gcov and gcovr: no .gcno files are generated after compiling - gcc

I am trying to get code coverage in my unit test project in windows system.
Description
After compiling with -fprofile-arcs -ftest-coverage, I found out the execution file is generated and works fine. However there's no any .gcno files in the folder. So I cannot output the coverage report properly by gcovr.
Software version
gcc 8.1.0/gcov 8.1.0/gcovr 5.1/python 3.10.2
Steps
Here's what I've done during the whole process. Please help me if there's something wrong.
There are only .c and .h files in one folder
Compile my project using gcc
gcc -Wall -Wno-unknown-pragmas -fcompare-debug-second -fprofile-arcs -ftest-coverage -DUTEST AllTests.c CuTest.c BZR2.c BZR2_test.c -o beta.exe
Then I got beta.exe in the folder.
After runing beta.exe, there's my test result(All tests are passed.) showing in the command line window. Besides there're .gcda files with the same filename as my .c files.
Then I run gcovr -r ., the result is showing below. I think the reson why gcovr can't show the coverage information is there's no any .gcno files generated after compiling my project. But I don't understand why and how to solve this.
------------------------------------------------------------------------------
GCC Code Coverage Report
Directory: .
------------------------------------------------------------------------------
File Lines Exec Cover Missing
------------------------------------------------------------------------------
------------------------------------------------------------------------------
TOTAL 0 0 --%
------------------------------------------------------------------------------
Thanks for your time!

Remove the -fcompare-debug-second option. It is used for debugging the compiler itself, and causes the compiler
to silence warnings, and omitting other options that would cause the compiler to produce output to files or to standard output as a side effect.
(see: https://gcc.gnu.org/onlinedocs/gcc-8.5.0/gcc/Developer-Options.html)
Creation of gcno files is such a side effect.
General tips:
Instead of -fprofile-arcs -test-coverage you can simply use the --coverage option.
When you compile multiple source files in one go, then GCC tries to figure out file names for intermediate files, and also automatically derives some name for secondary outputs like gcno files. This used to be somewhat unintuitive, at least until reasonable behaviour was implemented in GCC 11.
To compile all of the files individually, we would use the structure:
OPTIONS="-Wall -Wno-unknown-pragmas --coverage -DUTEST"
# compile the individual compilation units
gcc -c $OPTIONS AllTests.c -o AllTests.o
gcc -c $OPTIONS BZR2.c -o BZR2.o
gcc -c $OPTIONS BZR2_test.c -o BZR2_test.o
# we should now have three gcno files
ls *.gcno
# link the final executable
gcc $OPTIONS CuTest.o BZR2.o BZR2_test.o -o beta.exe
At this point, it's typically appropriate to use a build system, for example by writing a Makefile:
CFLAGS += -Wall -Wno-unknown-pragmas --coverage -DUTEST
SOURCES = AllTests.c BZR2.c BZR2_tests.c
OBJECTS = $(SOURCES:.c=.o)
beta.exe: $(OBJECTS)
$(CC) $(CFLAGS) $^ -o $#

Related

Corrected usage of gcov on executable and static library

I have a very simple example of using gcov:
library.cpp file compiled and turned into library.a
main.cpp file compiled into executable and uses library.a
All of this done via a simple bash script:
g++ -c library.cpp -Wall -fprofile-arcs -ftest-coverage -o library.o
ar rvs library.a library.o
g++ main.cpp -Wall -fprofile-arcs -ftest-coverage library.a -o main
Now at this point I have the folllowing files (ignoring source and build script):
library.o
library.gcno
library.a
main.cpp
main
main.gcno
So far so good. Now I run my main executable, which creates:
main.gcda
library.gcda
Again all as expected. Now for the question - when I run gcov main.cpp I don't get any gcov files for library.cpp. Is that expected?
Do I really need to call gcov on every source file I may have at any point in time? Is there not a way to call the first source file i.e main.cpp and have it produce coverage stats for each piece of source main goes on to call?
I appear to get gcov files for a lot of core library code that main.cpp uses without need to call them directly with gcov (ostream.gov, locale.gcov...) just not library.gcov
Normally you'd call gcov *.gcno.

Run two instances of the same C++ program simultaneously

I've got a C++ program with a Makefile, building (g++) and running on Windows cmd. Thing is, sometimes it takes a while to run and save the results, and I want to run it with different parameters at the same time so that I can do something else while I wait for the first instance to finish. It doesn't work though, because of the executable I guess:
>make
g++ -c -o main.o main.cpp
Assembler messages:
Fatal error: can't create main.o: Permission denied
make: *** [main.o] Error 1
You have two problems: The one you ask about, and the reason you ask this question in the first place.
Lets start with the problem you have...
Judging by the Makefile you show, you have it all wrong.
Rules are in the format
target: sources_the_target_depend_on
The target is usually a file that need to be created. For an object file that is the name of the actual object file itself. The source files that the object files then depend on should be on the right-hand side.
To take an example from you Makefile (before you edited it away):
graph2: graph2.o
g++ -g -c graph.cpp -o graph2.o
Here you tell make that the file graph2 depends on the file graph2.o, and then it creates the graph2.o file. That's wrong. The rule should be that the file graph2.o depends om the file graph.cpp and go on to generate the file graph2.o:
graph2.o: graph.cpp
g++ -g -c graph.cpp -o graph2.o
This indirectly leads to the problem you have, with this line (deduced from your error and the Makefile):
main: main.o utils.o graph.o heuristics.o
g++ -g main.cpp -o main.o utils.o graph.o heuristics.o
This contains the same error as discussed above: You say that the file main depends on main.o and then the rule create main.o. Your rule should be
main: main.cpp utils.o graph.o heuristics.o
g++ -g main.cpp -o main utils.o graph.o heuristics.o
Note also how I no longer name the executable file main.o, as that is supposed to be used for object files.
Now lets continue with the reason you have the problem in the first place: That you need to edit the code to change data or values.
This is a problem that you need to solve. One common way to solve it is through command line arguments. If your program parses the command line arguments passed to your program you can pass it the values that could change from run to run.
How to do this is whole chapter on its own, so I wont give you any more details. There are plenty of tutorials online.
Lastly, you can simplify your Makefile considerably, by using implicit rules and variables.
I would simply create the Makefile to look something like this
# The compiler to use
CXX = g++
# Flags to pass to the compiler (add warnings when building)
CXXFLAGS = -Wall
# The main executable file to generate
TARGET = main
# List the object files needed to generate the main executable file
OBJECTS = main.o utils.o graph.o heuristics.o
# The all target depends on your main executable file
# Also as the first target in the Makefile, if no specific target is specified
# this will be the one that is used (it's the "default" target for the Makefile)
all: $(TARGET)
# The main executable file depends on the object files
$(TARGET): $(OBJECTS)
This is really it. the object files will be built automatically from their respective source files, and then the executable program will be linked using the object files listed.

How to force compiler to compile same source file every time used in different shared libraries in cmake? [duplicate]

I have a project directory structure of:
Root
Source
Common
MyFolder
++ My 3 source files and header
When I am building my project it generates 3 to 4 shared libraries. Lib1 compiled using c++98 and others using c++11. Flags are added in CmakeList.txt which is at root.
I need my 3 source files to be compiled for Lib1 and for other Libs as as well. but here what happens is compiler is first compiling my source file for lib using c++11 and then it is trying to use same .o file for Lib1 as well. So for .o file which is generated using c++11 is throwing exception when same is used for c++98 compiled library.
So how do write this in CmakeList.txt such that compiler rather than trying to use same .o file will compile source file again for Lib1(c++98 compiled library)
Is there any flag I can specify so that it won't take precompiled .o file and will compile it again ?
Here flags are not being overridden for different shared libraries but actually same object file by make file is being used for different flags
This is sort of counter to how makefiles and cmake usually work.
Most users consider it really important that make performs an incremental build.
The usual way with makefiles is to do make clean which is supposed to remove any binaries and object files that were created.
However, sometimes I write cmake scripts that use globbing over the source directory to assemble the project. (That means, it says "just grab all *.cpp files in the /src folder and make an executable from them".) A makefile cannot check what files in a directory, so the make build will be broken after I add a new file, and make clean won't fix it -- the whole makefile will need to be regenerated by cmake.
Usually what I do is, I write a simple bash script, named rebuild.sh or something,
#!/bin/bash
rm -rf build
mkdir build
cd build
cmake ..
make -j3
./tests
And I put that in the root of my repository, and add /build to my .gitignore. I call that when I want to do a full rebuild -- it nukes the build directory, so its foolproof. When I want an incremental rebuild, I just type make again in the /build directory.
The rebuild.sh script can also serve a double purpose if you use travis-ci for continuous integration.
Most build system assume the compiled objects remain the same within the same pass. To avoid shooting your foot I would suggest telling the build system they were actually different objects, while still compiled from same source files.
I'm not familiar with cmake but this is how you do with make:
For example you have a a.cpp which you want to compile 2 times for different compiler options:
#include <stdio.h>
int main(int argc, char* argv[]) {
printf ("Hello %d\n", TOKEN);
return 0;
}
And the Makefile would looks like:
SRC := $(wildcard *.cpp)
OBJ_1 := $(patsubst %.cpp,%_1.o,$(SRC))
OBJ_2 := $(patsubst %.cpp,%_2.o,$(SRC))
all: pass1 pass2
pass1: $(OBJ_1)
gcc -o $# $(OBJ_1) -lstdc++
pass2: $(OBJ_2)
gcc -o $# $(OBJ_2) -lstdc++
%_1.o: %.cpp
gcc -DTOKEN=1 -c $< -o $#
%_2.o: %.cpp
gcc -DTOKEN=2 -c $< -o $#
clean:
rm -f $(OBJ_1) $(OBJ_2)
What I do here is generate two different list of object from the same source files, which you can even do the same for dependency(-MMD -MP flags).

Cmake vs make sample codes?

I was wondering if there was any sample code for Makefiles (make) and CMakeLists.txt (cmake) that both do the same thing (the only difference being that one is written in make and the other in cmake).
I tried looking for 'cmake vs make', but I never found any code comparisons. It would be really helpful to understand the differences, even if just for a simple case.
The following Makefile builds an executable named prog from the sources
prog1.c, prog2.c, prog3.c and main.c. prog is linked against libmystatlib.a
and libmydynlib.so which are both also built from source. Additionally, prog uses
the library libstuff.a in stuff/lib and its header in stuff/include. The
Makefile by default builds a release target, but offers also a debug target:
#Makefile
CC = gcc
CPP = g++
RANLIB = ar rcs
RELEASE = -c -O3
DEBUG = -c -g -D_DEBUG
INCDIR = -I./stuff/include
LIBDIR = -L./stuff/lib -L.
LIBS = -lstuff -lmystatlib -lmydynlib
CFLAGS = $(RELEASE)
PROGOBJS = prog1.o prog2.o prog3.o
prog: main.o $(PROGOBJS) mystatlib mydynlib
$(CC) main.o $(PROGOBJS) $(LIBDIR) $(LIBS) -o prog
debug: CFLAGS=$(DEBUG)
debug: prog
mystatlib: mystatlib.o
$(RANLIB) libmystatlib.a mystatlib.o
mydynlib: mydynlib.o
$(CPP) -shared mydynlib.o -o libmydynlib.so
%.o: %.c
$(CC) $(CFLAGS) $(INCDIR) $< -o $#
%.o: %.cpp
$(CPP) $(CFLAGS) $(INCDIR) -fPIC $< -o $#
Here is a CMakeLists.txtthat does (almost) exactly the same, with some comments to underline the
similarities to the Makefile:
#CMakeLists.txt
cmake_minimum_required(VERSION 2.8) # stuff not directly
project(example) # related to building
include_directories(${CMAKE_SOURCE_DIR}/stuff/include) # -I flags for compiler
link_directories(${CMAKE_SOURCE_DIR}/stuff/lib) # -L flags for linker
set(PROGSRC prog1.c prog2.c prog3.c) # define variable
add_executable(prog main.c ${PROGSRC}) # define executable target prog, specify sources
target_link_libraries(prog mystatlib mydynlib stuff) # -l flags for linking prog target
add_library(mystatlib STATIC mystatlib.c) # define static library target mystatlib, specify sources
add_library(mydynlib SHARED mydynlib.cpp) # define shared library target mydynlib, specify sources
#extra flags for linking mydynlib
set_target_properties(mydynlib PROPERTIES POSITION_INDEPENDENT_CODE TRUE)
#alternatively:
#set_target_properties(mydynlib PROPERTIES COMPILE_FLAGS "-fPIC")
In this simple example, the most important differences are:
CMake recognizes which compilers to use for which kind of source. Also, it
invokes the right sequence of commands for each type of target. Therefore, there
is no explicit specification of commands like $(CC) ..., $(RANLIB) ... and so on.
All usual compiler/linker flags dealing with inclusion of header files, libraries, etc.
are replaced by platform independent / build system independent commands.
Debugging flags are included by either setting the variable CMAKE_BUILD_TYPE to "Debug",
or by passing it to CMake when invoking the program: cmake -DCMAKE_BUILD_TYPE:STRING=Debug.
CMake offers also the platform independent inclusion of the '-fPIC' flag (via
the POSITION_INDEPENDENT_CODE property) and many others. Still, more obscure settings can be implemented by hand in CMake just as well as in a Makefile (by using COMPILE_FLAGS
and similar properties). Of course CMake really starts to shine when third party
libraries (like OpenGL) are included in a portable manner.
The build process has one step if you use a Makefile, namely typing make at the command line. For CMake, there are two steps: First, you need to setup your build environment (either by typing cmake <source_dir> in your build directory or by running some GUI client). This creates a Makefile or something equivalent, depending on the build system of your choice (e.g. make on Unixes or VC++ or MinGW + Msys on Windows). The build system can be passed to CMake as a parameter; however, CMake makes reasonable default choices depending on your system configuration. Second, you perform the actual build in the selected build system.
Sources and build instructions are available at https://github.com/rhoelzel/make_cmake.
Grab some software that uses CMake as its buildsystem (there's plenty of opensource projects to choose from as an example). Get the source code and configure it using CMake. Read resulting makefiles and enjoy.
One thing to keep in mind that those tools don't map one-to-one. The most obvious difference is that CMake scans for dependencies between different files (e.g. C header and source files), whereas make leaves that to the makefile authors.
If this question is about a sample Makefile output of the CMakeList.txt file then please check the cmake-backend sources and generate one such Makefile. If it is not then adding to the reply of #Roberto I am trying to make it simple by hiding the details.
CMake function
While Make is flexible tool for rules and recipe, CMake is a layer of abstraction that also adds the configuration feature.
My plain CMakeLists.txt will look like the following,
cmake_minimum_required(VERSION 2.8)
project(example)
file(GLOB testapp_SOURCES *.cc)
add_executable(testapp ${testapp_SOURCES})
Note, that CMake hides how the build can be done. We only specified what is the input and output.
The CMakeLists.txt contains list of function-calls that are defined by cmake.
(CMake function) Vs Make rules
In Makefile the rules and recipes are used instead of functions . In addition to function-like feature, rules and recipes provide chaining. My minimalistic Makefile will look like the following,
-include "executable.mk"
TARGETS=testapp.bin
all:${TARGETS}
While the executable.mk will look like the following,
SOURCES=$(wildcard *.cpp)
OBJECTS=$(SOURCES:.cpp=.o)
DEPS=$(SOURCES:.cpp=.d)
%.bin:$(OBJECTS)
$(CC) $(CFLAGS) -o $# $^ $(LFLAGS) $(LIBS)
.PHONY: all clean
clean:
$(RM) $(OBJECTS) $(DEPS) $(TARGETS)
-include $(DEPS)
Starting from the scratch I shall start with a Makefile like the following,
all: testapp.bin
testapp.bin:sourcea.o sourcb.o
$(CC) $(CFLAGS) -o $# $^ $(LFLAGS) $(LIBS)
.PHONY: all clean
clean:
$(RM) $(OBJECTS) testapp.bin
I got this snippet from here and modified it. Note that some implicit-rules are added to this file which can be found in the makefile-documentation. Some implicit variables are also relevant here.
Note, that Makefile provides the detail recipe showing how the build can be done. It is possible to write executable.mk to keep the details defined in one file. In that way the makefile can be reduced as I showed earlier.
Internal Variables in CMake and Make
Now getting little advanced, in CMake we can set a compiler flag like the following,
set(CMAKE_C_FLAGS "-Wall")
Please find out more about CMake default variables in CMakeCache.txt file.
The CMake code above will be equivalent to Make code below,
CFLAGS = -Wall
Note that CFLAGS is an internal variable in Make, the same way, CMAKE_C_FLAGS is internal variable in CMake .
adding include and library path in CMake
We can do it in cmake using functions.
target_include_directories(testapp PRIVATE "myincludes")
list(APPEND testapp_LIBRARIES
mytest mylibrarypath
)
target_link_libraries(testapp ${testapp_LIBRARIES})
Vs adding include and library path in Make
We can add include and libraries by adding lines like the following,
INCLUDES += -Imyincludes
LIBS += -Lmylibrarypath -lmytest
Note this lines above can be generated from auto-gen tools or pkg-config. (though Makefile is not dependent of auto-config tools)
CMake configure/tweek
Normally it is possible to generate some config.h file just like auto-config tools by using configure_file function. It is possible to do more trick writing custom functions. And finally we can select a config like the following,
cmake --build . --config "Release"
It is possible to add some configurable option using the option function.
Makefile configure/tweak
If somehow we need to compile it with some debug flag, we can invoke the make like,
make CXXFLAGS=NDEBUG
I think internal variables, Makefile-rules and CMake-functions are good start for the comparison, good luck with more digging.

how to debug fortran program with multiple object files?

I have a fortran program that calls some dependent .o object files. I would like to be able to step across files when debugging, is this possible?
the compilation routine goes something like this:
gfortran -g -o analyze.x analyze.o active.o analysis.o angles.o attach.o basefile.o beeman.o bicubic.o
where analyze.x is the executable. All of the .o files have been compiled using the -g flag as well.
When i do (gdb) break main and then attempt to step through the program, most of the subroutines take place in the object files. I was wondering if it is possible to be able to step through the object file code as well.
This will work only if the object files linked into the executable have debug information in them, i.e. have been compiled with the -g option. So, this should work:
# Compile all Fortran and C files with debug info
gfortran -g -c *.f90
gcc -g -c *.c
# Link everything together
gfortran -g -o myexe *.o

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