How to Use Ajax and post data request on another URL?
solve ajax Issue
$.ajax({
type: 'POST',
url: 'https://kyleschaeffer.com/feed/',
data: { postVar1: 'theValue1', postVar2: 'theValue2' },
beforeSend:function(){
// this is where we append a loading image
$('#ajax-panel').html('<div class="loading"><img src="/images/loading.gif" alt="Loading..." /></div>');
},
success:function(data){});
});
This jQuery function is perfect in the sense that it handles 99% of all the AJAX requests you’ll ever need to make, it includes a success and failure function to ensure that users get the proper feedback they need, and you’ll get a spinning loading image while the request is being processed to boot.
$.ajax({
type: 'POST',
url: 'https://kyleschaeffer.com/feed/',
data: { postVar1: 'theValue1', postVar2: 'theValue2' },
beforeSend:function(){
// this is where we append a loading image
$('#ajax-panel').html('<div class="loading"><img src="/images/loading.gif" alt="Loading..." /></div>');
},
success:function(data){
// successful request; do something with the data
$('#ajax-panel').empty();
$(data).find('item').each(function(i){
$('#ajax-panel').append('<h4>' + $(this).find('title').text() + '</h4><p>' + $(this).find('link').text() + '</p>');
});
},
error:function(){
// failed request; give feedback to user
$('#ajax-panel').html('<p class="error"><strong>Oops!</strong> Try that again in a few moments.</p>');
}
});
Related
I'm currently trying to make an ajax POST request to send a testimonial simple form to a Django view. The problem is this request is returning a GET instead of a POST.
This is my ajax:
<script>
$(document).ready(function(){
$("form.testimonial-form").submit(function(e){
e.preventDefault();
var dataString = $(this).serialize();
$.ajax({
type: "POST",
url: "/testimonials",
data: dataString,
success: function(_data) {
if (_data[0]){
$('.modal-text').css({display: "none"});
}
else{
$('.unsuccess').css({display: "block"});
}
}
});
});
});
</script>
Any idea what could I be doing wrong?
replace type by method
method: 'post',
also you may need send headers:
headers: {
'X-CSRFToken': getCSRFToken()
},
where getCSRFToken is:
function getCSRFToken() {
return $('input[name="csrfmiddlewaretoken"]').val();
}
I am not really sure why this is happening, but i would write the function in a bit different way. since ajax();'s default type is "GET", i suspect somewhere it is being set to default.
first set the type="button" of submit button (whose id is e.g. "submit_button_id"), so it doesnot submits if you click on it. or put the button outside of <form>
then try this code
<script>
$(function(){ // same as "$(document).ready(function()"..
$("#submit_button_id").on('click',function(){
var dataString = $('form.testimonial-form').serialize();
$.ajax({
type: "POST",
url: "/testimonials",
data: dataString,
success: function(_data) {
if (_data[0]){
$('.modal-text').css({display: "none"});
}
else{
$('.unsuccess').css({display: "block"});
}
}
});
});
});
</script>
I have a real problem. I have a php code and a form where when the form is submitted a POST request is sent and the page reloads again and ofcourse the post is viwed in the page.But i want to work with AJAX in order page not to be refreshed.I know the basics of AJAX but i don't want to build all the project from the beggining.Is there a way in success function of AJAX to link to my php code??
$.ajax({
type: "POST",
url: "index.php",
datatype: "html",
data: dataString,
success: function(data) {
//How can i link here to start running my php code which is located in the same page.
}
});
$.ajax({
type: "POST",
url: "somescript.php",
datatype: "html",
data: dataString,
success: function(data) {
// try this
console.log(data);
// see what 'data' actually is
}
});
then check in the browser by hitting F12 to look at the console.
also are you sure you want datatype of html ? you probably want a data type of json or XML , what is the server returning to you after the ajax post?
You have to cancel the form's submission so that the ajax request will take place, otherwise it is canceled. Also use .serialize to get a name-value pair string of the form data to use in the ajax call.
Html
<form id="MyForm">
<button id="MyButtonId">Submit</button>
</form>
JS
$("#MyForm").submit(function(e){
//Prevents the form from being submitted
e.preventDefault();
$.ajax({
type: "POST",
data: $("#MyForm").serialize(),
url: "somescript.php",
datatype: "html",
data: dataString,
success: function(data) {
alert(data);
}
});
});
The following image tag is in my Login Page
<img id="CaptchaImg" alt="Captcha" src="#url.action("Captcha","Login")" style="" />
Now when I refresh my login Page, it works fine, and gets the image from the controller, but when I logOut and the login Page renders .the controller method is not being called.Problem is only in IE works fine on Chrome.Is there are work around?
Can I do something with jQuery Ajax call to the controller, I tried this but the success method is not called. Is there any other way?
$.ajax({
type: "GET",
url: '/Login/CaptchaImage',
datatype: "image",
success: function(data) {
debugger
$('#CaptchaImg').attr('src', data);
}
});
Try this
$.ajax({
type: "GET",
url: '#Url.Action("Captcha","Login")',
dataType:"image/jpg",
success: function (data) {
$('#CaptchaImg').attr('src', data);
}
});
web Server should return base64 Data. like this
{ base64Data:"blahblahblah" }
your ajax request content-type could be plain json ;
in your success function in ajax you could do like this
success:function(data){
var src="data:image/png;base64,"+data.base64Data;
$('#CaptchaImg').attr(src,src)
}
The following code is alerting 'undefined' and not appending the html from the response data as I expected. Does anyone know why?
JavaScript:
$(function() {
$('.document').on('click', '.ajax', function(e) {
e.preventDefault();
// ajax request
$.ajax({
async: true,
cache: false,
type: 'post',
url: '/echo/html/',
data: {
html: '<p>This is echoed the response in HTML format</p>',
delay: 1
},
dataType: 'html',
beforeSend: function() {
console.log('Fired prior to the request');
},
success: function(data) {
console.log('Fired when the request is successfull');
$('.document').append(data);
},
complete: function() {
console.log('Fired when the request is complete');
}
});
});
});
HTML:
<div class="document">
<a class="ajax" href="#">Fire an AJAX request</a>
</div>
Example jsFiddle: http://jsfiddle.net/L6bJ2/3/
The HTTP method is specified with by type rather than method, so you should be using;
type: 'post',
Because you've specified the response type as HTML, you get a String passed in the data parameter of the success callback; but it looks like you're expecting JSON as you're trying to use data.html. Instead, use data directly;
success: function(data) {
console.log('Fired when the request is successfull');
$('.document').append(data);
},
With these changes, you'll find it works: http://jsfiddle.net/L6bJ2/6/
Live Example is here
https://stackoverflow.com/a/34940340/5361795
use beforeSend or complete callback functions in ajax call,
Source ShoutingCode
i have a page loaded via jquery tabs ajax, i have a form within this page that i want to show form response via ajax. response is loading from this code:
$('#whois').submit(function() {
$.ajax({
data: $('#whois').serialize(),
cache:false,
type: "POST",
url: $('#whois').attr('/lib/domainchecker.php'),
success: function(response) {
$('#reply').html(response);
}
});
return false;
);
but my form submit to parent page instead of /lib/domainchecker.php. so i see headers of my page instead of response!
any idea what makes this happen?
When you are loading content on the page via AJAX and you need to apply events to the loaded content you need to use the jquery live().
$('#whois').live('submit', function() {
$.ajax({
data: $('#whois').serialize(),
cache:false,
type: "POST",
url: $('#whois').attr('/lib/domainchecker.php'),
success: function(response) {
$('#reply').html(response);
}
});
This of course goes on the main host page rather than the loaded content page.
problem is solved, no thing related to loading page via ajax but there was an error with code, i shouldn't post to $('#whois').attr('/lib/domainchecker.php') but just '/lib/domainchecker.php'
corrected code:
$('#whois').live('submit', function() {
$.ajax({
data: $('#whois').serialize(),
cache:false,
type: "POST",
url: '/lib/domainchecker.php',
success: function(response) {
$('#reply').html(response);
}
});