The following image tag is in my Login Page
<img id="CaptchaImg" alt="Captcha" src="#url.action("Captcha","Login")" style="" />
Now when I refresh my login Page, it works fine, and gets the image from the controller, but when I logOut and the login Page renders .the controller method is not being called.Problem is only in IE works fine on Chrome.Is there are work around?
Can I do something with jQuery Ajax call to the controller, I tried this but the success method is not called. Is there any other way?
$.ajax({
type: "GET",
url: '/Login/CaptchaImage',
datatype: "image",
success: function(data) {
debugger
$('#CaptchaImg').attr('src', data);
}
});
Try this
$.ajax({
type: "GET",
url: '#Url.Action("Captcha","Login")',
dataType:"image/jpg",
success: function (data) {
$('#CaptchaImg').attr('src', data);
}
});
web Server should return base64 Data. like this
{ base64Data:"blahblahblah" }
your ajax request content-type could be plain json ;
in your success function in ajax you could do like this
success:function(data){
var src="data:image/png;base64,"+data.base64Data;
$('#CaptchaImg').attr(src,src)
}
Related
I have the following ajax link:
#Html.AjaxActionLink(item.Name, "https://test.testspace.space/storage/Data/stream?tokenValue=e58367c8-ec11-4c19-995a-f37ad236e0d2&fileId=2693&position=0", new AjaxOptions { HttpMethod = "POST" })
However, although it is set to POST, it seems that it still sends GET request.
UPDATE:
As suggested below, I also tried with js functuion like this:
function DownloadAsset() {
alert("downloading");
$.ajax({
type: "POST",
url: 'https://test.testspace.space/storage/Data/stream?tokenValue=add899c5-7851-4416-9b06-4587528a72db&fileId=2693&position=0',
success: function () {
}
});
}
However, it still seems to be GET request. Parameters must be passed as query and not in the body of the request because they are expected like that by the target action. I don't know why (it would be more natural to have GET request) but back-end developer designed it like this due to some security reason.
If I use razor form like this, then it works:
<html>
<form action="https://test.testspace.space/storage/Data/stream?tokenValue=2ec3d6d8-bb77-4c16-bb81-eab324e0d29a&fileId=2693&position=0" method="POST">
<div>
<button>Send my greetings</button>
</div>
</form>
</html>
However, I can not use this because I already have bigger outer form on the page and I'll end up with nested forms which is not allowed by razor/asp.
The only way is to use javascript but for some reason it does not make POST request.
#Html.AjaxActionLink will generate to <a> tag,and tag will only have HttpGet request method.If you want to send HttpPost with <a> tag,you can use it call a function with ajax,here is a demo:
link
<script>
function myFunction() {
$.ajax({
type: "POST",
url: "https://test.testspace.space/storage/Data/stream",
data: { tokenValue: "e58367c8-ec11-4c19-995a-f37ad236e0d2", fileId: "2693", position:0 },
success: function (data) {
}
});
</script>
Since you want to make a POST request, but the values need to be as query string params in the URL, you need to use jquery.Param.
see https://api.jquery.com/jquery.param/.
You should set the params, like below :
$.ajax({
url: 'your url',
type: 'POST',
data: jQuery.param({ tokenValue: "your token", fileId : "2693", position: 0}) ,
...
Try this instead,
First remove the action url from the from
Second put the result in the success function to return response
and for parameters, I always use FormData() interface to post with Ajax
And last don't forget to include dataType, contentType, processData to not get an unexpected behavior
your code will look like this
var form_data = new FormData();
form_data.append('tokenValue' ,'add899c5-7851-4416-9b06-4587528a72db&fileId=2693');
form_data.append('position' ,'position');
$.ajax({
type: "POST",
dataType: 'json',
contentType:false,
processData:false,
data: form_data,
url: 'https://test.testspace.space/storage/Data/stream',
success: function (result) {
}
});
I use Ajax to send data from form to server. But I want to check data in form before Submit by Ajax:
<form id='#id_form' onsubmit='return checkInputSubmit();' >
...
</form>
In Ajax:
$('#id_form').submit(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: url,
dataType: 'json',
data: $('#id_form').serialize(), // serializes the form's elements.
success: function(data) {
if(data.result == true) {
//My code
}
else {
//My code
}
}
});
});
But checkInputSubmit() can't prevent submit from Ajax. You can explain for me and give me solution to check data in form before Submit by Ajax.
Thanks.
in the $('#id_form').submit(function(e) event, you can check/edit/return... any thing you want before call Ajax. Within Ajax, i think it won't work and don't good. (we just check ajax result, not input)
#Blurp, I found the solution by use your help.
$('#id_form').validate({
submitHandler: function(form) {
e.preventDefault();
$.ajax({
type: 'POST',
url: url,
dataType: 'json',
data: $('#id_form').serialize(), // serializes the form's elements.
success: function(data) {
if(data.result == true) {
//My code
}
else {
//My code
}
}
});
}
});
I have a real problem. I have a php code and a form where when the form is submitted a POST request is sent and the page reloads again and ofcourse the post is viwed in the page.But i want to work with AJAX in order page not to be refreshed.I know the basics of AJAX but i don't want to build all the project from the beggining.Is there a way in success function of AJAX to link to my php code??
$.ajax({
type: "POST",
url: "index.php",
datatype: "html",
data: dataString,
success: function(data) {
//How can i link here to start running my php code which is located in the same page.
}
});
$.ajax({
type: "POST",
url: "somescript.php",
datatype: "html",
data: dataString,
success: function(data) {
// try this
console.log(data);
// see what 'data' actually is
}
});
then check in the browser by hitting F12 to look at the console.
also are you sure you want datatype of html ? you probably want a data type of json or XML , what is the server returning to you after the ajax post?
You have to cancel the form's submission so that the ajax request will take place, otherwise it is canceled. Also use .serialize to get a name-value pair string of the form data to use in the ajax call.
Html
<form id="MyForm">
<button id="MyButtonId">Submit</button>
</form>
JS
$("#MyForm").submit(function(e){
//Prevents the form from being submitted
e.preventDefault();
$.ajax({
type: "POST",
data: $("#MyForm").serialize(),
url: "somescript.php",
datatype: "html",
data: dataString,
success: function(data) {
alert(data);
}
});
});
Supposing I have the following code which returns a Javascript object which I can read in Firebug's console:
FB.api('/me',function(apiresponse){
console.log(apiresponse);
});
How can I then use the data from apiresponse in an Ajax request on the same page?
Currently my Ajax request looks as follows:
$.ajax({
// CodeIgniter URL
url: "<?=site_url?>('login/add_fb_users'); ?>",
type: 'POST',
data: apiresponse,
success: function(data) {
alert(data);
}
});
I know very little about Javascript, but reading around the subject leads me to think I have to convert the Javascript object to a JSON string. Is that correct? Am I on the right track?
You could put your AJAX call inside the handler for the API call like below..
FB.api('/me', function(apiresponse){
console.log(apiresponse);
$.ajax({
// CodeIgniter URL
url: "<?=site_url?>('login/add_fb_users'); ?>",
type: 'POST',
data: apiresponse,
success: function(data) {
alert(data);
}
});
});
one possible way:
define a global variable in your javascript, e.g. var myVar1;
set apireponse to the global variable in your FB.api callback (i.e. where u call console.log)
reference the var myVar1 in your ajax fcn.
i have a page loaded via jquery tabs ajax, i have a form within this page that i want to show form response via ajax. response is loading from this code:
$('#whois').submit(function() {
$.ajax({
data: $('#whois').serialize(),
cache:false,
type: "POST",
url: $('#whois').attr('/lib/domainchecker.php'),
success: function(response) {
$('#reply').html(response);
}
});
return false;
);
but my form submit to parent page instead of /lib/domainchecker.php. so i see headers of my page instead of response!
any idea what makes this happen?
When you are loading content on the page via AJAX and you need to apply events to the loaded content you need to use the jquery live().
$('#whois').live('submit', function() {
$.ajax({
data: $('#whois').serialize(),
cache:false,
type: "POST",
url: $('#whois').attr('/lib/domainchecker.php'),
success: function(response) {
$('#reply').html(response);
}
});
This of course goes on the main host page rather than the loaded content page.
problem is solved, no thing related to loading page via ajax but there was an error with code, i shouldn't post to $('#whois').attr('/lib/domainchecker.php') but just '/lib/domainchecker.php'
corrected code:
$('#whois').live('submit', function() {
$.ajax({
data: $('#whois').serialize(),
cache:false,
type: "POST",
url: '/lib/domainchecker.php',
success: function(response) {
$('#reply').html(response);
}
});