gb0500-koetlin-log4j2-web-1.3.2.0-javadoc.jar
/home/user/Documents/test/gb0500/gb0500-koetlin-log4j2-web-1.3.2.1-javadoc.jar
/home/user/Documents/test/gb0500/gb0500-koetlin-log4j2-web-1.3.2.2-javadoc.jar
/home/user/Documents/test/gb0500-co-log4j2-web-1.2.0.0-javadoc.jar
/home/user/Documents/test/gb0500-commons-log4j2-web-1.3.0.0-javadoc.jar
As the both variables version and path are newline-separated, how about:
file=$(find /home/user/Documents/test/ -path *.jar)
version=$(echo "$file" | grep -P -o '[0-9].[0-9].[0-9].[0-9]')
path=$(echo "$file" | sed 's/\(.*\)[/].*/\1/')
paste -d "/" <(echo "$path") <(echo "$version")
Result:
/home/user/Documents/test/gb0500/1.3.2.0
/home/user/Documents/test/gb0500/1.3.2.1
/home/user/Documents/test/gb0500/1.3.2.2
/home/user/Documents/test/1.2.0.0
/home/user/Documents/test/1.3.0.0
BTW I do not recommend to store multiple filenames in a single variable
as a newline-separated variable due to several reasons:
Filenames may contain a newline character.
It is not easy to manipulate the values of each line.
For instance you could simply say
the third line as path=${file%/*} if file contains just one.
Hope this helps.
Related
This question already has answers here:
Run script on multiple files
(3 answers)
Closed 3 years ago.
I'm very new to bash. I have ten text files that I want to edit with the same line of code.
#!/bin/bash
sed -i -e 's/.\{6\}/&\n/g' -e 's/edit/edit2/g' | tr -d "\n" | sed 's/edit2/edit/g'| grep -o "here.*there" | sed -r '/^.{,100}$/d'
< files 1-10
I know I could use sed -f sed.sh <file1 >file1 but that only works with sed commands and it only works one file at a time?
Do I have to run a loop?
There's some great existing answers on the Unix stack exchange that help deal with your problem. Specifically, from this post, they use a loop to recursively loop through all the files in a particular directory, as follows:
( shopt -s globstar dotglob;
for file in **; do
if [[ -f $file ]] && [[ -w $file ]]; then
sed -i -- 's/foo/bar/g' "$file"
fi
done
)
Note the line, shopt -s globstar dotglob;, which allows us to use globbing patterns in the for loop. We also enclose the code in brackets, to prevent the shopt -s globstar dotglob; line option from becoming a global setting.
If you would like to apply this example to your file, you can just place your files in the current directory, and the code would probably look something like this:
( shopt -s globstar dotglob;
for file in **; do
if [[ -f $file ]] && [[ -w $file ]]; then
sed -i -e 's/.\{6\}/&\n/g' -e 's/edit/edit2/g' | tr -d "\n" | sed 's/edit2/edit/g' | grep -o "here.*there" | sed -r '/^.{,100}$/d' "$file"
fi
done
)
Note that we have placed a "$file" variable beside each of the seds that you used in your code, this replaces the name of the file for each command.
There is another example given in the code that allows you to pick which files to run on, rather than all the files in a directory, which you can also re-purpose for your code, as given here:
( shopt -s globstar dotglob
sed -i -- 's/foo/bar/g' **baz*
sed -i -- 's/foo/bar/g' **.baz
)
To answer your question of doing a loop on each line, you will need to put a loop for each line inside your for loop, like so:
while read line ; do
: sed -i -e 's/.\{6\}/&\n/g' -e 's/edit/edit2/g' | tr -d "\n" | sed 's/edit2/edit/g' | grep -o "here.*there" | sed -r '/^.{,100}$/d' "$line”
done
)
Although the for loop can be useful for dealing with files in recursive directories, I would recommend against also using another loop to grab lines, since it muddies your code, and it’s possible there is a better way to do it without parsing line by line.
The linked question is a fairly complete guide to many of the cases you may come across, and is also worth a read if you want to learn more.
Hope that helps!
You could use a for loop.
You could use the tool parallel.
Example
Create a set of test files using a for-loop
mkdir -p /tmp/so58333536
cd /tmp/so58333536
for i in 1.txt 2.txt 3.txt 4.txt 5.txt;do echo "The answer is 41" > $i;done
cat /tmp/so58333536/*
Now correct your mistake using parallel [1].
mkdir /tmp/so58333536.new
ls /tmp/so58333536/* |parallel "sed 's/41/42/' {} > /tmp/so58333536.new/{/}"
cat /tmp/so58333536.new/*
{}:: refers to the current file
{/}:: refers to name of the current file (path is removed)
Reads: List all files in so58333536 and apply the following sed command to each file and write the output to so58333536.new.
[1] Another option is to use sed -i for in-place editing.
Be very carefull with this!! Mistakes can cause serious damages!
# !! Do not use -i option regularly !!
ls /tmp/so58333536/* |parallel "sed -i 's/41/42/'"
I want to copy only 20180721 files from Outgoing to Incoming folder. I also want to remove the first numbers from the file name and want to rename from -1 to -3. I want to keep my commands to minimum so I am using pax command below.
Filename:
216118105741_MOM-09330-20180721_102408-1.jar
Output expected:
MOM-09330-20180721_102408-3.jar
I have tried this command and it's doing most of the work apart from removing the number coming in front of the file name. Can anyone help?
Command used:
pax -rw -pe -s/-1/-3/ ./*20180721*.jar ../Incoming/
Try this simple script using just parameter expansion:
for file in *20180721*.jar; do
new=${file#*_}
cp -- "$file" "/path/to/destination/${new%-*}-3.jar"
done
You can try this
In general
for i in `ls files-to-copy-*`; do
cp $i `echo $i | sed "s/rename-from/rename-to/g"`;
done;
In your case
for i in `ls *_MOM*`; do
cp $i `echo $i | sed "s/_MOM/MOM/g" | sed "s/-1/-3/g"`;
done;
pax only applies the first successful substitution even if the -s option is specified more than once. You can pipe the output to a second pax instance, though.
pax -w -s ':^[^_]*_::p' *20180721*.jar | (builtin cd ../Incoming; pax -r -s ':1[.]jar$:3.jar:p')
I want to make UNIX script, which will automatically move my working directory files to newly created directories.
Example: In you dir you got files:
001-file.html,
001-file.rb,
002-file.html,
002-file.rb
And 2 files will be moved to ./NewDir/001-file and another 2 to ./NewDir/002-file
My problem is that after I get correct string from Unix commands I cannot assign it to variable.
Here is my code:
clear
echo "Starting script"
echo "Dir = "$(pwd)
read -p "Please enter count(max '999') of different file groups:" max_i
read -p "Enter new dir name:" outer_dir_name
for ((i=0; i<=$max_i;i++)) do
a1=$(($i/100))
a2=$((($i-$a1*100)/10))
a3=$(($i-($a2*10)-($a1*100)))
inner_dir_name=$((ls *[$a1][$a2][$a3]* 2>/dev/null | head -n 1 | cut -f1 -d"."))
echo $inner_dir_name
echo "--------------"
done
One pair of round parentheses is enough for command substitution.
inner_dir_name=$(ls *[$a1][$a2][$a3]* 2>/dev/null | head -n 1 | cut -f1 -d".")
It looks like you're going about the operation the hard way. I would probably do something like this, assuming that there are no spaces in the file names:
ls | sed 's/\..*$//' | sort -u |
while read prefix
do
mkdir -p $outer_dir_name/$prefix
mv $prefix.* $outer_dir_name/$prefix
done
The ls could be made more precise with:
ls [0-9][0-9][0-9]-file.*
If I was worried about blanks and other odd-ball characters in the file names, I'd have to use something more careful:
for file in [0-9][0-9][0-9]-file.*
do
prefix=${file%%.*}
[ -d "$outer_dir_name/$prefix" ] || mkdir -p "$outer_dir_name/$prefix"
mv "$file" "$outer_dir_name/$prefix"
done
This executes more mv commands, in general.
I am trying to recreate the folder structure from a source in a target location and perform a command on each file found in the process using BASH.Based on some feedback and some searches I am trying to get this solution to work properly. Right now it is breaking because the windows folders have directories with spaces that it refuses to find.
I was able to get this to work after installing some additional features for my cygwin.
source='/cygdrive/z/austin1/QA/Platform QA/8.0.0/Test Cases'
target='/cygdrive/c/FullBashScripts'
# let ** be recursive
shopt -s globstar
for file in "$source"/**/*.restomatic; do
cd "${file%/test.restomatic}"
locationNew="$target${file#$source}"
mkdir -p "$(dirname "$target${file#$source}")"
sed -e 's/\\/\//g' test.restomatic | awk '{if ($1 ~ /^(LOAD|IMPORT)/) system("cat " $2); else print;}' | sed -e 's/\\/\//g' |awk '{if ($1 ~ /^(LOAD|IMPORT)/) system("cat " $2); else print;}' > $locationNew
done
If your bash version is 4 or above, this should work:
source="testing/web testing/"
target="c:/convertedFiles/"
# let ** be recursive
shopt -s globstar
for file in "$source"/**/*.test; do
newfile= "$target/${file#$source}"
mkdir -p "$(dirname "$newfile")"
conversion.command "$file" > "$newfile"
done
${file#$source} lops $source off the beginning of $file.
If you can guarantee that no files have newlines in their name, you can use find to get the names:
source="testing/web testing/"
target="c:/convertedFiles/"
find "$source" -name \*.test | while read file; do
newfile= "$target/${file#$source}"
mkdir -p "$(dirname "$newfile")"
conversion.command "$file" > "$newfile"
done
Your best bet would be to find to get the list of files:
You can do it as follows:
export IFS=`/bin/echo -ne "\n"` # set field separator to new lines only
cd testing # change to the source directory
find . -type d > /tmp/test.dirs # make a list of local directories
for i in `cat /tmp/test.dirs`; do # for each directory
mkdir -p "c:/convertedFiles/$i" # create it in the new location
done
find . -iname *.test > /tmp/test.files # record local file paths as needed
for i in `cat /tmp/test.files`; do # for each test file
process "$i" > "c:/convertedFiles/$i" # process it and store in new dir
done
Note that this is not the most optimal way -- but the easiest to understand and follow. This should work with spaces in filenames. You may have to tweak it further to get it to work under windows.
I would look into a tool called sshfs, or Secure Shell File System. It lets you mount a portion of a remote file system to somewhere local to you.
Once you have the remote fs mounted locally, you can run the follow shell script:
for f in *.*;
do
echo "do something to $f file..";
done
EDIT: I initially did not realize that target was always local anyway.
I want to create a shellscript that reads files from a .diz file, where information about various source files are stored, that are needed to compile a certain piece of software (imagemagick in this case). i am using Mac OSX Leopard 10.5 for this examples.
Basically i want to have an easy way to maintain these .diz files that hold the information for up-to-date source packages. i would just need to update these .diz files with urls, version information and file checksums.
Example line:
libpng:1.2.42:libpng-1.2.42.tar.bz2?use_mirror=biznetnetworks:http://downloads.sourceforge.net/project/libpng/00-libpng-stable/1.2.42/libpng-1.2.42.tar.bz2?use_mirror=biznetnetworks:9a5cbe9798927fdf528f3186a8840ebe
script part:
while IFS=: read app version file url md5
do
echo "Downloading $app Version: $version"
curl -L -v -O $url 2>> logfile.txt
$calculated_md5=`/sbin/md5 $file | /usr/bin/cut -f 2 -d "="`
echo $calculated_md5
done < "files.diz"
Actually I have more than just one question concerning this.
how to calculate and compare the checksums the best? i wanted to store md5 checksums in the .diz file and compare it with string comparison with "cut"ting out the string
is there a way to tell curl another filename to save to? (in my case the filename gets ugly libpng-1.2.42.tar.bz2?use_mirror=biznetnetworks)
i seem to have issues with the backticks that should direct the output of the piped md5 and cut into the variable $calculated_md5. is the syntax wrong?
Thanks!
The following is a practical one-liner:
curl -s -L <url> | tee <destination-file> |
sha256sum -c <(echo "a748a107dd0c6146e7f8a40f9d0fde29e19b3e8234d2de7e522a1fea15048e70 -") ||
rm -f <destination-file>
wrapping it up in a function taking 3 arguments:
- the url
- the destination
- the sha256
download() {
curl -s -L $1 | tee $2 | sha256sum -c <(echo "$3 -") || rm -f $2
}
while IFS=: read app version file url md5
do
echo "Downloading $app Version: $version"
#use -o for output file. define $outputfile yourself
curl -L -v $url -o $outputfile 2>> logfile.txt
# use $(..) instead of backticks.
calculated_md5=$(/sbin/md5 "$file" | /usr/bin/cut -f 2 -d "=")
# compare md5
case "$calculated_md5" in
"$md5" )
echo "md5 ok"
echo "do something else here";;
esac
done < "files.diz"
My curl has a -o (--output) option to specify an output file. There's also a problem with your assignment to $calculated_md5. It shouldn't have the dollar sign at the front when you assign to it. I don't have /sbin/md5 here so I can't comment on that. What I do have is md5sum. If you have it too, you might consider it as an alternative. In particular, it has a --check option that works from a file listing of md5sums that might be handy for your situation. HTH.