I can compile the code but nothing shows
int main(void){
lcd_init(LCD_DISP_ON);
lcd_clrscr();
lcd_set_contrast(0x00);
lcd_gotoxy(0,3);
lcd_puts((char*)&temperature);
lcd_gotoxy(1,2);
lcd_puts((char*)&humidity);
lcd_puts("Hello World");
}
You need to first convert the numerical data (e.g. uint8_t) to a string before you can display it.
E.g., the uint8_t value 123 is one byte, but to display it, it must be converted to a three-character/-byte string 1, 2, 3, i.e. the three chars 0x31, 0x32, 0x33.
For that, you can use the function itoa() ("integer to ascii") to copy the integer value to a char array you provide. Note that the char array must be big enough to hold any possible number-string, i.e. if your values are uint8_t's (range 0...255) the array must be at least three characters long.
To have a character array handled as a string in C(-libraries), you need an additional char to hold the string terminator '\0'.
Example:
char tempStr[3+1]; // One extra for terminator
// Clear tempStr and make sure there's always a string-terminating `\0` at the end
for ( uint8_t i = 0; i < sizeof(tempStr); i++ ) {
tempStr[i] = '\0';
}
itoa(temperature, tempStr, 10);
// Now we have the string representation of temperature in tempStr, followed by at least one '\0' to make it a valid string.
// For example:
// 1 --> [ '1', '\0', '\0', '\0' ]
// 255 --> [ '2', '5', '5', '\0' ]
Related
I have a byte array and I need to print the elements in a single line.
I tried using 'snprintf()' but it won't take a byte array as its input parameter.
I tried copying the byte array into an integer array and then used the snprintf(), but instead of printing the HEX values, corresponding ASCII values are printed.
You can try this code :
variables
{
int ar[100];
}
on diagResponse TCCM.*
{
char tmp[8]; // Temporary buffer containing single HEX value
char out[301]; // Bigger output string and "local" to function
// Better to place them there (i and response) if they are not global
int i;
byte response[100];
out[0] = 0; // Clear output string
s1 = DiagGetPrimitiveData(this, response, elcount(response));
for (i = 0; i < s1; i++)
{
ar[i] = response[i];
snprintf(tmp, elcount(tmp), "%.2X ", response[i]); // byte to HEX convert
strncat(out, tmp, elcount(out)); // Concatenate HEX value to output string
}
write("HEX Response : %s", out);
}
Olivier
I have stored hex values in a text file with .ini extension along with address. But when i read it, it will not be in hex format it will be in character so is there any way to read value as hex and store it in byte in C language or in CAPL script?
I assume that you know how to read a text file in CAPL...
You can convert a hex string to a number using strtol(char s[], long result&):long. See the CAPL help (CAPL Function Overview -> General -> strol):
The number base is
haxadecimal if the string starts with "0x"
octal if the string starts with "0"
decimal otherwise
Whitespace (space or tabs) at the start of the staring are ignored.
Example:
on start
{
long number1, number2;
strtol("0xFF", number1);
strtol("-128", number2);
write("number1 = %d", number1);
write("number2 = %d", number2);
}
Output:
number1 = 255
number2 = -128
See also: strtoll(), strtoul(), strtoull(), strtod() and atol()
Update:
If the hex string does not start with "0x"...
on message 0x200
{
if (this.byte(0) == hextol("38"))
write("byte(0) == 56");
}
long hextol(char s[])
{
long res;
char xs[8];
strncpy(xs, "0x", elcount(xs)); // cpy "0x" to 'xs'
strncat(xs, s, elcount(xs)); // cat 'xs' and 's'
strtol(xs, res); // convert to long
return res;
}
I have a problem in regards of extracting signed int from string in c++.
Assuming that i have a string of images1234, how can i extract the 1234 from the string without knowing the position of the last non numeric character in C++.
FYI, i have try stringstream as well as lexical_cast as suggested by others through the post but stringstream returns 0 while lexical_cast stopped working.
int main()
{
string virtuallive("Images1234");
//stringstream output(virtuallive.c_str());
//int i = stoi(virtuallive);
//stringstream output(virtuallive);
int i;
i = boost::lexical_cast<int>(virtuallive.c_str());
//output >> i;
cout << i << endl;
return 0;
}
How can i extract the 1234 from the string without knowing the position of the last non numeric character in C++?
You can't. But the position is not hard to find:
auto last_non_numeric = input.find_last_not_of("1234567890");
char* endp = &input[0];
if (last_non_numeric != std::string::npos)
endp += last_non_numeric + 1;
if (*endp) { /* FAILURE, no number on the end */ }
auto i = strtol(endp, &endp, 10);
if (*endp) {/* weird FAILURE, maybe the number was really HUGE and couldn't convert */}
Another possibility would be to put the string into a stringstream, then read the number from the stream (after imbuing the stream with a locale that classifies everything except digits as white space).
// First the desired facet:
struct digits_only: std::ctype<char> {
digits_only(): std::ctype<char>(get_table()) {}
static std::ctype_base::mask const* get_table() {
// everything is white-space:
static std::vector<std::ctype_base::mask>
rc(std::ctype<char>::table_size,std::ctype_base::space);
// except digits, which are digits
std::fill(&rc['0'], &rc['9'], std::ctype_base::digit);
// and '.', which we'll call punctuation:
rc['.'] = std::ctype_base::punct;
return &rc[0];
}
};
Then the code to read the data:
std::istringstream virtuallive("Images1234");
virtuallive.imbue(locale(locale(), new digits_only);
int number;
// Since we classify the letters as white space, the stream will ignore them.
// We can just read the number as if nothing else were there:
virtuallive >> number;
This technique is useful primarily when the stream contains a substantial amount of data, and you want all the data in that stream to be interpreted in the same way (e.g., only read numbers, regardless of what else it might contain).
I found this code below on the internet which is suppose to count the sentences on an 8051 MCU.
Can someone please explain to me what is exactly happening where there are question marks.
Any kind of help would be highly appreciated.
#include<string.h>
char code *text=" what is a program? that has, a a lot of errors! When " ;
char code *text1=" you compile. this file, uVision. reports a number of? ";
char code *text2=" problems that you! may interactively correct. " ; //Null characters are also included in array!!!
void count ( char pdata* , char pdata*);
void main (void){
char pdata Nw,Ns;
char data TextNw[2],TextNs[2];
count(&Nw, &Ns); // call subroutine
TextNw[0]=Nw/10; //?????????????????????????????????
TextNw[1]=Nw%10; //?????????????????????????????????
TextNs[0]=Ns/10; //?????????????????????????????????
TextNs[1]=Ns%10; //?????????????????????????????????
while(1);
}
void count ( char pdata *Nw, char pdata *Ns ){
unsigned char N, i, ch;
typedef enum {idle1, idle2} state; //?????????????????????????????????
state S; // begining state
P2=0x00; // pdata bank definition it must be performed first!!
*Ns=*Nw=0; // without proper start-up there is no initialisation, initialise now!!
S=idle1; // beginning state
N=strlen(text)+strlen(text1)+strlen(text2)+3; //????????????? + 3 to acount 3 Null characters!
P2=0x00; // pdata bank definition
for(i=0;i!=N;i++){
ch=text[i]; // take a caharacter from the text
switch (S)
{
case (idle1):{
if (ch==0) break; // skip NULL terminating character!
if (ch!=' '){
S=idle2;
(*Nw)++;
}
break;
}
case(idle2):{
if (ch==0) break; // skip NULL terminating character!
if((ch==' ')||(ch==','))S=idle1;
else if ((ch=='?')||(ch=='.')||(ch=='!')){
S=idle1;
(*Ns)++;
}
break;
}
}
}
}
This program does 2 things in conjunction - counts number of sentences in the text and counts the number of words in the text. Once the counting is done, the results are stored in 2-char arrays. For example, for 57 words in 3 sentences the results will be stored as this: TextNw = {'5','7'} and TextNs = {'0','3'}.
The variable N contains the full length of the text with the addition of 3 null terminating characters (one per sentence).
The algorithm simultaneously counts words and sentences. In idle1 state the counting is in word-counting mode. In idle2 state the counting is in sentence-counting mode. The modes are interchanged according to current character being read - if delimiter is encountered, the appropriate counter is increased.
i have a function like this:
BOOL WINAPI MyFunction(HDC hdc, LPCWSTR text, UINT cbCount){
char AnsiBuffer[255];
int written = WideCharToMultiByte(CP_ACP, 0, text, cbCount, AnsiBuffer , 0, NULL, NULL);
if(written > -1) AnsiBuffer[written] = '\0';
if(written>0){
ofstream myfile;
myfile.open ("C:\\example.txt", ios::app);
myfile.write(AnsiBuffer, sizeof(AnsiBuffer));
myfile.write("\n", 1);
myfile.close();
}
....
When i display the input LPCWSTR text with MessageBoxW(), the text shows up fine. When i try to convert it to multibyte, the return value looks normal (ex: 22, 45, etc), but the result is strings of gibberish (ex ÌÌÌÌÌÌÌÌÌÌÌÌÌÌÌÌÌÌ). Suggestions?
I see two problems;
1) You are passing '0' to WideCharToMultiByte for the size of the multibyte buffer. If you read the documents this results in the function returning the NUMBER of bytes needed but performing no actual conversion. (This is to allow you to subsequently allocate a buffer of the correct size and recall the function).
2) in file.write sizeof(AnsiBuffer) will result in 255 bytes being written regardless of what is in the buffer. sizeof is a compile-time calculation that returns the size of a variable. You should replace this with the 'written' variable that represents the length of the string.
You need to pass the length of the buffer to the API, instead of passing 0. When you pass 0, the function returns the required length of the buffer, but doesn't write to it. You're seeing the results of the uninitialized array.
Here's the right call, with the 255 in the right place:
int written = WideCharToMultiByte(CP_ACP, 0, text, cbCount, AnsiBuffer , 255, NULL, NULL);