I am wanting to return the last transaction date grouped by CustomerID, and I am using SQLiteStudio 3.2.1. My table looks like this:
CustomerID Date TransactionID Amount
1 2000-07-01 1 20.00
2 2000-07-04 2 40.00
1 2002-08-01 3 20.00
1 2007-01-01 4 60.00
2 2010-05-09 5 70.00
1 2012-06-25 6 35.00`
This is what I would like the end result to look like: `
CustomerID Date TransactionID Amount Last Transaction Date
1 2000-07-01 1 20.00 NULL
2 2000-07-04 2 40.00 NULL
1 2002-08-01 3 20.00 2000-07-01
1 2007-01-01 4 60.00 2002-01-01
2 2010-05-09 5 70.00 2000-07-04
1 2012-06-25 6 35.00` 2007-01-01
I was attempting to use the following code:
SELECT CustomerID, Date, Amount, LAG(Date,1) OVER (PARTITIONED BY CustomerID ORDER BY Date)
FROM table
However, the lag function is not supported in SQLiteStudio (or maybe I am missing something?). The SQL Editor is also not recognizing the PARTITION BY clause either. Is there a way to use the LAG function or the PARTITION BY clause in the SQL Function Editor? Any help would be greatly appreciated! Thanks!
Also: does anyone have any resources for aggregate function creation in the SQL Function Editor for SQLiteStudio? I know it takes the three parameters of "Initialization code", "Per step code", and "Final step implementation code", but I am looking for examples of the syntax/requirements for these three parameters in SQLiteStudio. (Thanks again!)
Your partition clause, as your pasted above, has a typo, and it should be PARTITION BY, not PARTITIONED BY. If this be the only problem, then just fix the typo:
SELECT CustomerID, Date, Amount,
LAG(Date) OVER (PARTITION BY CustomerID
ORDER BY Date) AS "Last Transaction Date"
FROM yourTable
ORDER BY Date;
If the above still does not work, then perhaps your version of SQLite does not support LAG. One workaround in this case would be to use a correlated subquery in place of LAG:
SELECT CustomerID, Date, Amount,
(SELECT t2.Date
FROM yourTable t2
WHERE t2.CustomerID = t1.CustomerID AND
t2.TransactionID < t1.TransactionID
ORDER BY t2.TransactionID DESC
LIMIT 1) AS "Last Transaction Date"
FROM yourTable t1
ORDER BY Date;
Related
In Oracle SQL Developer, I have a table called t1 who have two columns col1 defined as NUMBER(19,0) and col2 defined as TIMESTAMP(3).
I have these rows
col1 col2
1 03/01/22 12:00:00,000000000
2 03/01/22 13:00:00,000000000
3 26/11/21 10:27:11,750000000
4 26/11/21 10:27:59,606000000
5 16/12/21 11:47:04,105000000
6 16/12/21 12:29:27,101000000
My sysdate looks like this:
select sysdate from dual;
SYSDATE
03/03/22
I want to create a stored procedure (SP) which will delete rows older than 2 months and displayed message n rows are deleted
But when i execute this statement
select * from t1 where to_date(TRUNC(col2), 'DD/MM/YY') < add_months(sysdate, -2);
I don't get the first 2 rows of my t1 table. I get more than 2 rows
1 03/01/22 12:00:00,000000000
2 03/01/22 13:00:00,000000000
How can i get these rows and deleted it please ?
In Oracle, a DATE data type is a binary data type consisting of 7 bytes (century, year-of-century, month, day, hour, minute and second). It ALWAYS has all of those components and it is NEVER stored with a particular formatting (such as DD/MM/RR).
Your client application (i.e. SQL Developer) may choose to DISPLAY the binary DATE value in a human readable manner by formatting it as DD/MM/RR but that is a function of the client application you are using and not the database.
When you show the entire value:
SELECT TO_CHAR(ADD_MONTHS(sysdate, -2), 'YYYY-MM-DD HH24:MI:SS') AS dt FROM DUAL;
Then it outputs (depending on time zone):
DT
2022-01-03 10:11:28
If you compare that to your values then you can see that 2022-01-03 12:00:00 is not "more than 2 months ago" so it will not be matched.
What you appear to want is not "more than 2 months ago" but "equal to or more than 2 months, ignoring the time component, ago"; which you can get using:
SELECT *
FROM t1
WHERE col2 < add_months(TRUNC(sysdate), -2) + INTERVAL '1' DAY;
or
SELECT *
FROM t1
WHERE TRUNC(col2) <= add_months(TRUNC(sysdate), -2);
(Note: the first query would use an index on col2 but the second query would not; it would require a function-based index on TRUNC(col2) instead.)
Also, don't use TO_DATE on a column that is already a DATE or TIMESTAMP data type. TO_DATE takes a string as the first argument and not a DATE or TIMESTAMP so Oracle will perform an implicit conversion using TO_CHAR and if the format models do not match then you will introduce errors (and since any user can set their own date format in their session parameters at any time then you may get errors for one user that are not present for other users and is very hard to debug).
db<>fiddle here
Perhaps just:
select *
from t1
where col2 < add_months(sysdate, -2);
My tables are as below
MS_ISM_ISSUE
ISSUE_ID ISSUE_DUE_DATE ISSUE_SOURCE_TYPE
I1 25-11-2018 1
I2 25-12-2018 1
I3 27-03-2019 2
MS_ISM_SOURCE_SETUP
SOURCE_ID MODULE_NAME
1 IT-Compliance
2 Risk Assessment
I have written following query.
with rs as
(select
count(ISSUE_ID) as ISSUE_COUNT, src.MODULE_NAME,
case
when ISSUE_DUE_DATE<sysdate then 'Overdue'
when ISSUE_DUE_DATE between sysdate and sysdate + 90 then 'Within 3 months'
when ISSUE_DUE_DATE>sysdate+90 then 'Beyond 90 days'
end as date_range
from MS_ISM_ISSUE issue, MS_ISM_SOURCE_SETUP src
where issue.Issue_source_type = src.source_id
group by src.MODULE_NAME, case
when ISSUE_DUE_DATE<sysdate then 'Overdue'
when ISSUE_DUE_DATE between sysdate and sysdate + 90 then 'Within 3 months'
when ISSUE_DUE_DATE>sysdate+90 then 'Beyond 90 days'
end)
select ISSUE_COUNT,MODULE_NAME, DATE_RANGE,
(select count(ISSUE_COUNT) from rs where rs.MODULE_NAME=MODULE_NAME) as total from rs;
The output of the code is as below.
ISSUE_COUNT MODULE_NAME DATE_RANGE Total
1 IT-Compliance Overdue 3
1 IT-Compliance Within 3 months 3
1 Risk Assessment Beyond 90 days 3
The result is correct till 3rd column. In 4th column what I want is, total of Issue count for given module name. Hence in above case Total column will have value as 2 for first and second row (since there are 2 Issues for IT-Compliance) and value 1 for the third row (since one issue is present for Risk Assessment).
Essentially, I want to achieve is to replace current row's MODULE_NAME in last where clause. How do I achieve this using query?
OK, this condition
where rs.MODULE_NAME=MODULE_NAME
is essentially the same as if you wrote
where MODULE_NAME = MODULE_NAME
which is simply always true (if there are no nulls in module_name).
Try using different table alias for inner query and outer query, e.g.
select count(ISSUE_COUNT) from rs rs2 where rs2.MODULE_NAME=rs.MODULE_NAME
You can also try to use analytic function here, something like
select ISSUE_COUNT,
MODULE_NAME,
DATE_RANGE,
COUNT(ISSUE_COUNT) OVER (PARTITION BY RS.MODULE_NAME) AS TOTAL
from rs
instead of your subquery
I'm trying to cut down on rows a report has. There are 2 assets that return on this query but I want them to show up on one row.
Basically if dc.name LIKE '%CT/PT%' then I want it to be same row as the asset. The SP.SVC_PT_ID is the common field to join them.
There will be times when there is no dc.name LIKE '%CT/PT%' however I still want the DV.MFG_SERIAL_NUM to populated just with a Null to the right.
Select SP.SVC_PT_ID, SP.DEVICE_ID, DV.MFG_SERIAL_NUM, dc.name,
substr(dc.name,26)
From EIP.SVC_PT_DEVICE_REL SP,
eip.device_class dc,
EIP.DEVICE DV
Where SP.EFF_START_TIME < To_date('20170930', 'YYYYMMDD') + 1
and SP.EFF_END_TIME is null
and dc.id = DV.device_class_id
and DV.ID = SP.device_id
ORDER BY SP.SVC_PT_ID, DV.MFG_SERIAL_NUM;
I'm not sure I understand what you are saying; test case would certainly help. You said that query you posted returns two rows (only if we saw which ones ...) but you want them to be displayed as the image you attached to the message.
Generally speaking, you can do that using an aggregate function (such as MAX) on certain column(s), along with the GROUP BY clause that contains the rest of them.
Just for example:
select svc_pt_id, max(ctpt_name) ctpt_name, sum(ctpt_multipler) ctpt_multipler
from ...
group by svc_pt_id
As I said: a test case would help people who'd want to answer the question. True - someone might have understood it far better than I did and will provide assistance nevertheless.
EDIT: after you posted sample data (which, by the way, don't match screenshot you posted previously), maybe something like this might do the job: use analytic function to check whether name contains CT/PT; if so, take its data. Otherwise, display both rows.
SQL> with test as (
2 select 14 svc_pt_id, 446733 device_id, 'Generic Electric' name from dual union
3 select 14, 456517, 'Generic CT/PT, Multiplier' from dual
4 ),
5 podaci as
6 (select svc_pt_id, device_id, name,
7 rank() over (partition by svc_pt_id
8 order by case when instr(name, 'CT/PT') > 1 then 1
9 else 2
10 end) rnk
11 from test
12 )
13 select svc_pt_id, device_id, name
14 from podaci
15 where rnk = 1;
SVC_PT_ID DEVICE_ID NAME
---------- ---------- -------------------------
14 456517 Generic CT/PT, Multiplier
SQL>
My TEST table (created by WITH factoring clause) would be the result of your current query.
I have someting like this
id day descrition
1 1 hi
1 1 today
1 1 is a beautifull
1 1 day
1 2 exemplo
1 2 for
1 2 this case
I need to do a funtion that for each day concatenate the descrtiomn colunm and return the result like this
id day descrition
1 1 hi today is a beautifull thay
1 2 exemplo for this case
Anny ideia about how can i do this usisng a loop in a function in oracle
You need a way of determining which order the values should be aggregated. The snippet below will rely on the implicit order in which Oracle reads the rows from the datafiles - if you have row movement enabled then you may get inconsistent results as the rows can be read in different orders as they are relocated in the underlying datafiles.
SELECT LISTAGG( description, ' ' ) WITHIN GROUP ( ORDER BY ROWNUM ) AS description
FROM your_table
GROUP BY id, day
It would be better to have another column that stores the order within each day.
I wonder how do I select a range of data depending on the date range?
I have these data in my payment table in format dd/mm/yyyy
Id Date Amount
1 4/1/2011 300
2 10/1/2011 200
3 27/1/2011 100
4 4/2/2011 300
5 22/2/2011 400
6 1/3/2011 500
7 1/1/2012 600
The closing date is on the 27 of every month. so I would like to group all the data from 27 till 26 of next month into a group.
Meaning to say I would like the output as this.
Group 1
1 4/1/2011 300
2 10/1/2011 200
Group 2
1 27/1/2011 100
2 4/2/2011 300
3 22/2/2011 400
Group 3
1 1/3/2011 500
Group 4
1 1/1/2012 600
It's not clear the context of your qestion. Are you querying a database?
If this is the case, you are asking about datetime but it seems you have a column in string format.
First of all, convert your data in datetime data type (or some equivalent, what db engine are you using?), and then use a grouping criteria like this:
GROUP BY datepart(month, dateadd(day, -26, [datefield])), DATEPART(year, dateadd(day, -26, [datefield]))
EDIT:
So, you are in Linq?
Different language, same logic:
.GroupBy(x => DateTime
.ParseExact(x.Date, "dd/mm/yyyy", CultureInfo.InvariantCulture) //Supposed your date field of string data type
.AddDays(-26)
.ToString("yyyyMM"));
If you are going to do this frequently, it would be worth investing in a table that assigns a unique identifier to each month and the start and end dates:
CREATE TABLE MonthEndings
(
MonthID INTEGER NOT NULL PRIMARY KEY,
StartDate DATE NOT NULL,
EndDate DATE NOT NULL
);
INSERT INTO MonthEndings VALUES(201101, '27/12/2010', '26/01/2011');
INSERT INTO MonthEndings VALUES(201102, '27/01/2011', '26/02/2011');
INSERT INTO MonthEndings VALUES(201103, '27/02/2011', '26/03/2011');
INSERT INTO MonthEndings VALUES(201112, '27/11/2011', '26/01/2012');
You can then group accurately using:
SELECT M.MonthID, P.Id, P.Date, P.Amount
FROM Payments AS P
JOIN MonthEndings AS M ON P.Date BETWEEN M.StartDate and M.EndDate
ORDER BY M.MonthID, P.Date;
Any group headings etc are best handled out of the DBMS - the SQL gets you the data in the correct sequence, and the software retrieving the data presents it to the user.
If you can't translate SQL to LINQ, that makes two of us. Sorry, I have never used LINQ, so I've no idea what is involved.
SELECT *, CASE WHEN datepart(day,date)<27 THEN datepart(month,date)
ELSE datepart(month,date) % 12 + 1 END as group_name
FROM payment