I have someting like this
id day descrition
1 1 hi
1 1 today
1 1 is a beautifull
1 1 day
1 2 exemplo
1 2 for
1 2 this case
I need to do a funtion that for each day concatenate the descrtiomn colunm and return the result like this
id day descrition
1 1 hi today is a beautifull thay
1 2 exemplo for this case
Anny ideia about how can i do this usisng a loop in a function in oracle
You need a way of determining which order the values should be aggregated. The snippet below will rely on the implicit order in which Oracle reads the rows from the datafiles - if you have row movement enabled then you may get inconsistent results as the rows can be read in different orders as they are relocated in the underlying datafiles.
SELECT LISTAGG( description, ' ' ) WITHIN GROUP ( ORDER BY ROWNUM ) AS description
FROM your_table
GROUP BY id, day
It would be better to have another column that stores the order within each day.
Related
My tables are as below
MS_ISM_ISSUE
ISSUE_ID ISSUE_DUE_DATE ISSUE_SOURCE_TYPE
I1 25-11-2018 1
I2 25-12-2018 1
I3 27-03-2019 2
MS_ISM_SOURCE_SETUP
SOURCE_ID MODULE_NAME
1 IT-Compliance
2 Risk Assessment
I have written following query.
with rs as
(select
count(ISSUE_ID) as ISSUE_COUNT, src.MODULE_NAME,
case
when ISSUE_DUE_DATE<sysdate then 'Overdue'
when ISSUE_DUE_DATE between sysdate and sysdate + 90 then 'Within 3 months'
when ISSUE_DUE_DATE>sysdate+90 then 'Beyond 90 days'
end as date_range
from MS_ISM_ISSUE issue, MS_ISM_SOURCE_SETUP src
where issue.Issue_source_type = src.source_id
group by src.MODULE_NAME, case
when ISSUE_DUE_DATE<sysdate then 'Overdue'
when ISSUE_DUE_DATE between sysdate and sysdate + 90 then 'Within 3 months'
when ISSUE_DUE_DATE>sysdate+90 then 'Beyond 90 days'
end)
select ISSUE_COUNT,MODULE_NAME, DATE_RANGE,
(select count(ISSUE_COUNT) from rs where rs.MODULE_NAME=MODULE_NAME) as total from rs;
The output of the code is as below.
ISSUE_COUNT MODULE_NAME DATE_RANGE Total
1 IT-Compliance Overdue 3
1 IT-Compliance Within 3 months 3
1 Risk Assessment Beyond 90 days 3
The result is correct till 3rd column. In 4th column what I want is, total of Issue count for given module name. Hence in above case Total column will have value as 2 for first and second row (since there are 2 Issues for IT-Compliance) and value 1 for the third row (since one issue is present for Risk Assessment).
Essentially, I want to achieve is to replace current row's MODULE_NAME in last where clause. How do I achieve this using query?
OK, this condition
where rs.MODULE_NAME=MODULE_NAME
is essentially the same as if you wrote
where MODULE_NAME = MODULE_NAME
which is simply always true (if there are no nulls in module_name).
Try using different table alias for inner query and outer query, e.g.
select count(ISSUE_COUNT) from rs rs2 where rs2.MODULE_NAME=rs.MODULE_NAME
You can also try to use analytic function here, something like
select ISSUE_COUNT,
MODULE_NAME,
DATE_RANGE,
COUNT(ISSUE_COUNT) OVER (PARTITION BY RS.MODULE_NAME) AS TOTAL
from rs
instead of your subquery
select * from user where username is equal to 'jw'
Add DISTINCT directly after SELECT, or alternatively, use the GROUP BY clause after your WHERE clause.
ex: GROUP BY works.memb_id
I think I understand what you are trying to do. WorkID, EmployeeID, and MembID all have to be 1:1 and then you want to group on all three fields.
You have asserted that each Memb_id is assigned to a unique employee. If WorkID is not then you will need to use an aggregate function to select one of the records returned after the group. Such as Min(), Max() or a window function like Row_Number and or Rank.
For example
WorkID, EmployeeID, MembID
1 1 1
2 1 1
3 2 2
4 1 1
If you use Min(WorkID), EmployeeID, MembID....Group By EmployeeID, MembID you will get:
WorkID, EmployeeID, MembID
1 1 1
3 2 2
If this is not what you are looking for some sample data as a whole and what results you expect would be necessary.
I have a scenario where I need to compare 2 or more dates for given period.
I'm able to succeed when comparing 1 date to a period using between function. But challenge is when I have 2 dates to compare in parallel, getting single row sub query error
select A
from ORDER
where Date1 between sysdate and (sysdate-10)
Above query works fine for single date, please help to get a solution when I have Date 1 and Date 2 and need to compare against the same period (sysdate and (sysdate-10)) and I may have more than 2 dates as well.
Thanks
Shankar
Not having a proper description of your tables or the data they contain, it is difficult to know what you want.
Perhaps something like:
SELECT A
FROM ORDER
GROUP BY A
HAVING COUNT( CASE WHEN datecolumn BETWEEN SYSDATE - 10 AND SYSDATE THEN 1 ELSE NULL END ) > 0
I have an MS Access Database table that records communication status of values from several meters. The data is logged directly to the table, but I need to make sure that the table is populating. From the sample data you can see that the Comm columns doesn't read false or 0, so I want to return a log whenever the difference between now and "Date / Time" is greater than 5 minutes.
Date / Time FCB Comm BOF Comm EAF Comm FGP Comm
9/6/2011 10:29:10 1 1 1 1
9/6/2011 10:28:01 1 1 1 1
9/6/2011 10:27:11 1 1 1 1
9/6/2011 10:26:20 1 1 1 1
9/2/2011 08:17:01 1 1 1 1
9/2/2011 08:16:10 1 1 1 1
9/2/2011 08:15:02 1 1 1 1
9/2/2011 08:14:08 1 1 1 1
I wanted to know if anyone could tell me if this could like a reasonable query to run?
SELECT Data.[Date / Time], Data.[Ford Chiller Building Comm Okay],
Data.[Basic Oxygen Furnace Comm Okay], Data.[Electro-Arc Furnace Comm Okay],
Data.[J-9 Shop Comm Okay], Data.[Ford Glass Plant Comm Okay]
FROM Data
where DateDiff("n",now(), Data.[Date / Time] ) < 5;
You need something running continuously that generates a notification whenever expected data doesn't appear, and there's a couple of approaches you can take to do that.
One is to continuously run a query like the one you have above, checking the most recent date in the table against the value of the now() function.
Another approach is to take the latest date in your table, wait (sleep) for 5 minutes, and then check the table again for any newer entries. My expectation is that this approach will generate fewer hits on your table.
You could also just check the most recent date every 5 minutes regardless of the previous time checked and see if data hasn't come in.
You need to set up your notification loop first, then you can experiment with different approaches.
all you should really need to do is return the number of rows in the table whose timestamp is within 5 minutes of now(). You shouldn't need additional row detail, just is the count 0 or not?
The standard SQL aggregate function max() will return the highest value in a group; min() will return the lowest.
Is there an aggregate function in Oracle to return a random value from a group? Or some technique to achieve this?
E.g., given the table foo:
group_id value
1 1
1 5
1 9
2 2
2 4
2 8
The SQL query
select group_id, max(value), min(value), some_aggregate_random_func(value)
from foo
group by group_id;
might produce:
group_id max(value), min(value), some_aggregate_random_func(value)
1 9 1 1
2 8 2 4
with, obviously, the last column being any random value in that group.
You can try something like the following
select deptno,max(sal),min(sal),max(rand_sal)
from(
select deptno,sal,first_value(sal)
over(partition by deptno order by dbms_random.value) rand_sal
from emp)
group by deptno
/
The idea is to sort the values within group in random order and pick the first.I can think of other ways but none so efficient.
You might prepend a random string to the column you want to extract the random element from, and then select the min() element of the column and take out the prepended string.
select group_id, max(value), min(value), substr(min(random_value),11)
from (select dbms_random.string('A', 10)||value random_value,foo.* from foo)
In this way you cand avoid using the aggregate function and specifying twice the group by, which might be useful in a scenario where your query is very complicated / or you are just exploring the data and are entering manually queries with a lengthy and changing list of group by columns.