I have a real problem. I have a php code and a form where when the form is submitted a POST request is sent and the page reloads again and ofcourse the post is viwed in the page.But i want to work with AJAX in order page not to be refreshed.I know the basics of AJAX but i don't want to build all the project from the beggining.Is there a way in success function of AJAX to link to my php code??
$.ajax({
type: "POST",
url: "index.php",
datatype: "html",
data: dataString,
success: function(data) {
//How can i link here to start running my php code which is located in the same page.
}
});
$.ajax({
type: "POST",
url: "somescript.php",
datatype: "html",
data: dataString,
success: function(data) {
// try this
console.log(data);
// see what 'data' actually is
}
});
then check in the browser by hitting F12 to look at the console.
also are you sure you want datatype of html ? you probably want a data type of json or XML , what is the server returning to you after the ajax post?
You have to cancel the form's submission so that the ajax request will take place, otherwise it is canceled. Also use .serialize to get a name-value pair string of the form data to use in the ajax call.
Html
<form id="MyForm">
<button id="MyButtonId">Submit</button>
</form>
JS
$("#MyForm").submit(function(e){
//Prevents the form from being submitted
e.preventDefault();
$.ajax({
type: "POST",
data: $("#MyForm").serialize(),
url: "somescript.php",
datatype: "html",
data: dataString,
success: function(data) {
alert(data);
}
});
});
Related
I did some admin panel in wordpress sheet but i'm adding options and have everything in one line in the data, it's pain if I keep adding options, works that way but it looks messy.
example
$.ajax({
type: 'POST',
url: ajaxurl,
data: 'action=general_settings_action&zkr_logo='+zkrlogo+'&zkr_favicon='+zkrfavicon+'&zkr_background='+zkrbackground+'&zkr_linkcolor='+zkrlinkcolor+'&zkr_linkhover='+zkrlinkhover+'&zkr_colorbackground='+zkrcolorbackground,
success: function(data){
alert(data);
}});
I would like to make some lines to that data field like for example
$.ajax({
type: 'POST',
url: ajaxurl,
data:
'action=general_settings_action&
zkr_logo='+zkrlogo+'&
zkr_favicon='+zkrfavicon+'&
zkr_background='+zkrbackground+'&
zkr_linkcolor='+zkrlinkcolor+'&
zkr_linkhover='+zkrlinkhover+'&
zkr_colorbackground='+zkrcolorbackground,
success: function(data){
alert(data);
}});
But putting the code like that doesn't work I have tried with \n and some other stuff but still wont do the work.
I apreciate the help... Thanks
Try doing this:
Make a JSON data object that contains the parameters you want to send
var DATA = {
action:'general_settings_action',
zkr_logo:zkrlogo,
zkr_favicon:zkrfavicon,
zkr_background:zkrbackground,
zkr_linkcolor:zkrlinkcolor,
zkr_linkhover:zkrlinkhover,
zkr_colorbackground:zkrcolorbackground
}
The send the data in your AJAX request using the data field
$.ajax({
type: 'POST',
url: ajaxurl,
data: DATA,
success: function(data){
alert(data);
}});
I checked this out at: David Walsh's guide
You need to add
'zkr_logo=' + zkrlogo + '' +
instead of
zkr_logo='+zkrlogo+'&
then it will form one String
I have been learning AJAX for the best part of 2 hours, trying to get my head around how to get this to work, it seems it is calling the function as if I put an alert in, it all works fine.
I tried using another method and it seemed to call the function on it's own and it would load what the .php page is echoing.
What am I doing wrong in order for it to not work at all?
<script type="text/javascript">
$('a.fire').click(call_ajax);
function call_ajax() {
$.ajax({
type: "GET",
url: "http://127.0.0.1/onlineshop/admin/scripts/test.php",
dataType: "html",
success: function(html){
$("#holder").append(html);
}
});
}
</script>
Edit: I have also just tried
$('a.fire').click(function() {
$.ajax({
type: "GET",
url: "http://127.0.0.1/onlineshop/admin/scripts/test.php",
dataType: "html",
success: function(html){
$("#holder").append(html);
}
});
});
Which also does not work.
EDIT: I have now got code that GET's the php file I wanted, but for some reason does it on it's own
<script type="text/javascript">
function call_ajax() {
$.ajax({
type: "GET",
url: "http://127.0.0.1/onlineshop/admin/scripts/test.php",
dataType: "html",
success: function(html){
$("#holder").append(html);
}
});
}
<script type="text/javascript">
$(function() {
$(document).ready(function() {
$('a.fire').click(call_ajax());
});
});
The issue with this code is that it fires on it's own
EDIT: Now have new code, that is attempting to fire according to Firebug console but I get the alert ERROR: error, so I don't have a clue what is happening in order for it to fail, I have also tried many different URL's with no working solution
$('a.fire').click(function () {
$.ajax({
type: "GET",
url: "/onlineshop/admin/scripts/test.php",
dataType: "html",
success: function(html){
$("#holder").append(html);
},
error:function(xhr, text, error){
alert("Error: " + text);
}
});
});
SOLVED: I have now got it to work! For some reason my anchor had a href of "", which would cause it to reload the page and removing my GET from the page
ajax will only work if it's the same domain. This means that if you execute jQuery from domain x to domain y, it won't work. This is for safety-reasons to prevent websites from loading from another website. Does your jQuery-ajax call work if you remove the 127.0.0.1 from your url?
Furthermore I guess you should add the click-function inside your $(document).ready(); function, like this:
$(document).ready(function(){
$('a.fire').click(function() {
$.ajax({
type: "GET",
url: "onlineshop/admin/scripts/test.php",
dataType: "html",
success: function(html){
$("#holder").append(html);
}
});
});
});
for testing purposes, you can also use the complete function inside your ajax and alert your data. firebug can be helpful too to find your problem :)
I have a problem to refresh a bloc in my page.
Here is the request:
> $("#pwd_lost_link").click(function(){
alert('1');
$.ajax({
type : 'POST',
url: 'test.php',
dataType: 'json',
data :{"nom" : "akbar"},
success : function(data){
$("#main_bloc").append(data.msg);
alert('2');
},
error : function(XMLHttpRequest, textStatus, errorThrown) {
alert(XMLHttpRequest.responseText);
alert(errorThrown); }
}); })
and here is the php file
<?php
$return['nom'] = "ffrfrfrfr";
echo json_encode($return)
?>
It doesn't work. It give me a status error ( 0 ) and the page is automatically reloaded
Thanks
Michaël
Confusing question Michael, not sure what you mean by "the page is automatically reloaded" but you should do 2 things:
In the $.ajax() method, make sure your success called back is handling the data correctly. You are looking for data.msg but I don't see where .msg comes from.
$.ajax({
type: "GET",
contentType: "application/json; charset=utf-8",
data: {},
dataType: "json",
url: url,
success: function(data) {
// parse data object so you can see what's being returned ex. alert(data) or alert(data[0]) or alert(data.nom)
},
error: function (xhr, status, error) {
// XHR DOM reference: http://www.w3schools.com/dom/dom_http.asp
// check for errors ex. alert(xhr.statusText);
}
});
On the PHP side, you may want to debug there to see what is being received and what you are sending back.
Aside from that using an XHR viewer like Firebug or Chrome's built-in utility (CTRL+SHIFT+I) can be very helpful.
And on a final note, if pwd_lost_link is a link elment a id="pwd_lost_link" href="..." then you will have to stop the browser from following the link before you process the AJAX.
$("#pwd_lost_link").click(function(e) {
e.preventDefault();
alert('1');
$.ajax({
...
});
If you aren't seeing the '1' being alerted then that is definitely your first problem.
You're trying to access data.msg, but your PHP script is only creating data.nom. So data.msg doesn't exist. Try changing data.msg to data.nom and see if this does what you want.
Supposing I have the following code which returns a Javascript object which I can read in Firebug's console:
FB.api('/me',function(apiresponse){
console.log(apiresponse);
});
How can I then use the data from apiresponse in an Ajax request on the same page?
Currently my Ajax request looks as follows:
$.ajax({
// CodeIgniter URL
url: "<?=site_url?>('login/add_fb_users'); ?>",
type: 'POST',
data: apiresponse,
success: function(data) {
alert(data);
}
});
I know very little about Javascript, but reading around the subject leads me to think I have to convert the Javascript object to a JSON string. Is that correct? Am I on the right track?
You could put your AJAX call inside the handler for the API call like below..
FB.api('/me', function(apiresponse){
console.log(apiresponse);
$.ajax({
// CodeIgniter URL
url: "<?=site_url?>('login/add_fb_users'); ?>",
type: 'POST',
data: apiresponse,
success: function(data) {
alert(data);
}
});
});
one possible way:
define a global variable in your javascript, e.g. var myVar1;
set apireponse to the global variable in your FB.api callback (i.e. where u call console.log)
reference the var myVar1 in your ajax fcn.
i have a page loaded via jquery tabs ajax, i have a form within this page that i want to show form response via ajax. response is loading from this code:
$('#whois').submit(function() {
$.ajax({
data: $('#whois').serialize(),
cache:false,
type: "POST",
url: $('#whois').attr('/lib/domainchecker.php'),
success: function(response) {
$('#reply').html(response);
}
});
return false;
);
but my form submit to parent page instead of /lib/domainchecker.php. so i see headers of my page instead of response!
any idea what makes this happen?
When you are loading content on the page via AJAX and you need to apply events to the loaded content you need to use the jquery live().
$('#whois').live('submit', function() {
$.ajax({
data: $('#whois').serialize(),
cache:false,
type: "POST",
url: $('#whois').attr('/lib/domainchecker.php'),
success: function(response) {
$('#reply').html(response);
}
});
This of course goes on the main host page rather than the loaded content page.
problem is solved, no thing related to loading page via ajax but there was an error with code, i shouldn't post to $('#whois').attr('/lib/domainchecker.php') but just '/lib/domainchecker.php'
corrected code:
$('#whois').live('submit', function() {
$.ajax({
data: $('#whois').serialize(),
cache:false,
type: "POST",
url: '/lib/domainchecker.php',
success: function(response) {
$('#reply').html(response);
}
});