In jenkins pipeline I'm defining a condition for where clause in sql statement:
else if (params.targetEnv == "dev"){
condition = "where DATABASENAME like '%dev%'"}
Then I want to replace the condition placeholder in sql file:
sh """sed -i 's/#condition#/${condition}/' ${sql_query_file}"""
But in the file I get where DATABASENAME like %dev% instead where DATABASENAME like '%dev%' that means without the single quotes.
Does anybody know how can I pass there the condition with the single quotes?
Solution
sh "sed -i \"s/#condition#/${condition}/\" ${sql_query_file}"
explanation
If you will use a sentence in which there is some variable, you should use double quotes. This is valid on jenkins and unix
def condition = "foo"
echo "$condition"
println "$condition"
sed sintax need single or double quotes
sed -i 's/SEARCH_REGEX/REPLACEMENT/g' INPUTFILE
sed -i "s/SEARCH_REGEX/REPLACEMENT/g" INPUTFILE
Double quote should be used if some var is used in the sed argument
You should escape the double quote inside of sed because in the parent string there are double quotes
echo " foo is \"bar\" "
Putting it all togeter
sh "sed -i \"s/#condition#/${condition}/\" ${sql_query_file}"
I have a comma separated strings inside brackets and I need to replace the string in matches the pattern.
And we have unknown string at the start and at the end. In the below example I need to replace c++ string with c if the row has string ruby.
I tried below sed command but it didnt work.
```
("java","php","ruby",".net","scala","c++",...n),
(".net","ruby","php","java","c++",...n),
("java",".net","ruby","php","c++",...n),
("ruby","java",".net","php","c++",...n);
```
```
sed -e "s/(\(.*\),\("ruby"\),\(.*\),"c++",\(.*\))/(\1,\2,\3,"c",\4)/g"
```
("java","php","ruby",".net","scala","c++",...n),
(".net","ruby","php","java","c++",...n),
("java",".net","ruby","php","c++",...n),
("ruby","java",".net","php","c++",...n);
'
{m,n,g}awk '/\42ruby\42/ ? NF = NF : NF' FS='"c[+][+]"' OFS='"c"'
'
("java","php","ruby",".net","scala","c",...n),
(".net","ruby","php","java","c",...n),
("java",".net","ruby","php","c",...n),
("ruby","java",".net","php","c",...n);
it seems like your sed command is not escaping double quotes
sed -e "s/(\(.*\),\("ruby"\),\(.*\),"c++",\(.*\))/(\1,\2,\3,"c",\4)/g"
change it to single quotes.
sed -e 's/(\(.*\),\("ruby"\),\(.*\),"c++",\(.*\))/(\1,\2,\3,"c",\4)/g' file.txt
or more simply use the below one...
sed -e 's/\("ruby"\),\(.*\),"c++"/\1,\2,"c"/g' my_file.txt
which will output
("jsjs","java",".net","php","c++",...n);
("java","php","ruby",".net","scala","c",...n),
(".net","ruby","php","java","c",...n),
("java",".net","ruby","php","c",...n),
("ruby","java",".net","php","c",...n);
("rubys","java",".net","php","c++",...n);
I'm trying to add a line in a file afile.xyz using my script. This is what I've done so far using sed:
n="$(grep ".method" "$m" | grep "onCreate(Landroid/os/Bundle;)V")"
sed -i '' -e '/$n/ a\
"test", /Users/username/Documents/afile.xyz
I'm getting the error:
"onCreate\(\Landroid\/ ...": bad flag in substitute command: 'g'
How do I solve this? Please do help. Thanks.
Edit: Content of n
method protected onCreate(Landroid/os/Bundle;)V
2 problems:
because the sed body is in single quotes, the variable $n will not be expanded,
the regular expression in $n contains the / dilimiters.
Try this:
n=$(...)
nn=${n//\//\\/} # escape all slashes
sed -i '' '/'"${nn}"'/ a ...
The single-quoted sed body is interrupted to append the double quoted shell variable.
You can also use a different delimiter for the RE:
sed -i '' -e "\#$n# a\\
\"test\"" /Users/username/Documents/afile.xyz
I have strings which contain double quotes like this one:
"[{"clientid":"*", "identityzone":"*"}]"
I would like to use set or grep to delete the double quotes at the beginning and at the end of it, the output should look like :
[{"clientid":"*", "identityzone":"*"}]
I have used : sed -e 's/\"//g' but this deletes all the " in a string
You need to use line anchors
$ echo '"[{"clientid":"*", "identityzone":"*"}]"' | sed 's/^"//; s/"$//'
[{"clientid":"*", "identityzone":"*"}]
^" match " only at start of line
"$ match " only at end of line
You can also combine them using | as sed 's/^"\|"$//g'
See Overview of basic regular expression syntax
easy:
sed 's/^\"\(.*\)\"$/\1/g' <<<'"[{"clientid":"*", "identityzone":"*"}]"'
I have a variable with a bunch of data.
text = "ABCDEFGHIJK"
file = garbage.txt //iiuhdsfiuhdsihf]sdiuhdfoidsoijsf
What I would like to do is replace the ] charachter in file with text. I've tried using sed but I keep getting odd errors.
output should be:
//iiuhdsfiuhdsihfABCDEFGHIJKsdiuhdfoidsoijsf
Just need to escape the ] character with a \ in regex:
text="ABCDEFGHIJK"
sed "s/\(.*\)\]\(.*\)/\1$text\2/" file > file.changed
or, for in-place editing:
sed -i "s/\(.*\)\]\(.*\)/\1$text\2/" file
Test:
sed "s/\(.*\)\]\(.*\)/\1$text\2/" <<< "iiuhdsfiuhdsihf]sdiuhdfoidsoijsf"
# output => iiuhdsfiuhdsihfABCDEFGHIJKsdiuhdfoidsoijsf
There is always the bash way that should work in your osx:
filevar=$(cat file)
echo "${filevar/]/$text}" #to replace first occurence
OR
echo "${filevar//]/$text}" #to replace all occurences
In my bash i don't even have to escape ].
By the way, the simple sed does not work?
$ a="AA"
$ echo "garbage.txt //iiuhdsfiuhdsihf]sdiuhdfoidsoijsf" |sed "s/]/$a/g"
garbage.txt //iiuhdsfiuhdsihfAAsdiuhdfoidsoijsf