Maven, exclude all classes but one under a package - maven

Question

This may sound silly, but I really want to know if I can do that (by adding some 'magic' configuration in pom.xml).
Let's say, I have a project which has a bunch of packages, one of them, say 'com.foo.bar', has quite a few .java files, including one named 'Dummy.java'.
Now, when generating the jar file, I want to exclude all classes under com.foo.bar, except the 'Dummy'.
I tried regular expression in a section, but no luck.
Is there an easy way to go? Many thanks.

Answer 1

With a "sledge hammer" (assuming Dummy.class not .java):
<plugin>
<artifactId>maven-jar-plugin</artifactId>
<configuration>
<includes>
<include>com/foo/bar/Dummy.class</include>
</includes>
<!-- alternatively(!) excludes/exclude* -->
</configuration>
</plugin>
... or with a "Swiss army knife": maven-assembly-plugin ... ^^!"%/"))
...
To use the Assembly Plugin in Maven, you simply need to:
choose or write the assembly descriptor to use,
configure the Assembly Plugin in your project's pom.xml,
and
run "mvn assembly:single" on your project.
...
with an assembly descriptor like:
<assembly xmlns="http://maven.apache.org/ASSEMBLY/2.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/ASSEMBLY/2.0.0
http://maven.apache.org/xsd/assembly-2.0.0.xsd">
<id>dummy-only</id>
<formats>
<format>jar</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<outputDirectory>/</outputDirectory>
<directory>${project.build.outputDirectory}</directory>
<includes>
<include>com/foo/bar/Dummy.class</exclude>
</includes>
</fileSet>
</fileSets>
</assembly>
see also: I wish to exclude some class files from my jar. I am using maven-assembly-plugin. It still adds the files. I dont get any error