I have a many to many relationship between users and achievements. Table layout is similar to this.
users
-id
-first_name
-last_name
-email
acheivements
-id
-type-name
-description
achievement_user
-id
-acievement_id
-user_id
-is_complete (boolean)
-percentage_complete (integer)
-completed_at
I can get the bulk of the stuff I want such as all achievements with type = badge for a user that are in the pivot table. I can also get a list of all the achievements that have type = badge. Where I am stuck is trying to get all achievements with type = badge along with is_complete, percentage_complete, completed_at for that given user. So if there are 8 total badges and they have started 3 of them I would want to return 8 records where 3 of them would have the information from the pivot table. I know I could grab all badges and loop through them to add on additional information but I know there is a eloquent way that would be easier.
Thank for any help.
This is in response to you recent comment.
To achieve what you want, I have introduced a new method on the User model called achievementsblock, which uses php array_map method.
I have not tested the code, but you should get the idea.
//in User model
public function achievements()
{
return $this->belongsToMany('App\Achievements')->withPivot('is_complete', 'percentage_complete', 'completed_at');
}
//in User model
public function achievementsblock()
{
$all_achievements = Achievement::all();
return array_map(function($temp_achievement){
$achievement_ids = $this->achievements()->pluck('id');
$new_temp = new \stdClass();
$new_temp->type_name = $temp_achievement->type_name;
$new_temp->description = $temp_achievement->description;
if(in_array($temp_achievement->id, $achievement_ids)){
$user_achievement = $this->achievements()->where("achievements.id","=",$temp_achievement->id)->first();
$new_temp->is_complete = $user_achievement->is_complete;
$new_temp->percentage_complete = $user_achievement->percentage_complete;
$new_temp->completed_at = $user_achievement->completed_at;
}
else {
$new_temp->is_complete = 0;
$new_temp->percentage_complete = 0;
$new_temp->completed_at = null;
}
return $new_temp;
}, $all_achievements);
}
In your controllers, you can get the achievementsblock for a user as follows:
$user_achievement_blocks = User::first()->achievementsblock();
On your belongsToMany relationship, use the withPivot function as follows:
//in User model
public function acheivements()
{
return $this->belongsToMany('App\Acheivement')->withPivot('is_complete', 'percentage_complete', 'completed_at');
}
//in Acheivement model
public function users()
{
return $this->belongsToMany('App\User')->withPivot('is_complete', 'percentage_complete', 'completed_at');
}
You need to learn about whereHas method which lets you query on relationship while getting results
In User model
// create achievements relationship
public function achievements()
{
return $this->belongsToMany(Achievement::class)
->withPivot('is_complete', 'percentage_complete', 'completed_at');
}
//then query it like shown below.
$achievements= $user->achievements;
Read more here
Related
Trying to get property from a object in laravel. I have this:
public function index()
{
$firmen = Companies::all();
$allcountcompanies = Companies::count();
$agent = Agent::find($firmen->agent_firma_id);
return view('companies',compact(['firmen'],['allcountcompanies'],['agent']));
}
The Exeption gives me that:
Property [agent_firma_id] does not exist on this collection instance.
But when i put the id eg 1001 it shows corrent entry in db field.
What i0'm doing wrong?
Info:
CompaniesController.php (table: br_firma)
AgentController.php (table: br_firma_agents)
Table "br_firma_agents" contains a foreign_key from table "br_firma".
You are getting id from collection.
$firmens = Companies::all();
it return collection you may be use it useing loop and get one by one data as
for($firmens as $firmen){
$agent = Agent::find($firmen->agent_firma_id);
}
Or you create relation between Company and agent as,
In company model define relation as
public function agents(){
return $this->hasMany(Agent::class);
}
and in agent model define relation as
public function company(){
return $this->belongsTo(Companies::class);
}
and then call it as in controller,
$data = Companies::with('agents')->get();
You are trying to access an agent_firma_id from a collection of companies, you could first use a loop on that collection,or use an index on that collection,
you could try
$firmens = Companies::all();
foreach($firmens as $firmen){
$agent = Agent::find($firmen->agent_firma_id);
}
I'm trying to create a function in our Laravel 5.8 app that would add multiple records to a pivot table. At present we have the following setup;
Users
Training Courses
Users Training Courses (pivot table for the above relationships, with a few extra fields)
I want to be able to show all users in the database, then check their name, pick a training course and hit "Add" and it'll create a record in the pivot table for each user that was selected.
I can't figure out where to start with this - it seems like I need to have a "for each user selected, run the store function" loop in the controller, but I have no idea where to start.
I wasn't sure if there was an easy way to do this in eloquent or not. Is there a simple way to do this?
Eloquent does this automatically if you set up the relationships correctly and you don't have to worry about pivot tables.
class Users
{
public function trainingCourses()
{
return $this->hasMany(TrainingCourses::class);
}
}
class TrainingCourses
{
public function user()
{
return $this->belongsTo(User::class);
}
}
Then you can use the save() method to create the relationship. But I find it better to wrap this function inside a helper method that you can use throughout your code:
class Users
{
...
public function assignTrainingCourse(TrainingCourse $trainingCourse)
{
return $this->trainingCourses()->save($trainingCourse);
}
}
In your code, you could then do something as simple as this:
$user = User::find(1);
$trainingCourse = TrainingCourse::find(1);
$user->assignTrainingCourse($trainingCourse);
Building on this, suppose you have the following route to assign a training course, where it expects a trainingcourse_id in the request:
Route::post('/users/{user}/trainingcourses', 'UserTrainingCoursesController#store');
Thanks to route model binding, Laravel can inference the parent model (user) from the URL, and your controller might look like this:
// UserTrainingCoursesController.php
public function store(User $user)
{
$trainingCourse = TrainingCourse::find(request()->input('trainingcourse_id'));
$user->assignTrainingCourse($trainingCourse);
return back();
}
Of course, you'll want to put some validation in here, but this should get you started.
i have a tournament and a club model.i use many to many relationship between them.now i want to find a club model using pivot table.
i've tried this:
$tournament = Tournament::find(1);
$club = $tournament->clubs->wherePivot('team_as_1','1');
return $club;
but it shows:Method Illuminate\Database\Eloquent\Collection::wherePivot does not exist.
My tournament model:
public function clubs(){
return $this->belongsToMany('App\Club','tbl_club_tournament')->withPivot('team_as_1','team_as_4','team_as_5','team_as_6');
}
My club model:
public function tournament(){
return $this->belongsToMany('App\Tournament','tbl_club_tournament')->withPivot('team_as_1','team_as_4','team_as_5','team_as_6');
}
i want to find a club where team_as_1 = 1.
Try doing
$tournament = Tournament::find(1);
$club = $tournament->clubs()->wherePivot('team_as_1','1')->get();
return $club;
With the current approach you're calling method wherePivot on a collection (but that method doesn't exist on the collection class), however by calling the function $tournament->clubs(), that returns a query builder object on which you can call wherePivot()
Edit:
Seems you only need one item, so you should probably do
$club = $tournament->clubs()->wherePivot('team_as_1','1')->first();
Use Below
$tournament = Tournament::find(1);
$clubs = $tournament->clubs()->wherePivot('team_as_1','1')->get();
return $clubs;
return $this->hasManyThrough('App\Club', 'App\Tournament');
i have 4 table
inst
id
subject
report
id
subject
object
id
type
container
id
obj_id
i want with obj_id of container table, achieve the The corresponding object record.
then if type of object = 1, fetch data from inst table or type = 2, fetch data from report table
based on your information,
you can do like #Mahfuz Shishir answer
or
create new appends attribute inside Object Model
protected $appends = ['data'];
public function getDataAttribute()
{
if($this->attributes['type'] == 1) {
return Inst::where('inst_column', $this->attributes['object_column_to_match']); //this just sample
} else {
return Report::where('inst_column', $this->attributes['object_column_to_match']); //this just sample
}
}
The relation looks like.
In your Object.php Model
public function containers()
{
return $this->hasMany('App\Container', 'foreign_id');
}
And in your Container.php Model
public function object()
{
return $this->belongsTo('App\Object', 'foreign_id');
}
You provide little information. Implement rest of the controller code in your own sense. Or put some code that you have tried.
I have this (simplified) table structure:
users
- id
- type (institutions or agents)
institutions_profile
- id
- user_id
- name
agents_profile
- id
- user_id
- name
And I need to create a profile relationship on the Users model, but the following doesn't work:
class User extends Model
{
public function profile()
{
if ($this->$type === 'agents')
return $this->hasOne('AgentProfile');
else
return $this->hasOne('InstitutionProfile');
}
}
How could I achieve something like that?
Lets take a different approach in solving your problem. First lets setup relationship for the various models respectively.
class User extends Model
{
public function agentProfile()
{
return $this->hasOne(AgentProfile::class);
}
public function institutionProfile()
{
return $this->hasOne(InstitutionProfile::class);
}
public function schoolProfile()
{
return $this->hasOne(SchoolProfile::class);
}
public function academyProfile()
{
return $this->hasOne(AcademyProfile::class);
}
// create scope to select the profile that you want
// you can even pass the type as a second argument to the
// scope if you want
public function scopeProfile($query)
{
return $query
->when($this->type === 'agents',function($q){
return $q->with('agentProfile');
})
->when($this->type === 'school',function($q){
return $q->with('schoolProfile');
})
->when($this->type === 'academy',function($q){
return $q->with('academyProfile');
},function($q){
return $q->with('institutionProfile');
});
}
}
Now you can access your profile like this
User::profile()->first();
This should give you the right profile. Hope it helps.
you can do this by use another method please check this:
a blog Post and Video model could share a polymorphic relation to a
Tag model. Using a many-to-many polymorphic relation allows you to
have a single list of unique tags that are shared across blog posts
and videos. First, let's examine the table structure:
https://laravel.com/docs/5.4/eloquent-relationships#many-to-many-polymorphic-relations
Looks like that should be $this->type rather than $this->$type - since type is a property, not a variable.