Unable to locate element by giving variable name inside XPATH - xpath

brand_name = 'LACOSTE'
element = browser.find_element_by_xpath("//*[text()= brand_name]")
This is giving error. However, if i do like this:
element = browser.find_element_by_xpath("//*[text()= 'LACOSTE']")
then element is found.
But i dont want to hardcode the value. Please help.enter image description here

The XPath needs apostrophe's around the search-string, so I think you need to concatenate the XPath expression like this
element = browser.find_element_by_xpath("//*[text()='" + brand_name + "']")

Related

Problems with '._ElementUnicodeResult'

While trying to help another user out with some question, I ran into the following problem myself:
The object is to find the country of origin of a list of wines on the page. So we start with:
import requests
from lxml import etree
url = "https://www.winepeople.com.au/wines/Dry-Red/_/N-1z13zte"
res = requests.get(url)
content = res.content
res = requests.get(url)
tree = etree.fromstring(content, parser=etree.HTMLParser())
tree_struct = etree.ElementTree(tree)
Next, for reasons I'll get into in a separate question, I'm trying to compare the xpath of two elements with certain attributes. So:
wine = tree.xpath("//div[contains(#class, 'row wine-attributes')]")
country = tree.xpath("//div/text()[contains(., 'Australia')]")
So far, so good. What are we dealing with here?
type(wine),type(country)
>> (list, list)
They are both lists. Let's check the type of the first element in each list:
type(wine[0]),type(country[0])
>> (lxml.etree._Element, lxml.etree._ElementUnicodeResult)
And this is where the problem starts. Because, as mentioned, I need to find the xpath of the first elements of the wine and country lists. And when I run:
tree_struct.getpath(wine[0])
The output is, as expected:
'/html/body/div[13]/div/div/div[2]/div[6]/div[1]/div/div/div[2]/div[2]'
But with the other:
tree_struct.getpath(country[0])
The output is:
TypeError: Argument 'element' has incorrect type (expected
lxml.etree._Element, got lxml.etree._ElementUnicodeResult)
I couldn't find much information about _ElementUnicodeResult), so what is it? And, more importantly, how do I fix the code so that I get an xpath for that node?
You're selecting a text() node instead of an element node. This is why you end up with a lxml.etree._ElementUnicodeResult type instead of a lxml.etree._Element type.
Try changing your xpath to the following in order to select the div element instead of the text() child node of div...
country = tree.xpath("//div[contains(., 'Australia')]")

Why doesn't this XPath query work as I assumed? (searching for elements with some # while excluding those with other #)

I have the following query (XPath 2.0):
//xref[contains(#href,'#') and #class='- topic/xref ' and #type!='step' and #type!='fig' and #type!='substep']
As you can see, I want to find topic/xref elements with a hash in their href attribute. I want to exclude ceratin types of elements.
Problem is, the above query does not display elements with #outputclass='expandable'
I had to run a seperate one to identify them:
//xref[contains(#href,'#') and #outputclass='expandable']
Why does the first, longer query, do not display those elements? I also tried contains(#class='- topic/xref ) instead of #class=' - topic/xref ' and it didn't help.
Try below XPath:
//xref[#class="- topic/xref " and contains(#href, "#") and not(#type=("fig", "substep", "table") or #outputclass="expandable")]
that will return xref elements with class="- topic/xref " and # in href attribute but doesn't have type attribute with values "fig", "substep", "table" or outputclass attribute with value "expandable"
You haven't shown your XML source, but I suspect you were expecting to retrieve elements having no #type attribute. However, the condition #type!='XYZ' is true only for an element that has an #type attribute whose value is something other than 'XYZ'. If my guess is correct, you intended not(#type='XYZ').

Use Datasource Properties in XPath Expression of SoapUI

I need to know whether it is possible to use a datasource property in XPath Expression panel of XPath Match Configuration. For instance, if we have the following XML document:
<ns1:Ions>
<ns1:Ion>UI</ns1:Ion>
<ns1:IonType>X</ns1:IonType>
<ns1:StartDate>2010-05-10</ns1:StartDate>
</ns1:Ions>
<ns1:Ions>
<ns1:Ion>HH</ns1:Ion>
<ns1:IonType>RI</ns1:IonType>
<ns1:StartDate>1998-11-23</ns1:StartDate>
</ns1:Ions>
<ns1:Ions>
<ns1:Ion>CF</ns1:Ion>
<ns1:IonType>A</ns1:IonType>
<ns1:StartDate>2000-06-10</ns1:StartDate>
</ns1:Ions>
I need to evaluate to see whether a content of IonType is 'A' only if its sibling node, Ion, has a value of 'CF'. I was hoping to accomplish this by setting XPath Match Configuration as following:
XPath Expression (DataSourceInput#ION is 'CF')
declare namespace ns1='http://my.namespace.com';
//ns1:Ions[ns1:Ion[text()=${DataSourceInput#ION}]]/ns1:IonType/text()
Expected Results (DataSourceInput#ION_TYPE is 'A')
${DataSourceInput#ION_TYPE}
Running the test would result in SoapUI [Pro] to error the following, Missing content for xpath declare. If I replace ${DataSourceInput#ION} with an actual value, i.e. 'CF', the test works accordingly (I even tried place single quotes around ${DataSourceInput#ION}, but it didn't work).
Is there another way of accomplish this in SoapUI?
I try what you do and it works for me if I put single quotes around the property:
declare namespace ns1='http://my.namespace.com';
//ns1:Ions[ns1:Ion[text()='${DataSourceInput#ION}']]/ns1:IonType/text()
Did you check that testStep name is exactly DataSourceInput? If there are spaces in the TestStep name (i.e your testStep name is Data Source Input you have to put ${Data Source Input#ION}).
Anyway I give you another way to do so, you can add a testStep of type groovy script after the testStep where you are getting the <Ions>response, and check the assert here like follows:
// get xml holder
def groovyUtils = new com.eviware.soapui.support.GroovyUtils(context);
def ionsHolder = groovyUtils.getXmlHolder("IonsTestStepName#response");
// generate xpath expression
def xpathExpression = "//*:Ions[*:Ion[text()='" + context.expand('${DataSourceInput#ION}') + "']]/*:IonType/text()";
log.info xpathExpression;
// get the node value
def nodeValue = ionsHolder.getNodeValue(xpathExpression);
// check expected value
assert nodeValue == context.expand('${DataSourceInput#ION_TYPE}'),'ERROR IONS VALUE';
Hope this helps,

Selenium WebDriver findElement(By.xpath()) not working for me

I've been through the xpath tutorials and checked many other posts, hence I'm not sure what I'm missing. I'm simply trying to find the following element by xpath:
<input class="t-TextBox" type="email" test-id="test-username"/>
I've tried many things, such as:
element = findElement(By.xpath("//[#test-id='test-username']"));
The error is Expression is not a legal expression.
I'm using Firefox on MacBook
Any suggestion would be greatly appreciated.
element = findElement(By.xpath("//*[#test-id='test-username']"));
element = findElement(By.xpath("//input[#test-id='test-username']"));
(*) - means any tag name.
You should add the tag name in the xpath, like:
element = findElement(By.xpath("//input[#test-id='test-username']");
your syntax is completely wrong....you need to give findelement to the driver
i.e your code will be :
WebDriver driver = new FirefoxDriver();
WebeElement element ;
element = driver.findElement(By.xpath("//[#test-id='test-username']");
// your xpath is: "//[#test-id='test-username']"
i suggest try this :"//*[#test-id='test-username']"
You missed the closing parenthesis at the end:
element = findElement(By.xpath("//[#test-id='test-username']"));
Just need to add * at the beginning of xpath and closing bracket at last.
element = findElement(By.xpath("//*[#test-id='test-username']"));
You can use contains too:
element = findElement(By.xpath("//input[contains (#test-id,"test-username")]");
You haven't specified what kind of html element you are trying to do an absolute xpath search on. In your case, it's the input element.
Try this:
element = findElement(By.xpath("//input[#class='t-TextBox' and #type='email' and #test-
id='test-username']");
Correct Xpath syntax is like:
//tagname[#value='name']
So you should write something like this:
findElement(By.xpath("//input[#test-id='test-username']"));

Selenium Webdriver + Ruby regex: Can I use regex with find_element?

I am trying to click an element that changes per each order like so
edit_div_123
edit_div_124
edit_div_xxx
xxx = any three numbers
I have tried using regex like so:
#driver.find_element(:css, "#edit_order_#{\d*} > div.submit > button[name=\"commit\"]").click
#driver.find_element(:xpath, "//*[(#id = "edit_order_#{\d*}")]//button").click
Is this possible? Any other ways of doing this?
You cannot use Regexp, like the other answers have indicated.
Instead, you can use a nifty CSS Selector trick:
#driver.find_element(:css, "[id^=\"edit_order_\"] > div.submit > button[name=\"commit\"]").click
Using:
^= indicates to find the element with the value beginning with your criteria.
*= says the criteria should be found anywhere within the element's value
$= indicates to find the element with with your criteria at the end of the value.
~= allows you to find the element based on a single criteria when the actual value has multiple space-seperated list of values.
Take a look at http://net.tutsplus.com/tutorials/html-css-techniques/the-30-css-selectors-you-must-memorize/ for some more info on other neat CSS tricks you should add to your utility belt!
You have no provided any html fragment that you are working on. Hence my answer is just based on the limited inputs provided your question.
I don't think WebDriver APIs support regex for locating elements. However, you can achieve what you want using just plain XPath as follows:
//*[starts-with(#id, 'edit_div_')]//button
Explanation: Above xpath will try to search all <button> nodes present under all elements whose id attribute starts with string edit_div_
In short, you can use starts-with() xpath function in order to match element with id format as edit_div_ followed by any number of characters
No, you can not.
But you should do something like this:
function hasClass(element, className) {
var re = new RegExp('(?:^|\\s+)' + className + '(?:\\s+|$)');
return re.test(element.className);
}
This worked for me
#driver.find_element(:xpath, "//a[contains(#href, 'person')]").click

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