I have the following function I want to call:
function print_something {
echo "test\
something\
yep"
}
when called it prints:
'test something yep'
I would like it to print:
'testsomethingyep'
I can get this to print if I do:
function print_something {
echo "test\
something\
yep"
}
but I don't think that looks great..
(Root problem is a curl command not an echo)
Consider assembling your pieces an array, and then combining them into a string later. Array definition syntax is far more forgiving -- not requiring backslashes at all, and also allowing comments on each line and between lines.
#!/usr/bin/env bash
# ^^^^- arrays and printf -v require bash, not sh
pieces=(
test # this also lets you use comments
something # and you don't need any backslashes at all!
# one can also have a full-line comment midway through your array
"space here" # plus if you want to add a literal space you can do it
)
printf -v oneword '%s' "${pieces[#]}"
echo "$oneword"
...properly emits:
testsomethingspace here
Here are three ideas:
#!/bin/bash
print_something() {
tr -d \\n <<- EOF
test
something
yep
EOF
echo
}
print_something2() {
echo "test"$(:
)"something"$(:
)"yep"
}
print_something3() {
tr -d \\t <<- EOF
test\
something\
yep
EOF
}
print_something
print_something2
print_something3
The first uses a <<- style heredoc to remove all of the leading indentation (that indentation must be hard-tabs for this to work, and coding styles that mandate the use of spaces for indentation render this solution unusable (this is one reason coding styles that mandate the use of spaces in shell scripts are IMO utterly useless)) and the extra tr to remove the newlines. (The additional echo is then needed to add the trailing newline.). The second uses the $(:) command substitution to discard all the intervening whitespace. The 3rd manually deletes all the hard tabs.
I have an TARGET.md file, I'm looking for a string and I want to replace it with the content of other md file, I have tried many combinations but it seems like the newline in the files are the ones sed is not liking, I just need to do this using pure bash(it doesn't have to be sed) because this is how the whole script is running:
This works:
local search="##### Header"
local replace="##### Header\\
\\
Line 1\\
Line 2\\
Line 3\\
Line 4"
sed -i '' -e "s/${search}/${replace}/" TARGET.md
But this won't:
file1.md content:
##### Header
Line 1
Line 2
Line 3
Line 4
Script:
local search="##### Header"
local replace=$(curl "path/to/file/in/other/place/file1.md")
sed -i '' -e "s/${search}/${replace}/" TARGET.md
NOTE: I don't have the file1.md in the same place, I'm doing a curl to get the raw content from it, this is why the replace is in a variable.
I'm assuming the concept is possible but my sed syntax is wrong knowing sed can handle newlines out of the box, but not sure what is the proper way to do this.
I've been searching for some days now, any help, tip or guide is appreciated!
You are using the wrong tool. sed is a line editor at heart. While you can repeatedly append to pattern space in some instances, awk with getline provides a more flexible solution. For example with your file1.md:
##### Header
Line 1
Line 2
Line 3
Line 4
and your TARGET.md as:
##### Unreleased
my dog
has fleas
The to replace "##### Unreleased" with the content of file1.md, you can do:
awk -v replace="file1.md" -v search="##### Unreleased" '
$0 == search {while (getline line < replace ) { print line }; next }
{ print }
' TARGET.md
Above you have your replace and search as with sed, but instead of using the line-editor, you use awk to locate the line containing search and the read all lines from replace using getline`. The second rule just prints all other lines as is.
Example Use/Output
In the directory containing each file, you can simply select-copy the above and middle-mouse paste into the terminal to test:
$ awk -v replace="file1.md" -v search="##### Unreleased" '
> $0 == search {while (getline line < replace ) { print line }; next }
> { print }
> ' TARGET.md
##### Header
Line 1
Line 2
Line 3
Line 4
my dog
has fleas
Look things over and let me know if you have further questions.
Taking TARGET.md file from David's answer:
cat TARGET.md
##### Unreleased
my dog
has fleas
You can run sed with r command like this:
search="##### Unreleased"
sed -e "/$search/{r file1.md" -e ';d;}' TARGET.md
##### Header
Line 1
Line 2
Line 3
Line 4
my dog
has fleas
I have a markdown file that has snippets of code resembling the following example:
```
$ cat docs/code_sample.sh
#!/usr/bin/env bash
echo "Hello, world"
```
This means there there's a file at the location docs/code_sample.sh, whose contents is:
#!/usr/bin/env bash
echo "Hello, world"
I'd like to parse the markdown file with sed (awk or perl works too) and replace the bottom section of the code snippet with whatever the above bash command evaluates to, for example whatever cat docs/code_sample.sh evaluates to.
Perl to the rescue!
perl -0777 -pe 's/(?<=```\n)^(\$ (.*)\n\n)(?^s:.*?)(?=```)/"$1".qx($2)/meg' < input > output
-0777 slurps the whole file into memory
-p prints the input after processing
s/PATTERN/REPLACEMENT/ works similarly to a substitution in sed
/g replaces globally, i.e. as many times as it can
/m makes ^ match start of each line instead of start of the whole input string
/e evaluates the replacement as code
(?<=```\n) means "preceded by three backquotes and a newline"
(?^s:.*?) changes the behaviour of . to match newlines as well, so it matches (frugally because of the *?) the rest of the preformatted block
(?=```) means "followed by three backquotes`
qx runs the parameter in a shell and returns its output
A sed-only solution is easier if you have the GNU version with an e command.
That said, here's a quick, simplistic, and kinda clumsy version I knocked out that doesn't bother to check the values of previous or following lines - it just assumes your format is good, and bulls through without any looping or anything else. Still, for my example code, it worked.
I started by making an a, a b, and an x that is the markup file.
$: cat a
#! /bin/bash
echo "Hello, World!"
$: cat b
#! /bin/bash
echo "SCREW YOU!!!!"
$: cat x
```
$ cat a
foo
bar
" b a z ! "
```
```
$ cat b
foo
bar
" b a z ! "
```
Then I wrote s which is the sed script.
$: cat s
#! /bin/env bash
sed -En '
/^```$/,/^```$/ {
# for the lines starting with the $ prompt
/^[$] / {
# save the command to the hold space
x
# write the ``` header to the pattern space
s/.*/```/
# print the fabricated header
p
# swap the command back in
x
# the next line should be blank - add it to the current pattern space
N
# first print the line of code as-is with the (assumed) following blank line
p
# scrub the $ (prompt) off the command
s/^[$] //
# execute the command - store the output into the pattern space
e
# print the output
p
# put the markdown footer back
s/.*/```/
# and print that
p
}
# for the (to be discarded) existing lines of "content"
/^[^`$]/d
}
' $*
It does the job and might get you started.
$: s x
```
$ cat a
#! /bin/bash
echo "Hello, World!"
```
```
$ cat b
#! /bin/bash
echo "SCREW YOU!!!!"
```
Lots of caveats - better to actually check that the $ follows a line of backticks and is followed by a blank line, maybe make sure nothing bogus could be in the file to get executed... but this does what you asked, with (GNU) sed.
Good luck.
A rare case when use of getline would be appropriate:
$ cat tst.awk
state == "importing" {
while ( (getline line < $NF) > 0 ) {
print line
}
close($NF)
state = "imported"
}
$0 == "```" { state = (state ? "" : "importing") }
state != "imported" { print }
$ awk -f tst.awk file
See http://awk.freeshell.org/AllAboutGetline for getline uses and caveats.
I needed to write a script to enter multi-line input to a program (psql).
After a bit of googling, I found the following syntax works:
cat << EOF | psql ---params
BEGIN;
`pg_dump ----something`
update table .... statement ...;
END;
EOF
This correctly constructs the multi-line string (from BEGIN; to END;, inclusive) and pipes it as an input to psql.
But I have no idea how/why it works, can some one please explain?
I'm referring mainly to cat << EOF, I know > outputs to a file, >> appends to a file, < reads input from file.
What does << exactly do?
And is there a man page for it?
The cat <<EOF syntax is very useful when working with multi-line text in Bash, eg. when assigning multi-line string to a shell variable, file or a pipe.
Examples of cat <<EOF syntax usage in Bash:
1. Assign multi-line string to a shell variable
$ sql=$(cat <<EOF
SELECT foo, bar FROM db
WHERE foo='baz'
EOF
)
The $sql variable now holds the new-line characters too. You can verify with echo -e "$sql".
2. Pass multi-line string to a file in Bash
$ cat <<EOF > print.sh
#!/bin/bash
echo \$PWD
echo $PWD
EOF
The print.sh file now contains:
#!/bin/bash
echo $PWD
echo /home/user
3. Pass multi-line string to a pipe in Bash
$ cat <<EOF | grep 'b' | tee b.txt
foo
bar
baz
EOF
The b.txt file contains bar and baz lines. The same output is printed to stdout.
This is called heredoc format to provide a string into stdin. See https://en.wikipedia.org/wiki/Here_document#Unix_shells for more details.
From man bash:
Here Documents
This type of redirection instructs the shell to read input from
the current source until a line
containing only word (with no trailing
blanks) is seen.
All of the lines read up to that point are then used as the
standard input for a command.
The format of here-documents is:
<<[-]word
here-document
delimiter
No parameter expansion, command substitution, arithmetic expansion, or
pathname expansion is performed on
word. If any characters in word are
quoted, the
delimiter is the result of quote removal on word, and the lines
in the here-document are not expanded.
If word is unquoted, all lines of the
here-document are subjected to parameter expansion, command
substitution, and arithmetic
expansion. In the latter case, the
character sequence \<newline> is
ignored, and \ must be used to quote the characters \, $, and `.
If the redirection operator is <<-, then all leading tab characters
are stripped from input lines and the
line containing delimiter. This
allows here-documents within shell scripts to be indented in a natural fashion.
In your case, "EOF" is known as a "Here Tag". Basically <<Here tells the shell that you are going to enter a multiline string until the "tag" Here. You can name this tag as you want, it's often EOF or STOP.
Some rules about the Here tags:
The tag can be any string, uppercase or lowercase, though most people use uppercase by convention.
The tag will not be considered as a Here tag if there are other words in that line. In this case, it will merely be considered part of the string. The tag should be by itself on a separate line, to be considered a tag.
The tag should have no leading or trailing spaces in that line to be considered a tag. Otherwise it will be considered as part of the string.
example:
$ cat >> test <<HERE
> Hello world HERE <-- Not by itself on a separate line -> not considered end of string
> This is a test
> HERE <-- Leading space, so not considered end of string
> and a new line
> HERE <-- Now we have the end of the string
POSIX 7
kennytm quoted man bash, but most of that is also POSIX 7: http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_07_04 :
The redirection operators "<<" and "<<-" both allow redirection of lines contained in a shell input file, known as a "here-document", to the input of a command.
The here-document shall be treated as a single word that begins after the next <newline> and continues until there is a line containing only the delimiter and a <newline>, with no <blank> characters in between. Then the next here-document starts, if there is one. The format is as follows:
[n]<<word
here-document
delimiter
where the optional n represents the file descriptor number. If the number is omitted, the here-document refers to standard input (file descriptor 0).
If any character in word is quoted, the delimiter shall be formed by performing quote removal on word, and the here-document lines shall not be expanded. Otherwise, the delimiter shall be the word itself.
If no characters in word are quoted, all lines of the here-document shall be expanded for parameter expansion, command substitution, and arithmetic expansion. In this case, the <backslash> in the input behaves as the <backslash> inside double-quotes (see Double-Quotes). However, the double-quote character ( '"' ) shall not be treated specially within a here-document, except when the double-quote appears within "$()", "``", or "${}".
If the redirection symbol is "<<-", all leading <tab> characters shall be stripped from input lines and the line containing the trailing delimiter. If more than one "<<" or "<<-" operator is specified on a line, the here-document associated with the first operator shall be supplied first by the application and shall be read first by the shell.
When a here-document is read from a terminal device and the shell is interactive, it shall write the contents of the variable PS2, processed as described in Shell Variables, to standard error before reading each line of input until the delimiter has been recognized.
Examples
Some examples not yet given.
Quotes prevent parameter expansion
Without quotes:
a=0
cat <<EOF
$a
EOF
Output:
0
With quotes:
a=0
cat <<'EOF'
$a
EOF
or (ugly but valid):
a=0
cat <<E"O"F
$a
EOF
Outputs:
$a
Hyphen removes leading tabs
Without hyphen:
cat <<EOF
<tab>a
EOF
where <tab> is a literal tab, and can be inserted with Ctrl + V <tab>
Output:
<tab>a
With hyphen:
cat <<-EOF
<tab>a
<tab>EOF
Output:
a
This exists of course so that you can indent your cat like the surrounding code, which is easier to read and maintain. E.g.:
if true; then
cat <<-EOF
a
EOF
fi
Unfortunately, this does not work for space characters: POSIX favored tab indentation here. Yikes.
Using tee instead of cat
Not exactly as an answer to the original question, but I wanted to share this anyway: I had the need to create a config file in a directory that required root rights.
The following does not work for that case:
$ sudo cat <<EOF >/etc/somedir/foo.conf
# my config file
foo=bar
EOF
because the redirection is handled outside of the sudo context.
I ended up using this instead:
$ sudo tee <<EOF /etc/somedir/foo.conf >/dev/null
# my config file
foo=bar
EOF
<< EoF basically means:
<< - "read the multi-line input that begins from the next line onward, and treat it as if it's code in a separate file"
EoF - "stop reading immediately after the word EoF is found in the multi-line input"
As other answers have explained, the multi-line input is called a Here Document
A Here Document is often used to generate output to be passed to a subsequent process. For example cat << EoF can be used to generate a desired output, using a Here Document.
Here's an example of using a Here Document to create a text document on the fly:
cat << EoF > ./my-document.txt
Hello world
Have a nice day
EoF
A little extension to the above answers. The trailing > directs the input into the file, overwriting existing content. However, one particularly convenient use is the double arrow >> that appends, adding your new content to the end of the file, as in:
cat <<EOF >> /etc/fstab
data_server:/var/sharedServer/authority/cert /var/sharedFolder/sometin/authority/cert nfs
data_server:/var/sharedServer/cert /var/sharedFolder/sometin/vsdc/cert nfs
EOF
This extends your fstab without you having to worry about accidentally modifying any of its contents.
note to mention that cat << \EOT (see the backslash) will not expand any variables inside, while cat << EOT will do.
examples:
FOO="bar"
cat << \EOT > foobar.txt
echo "$FOO"
EOT
will output:
echo $FOO
while:
FOO="bar"
cat << EOT > foobar.txt
echo "$FOO"
EOT
will output:
echo "bar"
Example to create a json file:
cat << EoF > ./allaccess.json
{
"Version": "2012-10-17",
"Statement": [
{
"Effect": "Allow",
"Action": [
"s3:*"
],
"Resource": [
"arn:aws:s3:::*"
]
}
]
}
EoF
As a result:
{
"Version": "2012-10-17",
"Statement": [
{
"Effect": "Allow",
"Action": [
"s3:*"
],
"Resource": [
"arn:aws:s3:::*"
]
}
]
}
Long story short, EOF marker(but a different literal can be used as well) is a heredoc format that allows you to provide your input as multiline.
A lot of confusion comes from how cat actually works it seems.
You can use cat with >> or > as follows:
$ cat >> temp.txt
line 1
line 2
While cat can be used this way when writing manually into console, it's not convenient if I want to provide the input in a more declarative way so that it can be reused by tools and also to keep indentations, whitespaces, etc.
Heredoc allows to define your entire input as if you are not working with stdin but typing in a separate text editor. This is what Wikipedia article means by:
it is a section of a source code file that is treated as if it were a
separate file.
This isn't necessarily an answer to the original question, but a sharing of some results from my own testing. This:
<<test > print.sh
#!/bin/bash
echo \$PWD
echo $PWD
test
will produce the same file as:
cat <<test > print.sh
#!/bin/bash
echo \$PWD
echo $PWD
test
So, I don't see the point of using the cat command.
Worth noting that here docs work in bash loops too.
This example shows how-to get the column list of table:
export postgres_db_name='my_db'
export table_name='my_table_name'
# start copy
while read -r c; do test -z "$c" || echo $table_name.$c , ; done < <(cat << EOF | psql -t -q -d $postgres_db_name -v table_name="${table_name:-}"
SELECT column_name
FROM information_schema.columns
WHERE 1=1
AND table_schema = 'public'
AND table_name =:'table_name' ;
EOF
)
# stop copy , now paste straight into the bash shell ...
output:
my_table_name.guid ,
my_table_name.id ,
my_table_name.level ,
my_table_name.seq ,
or even without the new line
while read -r c; do test -z "$c" || echo $table_name.$c , | perl -ne
's/\n//gm;print' ; done < <(cat << EOF | psql -t -q -d $postgres_db_name -v table_name="${table_name:-}"
SELECT column_name
FROM information_schema.columns
WHERE 1=1
AND table_schema = 'public'
AND table_name =:'table_name' ;
EOF
)
# output: daily_issues.guid ,daily_issues.id ,daily_issues.level ,daily_issues.seq ,daily_issues.prio ,daily_issues.weight ,daily_issues.status ,daily_issues.category ,daily_issues.name ,daily_issues.description ,daily_issues.type ,daily_issues.owner
I have the following code in a shell script.
This only seems to work when it is not defined in a function.
The problematic line is the one containing the "<<".
The error message is
"./run: line 210: syntax error:
unexpected end of file"
How can I write this correctly within a function?
init_database()
{
cd ../cfg
db.sh << ENDC
$DB_ADMIN
0
y
n
ENDC
check_status
sqlplus $DB_SCHEMA#$DB_NAME < initial_data.sql
cd -
}
There are a number of ways to fix that problem.
1/ Unindent the here document end marker, such as:
cat <<EOF
hello
$PWD
EOF
but that will make your code look ugly.
2/ "Indent" the here document begin marker:
cat <<' EOF'
hello
$PWD
EOF
where that bit before the first EOF is exactly the same as the before the second (tab, four spaces, two tabs, whatever). This allows you to keep your nice indenting, although it doesn't expand variables inside the here-document ($PWD doesn't change).
3/ Allow tabs to be stripped from the start of input lines and the end marker.
cat <<-EOF
hello
$PWD
EOF
but there's no way to get tabs into the beginnings of lines.
4/ For your purposes, you can also use:
( echo "$DB_ADMIN";
echo "" ;
echo "0" ;
echo "y" ;
echo "n"
) | db.sh
check_status
sqlplus $DB_SCHEMA#$DB_NAME < initial_data.sql
cd -
I believe number 4 is the best option for you. It allows nice lining up of the input, tabs and spaces anywhere in the lines and variable expansion.
The end of your "Here document" needs to be unindented, I'm afraid.
The ENDC label must be alone in a line without leading/trailing whitspaces.