what kind of variable/function/object is session("var") = "Value" - session

I am trying to make modifications to a vbscript that uses the line:
Session("Variable") = "MyVariable String"
This line requires it to be ran within a different program which is not available where I am doing my development. This line is NOT important to the development that I am doing and I just need it to NOT blow up with 'undefined variable session' when I am running with 'Option explicit'. What class, dictionary, variable type, or whatever do I need to create in order for that line to work without warnings/errors? I am currently just commenting them out, but when I copy and paste my code back in production I have to go back through and hope that I have uncommitted all of them back out. I'd rather just add a for instance "Set Session = New FooSomething" at the top of the code that will make it work and just remove that line when I add to production code. Thanks for your time.

Related

golang is executing the certian code which it shuoldn't in if else (log checked)

All log in this area is not printed (showing inside it's not running). However the last line is execute anyway. I'm so frustrated and sad, totally had no idea. Many thanks if there's any idea on it.
if !reflect.DeepEqual(MachineNow.TCP_machine.Two_D_Dta_Old, twoD_new) {
//the situation should not be executed
log.Println("new to old updated") //all log is not printing (O)
fmt.Println("new", twoD_new[0][0])
fmt.Println("old", MachineNow.TCP_machine.Two_D_Dta_Old[0][0])
MachineNow.TCP_machine.Two_D_Dta_Old = twoD_new //this line is doing anyway (X)
}
Have you checked your “log” output and level?
Maybe you set the output level to be higher than “Println”, so it’s simply ignored.
Try to use debug to know if this runs into this code block or just your assumption.
One more thing to check is: that if you run it by unit test, you need to add the “-v” flag to show output.
Solution: I trasform the object into JSON format and assign to the object. I don't know why but this is the only way to avoid execute that line no matter what. I thought it was just a mistake, now seems that line was indeed executed for unknown reason. it was running windows x64.
new_json, _ := json.Marshal(twoD_new)
_ = json.Unmarshal([]byte(new_json), &MachineNow.TCP_machine.Two_D_Dta_Old)

Kamailio 4.4 seturi Only Accepts Explicit Strings?

I've been working at implementing a simple serial forking described in the TM module's documentation (the Q values are stored as a priority weight in a mysql table) where my proxy is querying a database to determine to what domain to forward to.
I've verified through extensive use of xlog that a variable I'm using to build the new URI to use with seturi is getting everything correctly. I use an append_branch call in a subsequent while loop iterating over my sql query results, which doesn't have any problems with taking a very similarly formatted parameter. However, when I go to restart Kamailio it simply gripes at me that a string is expected. The line it corresponds to from console is just the seturi call. I've tried casting as a string, but that doesn't seem to be part of 4.4 (or my syntax is wrong).
I've thought about building the URI strings and storing into avp, but I suspect I'd have the same problem.
For reference, this is what I'm doing:
$var(basedest) = "sip:" + $var(number) + "#" + $(dbr(destination=>[0,0]))+ ":" + $var(port);
seturi($var(basedest));
And what it's outputting when trying to load the config:
<core> [cfg.y:3368]: yyerror_at(): parse error in config file //etc/kamailio/kamailio.cfg, line 570, column 9-22: syntax error
<core> [cfg.y:3371]: yyerror_at(): parse error in config file //etc/kamailio/kamailio.cfg, line 570, column 23: bad argument, string expected
Naturally, when I put $var(basedest) in double quotes, it's literally interpreted as a string. Single quotes behave similarly. Is there something I can do to work around this? When I feed it an explicit hardcoded string, it's happy as a can be and the routing works fine. When I try to do something very simple like the above, it gets upset. If possible, I'd like to avoid updating as I initially grabbed Kamailio from the yum repo.
Thanks in advance - this has been bugging me a good while.
Apparently, not a new problem. I ended up finding out what I can do to work around it.
For reference, seturi and $ru pseudo variable refer to the same thing. So basically you'd just do:
$var(mynewru) = "sip:user#domain:5060";
$ru = $var(mynewru);
This would achieve the same thing I was originally attempting to do before based on the TM module's documentation. For serial forking, issuing some number of append_branch calls is fine.

Darwin Streaming Server install problems os x

My problem is the same as the one mentioned in this answer. I've been trying to understand the code and this is what I learned:
It is failing in the file parse_xml.cgi, tries to get messages (return $message{$name}) from a file named messages (located in the html_en directory).
The $messages value comes from the method GetMessageHash in file adminprotocol-lib.pl:
sub GetMessageHash
{
return $ENV{"QTSSADMINSERVER_EN_MESSAGEHASH"}
}
The $ENV{"QTSSADMINSERVER_EN_MESSAGEHASH"} is set in the file streamingadminserver.pl:
$ENV{"QTSSADMINSERVER_EN_MESSAGEHASH"} = $messages{"en"}
I dont know anything about Perl so I have no idea of what the problem can be, for what I saw $messages{"en"} has the correct value (if I do print($messages{"en"}{'SunStr'} I get the value "Sun")).
However, if I try to do print($ENV{"QTSSADMINSERVER_EN_MESSAGEHASH"}{'SunStr'} I get nothing. Seems like $ENV{"QTSSADMINSERVER_EN_MESSAGEHASH"} is not set
I tried this simple example and it worked fine:
$ENV{"HELLO"} = "hello";
print($ENV{"HELLO"});
and it works fine, prints "hello".
Any idea of what the problem can be?
Looks like $messages{"en"} is a HashRef: A pointer to some memory address holding a key-value-store. You could even print the associated memory address:
perl -le 'my $hashref = {}; print $hashref;'
HASH(0x1548e78)
0x1548e78 is the address, but it's only valid within the same running process. Re-run the sample command and you'll get different addresses each time.
HASH(0x1548e78) is also just a human-readable representation of the real stored value. Setting $hashref2="HASH(0x1548e78)"; won't create a real reference, just a copy of the human-readable string.
You could easily proof this theory using print $ENV{"QTSSADMINSERVER_EN_MESSAGEHASH"} in both script.
Data::Dumper is typically used to show the contents of the referenced hash (memory location):
use Data::Dumper;
print Dumper($messages{"en"});
# or
print Dumper($ENV{"QTSSADMINSERVER_EN_MESSAGEHASH"});
This will also show if the pointer/reference could be dereferenced in both scripts.
The solution for your problem is probably passing the value instead of the HashRef:
$ENV{"QTSSADMINSERVER_EN_SUN"} = $messages{"en"}->{SunStr};
Best Practice is using a -> between both keys. The " or ' quotes for the key also optional if the key is a plain word.
But passing everything through environment variables feels wrong. They might not be able to hold references on OSX (I don't know). You might want to extract the string storage to a include file and load it via require.
See http://www.perlmaven.com/ or http://learn.perl.org for more about Perl.
fix code:
$$ENV{"QTSSADMINSERVER_EN_MESSAGEHASH"} = $messages{"en"};
sub GetMessageHash
{
return $$ENV{"QTSSADMINSERVER_EN_MESSAGEHASH"};
}
ref:
https://github.com/guangbin79/dss6.0.3-linux-patch

How do I remove the 'Done' message after my program has executed?

I made a program that is similar to clearing RAM. However, it always leaves a "Done" message followed by a dotted line after being executed. In addition, if you scroll up, you can see that the program was executed. Is there a way to remove both of these things? If you can't hide the fact that a program was executed, could you suppress the 'Done' message?
I have tried adding ClearHome" and " as the last line of my program, and neither stops the Done message from displaying.
Bonus points if your solution can be contained within the original program.
In a separate program, type the following line of code:
AsmPrgmFDCB00AEC9
Then at the end of the original program, type the following line of code:
Asm(prgmPROGRAMNAME
It is recommended that you test this out first with all programs archived, just running the above line of code alone, in case it fails. Hex codes like that one have been known to fail, and sometimes clears the RAM.
You can also try these other hex codes, but always keep in mind the warning above. My RAM has been cleared by this before, so use caution:
http://tibasicdev.wikidot.com/hexcodes
This works on TI 83 and 84, may be different with other calculator types.
EDIT:
I found a way to do this without an external program, and is much simpler.
Just add the following line of code to the end of your program:
Output(1,1," //no space, just a quote
You may or may not have to add ClrHome before that line of code.
This should prevent the Done message from appearing at the end.
Hope this helps!
Put an empty string at the end of your program, so your last line looks like this:
""
Or this
"
The empty string is stored to ans and will be displayed as a blank line rather than the Done message.
There is also an assembly hexcode to do this without leaving the blank line at the top:
FDCB00AEC9
When run at the end of the program using one of the various methods of running assembly, it will leave you with a blank, fully operational homescreen.
Outputting an empty string will prevent the Done message and also preserve Ans, in case a calling program is expecting to use it.
Output(Y,X,"")
See http://tibasicdev.wikidot.com/output for more details on Output(.
In your situation, run Clear Entries (found under Mem), then scroll up so that the Done message is selected and press Clear to get rid of it.

VBScript and presenting an input box

I am writing a script to capture the login time. In the final production, there would be no input from any user. However I am testing it and I wanted to know how I add extra code to determine that
If its in 'debug' mode AND
The user that is logging in is me (lets say my username is joe.smith on the domain called EXAMPLE)
then present an input box to allow me to type the date, time for logging in.
All other users would never see this and it would capture today with the system time.
I would also like to hide the code so if the script is opened by the wrong person, they wouldnt be able to make heads or tails of whats going on.
You can use a command line parameter as Matt says to set the script into debug mode, eg
dim isdebug: isdebug = WScript.Arguments.Named.Exists("debug")
WScript.Echo("in debug mode: " & isdebug)
Which you can invoke with
wscript debugscript.vbs /debug
To get the current user name, you can use either the WMI Service or the WScript.Network object.
Once you have the username, you can conditionally throw up an InputBox and collect the value returned:
dim date_: date_ = Now()
if isdebug and username = "me" then
dim value: value = CDate(InputBox("enter the date and time (dd/mm/yyyy hh:mm:ss)", "please", Now()))
' validate the input here
date_ = CDate(value)
end if
And finally, to obfuscate your code you could use the Scripting.Encoder although it looks like this doesn't seem to be supported on Vista or Windows 7. There does seem to be a few hits on googling the phrase obfuscating vbscript, anyway.
Most of this sounds like it can be resolved by the logic of the script.
Have a command line parameter (debug is an appropriate name) and then have some if logic in the code to do as you wish (present the input box).
For the code obfuscation, I don't know how this could be done in vbscript. Windows scripting host works with JavaScript as well though and there are plenty of tools on the web for making JS harder to read. Maybe you want to look a using JS...
HTH,
Matt
I think you can check the property App.LogMode to see if you are in 'debug' mode or not. If it is 0 then you are running debug mode and if it is 1 you are not.

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