Can this simple Makefile support cross-compilation? - makefile

I have a very simple Makefile:
override CFLAGS+=-Wall -g
OBJS=myobj.o
all: mymain
mymain: $(OBJS)
myobj.o: myheader1.h myheader2.h
It works perfectly on a target system, but can I somehow pass it some arguments to not compile with gcc but with mypreferred-gcc?
Or I have to introduce some extra CC parameters and I have to build the compilation line in the Makefile to do this?

Related

Creating multiple executables in Makefile

Im fairly new to makefiles. I want to compile multiple executables through my makefile, and it was to my understanding that having a target with multiple entries would run the recipe for that target through all entries. My example is:
$(EXE): $(OBJS)
g++ -o $# $< -L$(LIBPATH) -lOSApi -lrt -lpthread
My EXE variable contains all files that should be created, something like: prog1 prog2 and so on. My OBJS contains prog1.o prog2.o and so on.
When running make i create all .o files perfectly, but i only create one executable. I have tried replacing $# with $(EXE) and such, but no luck so far.
Any help would be appreciated.
EDIT:
I found the solution through MadScientist, who suggested to add an all target, and then changing my executable target to:
$(EXE): % : %.o
g++ -o $# $< -L$(LIBPATH) -lOSApi -lrt -lpthread
.PHONY: all clean
all: $(EXE)
Which to my understanding makes every target in my EXE target dependant on its corresponding .o file.
It would help greatly if you provided a full (small) sample. In the question you don't show us what the definition of EXE or OBJS is which makes it hard to say exactly.
Also, please be sure to format your question correctly.
By default make only builds the FIRST target in the makefile. It doesn't build ALL the targets in the makefile. So, if EXE contains multiple targets and the first rule in your makefile is $(EXE) : ... then only the first target in that list will be built.
You should add a new target before the above, saying that you want the default to build all the exe's. You can call it anything you like but the convention is to call it all:
all: $(EXES)
(you can also add a .PHONY: all for safety). Now the first target in the makefile is all, and as prerequisites it will build all the targets in the EXES variable.

Cannot pass flags to Makefile to compile my code

I have a project that basically compiles from the command line in the following form:
g++ -o stack_raster stack_raster.cpp -lgdal -lboost_filesystem -lboost_system
I made a Makefile, and this is the content:
CXX =g++
LDDFLAGS = -lgdal -lboost_system -lboost_filesystem
all: clean stack_raster
clean:
rm -f stack_raster
However I got a collect2: error: ld returned 1 exit status.
A second variation of my Makefile I tried was:
CXX = g++
CPPFLAGS = -lgdal -lboost_system -lboost_filesystem
all: clean stack_raster
clean:
rem -f stack_raster
but I still receive the following message (even though the compile flags appear as they should for my program to compile successfully).
collect2: error: ld returned 1 exit status
<builtin>: recipe for target `stack_raster` failed
make: *** [stack_raster] Error 1
Does anyone could help me with a reference or hint about my problem, and how could I tackle it?
Does anyone could help me with a reference or hint about my problem, and how could I tackle it?
To begin with, you should have a look at the actual link command that make executed. It should have been echoed to make's output just before the error message from collect2. Understanding what's wrong with the command is the first step in determining how to fix your makefile.
In the first case, the command is probably something like
g++ stack_raster.cpp -o stack_raster
In the second, it is probably something like
g++ -lgdal -lboost_system -lboost_filesystem stack_raster.cpp -o stack_raster
The latter is probably also very similar to what you would get with the first makefile if you corrected the spelling of LDDFLAGS to LDFLAGS.
You will note that the library flags come in a different place in that command than they do in your manual command, and I assume you know that the order of objects and library flags on the linker command line is significant to Unix-style linkers such as GNU's (which is the one that the g++ driver will use).
You can certainly fix this by writing an explicit rule, as you describe in your own answer, but your makes' built-in rules may be up to the task, too. If you are using GNU make then they certainly are. For this purpose it is useful to know what the built-in rules actually are, and essential to know what the variables on which these rules depend mean.
Specifically,
LDFLAGS provides options to pass when invoking the linker, and conventionally, they appear on the command line before the objects being linked. As a result, this variable typically is not appropriate for specifying libraries (but it is fine for other link-specific options, such as -L to add directories to the library search path).
CPPFLAGS provides options for modulating the behavior of the C preprocessor (including when compiling C++). These do not typically appear at all in link(-only) commands executed by make, but they will appear (early) in commands for compiling object files from C or C++ sources, and in rules for building executables directly from C or C++ sources.
Neither of those is what you want, but if you are using GNU make, then its documentation for the former explicitly tells you what (with that make implementation) you should do instead:
Extra flags to give to compilers when they are supposed to invoke the
linker, ‘ld’, such as -L. Libraries (-lfoo) should be added to the
LDLIBS variable instead.
(emphasis added)
In GNU make, and perhaps some others, the LDLIBS variable serves exactly the purpose you need: to specify the libraries to link. These will appear at the end of the link command line from built-in rules, as you can confirm from GNU make's catalog of implicit rules, or from the list obtainable by running make -p in a directory containing no makefile.
So, with GNU make you can get the build you seem to want from the built-in rules, with this:
CXX = g++
LDLIBS = -lgdal -lboost_system -lboost_filesystem
all: clean stack_raster
clean:
rm -f stack_raster
In closing, I note that cleaning before building by default, as your examples do and mine imitates, largely defeats the purpose of using make instead of a simple script. Part of the point of make is to do the minimum work necessary, and if your target executable is present and not out of date with respect to its sources then there is no reason to force it to be rebuilt.
Check out the answer:
Set up my makefile to compile C with just "make"
YOu have to specify in the Makefile the file you want to create in this case stack_raster.exe and the objective file in this case stack_raster.cpp and specify the command line arguments you normally pass for compiling. So the Makefile would be something like:
CXX=g++
stack_raster.exe: stack_raster.cpp
g++ -o stack_raster.exe stack_raster.cpp -lgdal -lboost_filesystem -lboost_system
all: clean stack_raster.exe
clean:
rm -f stack_raster.exe

Default link script in GNU Make

I have this very simple makefile:
P = hello_world.exe
OBJECTS = main.o
CFLAGS = -g -Wall -O3
LDLIBS =
CC = clang
$(P): $(OBJECTS)
When I run make it will compile main.c but it will not link to hello_world.exe. Shouldn't that be happening automatically?
My environment is cygwin 64bit.
The output of make -p is here: http://pastebin.com/qbr0sRXL
There's no default rule for .exe files that I'm aware of (or can find in that output).
You'll need to write one yourself.
If your output was hello_world and you had a hello_world.c/hello_world.cpp source file and also a main.c/main.cpp file then your makefile as written would work I believe (since the default %: %.o rule would apply and your added prerequisite would be added to the hello_world prerequisite list).

Cmake vs make sample codes?

I was wondering if there was any sample code for Makefiles (make) and CMakeLists.txt (cmake) that both do the same thing (the only difference being that one is written in make and the other in cmake).
I tried looking for 'cmake vs make', but I never found any code comparisons. It would be really helpful to understand the differences, even if just for a simple case.
The following Makefile builds an executable named prog from the sources
prog1.c, prog2.c, prog3.c and main.c. prog is linked against libmystatlib.a
and libmydynlib.so which are both also built from source. Additionally, prog uses
the library libstuff.a in stuff/lib and its header in stuff/include. The
Makefile by default builds a release target, but offers also a debug target:
#Makefile
CC = gcc
CPP = g++
RANLIB = ar rcs
RELEASE = -c -O3
DEBUG = -c -g -D_DEBUG
INCDIR = -I./stuff/include
LIBDIR = -L./stuff/lib -L.
LIBS = -lstuff -lmystatlib -lmydynlib
CFLAGS = $(RELEASE)
PROGOBJS = prog1.o prog2.o prog3.o
prog: main.o $(PROGOBJS) mystatlib mydynlib
$(CC) main.o $(PROGOBJS) $(LIBDIR) $(LIBS) -o prog
debug: CFLAGS=$(DEBUG)
debug: prog
mystatlib: mystatlib.o
$(RANLIB) libmystatlib.a mystatlib.o
mydynlib: mydynlib.o
$(CPP) -shared mydynlib.o -o libmydynlib.so
%.o: %.c
$(CC) $(CFLAGS) $(INCDIR) $< -o $#
%.o: %.cpp
$(CPP) $(CFLAGS) $(INCDIR) -fPIC $< -o $#
Here is a CMakeLists.txtthat does (almost) exactly the same, with some comments to underline the
similarities to the Makefile:
#CMakeLists.txt
cmake_minimum_required(VERSION 2.8) # stuff not directly
project(example) # related to building
include_directories(${CMAKE_SOURCE_DIR}/stuff/include) # -I flags for compiler
link_directories(${CMAKE_SOURCE_DIR}/stuff/lib) # -L flags for linker
set(PROGSRC prog1.c prog2.c prog3.c) # define variable
add_executable(prog main.c ${PROGSRC}) # define executable target prog, specify sources
target_link_libraries(prog mystatlib mydynlib stuff) # -l flags for linking prog target
add_library(mystatlib STATIC mystatlib.c) # define static library target mystatlib, specify sources
add_library(mydynlib SHARED mydynlib.cpp) # define shared library target mydynlib, specify sources
#extra flags for linking mydynlib
set_target_properties(mydynlib PROPERTIES POSITION_INDEPENDENT_CODE TRUE)
#alternatively:
#set_target_properties(mydynlib PROPERTIES COMPILE_FLAGS "-fPIC")
In this simple example, the most important differences are:
CMake recognizes which compilers to use for which kind of source. Also, it
invokes the right sequence of commands for each type of target. Therefore, there
is no explicit specification of commands like $(CC) ..., $(RANLIB) ... and so on.
All usual compiler/linker flags dealing with inclusion of header files, libraries, etc.
are replaced by platform independent / build system independent commands.
Debugging flags are included by either setting the variable CMAKE_BUILD_TYPE to "Debug",
or by passing it to CMake when invoking the program: cmake -DCMAKE_BUILD_TYPE:STRING=Debug.
CMake offers also the platform independent inclusion of the '-fPIC' flag (via
the POSITION_INDEPENDENT_CODE property) and many others. Still, more obscure settings can be implemented by hand in CMake just as well as in a Makefile (by using COMPILE_FLAGS
and similar properties). Of course CMake really starts to shine when third party
libraries (like OpenGL) are included in a portable manner.
The build process has one step if you use a Makefile, namely typing make at the command line. For CMake, there are two steps: First, you need to setup your build environment (either by typing cmake <source_dir> in your build directory or by running some GUI client). This creates a Makefile or something equivalent, depending on the build system of your choice (e.g. make on Unixes or VC++ or MinGW + Msys on Windows). The build system can be passed to CMake as a parameter; however, CMake makes reasonable default choices depending on your system configuration. Second, you perform the actual build in the selected build system.
Sources and build instructions are available at https://github.com/rhoelzel/make_cmake.
Grab some software that uses CMake as its buildsystem (there's plenty of opensource projects to choose from as an example). Get the source code and configure it using CMake. Read resulting makefiles and enjoy.
One thing to keep in mind that those tools don't map one-to-one. The most obvious difference is that CMake scans for dependencies between different files (e.g. C header and source files), whereas make leaves that to the makefile authors.
If this question is about a sample Makefile output of the CMakeList.txt file then please check the cmake-backend sources and generate one such Makefile. If it is not then adding to the reply of #Roberto I am trying to make it simple by hiding the details.
CMake function
While Make is flexible tool for rules and recipe, CMake is a layer of abstraction that also adds the configuration feature.
My plain CMakeLists.txt will look like the following,
cmake_minimum_required(VERSION 2.8)
project(example)
file(GLOB testapp_SOURCES *.cc)
add_executable(testapp ${testapp_SOURCES})
Note, that CMake hides how the build can be done. We only specified what is the input and output.
The CMakeLists.txt contains list of function-calls that are defined by cmake.
(CMake function) Vs Make rules
In Makefile the rules and recipes are used instead of functions . In addition to function-like feature, rules and recipes provide chaining. My minimalistic Makefile will look like the following,
-include "executable.mk"
TARGETS=testapp.bin
all:${TARGETS}
While the executable.mk will look like the following,
SOURCES=$(wildcard *.cpp)
OBJECTS=$(SOURCES:.cpp=.o)
DEPS=$(SOURCES:.cpp=.d)
%.bin:$(OBJECTS)
$(CC) $(CFLAGS) -o $# $^ $(LFLAGS) $(LIBS)
.PHONY: all clean
clean:
$(RM) $(OBJECTS) $(DEPS) $(TARGETS)
-include $(DEPS)
Starting from the scratch I shall start with a Makefile like the following,
all: testapp.bin
testapp.bin:sourcea.o sourcb.o
$(CC) $(CFLAGS) -o $# $^ $(LFLAGS) $(LIBS)
.PHONY: all clean
clean:
$(RM) $(OBJECTS) testapp.bin
I got this snippet from here and modified it. Note that some implicit-rules are added to this file which can be found in the makefile-documentation. Some implicit variables are also relevant here.
Note, that Makefile provides the detail recipe showing how the build can be done. It is possible to write executable.mk to keep the details defined in one file. In that way the makefile can be reduced as I showed earlier.
Internal Variables in CMake and Make
Now getting little advanced, in CMake we can set a compiler flag like the following,
set(CMAKE_C_FLAGS "-Wall")
Please find out more about CMake default variables in CMakeCache.txt file.
The CMake code above will be equivalent to Make code below,
CFLAGS = -Wall
Note that CFLAGS is an internal variable in Make, the same way, CMAKE_C_FLAGS is internal variable in CMake .
adding include and library path in CMake
We can do it in cmake using functions.
target_include_directories(testapp PRIVATE "myincludes")
list(APPEND testapp_LIBRARIES
mytest mylibrarypath
)
target_link_libraries(testapp ${testapp_LIBRARIES})
Vs adding include and library path in Make
We can add include and libraries by adding lines like the following,
INCLUDES += -Imyincludes
LIBS += -Lmylibrarypath -lmytest
Note this lines above can be generated from auto-gen tools or pkg-config. (though Makefile is not dependent of auto-config tools)
CMake configure/tweek
Normally it is possible to generate some config.h file just like auto-config tools by using configure_file function. It is possible to do more trick writing custom functions. And finally we can select a config like the following,
cmake --build . --config "Release"
It is possible to add some configurable option using the option function.
Makefile configure/tweak
If somehow we need to compile it with some debug flag, we can invoke the make like,
make CXXFLAGS=NDEBUG
I think internal variables, Makefile-rules and CMake-functions are good start for the comparison, good luck with more digging.

Compiling with different flags in Makefile?

I have a single program used to interact with a joystick. It uses conditional compilation to specify a specific joystick. We do this right now by just hard coding the correct flag into the Makefile.
I'd like to make it so it uses a different flag based on the command given to the Makefile. So for example, I currently have this:
.PHONY: saitek
saitek: $(SOURCES)
$(COMPILE) -DSAITEK
.PHONY: logitech
logitech: $(SOURCES)
$(COMPILE) -DLOGITECH
I want only one of these commands to ever be run, and I want them all to make the same executable. But if I rerun 'make' it will compile the program again. I'd like it to recognize that it's already built the program.
Is there anyway to do this with a Makefile?
If you're using GNUMake, this will do what you're asking. It uses a different flag based on the command given to Make, and it doesn't rebuild the program unnecessarily.
.PHONY: saitek logitech
saitek: JOYSTICK=SAITEK
logitech: JOYSTICK=LOGITECH
# Suppose the actual name of your executable is "program"
saitek logitech: program
program: $(SOURCES)
$(COMPILE) -D$(JOYSTICK)
GNU make inherits variables from its environment, so if you specify
$ JOYSICK=LOGITECH
in your shell, and use
CFLAGS+=-D$(JOYSTICK)
in your makefile.
I question the necessity of this. You could just call make as something like make CFLAGS=-DSAITEK or use autoconf and substitute in the correct defines.
That said, how about something like this:
saitek logitech: program
.PHONY: saitek logitech
ifeq ($(MAKECMDGOALS),saitek)
CFLAGS += -DSAITEK
endif
ifeq ($(MAKECMDGOALS),logitech)
CFLAGS += -DLOGITECH
endif
program: $(OBJS)
# Whatever

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