Insert Data Using Ajax - ajax

I am using Laravel 5.3. I want to insert the data using blade template.But my when i press submit button it gets refreshed every time. what to do? and please anyone tell me how to use ajax url,type,data

If you try to submit via Javascript make sure prevent form default action with e.preventDefault(). This code prevent the form submitted in a regular way. Just add this code to wrap your AJAX call:
$('#form-id').submit(function(e){
e.preventDefault();
$.ajax({...});
});

I just assume you are using jquery if you are talking about ajax. It's really simple. Your laravel routes listen to "post", "get", "patch", "delete" methods.
Everything of these can be created with a ajax request - example:
$.ajax({
method: "POST",
url: "/posts",
data: { title: "Hello World", text: "..." }
})
.done(function( post ) {
// assuming you return the post
alert(post.title + " created");
});
Now that you use ajax you will not want to return a view to the ajax call. You have different options here (create a new route, helper functions etc.) I will give the most easy example
Controller function:
public function store(Request $request) {
$post = App\Post::create($request->all());
if($request->ajax()) {
return $post;
} else {
return redirect('/posts');
}
}
now you controller will return data on ajax calls and will redirect you on default calls without ajax.
Finally you have a last thing to keep in mind. If you have web middleware applied ( done by default ) you need to handle the csrf token. The most easy way to handle this is by adding a meta tag to your html head
and then (before doing all your calls etc.) add this to configure your ajax
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="_token"]').attr('content')
}
});
this will add the valid csrf token which is in your head to every ajax call and will ensure you not run into token missmatch exceptions.
Things to keep in mind:
- if you stay very long on one page tokens might expire ( laravel-caffeine will help here )
- you need to handle validation for ajax calls

Related

Do I sent two requests to the ActionResult?

I have an ASP.net MVC project and depending on the filter options chosen by the user I am sending different ajax requests to the same actionresult, for example:
$(document).on("click", "#filter_reset_button", function () {
var url = "/Admin/Index";
ajaxRequest({
url: url,
type: "get",
data: { reset: true },
successCallback: function () {
window.location.href = url;
}
});
});
Other listeners sent different data, something like:
data: { page: 2, filterUpdate: true }
and so on. The Index ActionResult returns different lists of items, depending on different options chosen in the data and the code works completely fine.
A colleage of mine told me, that my code is actually sending two get requests to the AR everytime, so its not efficient. Is that true? And if its the case, how can I refactor it. to make it just one request? If I let window.location.href = url part out, the site actually doesnt load the server response.
Yes you are doing 2 request in button click. First in Ajax Get, Second in Success Call Back.
But Why are you calling window.location.href = url; success call back. ?
If you want update the page after click, you can do partial updates to page. Check this post.
That is correct 2 request called.
First request when you call AJAX get to Action Index in Admin Controller.
Second request when you set window.location.href = url, it will same as you enter /Admin/Index in browser.
In this case you only need window.location.href = '/admin/index?reset=true' in click function
You can see the post here at this post
Actually on success callback you must change your code accordingly to the above post

Prestashop: How to submit data from adminpanel template to Admin Controller?

I'm trying to make a custom page in the adminpanel of Prestashop where the shopowner can fill in his upcoming events that will appear in a column in the header.tpl page. The templates and controller are working so far, with a structure based on an answer here at Stack Overflow:
How to create a new page in prestashop admin panel?
Now I have made in the content.tpl (with the added custom JavaScript and CSS files) the form with the input fields. The next step is to send it to the controller to save it in the database. But I'm stuck this part. I can't find how I can nicely submit the form to the controller. First I tried it with an Ajax function but I couldn't find the right way. Also without Ajax no success.
$.ajax({
type: 'POST',
headers: { "cache-control": "no-cache" },
url: baseUri + '?rand=' + new Date().getTime(),
async: true,
cache: false,
dataType : "json",
data:{
processEvents: true,
ajax: 'true',
controller: 'AdminEvents',
token: static_token
},
//success: function(jsonData){
//}
});
This is an example of an Ajax function that I tried. My questions:
How does other tpl or js files receive the baseUri, where is that
variable set?
What is the function of the ?rand date and time in that line? A kind
of security token?
What is the url of the controller? Also the url when I use
I guess the processEvents : true and Ajax : true is for security
reasons and to check if the form is submitted by Ajax or not?
Why is it necessary to send the controller name?
Where does the token come from?
Questions about the controller:
Which (Prestashop default functions) can or do need to use? For
example:
if (Tools::isSubmit('name')){
etc.
if (Tools::getValue('create_account')){
etc.
Can I use that functions anywhere or maybe only in an Init function?
A lot of questions, feel free to answer only a part of it, I just need a good push in the right direction, searching and reading in the online documentation and on the internet doesn't brought me the solution and brainwashed me a little.
EDIT:
I made a little progress by myself:
Where does the token come from?
What is the url of the controller? Also the url when I use
With the tools getAdminTokenLite and the controller name I generated the controller url:
$token = '?controller=AdminEvents&token='.Tools::getAdminTokenLite('AdminEvents');
The url to post to is the token plus the domain, admin directory and index.php.
With the tool getValue I get the POST data like in PHP with $_POST["name"].
Tools::getValue('event_name')
So its working but I guess it can be better with other Presta default tools.
I know that it's very late to answer you, but for sure it will help other mates with same problem.
Here is an example about how to implement ajax calls in Prestashop 1.6 on Admin panel using ANY Controller from BackOffice (if you want also, you can use ajax.php controller, but I'm using for this AdminImportController() )
tpl part:
$('#mybtn').click(function(e) {
var data = $('#datalist').val();
// Ajax call with secure token
$.post( "{$current|escape:'html':'UTF-8'}&token= {$token|escape:'html':'UTF-8'}",
{ ajax: true, action: "MyFunction", mydata: data } );
  });
And in admin controller side:
public function ajaxProcessMyFunction()
{
// Get param
$mydata = (int)Tools::getValue('mydata');
$answer = 0;
if( $mydata > 0 ) {
$this->importProfList = Db::getInstance()->executeS(
"SELECT * FROM .... LIMIT 1"
);
...
$answer = $someOperationResult;
}
// Response
die(Tools::jsonEncode(array(
'answer' => htmlspecialchars($answer)
)));
}
Tested and working like a charm.
Regards

dynamicly fill table using zpt and ajax as update

I'm creating a webproject in pyramid where I'd like to update a table every few secondes. I already decided to use ajax, but I'm stuck on something.
On the client side I'm using the following code:
function update()
{
var variable = 'variable ';
$.ajax({
type: "POST",
url: "/diagnose_voorstel_get_data/${DosierID}",
dataType: "text",
data: variable ,
success: function (msg) {
alert(JSON.stringify(msg));
},
error: function(){
alert(msg + 'error');
}
});
}
Pyramid side:
#view_config(route_name='diagnose_voorstel_get_data', xhr=True, renderer='string')
def diagnose_voorstel_get_data(request):
dosierid = request.matchdict['dosierid']
dosieridsplit = dosierid.split
Diagnoses = DBSession.query(Diagnose).filter(and_(Diagnose.code_arg == str(dosieridsplit[0]), Diagnose.year_registr == str(dosieridsplit[1]), Diagnose.period_registr == str(dosieridsplit[2]), Diagnose.staynum == str(dosieridsplit[3]), Diagnose.order_spec == str(dosieridsplit[4])))
return {'Diagnoses ' : Diagnoses }
Now I want to put this data inside a table with zpt using the tal:repeat statement.
I know how to use put this data in the table when the page loads, but I don't know how to combine this with ajax.
Can anny1 help me with this problem ? thanks in adance.
You can do just about anything with AJAX, what do you mean "there's no possibility"? Things become much cleaner once you clearly see what runs where and in what order - as Martijn Pieters points out, there's no ZPT in the browser and there's no AJAX on the server, so the title of the question does not make much sense.
Some of the options are:
clent sends an AJAX request, server does its server-side stuff, in the AJAX call success handler the client reloads the whole page using something like window.location.search='ts=' + some_timestamp_to_invalidate_cache. The whole page will reload with the new data - although it works almost exactly like a normal form submit, not much sense using AJAX like this at all.
client sends an AJAX request, server returns an HTML fragment rendered with ZPT which client then appends to some element on your page in the AJAX success handler:
function update()
{
var variable = 'variable ';
$.post("/diagnose_voorstel_get_data/${DosierID}")
.done(function (data) {'
$('#mytable tbody').append(data);
});
}
client sends an AJAX request, server returns a JSON object which you then render on the client using one of the client-side templating engines. This probably only make sense if you render your whole application on the client and the server provides all data as JSON.

jQuery .ajax 'success' function never runs

I am trying to use jQuery for the first time, and my POST function using .ajax is giving me grief.
The POST is successful; my PHP page runs the MySQL query correctly and the newly created user ID is returned. The only problem is that instead of running the 'success' function; it simply loads the PHP page that I called, which simply echoes the user ID.
Here's the jQuery function:
function register() {
$.ajax({
type: "POST",
url: 'sendRegistration.php',
data: dataString,
datatype: 'html',
success: function(response){alert(response);},
complete: function(response,textStatus){console.log(textStatus);},
error: function(response){alert(response);}
});
}
... and the PHP return stuff:
// Create a new send & recieve object to store and retrieve the data
$sender = new sendRecieve();
$custId = $sender->submitUser($userVars);
if ($custId != 0) {
echo $custId;
} else {
echo "Database connection problems...";
}
The database object is created, and then the php page from the 'url' parameter loads, displaying the id that the $sender->submitUser() function returns.
Ideally, I would like it to never display the 'sendRegistration.php' page, but run another js function.
I'm sure there's a simple solution, but I've not been able to find it after hours of searching.
Thanks for your help.
You are likely handling this from a form. If you don't prevent the default form submittal process of the browser, the page will redirect to the action url of the form. If there is no action in form, the current page will reload, which is most likely what is happening in your case.
To prevent this use either of the following methods
$('form').submit(function(event){
/* this method before AJAX code*/
event.preventDefault()
/* OR*/
/* this method after all other code in handler*/
return false;
})
The same methods apply if you are sending the AJAX from a click handler on the form submit button
how are you calling the register() function? It could be the form is being submitted traditionally, you might need to prevent the default action(standard form submit).

How to avoid redirect after form submission if you have a URL in your form's action?

I have a form that looks like this:
<form name="formi" method="post" action="http://domain.name/folder/UserSignUp?f=111222&postMethod=HTML&m=0&j=MAS2" style="display:none">
...
<button type="submit" class="moreinfo-send moreinfo-button" tabindex="1006">Subscribe</button>
In the script file I have this code segment where I submit the datas, while in a modal box I say thank you for the subscribers after they passed the validation.
function () {
$.ajax({
url: 'data/moreinfo.php',
data: $('#moreinfo-container form').serialize() + '&action=send',
type: 'post',
cache: false,
dataType: 'html',
success: function (data) {
$('#moreinfo-container .moreinfo-loading').fadeOut(200, function () {
$('form[name=formi]').submit();
$('#moreinfo-container .moreinfo-title').html('Thank you!');
msg.html(data).fadeIn(200);
});
},
Unfortunately, after I submit the datas, I'm navigated to the domain given in the form's action. I tried to insert return false; in the code (first into the form tag, then into the js code) but then the datas were not inserted into the database. What do I need to do if I just want to post the data and stay on my site and give my own feedback.
I edited Eric Martin's SimpleModal Contact Form, so if more code would be necessary to solve my problem, you can check the original here: http://www.ericmmartin.com/projects/simplemodal-demos/ (Contact Form)
Usually returning false is enough to prevent form submission, so double check your code. It should be something like this
$('form[name="formi"]').submit(function() {
$.ajax(...); // do your ajax call here
return false; // this prevent form submission
});
Update
Here is the full answer to your comment
I tried this, but it didn't work. I need to submit the data in the succes part, no?
Maybe, it depends from your logic and your exact needs. Normally to do what you asking for I use the jQuery Form Plugin which handle this kind of behavior pretty well.
From your comment I see that you're not submitting the form itself with the $.ajax call, but you retrieve some kind of data from that call, isn't it? Then you have two choices here:
With plain jQuery (no form plugin)
$('form[name="formi"]').submit(function() {
$.ajax(...); // your existing ajax call
// this will post the form using ajax
$.post($(this).attr('action'), { /* pass here form data */ }, function(data) {
// here you have server response from form submission in data
})
// this prevent form submission
return false;
});
With form plugin it's the same, but you don't have to handle form data retrieval (the commented part above) and return false, because the plugin handle this for you. The code would be
$(document).ready(function() {
// bind 'myForm' and provide a simple callback function
$(form[name="formi"]).ajaxForm(function() {
// this call back is executed when the form is submitted with success
$.ajax(...); // your existing ajax call
});
});
That's it. Keep in mind that with the above code your existing ajax call will be executed after the form submission. So if this is a problem for your needs, you should change the code above and use the alternative ajaxForm call which accepts an options object. So the above code could be rewritten as
$(document).ready(function() {
// bind 'myForm' and provide a simple callback function
$(form[name="formi"]).ajaxForm({
beforeSubmit: function() { $.ajax(...); /* your existing ajax call */},
success: function(data) { /* handle form success here if you need that */ }
});
});

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