I have a logical issue, trying to do a nested for loop for a fpöder which holds two subfolders with code files in it.
for folder in $(twofolders); do \
for file in $$folder; do \
zip -j $$file"_lambda.zip" $(PYTHONPATH)/$$file/*.py; \
aws s3 cp ./$$file"_lambda.zip" s3://$(S3_BUCKET)/$(SOURCE_CODE_VERSION)/lambda/; \
done
done
But I receive the following error
/bin/bash: -c: line 5: syntax error: unexpected end of file
make: *** [Makefile:62: build] Error 1
Anyone knows what Iam doing wrong?
You forgot a line continuation after the first done. And you should definitely double-quote bash and make variable expansions:
target: prerequisites
for folder in $(twofolders); do \
for file in "$$folder"; do \
zip -j "$${file}_lambda.zip" "$(PYTHONPATH)/$$file"/*.py; \
aws s3 cp ./"$${file}_lambda.zip" s3://"$(S3_BUCKET)/$(SOURCE_CODE_VERSION)"/lambda/; \
done \
done
Related
I'm trying to run the LiteCart bash installer script located here:
https://github.com/litecart/installer/tree/master/cli
Unfortunately, it's giving me a problem when I add preset arguments like this:
--document_root=/var/www/litecart/public_html \
--db_server=localhost \
--db_user=johndoe \
--db_password=mycatsname \
--db_database=mylitecartdb \
--db_prefix=lc_ \
--timezone=Europe/London \
--admin_folder=admin \
--admin_user=admin \
--admin_password=mydogsname \
--development_type=standard
I keep getting:
Error: Invalid argument (--document_root=/var/www/litecart/public_html)
My computer is running MacOS 10.15 and the server is running CentOS 7.9. The script runs fine without the arguments.
I can't find anything that even resembles this situation here. What's the proper way to run a script like this? Thanks.
Script contains no case for --document_root.
Try:
export document_root="/var/www/litecart/public_html"
./install.sh --db_server=localhost \
--db_user=johndoe \
--db_password=mycatsname \
--db_database=mylitecartdb \
--db_prefix=lc_
I assume that there are more problems in the script.
I want to be able to specify a directory with fastq files with a script that will loop through all the files and do some stuff. Here is my attempt:
threads=24
current_path=`pwd`
input_file=${current_path}/raw/
files=${current_path}/raw/*
for file in ${files}; do
output_file=${current_path}/${file}_out/
mkdir -m gu=wrx,o=rx ${output_file}
spades.py \
--s1 ${input_file}${file} \
-t ${threads} \
--plasmid \
--careful \
-o ${output_file}
done
So in this script I get an error: cannot make directory, directory does not exist The script generates a /home folder. I don't know if I am specifying the files incorrectly or if I am using the for loop incorrectly.
Thank you!
you concatenate full path to file with folder in line
output_file=${current_path}/${file}_out/
it should be
output_file=${file}_out/
I'm trying to make a Makefile that exports a markdown file to a pdf file that uses the same filename as the original markdown file. I used "basename" command but it produces "inputfile.md.pdf" instead of "inputfile.pdf".
Please see my code below (I adapted a code I found on the Internet. Thank you!):
.PHONY: pdf docx apa format
FILES := $(wildcard ./*.md)
pdf:
for file in $(FILES); do \
pandoc $$file \
--bibliography mypath \
--csl mypath \
--filter pandoc-citeproc \
--template eisvogel \
-o $(basename $$file).pdf; \
open $(basename $$file).pdf; \
done
Anyone who can help me? I'm a novice in Makefile (and programming in general) so any detailed help would be very much appreciated.
I also tried these codes below, but they generated an error message:
-o $(basename -s ".md" $$file).pdf; \
-o $(basename -s .md $$file).pdf; \
The way you write $(basename …) you get the basename make function. This would normally the right thing, but you try to reference a shell variable file in its argument, which is unavailable at the make layer.
In this case, it is probably easiest to call the basename shell utility, at the shell level. Therefore, you need to escape the $ to get shell substitution, like this:
-o "$$(basename -s .md $$file)".pdf; \
open "$$(basename -s .md $$file)".pdf; \
Alternatively, you could try to move the loop to the make layer, perhaps using foreach.
I have this bash script code:
#!/bin/bash
FILES=/home/user/Downloads/asd/
for f in $FILES
do
curl -F dir="#/home/user/Downloads/asd;$f" -F Match=3 -F "Name=DrKla" \
-F countNo=1 -F outputFormat=json "http://somelink.com"
done
Inside the asd folder there are 6 files and I want them to be uploaded 1 by 1 with this code as an argument of -F "dir=#...."
When I run my code I get the error:
Warning: skip unknown form field: /home/user/Downloads/asd/
curl: (43) A libcurl function was given a bad argument
Here is a working version of the code for a single file:
curl -F dir="#/home/user/Downloads/asd/count.txt" -F Match=3 -F "Name=DrKla" \
-F countNo=1 -F outputFormat=json "http://somelink.com"
So I want to have all the files in asd folder to be read and uploaded like this. I don't see what's wrong with my do loop.
The issues appear to be that you only give a path, not a reference to all files in the path * and there is a strange semi-colon ; in your path:
#!/bin/bash
FILES=/home/user/Downloads/asd/*
for f in $FILES
do
curl -F dir="#$f" -F Match=3 -F "Name=DrKla" \
-F countNo=1 -F outputFormat=json "http://somelink.com"
done
I'm not sure what the # is for or if it is needed, but $f should already contain the path.
I compiled the source code with the Makefile, I got Makefile Error:
/bin/sh: line 8: : command not found
make: *** [lib_build] Error 127
My lib_build target is as below:
lib_build:
#echo "--------------------------------------------------------------------";
#echo "VZW Compiling DM Agent 3rd party and native Libraries..." ;
#echo "--------------------------------------------------------------------";
mkdir -p $(VZW_LIB_DIR) ; \
mkdir -p $(VZW_BIN_DIR) ; \
mkdir -p $(VZW_SCR_DIR) ; \
mkdir -p $(VZW_CFG_DIR) ; \
mkdir -p $(VZW_OBJ_DIR) ; \
mkdir -p $(VZW_LOG_DIR) ; \
cd $(VZW_BASE_DIR)/lib/ ; \
make all ; \
cd $(VZW_SYNCML_DIR)/src/bld/linux ; \
make all;
cp -r $(VZW_SYNCML_DIR)/bin/linux/libsml.so $(VZW_LIB_DIR) ;
cp -r $(VZW_SYNCML_DIR)/bin/linux/libxpt.so $(VZW_LIB_DIR) ;
cp -r $(VZW_BASE_DIR)/3rd_party/iksemel-1.4/src/.libs/* $(VZW_LIB_DIR) ;
It was working fine then I try to modify some line in the above source code and later reverted everything. Then something went wrong and I got the error. I am not able to understand what went wrong.
One more thing to add here. Is there any way to know in which line exactly in the Makefile this kind of problem is happening. If there is no way then it is very difficult to spot these kind of problems.
I would suggest restructuring the commands. As the rule is written, it ignores all errors because this is how shell works. At least prepend set -e to this sequence of shell commands.
A lot more mind-tweaking to find if any syntactical mistake is there, I found the solution that there was a space after a line in Makefile ie. after the "/"
cd $(VZW_SYNCML_DIR)/src/bld/linux ; \
This was very difficult to spot though as spaces are not visible.