Cannot pass flags to Makefile to compile my code - makefile

I have a project that basically compiles from the command line in the following form:
g++ -o stack_raster stack_raster.cpp -lgdal -lboost_filesystem -lboost_system
I made a Makefile, and this is the content:
CXX =g++
LDDFLAGS = -lgdal -lboost_system -lboost_filesystem
all: clean stack_raster
clean:
rm -f stack_raster
However I got a collect2: error: ld returned 1 exit status.
A second variation of my Makefile I tried was:
CXX = g++
CPPFLAGS = -lgdal -lboost_system -lboost_filesystem
all: clean stack_raster
clean:
rem -f stack_raster
but I still receive the following message (even though the compile flags appear as they should for my program to compile successfully).
collect2: error: ld returned 1 exit status
<builtin>: recipe for target `stack_raster` failed
make: *** [stack_raster] Error 1
Does anyone could help me with a reference or hint about my problem, and how could I tackle it?

Does anyone could help me with a reference or hint about my problem, and how could I tackle it?
To begin with, you should have a look at the actual link command that make executed. It should have been echoed to make's output just before the error message from collect2. Understanding what's wrong with the command is the first step in determining how to fix your makefile.
In the first case, the command is probably something like
g++ stack_raster.cpp -o stack_raster
In the second, it is probably something like
g++ -lgdal -lboost_system -lboost_filesystem stack_raster.cpp -o stack_raster
The latter is probably also very similar to what you would get with the first makefile if you corrected the spelling of LDDFLAGS to LDFLAGS.
You will note that the library flags come in a different place in that command than they do in your manual command, and I assume you know that the order of objects and library flags on the linker command line is significant to Unix-style linkers such as GNU's (which is the one that the g++ driver will use).
You can certainly fix this by writing an explicit rule, as you describe in your own answer, but your makes' built-in rules may be up to the task, too. If you are using GNU make then they certainly are. For this purpose it is useful to know what the built-in rules actually are, and essential to know what the variables on which these rules depend mean.
Specifically,
LDFLAGS provides options to pass when invoking the linker, and conventionally, they appear on the command line before the objects being linked. As a result, this variable typically is not appropriate for specifying libraries (but it is fine for other link-specific options, such as -L to add directories to the library search path).
CPPFLAGS provides options for modulating the behavior of the C preprocessor (including when compiling C++). These do not typically appear at all in link(-only) commands executed by make, but they will appear (early) in commands for compiling object files from C or C++ sources, and in rules for building executables directly from C or C++ sources.
Neither of those is what you want, but if you are using GNU make, then its documentation for the former explicitly tells you what (with that make implementation) you should do instead:
Extra flags to give to compilers when they are supposed to invoke the
linker, ‘ld’, such as -L. Libraries (-lfoo) should be added to the
LDLIBS variable instead.
(emphasis added)
In GNU make, and perhaps some others, the LDLIBS variable serves exactly the purpose you need: to specify the libraries to link. These will appear at the end of the link command line from built-in rules, as you can confirm from GNU make's catalog of implicit rules, or from the list obtainable by running make -p in a directory containing no makefile.
So, with GNU make you can get the build you seem to want from the built-in rules, with this:
CXX = g++
LDLIBS = -lgdal -lboost_system -lboost_filesystem
all: clean stack_raster
clean:
rm -f stack_raster
In closing, I note that cleaning before building by default, as your examples do and mine imitates, largely defeats the purpose of using make instead of a simple script. Part of the point of make is to do the minimum work necessary, and if your target executable is present and not out of date with respect to its sources then there is no reason to force it to be rebuilt.

Check out the answer:
Set up my makefile to compile C with just "make"
YOu have to specify in the Makefile the file you want to create in this case stack_raster.exe and the objective file in this case stack_raster.cpp and specify the command line arguments you normally pass for compiling. So the Makefile would be something like:
CXX=g++
stack_raster.exe: stack_raster.cpp
g++ -o stack_raster.exe stack_raster.cpp -lgdal -lboost_filesystem -lboost_system
all: clean stack_raster.exe
clean:
rm -f stack_raster.exe

Related

Run two instances of the same C++ program simultaneously

I've got a C++ program with a Makefile, building (g++) and running on Windows cmd. Thing is, sometimes it takes a while to run and save the results, and I want to run it with different parameters at the same time so that I can do something else while I wait for the first instance to finish. It doesn't work though, because of the executable I guess:
>make
g++ -c -o main.o main.cpp
Assembler messages:
Fatal error: can't create main.o: Permission denied
make: *** [main.o] Error 1
You have two problems: The one you ask about, and the reason you ask this question in the first place.
Lets start with the problem you have...
Judging by the Makefile you show, you have it all wrong.
Rules are in the format
target: sources_the_target_depend_on
The target is usually a file that need to be created. For an object file that is the name of the actual object file itself. The source files that the object files then depend on should be on the right-hand side.
To take an example from you Makefile (before you edited it away):
graph2: graph2.o
g++ -g -c graph.cpp -o graph2.o
Here you tell make that the file graph2 depends on the file graph2.o, and then it creates the graph2.o file. That's wrong. The rule should be that the file graph2.o depends om the file graph.cpp and go on to generate the file graph2.o:
graph2.o: graph.cpp
g++ -g -c graph.cpp -o graph2.o
This indirectly leads to the problem you have, with this line (deduced from your error and the Makefile):
main: main.o utils.o graph.o heuristics.o
g++ -g main.cpp -o main.o utils.o graph.o heuristics.o
This contains the same error as discussed above: You say that the file main depends on main.o and then the rule create main.o. Your rule should be
main: main.cpp utils.o graph.o heuristics.o
g++ -g main.cpp -o main utils.o graph.o heuristics.o
Note also how I no longer name the executable file main.o, as that is supposed to be used for object files.
Now lets continue with the reason you have the problem in the first place: That you need to edit the code to change data or values.
This is a problem that you need to solve. One common way to solve it is through command line arguments. If your program parses the command line arguments passed to your program you can pass it the values that could change from run to run.
How to do this is whole chapter on its own, so I wont give you any more details. There are plenty of tutorials online.
Lastly, you can simplify your Makefile considerably, by using implicit rules and variables.
I would simply create the Makefile to look something like this
# The compiler to use
CXX = g++
# Flags to pass to the compiler (add warnings when building)
CXXFLAGS = -Wall
# The main executable file to generate
TARGET = main
# List the object files needed to generate the main executable file
OBJECTS = main.o utils.o graph.o heuristics.o
# The all target depends on your main executable file
# Also as the first target in the Makefile, if no specific target is specified
# this will be the one that is used (it's the "default" target for the Makefile)
all: $(TARGET)
# The main executable file depends on the object files
$(TARGET): $(OBJECTS)
This is really it. the object files will be built automatically from their respective source files, and then the executable program will be linked using the object files listed.

Trouble with simple makefile in C

I am somewhat of a beginner in C and have a project due where I need to include a makefile to compile my single file program that uses pthreads and semaphores. My makefile looks like:
# Makefile for pizza program
pizza: pizza.o
gcc -lrt -lpthread -g -o pizza pizza.o
pizza.o: pizza.c
gcc -lrt -lpthread -g -c pizza.o pizza.c
and I keep getting:
make: Nothing to be done for 'Makefile'.
I have done several makefiles before and have never gotten this message. I've tried different semantics in the makefile and have only gotten this same message. And yes, the command is tabbed after the target and dependency line.
Using gcc on tcsh. I have read other makefile posts on SO but I wasn't able to use any of the answers to figure it out for my case.
Any help would be greatly appreciated!
The arguments to make are the targets to be built.
You are running make Makefile which is telling make to try to build the Makefile target.
There is no such target in your makefile, make has no built-in rule that applies to that target and the file exists (and is assumed to be up-to-date) which is what that message is telling you.
To run the default target (by default the first target listed) you can just run make (assuming you are using a default name like Makefile for your makefile).
You can also use the -f argument to make to select an alternate makefile name.
So make -f Makefile will in this case (since Makefile is a default searched name) do the same thing as make.

make command with math library

I need to just run the make command for makefile. But when I run this make command I get the error that "undefined reference to `log'" because I know this fact that it doesn't include math Library and we have to include at runtime. I know that if I run this using gcc comiler then i can write -lm at the end, it will include math library. My problem is I need to run it using make command that is- make lu.
In this if I write make lu -lm it is not linking math library. Please help
Using this link How to use LDFLAGS in makefile
I updated my make file but still same problem persists. Please Help.
SHELL=/bin/sh
BENCHMARK=ep
BENCHMARKU=EP
include ../config/make.def
OBJS = ep.o ${COMMON}/c_print_results.o ${COMMON}/c_${RAND}.o \
${COMMON}/c_timers.o ${COMMON}/c_wtime.o
include ../sys/make.common
LDLIBS=-lm
LDFLAGS=-lm
${PROGRAM}: config ${OBJS}
${CLINK} ${CLINKFLAGS} -o ${PROGRAM} $(LDFLAGS) $(LOADLIBES) ${OBJS} ${C_LIB}
ep.o: ep.c npbparams.h
${CCOMPILE} ep.c
clean:
- rm -f *.o *~
- rm -f npbparams.h core
Why does your makefile refer to all sorts of variables that don't exist, like LOADLIBES, C_LIB? Why do you set variables that you never use, like LDLIBS?
The reason it doesn't work is that you're putting the library reference in the LDFLAGS variable, which comes early in your link command before any of your object files. So when the linker goes to link in the math library it thinks that it's not needed because nothing is using it yet.
You have to put libraries at the end of the link line.
Since you already have the C_LIB variable at the end which you are not using, if you add:
C_LIB = -lm
then it should work.

make target depends on execution

I want my make target to be dependent on execution file. For example I have simple makefile:
a.out: test.cpp
gcc test.cpp
I want something like that:
a.out: test.cpp, `which gcc`
gcc test.cpp
It means that changing your gcc (in particular updating) will lead rebuilding of a.out (even if test.cpp wasn't changed).
But it looks like unshapely solution, because you should add one more prerequisite for each rule each used in this rule tool.
Is there other solutions of this problem?
In a GNU make makefile, you could use:
CC := $(shell which gcc)
a.out: test.cpp ${CC}
${CC} -o $# test.cpp
Note that the build would only trigger if the compiler executable was modified, not simply because it was different from last time the program was built. Historically, SUN make had a '.make.state' file and a .KEEP_STATE target which kept track of such things. IBM Rational ClearCase has a clearmake that also tracks such issues if you choose to make it do so.

CFLAGS vs CPPFLAGS

I understand that CFLAGS (or CXXFLAGS for C++) are for the compiler, whereas CPPFLAGS is used by the preprocessor.
But I still don't understand the difference.
I need to specify an include path for a header file that is included with #include -- because #include is a preprocessor directive, is the preprocessor (CPPFLAGS) the only thing I care about?
Under what circumstances do I need to give the compiler an extra include path?
In general, if the preprocessor finds and includes needed header files, why does it ever need to be told about extra include directories? What use is CFLAGS at all?
(In my case, I actually found that BOTH of these allow me to compile my program, which adds to the confusion... I can use CFLAGS OR CPPFLAGS to accomplish my goal (in autoconf context at least). What gives?)
The implicit make rule for compiling a C program is
%.o:%.c
$(CC) $(CPPFLAGS) $(CFLAGS) -c -o $# $<
where the $() syntax expands the variables. As both CPPFLAGS and CFLAGS are used in the compiler call, which you use to define include paths is a matter of personal taste. For instance if foo.c is a file in the current directory
make foo.o CPPFLAGS="-I/usr/include"
make foo.o CFLAGS="-I/usr/include"
will both call your compiler in exactly the same way, namely
gcc -I/usr/include -c -o foo.o foo.c
The difference between the two comes into play when you have multiple languages which need the same include path, for instance if you have bar.cpp then try
make bar.o CPPFLAGS="-I/usr/include"
make bar.o CFLAGS="-I/usr/include"
then the compilations will be
g++ -I/usr/include -c -o bar.o bar.cpp
g++ -c -o bar.o bar.cpp
as the C++ implicit rule also uses the CPPFLAGS variable.
This difference gives you a good guide for which to use - if you want the flag to be used for all languages put it in CPPFLAGS, if it's for a specific language put it in CFLAGS, CXXFLAGS etc. Examples of the latter type include standard compliance or warning flags - you wouldn't want to pass -std=c99 to your C++ compiler!
You might then end up with something like this in your makefile
CPPFLAGS=-I/usr/include
CFLAGS=-std=c99
CXXFLAGS=-Weffc++
The CPPFLAGS macro is the one to use to specify #include directories.
Both CPPFLAGS and CFLAGS work in your case because the make(1) rule combines both preprocessing and compiling in one command (so both macros are used in the command).
You don't need to specify . as an include-directory if you use the form #include "...". You also don't need to specify the standard compiler include directory. You do need to specify all other include-directories.
You are after implicit make rules.
To add to those who have mentioned the implicit rules, it's best to see what make has defined implicitly and for your env using:
make -p
For instance:
%.o: %.c
$(COMPILE.c) $(OUTPUT_OPTION) $<
which expands
COMPILE.c = $(CXX) $(CXXFLAGS) $(CPPFLAGS) $(TARGET_ARCH) -c
This will also print # environment data. Here, you will find GCC's include path among other useful info.
C_INCLUDE_PATH=/usr/include
In make, when it comes to search, the paths are many, the light is one... or something to that effect.
C_INCLUDE_PATH is system-wide, set it in your shell's *.rc.
$(CPPFLAGS) is for the preprocessor include path.
If you need to add a general search path for make, use:
VPATH = my_dir_to_search
... or even more specific
vpath %.c src
vpath %.h include
make uses VPATH as a general search path so use cautiously. If a file exists in more than one location listed in VPATH, make will take the first occurrence in the list.
I installed httpd on Ubuntu 18.04 using the CPPFLAGS variable for the -DLINUX flag. When run, CPPFLAGS scans the code from top to bottom, file by file, looking for directives before compiling, and will not be extended by other meaningful things like size optimization, flags that do not increase the size of the output file; under the type of processor; to reduce the size of the code and speed up the program; disable all variables except case. The only difference between CPPFLAGS and CFLAGS is that CFLAGS can be set to specify additional switches to be passed to the compiler. That is, the CFLAGS environment variable creates a directory in the installation path (eg CFLAGS=-i/opt/include) to add debugging information to the executable target's path: include general alarm messages; turning off alarm information; independent location generation; display compiler driver, preprocessor, compiler version number.
Standard way to set CPPFLAGS:
sudo ./configure --enable-unixd=DLINUX #for example
list of some known variables:
CPPFLAGS - is the variable name for flags to the C preprocessor.
CXXFLAGS - is the standard variable name for flags to the C++ compiler.
CFLAGS is - the standard name for a variable with compilation flags.
LDFLAGS - should be used for search flags/paths (-L) - i.e. -L/usr/lib (/usr/lib are library binaries).
LDLIBS - for linking libraries.
CPPFLAGS seems to be an invention of GNU Make, referenced in some of its built-in recipes.
If your program is built by some Free software distributions, you may find that some of them require packages to interpolate this variable, using CPPFLAGS for passing down options like -D_WHATEVER=1 for passing down a macro definition.
This separation is a poor idea and completely unnecessary in the GNU environment because:
There is a way to run gcc to do preprocessing only (while ignoring compiler options unrelated to preprocessing).
The stand-alone GNU cpp is tolerant to compiler options, such as -W warnings that do not pertain to preprocessing and even code generation options like -fstrict-aliasing and the linker-pass through like -Wl,--whatever.
So generally speaking, build systems that need to call the stand-alone preprocessor for whatever reason can just pass it $(CFLAGS).
As an application developer writing a Makefile, you cannot rely on the existence of CPPFLAGS. Users who are not insider experts in open source building won't know about CPPFLAGS, and will do things like make CFLAGS=-Dfoo=bar when building your program. If that doesn't work, they will be annoyed.
As a distro maintainer, you cannot rely on programs to pull in CPPFLAGS; even otherwise well-behaved ones that pull in CFLAGS, LDFLAGS and LDLIBS.
It's easy enough for the application developers to write GNU Make code to separate preprocessor flags out of $(CFLAGS):
cpp_only_flags := $(foreach arg, \
$(CFLAGS), \
$(or $(filter -D%,$(arg)), \
$(filter -U%,$(arg)), \
$(filter -I%,$(arg)), \
$(filter -iquote%,$(arg)), \
$(filter -W%,$(arg)), \
$(filter -M%,$(arg)))) \
$(CPPFLAGS) # also pull this in
all:
#echo cpp_only_flags == $(cpp_only_flags)
Demo:
$ make CFLAGS="-Wall -I/path/to/include -W -UMAC -DFOO=bar -o foo.o -lm"
cpp_only_flags == -Wall -I/path/to/include -W -UMAC -DFOO=bar
In the case of the GNU compiler and preprocessor, this is probably unnnecessary; but it illustrates a technique that could be used for non-GNU compilers and preprocessors, in a build system based on GNU Make.

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