i have 4 table
inst
id
subject
report
id
subject
object
id
type
container
id
obj_id
i want with obj_id of container table, achieve the The corresponding object record.
then if type of object = 1, fetch data from inst table or type = 2, fetch data from report table
based on your information,
you can do like #Mahfuz Shishir answer
or
create new appends attribute inside Object Model
protected $appends = ['data'];
public function getDataAttribute()
{
if($this->attributes['type'] == 1) {
return Inst::where('inst_column', $this->attributes['object_column_to_match']); //this just sample
} else {
return Report::where('inst_column', $this->attributes['object_column_to_match']); //this just sample
}
}
The relation looks like.
In your Object.php Model
public function containers()
{
return $this->hasMany('App\Container', 'foreign_id');
}
And in your Container.php Model
public function object()
{
return $this->belongsTo('App\Object', 'foreign_id');
}
You provide little information. Implement rest of the controller code in your own sense. Or put some code that you have tried.
Related
Trying to get property from a object in laravel. I have this:
public function index()
{
$firmen = Companies::all();
$allcountcompanies = Companies::count();
$agent = Agent::find($firmen->agent_firma_id);
return view('companies',compact(['firmen'],['allcountcompanies'],['agent']));
}
The Exeption gives me that:
Property [agent_firma_id] does not exist on this collection instance.
But when i put the id eg 1001 it shows corrent entry in db field.
What i0'm doing wrong?
Info:
CompaniesController.php (table: br_firma)
AgentController.php (table: br_firma_agents)
Table "br_firma_agents" contains a foreign_key from table "br_firma".
You are getting id from collection.
$firmens = Companies::all();
it return collection you may be use it useing loop and get one by one data as
for($firmens as $firmen){
$agent = Agent::find($firmen->agent_firma_id);
}
Or you create relation between Company and agent as,
In company model define relation as
public function agents(){
return $this->hasMany(Agent::class);
}
and in agent model define relation as
public function company(){
return $this->belongsTo(Companies::class);
}
and then call it as in controller,
$data = Companies::with('agents')->get();
You are trying to access an agent_firma_id from a collection of companies, you could first use a loop on that collection,or use an index on that collection,
you could try
$firmens = Companies::all();
foreach($firmens as $firmen){
$agent = Agent::find($firmen->agent_firma_id);
}
I need to set a morphed model dynamically based upon the row:
On the model I set it inside:
public function getMorphClass()
{
}
How can I get the item type from the row in the query? Something like:
public function getMorphClass()
{
return $this->type; //currently null but want row's type value
}
I have a many to many relationship between users and achievements. Table layout is similar to this.
users
-id
-first_name
-last_name
-email
acheivements
-id
-type-name
-description
achievement_user
-id
-acievement_id
-user_id
-is_complete (boolean)
-percentage_complete (integer)
-completed_at
I can get the bulk of the stuff I want such as all achievements with type = badge for a user that are in the pivot table. I can also get a list of all the achievements that have type = badge. Where I am stuck is trying to get all achievements with type = badge along with is_complete, percentage_complete, completed_at for that given user. So if there are 8 total badges and they have started 3 of them I would want to return 8 records where 3 of them would have the information from the pivot table. I know I could grab all badges and loop through them to add on additional information but I know there is a eloquent way that would be easier.
Thank for any help.
This is in response to you recent comment.
To achieve what you want, I have introduced a new method on the User model called achievementsblock, which uses php array_map method.
I have not tested the code, but you should get the idea.
//in User model
public function achievements()
{
return $this->belongsToMany('App\Achievements')->withPivot('is_complete', 'percentage_complete', 'completed_at');
}
//in User model
public function achievementsblock()
{
$all_achievements = Achievement::all();
return array_map(function($temp_achievement){
$achievement_ids = $this->achievements()->pluck('id');
$new_temp = new \stdClass();
$new_temp->type_name = $temp_achievement->type_name;
$new_temp->description = $temp_achievement->description;
if(in_array($temp_achievement->id, $achievement_ids)){
$user_achievement = $this->achievements()->where("achievements.id","=",$temp_achievement->id)->first();
$new_temp->is_complete = $user_achievement->is_complete;
$new_temp->percentage_complete = $user_achievement->percentage_complete;
$new_temp->completed_at = $user_achievement->completed_at;
}
else {
$new_temp->is_complete = 0;
$new_temp->percentage_complete = 0;
$new_temp->completed_at = null;
}
return $new_temp;
}, $all_achievements);
}
In your controllers, you can get the achievementsblock for a user as follows:
$user_achievement_blocks = User::first()->achievementsblock();
On your belongsToMany relationship, use the withPivot function as follows:
//in User model
public function acheivements()
{
return $this->belongsToMany('App\Acheivement')->withPivot('is_complete', 'percentage_complete', 'completed_at');
}
//in Acheivement model
public function users()
{
return $this->belongsToMany('App\User')->withPivot('is_complete', 'percentage_complete', 'completed_at');
}
You need to learn about whereHas method which lets you query on relationship while getting results
In User model
// create achievements relationship
public function achievements()
{
return $this->belongsToMany(Achievement::class)
->withPivot('is_complete', 'percentage_complete', 'completed_at');
}
//then query it like shown below.
$achievements= $user->achievements;
Read more here
Im trying to use a laravel accessor to modify the content of a column when retrieving it. Im doing it like this:
On my model:
public function getMyColumnAttribute($value)
{
//Modify the content
return $value.'tttt';
}
On my controller:
public function test()
{
return MyModel::select('my_column')->find(1);
}
This works perfectly when the column in my DB is named 'my_column', but my entire database use camel case, so the actual name of the column is myColumn and the accessor just dont work in that case, I mean, it does return the value of my column, but without the modification I did in the accessor. I think it must be a way to it but I cant find how.
Thanks for the help
EDIT
I just realized that while this doesnt work: (myColumn is of type time on a MySql DB)
public function test()
{
return MyColumn::select('myColumn')->find(1);
//returns {"myColumn":"08:00:00"}
}
This acctually do what I expect
public function test()
{
$result = MyColumn::select('myColumn')->find(1);
return $result->myColumn;
// returns 08:00:00tttt
}
accessor doesnt modify the column raw data, it is used on create a new Attribute
use Mutator, save the modifyed raw data to db
use Accessor, get the raw data and modify it and assign to a new attribute
in your case
public function getMyColumnAttribute()
{
//Modify the content
return $this->attributes['type_column_name_here'] . 'tttt';
}
public function test()
{
// myColumn = the column name
$result = MyColumn::select('myColumn')->find(1);
// this is return the column value 08:00:00
return $result->myColumn;
// this will return accessor value 08:00:00tttt
return $result->my_column;
}
getMyColumnAttribute will convert to my_column
I have this (simplified) table structure:
users
- id
- type (institutions or agents)
institutions_profile
- id
- user_id
- name
agents_profile
- id
- user_id
- name
And I need to create a profile relationship on the Users model, but the following doesn't work:
class User extends Model
{
public function profile()
{
if ($this->$type === 'agents')
return $this->hasOne('AgentProfile');
else
return $this->hasOne('InstitutionProfile');
}
}
How could I achieve something like that?
Lets take a different approach in solving your problem. First lets setup relationship for the various models respectively.
class User extends Model
{
public function agentProfile()
{
return $this->hasOne(AgentProfile::class);
}
public function institutionProfile()
{
return $this->hasOne(InstitutionProfile::class);
}
public function schoolProfile()
{
return $this->hasOne(SchoolProfile::class);
}
public function academyProfile()
{
return $this->hasOne(AcademyProfile::class);
}
// create scope to select the profile that you want
// you can even pass the type as a second argument to the
// scope if you want
public function scopeProfile($query)
{
return $query
->when($this->type === 'agents',function($q){
return $q->with('agentProfile');
})
->when($this->type === 'school',function($q){
return $q->with('schoolProfile');
})
->when($this->type === 'academy',function($q){
return $q->with('academyProfile');
},function($q){
return $q->with('institutionProfile');
});
}
}
Now you can access your profile like this
User::profile()->first();
This should give you the right profile. Hope it helps.
you can do this by use another method please check this:
a blog Post and Video model could share a polymorphic relation to a
Tag model. Using a many-to-many polymorphic relation allows you to
have a single list of unique tags that are shared across blog posts
and videos. First, let's examine the table structure:
https://laravel.com/docs/5.4/eloquent-relationships#many-to-many-polymorphic-relations
Looks like that should be $this->type rather than $this->$type - since type is a property, not a variable.