I'm having an issue getting a Spring boot application to pick up a properties file after deploying.
My goal is to have a configuration folder external to the Jar so I have excluded the configuration in the Maven build:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<configuration>
<excludes>
<exclude>*.*</exclude>
</excludes>
</configuration>
</plugin>
and I have an build assembly configured as:
<assembly>
<id>bin</id>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<directory>src/main/resources</directory>
<outputDirectory>config</outputDirectory>
</fileSet>
<fileSet>
<directory>src/main/bin</directory>
<outputDirectory>bin</outputDirectory>
</fileSet>
<fileSet>
<directory>target</directory>
<outputDirectory>lib</outputDirectory>
<includes>
<include>jarname*.jar</include>
</includes>
</fileSet>
</fileSets>
</assembly>
Which create my folder structure as expected with the configuration files in the config folder and the jar in a lib folder
Now when I run the jar from the lib directory, I get an error advising it can't find the properties, which I would expect as the configuration files are excluded from the Spring Boot build:
java -jar jarname.jar
org.springframework.beans.factory.BeanDefinitionStoreException: Failed to parse configuration class [com.package.application.ApplicationMainClass]; nested exception is java.io.FileNotFoundException: class path resource [application.properties] cannot be opened because it does not exist
so I explicitly point the configuration to the jar as advised in the documentation:
java -jar jarname.jar --spring.config.location=file:C:\path-to-build\config\application.properties
but I am still getting the same error
You should load it this way
java -jar jarname.jar --spring.config.location=classpath:file:///C:/directory/jdbc.properties
So it wasn't a problem with the command, my issue was that I had explicitly referenced the file in one of the Java classes:
#PropertySource("classpath:application.properties")
Related
I want to delete all the files and subdirectories from the temp folder of Tomcat 8+ version.
In my application ActiveMQ is integrated which will create one folder inside temp folder of Tomcat on the server startup. So I want to clear my temp folder before creating another folder by ActiveMQ on server startup.
Is there any way to define any maven plugin to achieve this or there is any other way to get this done?
As I can understand you need to clean directories that are not exposed to maven.
So check this clean plugin for maven
<plugin>
<artifactId>maven-clean-plugin</artifactId>
<version>3.1.0</version>
<configuration>
<filesets>
<fileset>
<directory>some/relative/path</directory>
<includes>
<include>**/*.tmp</include>
<include>**/*.log</include>
</includes>
<excludes>
<exclude>**/important.log</exclude>
<exclude>**/another-important.log</exclude>
</excludes>
<followSymlinks>false</followSymlinks>
</fileset>
</filesets>
</configuration>
</plugin>
This may sound silly, but I really want to know if I can do that (by adding some 'magic' configuration in pom.xml).
Let's say, I have a project which has a bunch of packages, one of them, say 'com.foo.bar', has quite a few .java files, including one named 'Dummy.java'.
Now, when generating the jar file, I want to exclude all classes under com.foo.bar, except the 'Dummy'.
I tried regular expression in a section, but no luck.
Is there an easy way to go? Many thanks.
With a "sledge hammer" (assuming Dummy.class not .java):
<plugin>
<artifactId>maven-jar-plugin</artifactId>
<configuration>
<includes>
<include>com/foo/bar/Dummy.class</include>
</includes>
<!-- alternatively(!) excludes/exclude* -->
</configuration>
</plugin>
... or with a "Swiss army knife": maven-assembly-plugin ... ^^!"%/"))
...
To use the Assembly Plugin in Maven, you simply need to:
choose or write the assembly descriptor to use,
configure the Assembly Plugin in your project's pom.xml,
and
run "mvn assembly:single" on your project.
...
with an assembly descriptor like:
<assembly xmlns="http://maven.apache.org/ASSEMBLY/2.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/ASSEMBLY/2.0.0
http://maven.apache.org/xsd/assembly-2.0.0.xsd">
<id>dummy-only</id>
<formats>
<format>jar</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<outputDirectory>/</outputDirectory>
<directory>${project.build.outputDirectory}</directory>
<includes>
<include>com/foo/bar/Dummy.class</exclude>
</includes>
</fileSet>
</fileSets>
</assembly>
see also: I wish to exclude some class files from my jar. I am using maven-assembly-plugin. It still adds the files. I dont get any error
I'm trying to package a text based file into .tar using maven. To achieve this I used an assembly plugin and it worked, but along with the file tar a jar is also being generated. How can I avoid that?
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>all</id>
<formats>
<format>tar</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>configuration</directory>
<fileMode>0444</fileMode>
</fileSet>
</fileSets>
</assembly>
You can change the packaging of your project.
I guess current packaging is jar, and thus the creation of a jar.
You may use pom and configure the assembly plugin to attach its result (the tar) to your build.
You could also configure the jar plugin, to skip the creation of empty jar (if it is your case).
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<version>3.0.2</version>
<configuration>
<skipIfEmpty>true</skipIfEmpty>
</configuration>
</plugin>
I have a project which builds a war (no problem). And, that war needs to be packaged with a few shell scripts. Because that war contains properties files that vary from site-to-site, we can't simply install the war as is, but munge the properties files in it. That's what the shell scripts do.
I'd like to package my war in my assembly as a unpacked war. I see <unpacked> in the Assembly Descriptor, but I haven't been able to get that to work.
Here's my first bin.xml where I just packed the war as is. This works fine:
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>bin</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${project.basedir}/src/assembly/scripts</directory>
<includes>
<include>deploy.sh</include>
<include>lock_build.sh</include>
<include>description.sh</include>
<include>url-encode.pl</include>
</includes>
<outputDirectory>/</outputDirectory>
</fileSet>
<fileSet>
<directory>${project.build.directory}/${project.artifactId}-${project.version}</directory>
<outputDirectory>${project.artifactId}</outputDirectory>
</fileSet>
</fileSets>
</assembly>
Here's my first attempt at unpacked:
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>bin</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${project.basedir}/src/assembly/scripts</directory>
<includes>
<include>deploy.sh</include>
<include>lock_build.sh</include>
<include>description.sh</include>
<include>url-encode.pl</include>
</includes>
<outputDirectory>/</outputDirectory>
</fileSet>
</fileSets>
<moduleSets>
<moduleSet>
<includes>
<include>{$project.groupId}:${project.artifactId}:war</include>
</includes>
<binaries>
<includes>
<include>${project.build.directory}-${project.artifactId}-${project.version}.${project.packaging}</include>
</includes>
<outputDirectory>${project.artifactId}</outputDirectory>
<unpack>true</unpack>
</binaries>
</moduleSet>
</moduleSets>
</assembly>
Here's my last try at getting the unpacked war:
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>bin</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${project.basedir}/src/assembly/scripts</directory>
<includes>
<include>deploy.sh</include>
<include>lock_build.sh</include>
<include>description.sh</include>
<include>url-encode.pl</include>
</includes>
<outputDirectory>/</outputDirectory>
</fileSet>
</fileSets>
<moduleSets>
<moduleSet>
<binaries>
<attachmentClassifier>war</attachmentClassifier>
<outputDirectory>${project.artifactId}</outputDirectory>
<unpack>true</unpack>
<includeDependencies>true</includeDependencies>
<dependencySets>
<dependencySet/>
</dependencySets>
</binaries>
</moduleSet>
</moduleSets>
</assembly>
In each of these last two attempts, I am only packaging the scripts and the war isn't coming over.
I know I could use the ${project.build.directory}/${project.artifactId}-${project.version} directory which contains almost all of the files in the war, but it doesn't contain my MANIFEST.MF entries which includes information linking the war back to a particular Jenkins build and Subversion revision.
What do I need to do to include an unpacked war into my assembly?
Another Attempt
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>bin</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${project.basedir}/src/assembly/scripts</directory>
<includes>
<include>deploy.sh</include>
<include>lock_build.sh</include>
<include>description.sh</include>
<include>url-encode.pl</include>
</includes>
<outputDirectory>/</outputDirectory>
</fileSet>
</fileSets>
<dependencySets>
<dependencySet>
<outputDirectory>${project.artifactId}</outputDirectory>
<unpack>true</unpack>
<scope>runtime</scope>
</dependencySet>
</dependencySets>
</assembly>
When I ran this, I got:
[INFO] ------------------------------------------------------------------------
[INFO] Building My Project 1.0.0
[INFO] ------------------------------------------------------------------------
[INFO]
[INFO] --- maven-assembly-plugin:2.5.2:single (default-cli) # myproj ---
[INFO] Reading assembly descriptor: src/assembly/bin.xml
[WARNING] Cannot include project artifact: \
com.vegicorp:myproj:war:1.0.0; \
it doesn't have an associated file or directory.
[INFO] Building zip: ~/workdir/trunk/myproj/target/archive/myproj.zip
[INFO] ------------------------------------------------------------------------
[INFO] BUILD SUCCESS
[INFO] ------------------------------------------------------------------------
Inside the zip are all the jars in the war nice and unpacked, but not my unpacked war.
I know I should be able to add the unpacked war into my assembly. I see that unpack option, and I know it works for other dependencies. However, it looks like I can only access it via a <dependencySet> or a <moduleSet>. I should be able to specify my project as its own module. There must be something I am doing wrong.
Spleen Vent
This is the big thing I hate about Maven: Maven does a great job hiding things from you which is nice because it prevents you from doing stuff you shouldn't. I hate it when developers build Ant build.xml files because most developers don't understand how to do a build, and the build.xml becomes an unreadable mess. With Maven, this isn't an issue. Just configure your project, and Maven will take care of this for you.
But sometimes Maven is like a black box with a bunch of levers and buttons. You sit there pushing and pulling levers and buttons trying to figure out how to get it to do something you want to do. I spend way too much of my time trying to help developers to configure their Maven projects. They want to do something a little different like use hibernate or build source from WSDL files, and have no idea how to get Maven to do what they want.
One developer describes it as a self driving car which can't quite go where you want. You may even see the destination out the window, but you can't figure out how to manipulate the car's destination to get you there.
What I want to do should be easy. I just want to create an assembly, and instead of using the packed war file, I want it unpacked.
In Ant, this can be accomplished in a single task. In Maven, it's a mysterious process. I think I'm close, I am probably missing one little configuration parameter that will make it all work, but I've already spent hours working on this.
What I ended up doing
I used the maven-dependency-plugin to unpack my war. I wasn't sure whether this would work because I didn't want the dependency plugin downloading the war, but it seems to understand that when I specify my war, I am talking about the current build, and nothing is downloaded. (I don't even have the war in our Maven repo).
I also had to upgrade Maven from 2.x to 3.x because I need to make sure that the maven-dependency-plugin ran before the maven-assembly-plugin. Since both run in the packaging phase of the build, Maven 2.x can't guarantee the order the plugins run in.
Once I used that plugin, all I had to do was specify the directory where I unpacked the war in my assembly plugin, and it was included in my zip.
I still want to know how to use the <unpack> entity in the assembly plugin itself instead of having to use another plugin to unpack my war. If anyone can tell me how to do the unpack in the assembly file itself, I'll mark that as the correct answer.
pom.xml
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<version>2.9</version>
<executions>
<execution>
<id>unpack</id>
<phase>package</phase>
<goals>
<goal>unpack</goal>
</goals>
<configuration>
<outputDirectory>${project.build.directory}/unwar/${project.artifactId}</outputDirectory>
<artifactItems>
<artifactItem>
<groupId>${project.groupId}</groupId>
<artifactId>${project.artifactId}</artifactId>
<version>${project.version}</version>
<type>war</type>
</artifactItem>
</artifactItems>
</configuration>
</execution>
</executions>
</plugin>
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.5.2</version>
<configuration>
<finalName>${project.artifactId}</finalName>
<appendAssemblyId>false</appendAssemblyId>
<outputDirectory>${project.build.directory}/archive</outputDirectory>
<descriptors>
<descriptor>src/assembly/bin.xml</descriptor>
</descriptors>
</configuration>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
bin.xml (My Assembly)
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>bin</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${project.basedir}/src/assembly/scripts</directory>
<fileMode>0755</fileMode>
<lineEnding>lf</lineEnding>
<includes>
<include>deploy.sh</include>
<include>lock_build.sh</include>
<include>description.sh</include>
<include>url-encode.pl</include>
</includes>
<outputDirectory>/</outputDirectory>
</fileSet>
<fileSet>
<directory>${project.build.directory}/unwar</directory>
<outputDirectory>/</outputDirectory>
</fileSet>
</fileSets>
</assembly>
The ACTUAL Answer
Thanks to khmarbaise's link (see the comment below), I copied that project's assembly plugin and it almost worked. Like my attempt, it unpacked all the runtime jars, and not just the one I wanted. However, it also unpacked my war too.
There were only two differences between that link's answer and my attempt:
They included <useProjectArtifact>true</useProjectArtifact> and I didn't. However, this defaults to true. Removing it still allowed it to work.
They included a / in front of the directory name in the <outputDirectory>. Removing this made no difference.
This meant that it now matched what I had previously tried. So, why was it working this time.
Turns out, I was testing the assembly changes by simply running mvn assembly:single. After all, why do the whole build and repackage when I am simply trying to get the assembly to work. When you run just mvn assembly:single -- even though everything is already packaged, you get this error:
[WARNING] Cannot include project artifact: \
com.vegicorp:myproj:war:1.0.0; \
it doesn't have an associated file or directory.
And your war isn't unpacked. However, if you put the assembly into the package phase, and then run mvn package, everything works out just nifty.
I then spent time trying to just get my war and not all the associated runtime stuff with it. I used <includes/> to do this, but because I have a war and not a jar, I had to include a classifier in my <include>.
At last, I have everything working. I have this in my assembly:
<dependencySets>
<dependencySet>
<outputDirectory>${project.artifactId}</outputDirectory>
<unpack>true</unpack>
<scope>runtime</scope>
<includes>
<include>${project.groupId}:${project.artifactId}:*:${project.version}</include>
</includes>
</dependencySet>
</dependencySets>
And as long as I run mvn package, it works.
This is way better than what I had with the maven-dependency-plugin. Now, all of the information having to do with the assembly is in the assembly XML file.
I am using the maven-assembly-plugin to package my build.
I am able to perform some copying of file sets and modify file permissions fine, but I am unable to modify directory permissions. From the documentation, I am trying to use on the directories I care about. However, regardless of what permissions I specify, directories are ALWAYS created based off of the current umask (0022).
Does anyone know of a clean way to modify directory permissions in this way during a Maven build. The only thing that works is umask 0, but I would rather not be forced to do this, since everyone working on this project would have to have this set.
Example maven assembly.xml:
<?xml version="1.0"?>
<assembly>
<id>zip-with-dependencies</id>
<formats>
<format>dir</format>
<format>tar.gz</format>
</formats>
<includeBaseDirectory>true</includeBaseDirectory>
<dependencySets>
<dependencySet>
<includes>
<include>foo:bar</include>
</includes>
<outputDirectory>/resources/blah</outputDirectory>
<useProjectArtifact>true</useProjectArtifact>
<unpack>true</unpack>
<scope>runtime</scope>
</dependencySet>
</dependencySets>
<fileSets>
<fileSet>
<directory>${basedir}/src/main/web</directory>
<includes>
<include>some_dir</include>
</includes>
<outputDirectory>web</outputDirectory>
<fileMode>0777</fileMode>
<directoryMode>0777</directoryMode>
</fileSet>
</fileSets>
</assembly>
I had the same problem. I tested all the above solutions and none of them worked for me.
The best solution I had in mind and that worked for me was to pre create these parent folders as empty folders, before actually writing to them.
So, to relate to the original problem, you should use:
<fileSet>
<directory>./</directory>
<outputDirectory>/resources</outputDirectory>
<excludes>
<exclude>*/**</exclude>
</excludes>
<directoryMode>0700</directoryMode>
</fileSet>
This should be put before the actual copy to the subfolder of resources in your example.
./ - is simply some existing folder. It can be any other folder, as long as it exists. Note that we exclude any file from the fileSet.
So the result would be an empty folder with the appropriate set of permissions.
On a side note, whoever uses tar to pack the files, without this set, the tar file won't have the permissions set for this parent folder. So extraction will result with a new folder, but with permissions of the extracting user + his umask.
0700 was used only for the sake of the example, of course.
I've solved this problem with a combination of settings in the pom.xml and the assembly descriptor.
In pom specify the defaults for the entire zip file.
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.2.2</version>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
<configuration>
<descriptors>
<descriptor>src/main/assembly/descriptor.xml</descriptor>
</descriptors>
<archiverConfig>
<directoryMode>0755</directoryMode>
<defaultDirectoryMode>0755</defaultDirectoryMode>
<fileMode>0644</fileMode>
</archiverConfig>
</configuration>
</plugin>
Then in the assembly descriptor I provide the overrides for individual folders that shouldn't have the default permissions.
<fileSets>
<fileSet>
<directory>src/conf</directory>
<outputDirectory>conf</outputDirectory>
<fileMode>0600</fileMode>
<directoryMode>0700</directoryMode>
</fileSet>
<fileSet>
<directory>src/db</directory>
<outputDirectory>db</outputDirectory>
</fileSet>
<fileSet>
<directory>src/bin</directory>
<outputDirectory>bin</outputDirectory>
<fileMode>0755</fileMode>
</fileSet>
Here the files in the bin directory will be given executable state for all users. The conf directory and files in it are accessible only by the owner, and the db directory inherits the permissions from the settings in the pom.
The assembly file settings are described at http://maven.apache.org/plugins/maven-assembly-plugin/assembly.html
I couldn't find any official documentation on the configuration section other than the JIRA issue that amra identified.
I found a JIRA issue describing this behavior. A workaround should be
<configuration>
<archiverConfig>
<fileMode>420</fileMode> <!-- 420(dec) = 644(oct) -->
<directoryMode>493</directoryMode> <!-- 493(dec) = 755(oct) -->
<defaultDirectoryMode>493</defaultDirectoryMode>
</archiverConfig>
</configuration>