Whenever there is a call to Controller inside View, I want the Controller to return some variables to the View and do not refresh the View.
Already know:
return view("webpage" , compact('variable1', 'variable2') );
What I expect to achieve:
return compact('variable1', 'variable2');
This will not return the Webpage but only some of the variables.
Edit:
Thinking it from a complete different perspective, The question maybe rephrased as such
Is there a way to manipulate REQUEST variables of a web page from the controller? This way, i would be able to get new variables from the Controller without the web page being Refreshed.
With out much to work with, here is an example:
Ajax call:
$.ajax({
url: '/your/route/',
type: 'GET',
data: {getVariable: formInputValue},
})
.done(function (data) {
console.log(data);
})
.fail(function () {
console.log('Failed');
});
Controller Function:
public function getVariable(Request $request){
$resault = $request->getVariable;
return response()->json($results);
}
Update: as per comments on this answer try this and see if it works for you.
In your controller where you fetch records instead of using a ->get();
change it to paginate(5); this will return 5 records per page. and on your view at the bottom of your </table> add {{ $variable->links() }}
Related
I have an anchor tag and would like its data-id to be sent to a function in the controller which would in turn retrieved data from the database through the model.
However the data is not getting past the controller. The ajax response is showing that the data was sent but controller shows otherwise.
Here is my ajax code:
$(document).on("click",".learn-more",function(){
var sub_item_id = $(this).data("id");
$.ajax({
url:"<?php echo base_url();?>Designs/business_cards",
type:"POST",
data:{sub_item_id:sub_item_id},
success:function(data){
console.log(data);
},
error: function(error){
throw new Error('Did not work');
}
})
});
I had set datatype:"json" but the data was not being sent so I removed the datatype and it worked,the ajax part that is.Or atleast the response showed that data was sent.
My controller code is:
function business_cards(){
$id = $this->input->post('sub_item_id');
$data['quantity'] = $this->subproduct_model->get_quantities($id);
$this->load->view('category/business-cards',$data);
}
My model code is:
public function get_quantities($sub_item_id){
$this->db->select('quantities');
$this->db->where('id',$sub_item_id);
$query = $this->db->get('sub_products');
return $query->result_array();
}
HTML Code which includes the anchor tag
<?php foreach ($results as $object):?>
View Prices
<?php endforeach?>
The data-id is displaying the correct value as per the iteration.
When I check the result array of the model code it is an empty array showing that the $sub_item_id was not passed in the controller. What could be the problem?
I just copied your code and I was able to get the value in the controller.
In your controller function do var_dump($id). Then in your developer tools (F12) check the console. Since you have console.log(data) that var_dump should be in the console. It won't show on the screen.
Some other things to check:
Does your db have records with that ID? Could your db result array be empty because it actually should be?
Are you sure that the data-id actually has a value when you click the tag?
it is not passed to the controller because you forgot to put a parameter inside the function of your controller.
Note: you cannot use input post because you're not using form.
function business_cards($id){ //put a parameter here, serve as container of your passed variable from **ajax**
//$id = $this->input->post('sub_item_id');
$data['quantity'] = $this->subproduct_model->get_quantities($id); //pass the id to your model
$this->load->view('category/business-cards',$data);
}
change your ajax code to this..
$(document).on("click",".learn-more",function(){
var sub_item_id = $(this).data("id");
$.ajax({
url:"<?php echo base_url('Designs/business_cards/"+sub_item_id+"');?>", //pass the id here
type:"POST",
success:function(data){
console.log(data);
},
error: function(error){
throw new Error('Did not work');
}
})
});
I want to render a cakephp3 template by ajax and inject the html into a loaded page (without reloading the page).
According to
CakePHP 3 and partial View update via Ajax - How it should be done?,
the idea can be
Create dedicated template (*.ctp) file for every ajax action, render
it like any other action but without the main layout and inject the
HTML (kind of variant 1 but with separated VC logic).
It also provides a partial example code:
public function ajaxRenderAuditDetails($id = null)
{
if ($id == null) {
return null;
}
if ($this->request->is("ajax")) {
$this->set("result", $this->viewBuilder()->build()->cell("audits", [$id]));
}
}
May anyone suggest a full example?
For this you have to use a Ajax call for get data from server. In term of CakePhp you will call a controller function using Ajax. This function call a ctp file which render your partial view. Success function of Ajax should updated or append the partial view. A complete example code for this process is here -
Ajax code for call controller function -
$.ajax({
dataType: 'json',
url: basepath/controllername/controllerfunction,
type: "POST",
dataType : 'html',
success: function (data) {
$(selector).html(data);
}
});
public function ajaxRenderAuditDetails($id = null){
$this->viewBuilder()->layout(false);
if ($id == null) {
return null;
}
if ($this->request->is("ajax")) {
$this->set("result", $this->viewBuilder()->build()->cell("audits", [$id]));
}
}
Put your required html or logics in ctp file.
This is not a running code. It is sample example for updating partial view in CakePhp.
I am using Laravel 5.3. I want to insert the data using blade template.But my when i press submit button it gets refreshed every time. what to do? and please anyone tell me how to use ajax url,type,data
If you try to submit via Javascript make sure prevent form default action with e.preventDefault(). This code prevent the form submitted in a regular way. Just add this code to wrap your AJAX call:
$('#form-id').submit(function(e){
e.preventDefault();
$.ajax({...});
});
I just assume you are using jquery if you are talking about ajax. It's really simple. Your laravel routes listen to "post", "get", "patch", "delete" methods.
Everything of these can be created with a ajax request - example:
$.ajax({
method: "POST",
url: "/posts",
data: { title: "Hello World", text: "..." }
})
.done(function( post ) {
// assuming you return the post
alert(post.title + " created");
});
Now that you use ajax you will not want to return a view to the ajax call. You have different options here (create a new route, helper functions etc.) I will give the most easy example
Controller function:
public function store(Request $request) {
$post = App\Post::create($request->all());
if($request->ajax()) {
return $post;
} else {
return redirect('/posts');
}
}
now you controller will return data on ajax calls and will redirect you on default calls without ajax.
Finally you have a last thing to keep in mind. If you have web middleware applied ( done by default ) you need to handle the csrf token. The most easy way to handle this is by adding a meta tag to your html head
and then (before doing all your calls etc.) add this to configure your ajax
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="_token"]').attr('content')
}
});
this will add the valid csrf token which is in your head to every ajax call and will ensure you not run into token missmatch exceptions.
Things to keep in mind:
- if you stay very long on one page tokens might expire ( laravel-caffeine will help here )
- you need to handle validation for ajax calls
i had a user list form in laravel. so i want when i click the table row, it automatically load the user details from database without redirecting. i've heard about ajax. but i have no idea how to use it in laravel..
i want to make like this
but without redirecting page..
$("tr").click(function()
{
$.ajax({
type: "GET",
url: $(this).data("href"),
dataType: "text",
success : function(data) {
$('#details-container').load(data)
}
});
});
does it supposed to be like this? but how did i get the data from database? i have no idea. please help me..
Its the same in Laravel as in "native" PHP. With your Ajax request your are able to send and asynchronous request, and refresh just a little part of your website, so you dont need to reload your whole page.
If you want to make it work with laravel, you should:
create a route for your requests
Route::get('user/{id}', function($id)
{
// So all your GET requests with any user id goes to this script (in routes.php)
// here you should load your user information, maybe with ORM
$user = User::where('id','=',$id)->get();
// Build any HTML snippet, or build JSON data (and build the information in Javascript on your page)
//return here JSON / or html
$data = array() -> containts information for the blade template
return view('users.information', $data);
});
Your AJAX request returns now JSON / or HTML, append it to your site where you would like to show it.
Your page structure will be like this:
<table>
<thead>
...
</thead>
<tbody>
<tr data-details-link="http://your-domain/user/{user-id}/details">
...
</tr>
</tbody>
</table>
The page with the table, should have this jQuery codes:
$('table tr').on('click', function (event)
{
event.preventDefault();
var $this = $(this);
// not necessary but you should show a loading here
$.ajax({
url: $this.data('details-link')
})
.success(function (response)
{
// the `response` variable is HTML code. Insert it into a modal.
});
});
Your route:
...
Route::get('user/{id}/details', [ 'uses' => 'UserController#details' ]);
...
Your UserController method:
public function details($id)
{
$user = \App\User::find($id);
if (!$user)
abort(404);
return view('user.details')->with('user', $user);
}
**Your user/details.blade.php should have the HTML that will be send as the AJAX response.
I would like to be able to construct a query using laravel, and serialize it into a url string.
This would allow me to create routes which would unserialize a query builder, run the query, and make a view which displays the database results.
For example, to implement a button which refreshes a list of posts made by kryo:
http://example.com/ajax/posts.php?name=kryo&order_by=created_at&order_type=desc
Posts.php would simply be a route which unserializes, validates, and runs the query in the url params, and provides the results to a view.
Perhaps this is not useful in general, but I would personally find it handy specifically for ajax requests. If anyone knows how to implement this as a laravel plugin of some nature, that would be fantastic.
I'll try to give you a basic idea:
In Laravel you have to create a route to make a request to a function/method, so at first you need to create a route which will be listening for the ajax request, for example:
Route::get('/ajax/posts', array('uses' => 'PostController#index', 'as' => 'showPosts'));
Now, create a link in the view which points to this route, to create a link you may try this:
$url = to_route('showPosts');
If you use something like this:
<a class='ajaxPost' href="{{ $url }}?name=kryo&order_by=created_at&order_type=desc">Get Posts</a>
It'll create a ink to that route. So, make sure you are able to pass that $url to your JavaScript or manually you can write the url using /ajax/posts?name=.... Once you done creating the link then you need to create your JavaScript handler for this link (maybe using click event) then handle the click event from your handler, make ajax request, if it's jQuery then it could be something like this:
$('.ajaxPost').on('clcik', function(e){
e.preventDefault();
var url = $(this).attar('href');
$.getJSON(url, function(response){
$.each(response, function(key, value){
// loop... you may use $(this) or value
});
});
});
In your PostController controller class, create the index method:
class PostController extends BaseController {
public function index()
{
$name = Input::get('name');
$order_by = Input::get('order_by');
$created_at = Input::get('created_at');
$order_type = Input::get('order_type');
$posts = Post::whereName($name)->orderBy($order_by, $order_type)->get();
if(Request::ajax()) {
return Response::json($posts);
}
else {
// return a view for non ajax
}
}
}
If you want to send a rendered view from the server side to your JavaScript handler as HTML then change the getJson to get and instead of return Response::json($posts); use
return View::make('viewname')->with('posts', $posts);
In this case make sure that, your view doesn't extends the master layout. This may not be what you need but it gives you the idea how you can implement it.