I trying to use ImageInfo and Jython to get information from a image on my harddrive.
I have imported the module fine but keep getting this error:
TypeError: setInput(): expected 2 args; got 1
And this is the code I am trying to use:
filename = "C:\\image.jpg"
img = ImageInfo.setInput(filename)
Could anyone point out what I am doing wrong.
Cheers
Eef
The missing argument Jython complains about is the ImageInfo object itself, which doesn't exist yet. You must construct it first. So:
filename = "C:\\image.jpg"
ii = ImageInfo()
img = ii.setInput(filename)
or
filename = "C:\\image.jpg"
img = ImageInfo().setInput(filename)
may work also.
Related
I am getting this error when running a correlation matrix with the R package ggstatsplo
ggcorrmat(data = d, type = "nonparametric", p.adjust.method = "hochberg",pch = "")
Error: 'data_to_numeric' is not an exported object from 'namespace:datawizard'
Somebody could help me.
I expected to have the script to run normally as I have used it before (around July) without any errors.
Is there anything that has changed about the ggstatsplot package?
I am porting an application from PyQT5 to PyQt6. It displays multiple images in a QTextEdit. I need to add an image resource to QTextEdit QTextDocument but am getting an error.
TypeError: addResource(self, int, QUrl, Any): argument 1 has unexpected type 'ResourceType'
Method variables are img: Dictionary, counter: Integer, text_edit: QTextEdit
path_ = self.app.project_path
if img['mediapath'][0] == "/":
path_ = path_ + img['mediapath']
else:
path_ = img['mediapath'][7:]
document = text_edit.document()
image = QtGui.QImageReader(path_).read()
image = image.copy(img['x1'], img['y1'], img['width'], img['height'])
# Need unique image names or the same image from the same path is reproduced
imagename = self.app.project_path + '/images/' + str(counter) + '-' + img['mediapath']
url = QtCore.QUrl(imagename)
document.addResource(QtGui.QTextDocument.ResourceType.ImageResource, url, QtCore.QVariant(image))
The Qt6 documentation at https://doc.qt.io/qt-6/qtextdocument.html#addResource says:
For example, you can add an image as a resource in order to reference it from within the document:
document->addResource(QTextDocument::ImageResource,
QUrl("mydata://image.png"), QVariant(image));
Note: I have tried the following which matches the Qt6 documentation:
document.addResource(QtGui.QTextDocument.ImageResource, url, QtCore.QVariant(image))
This gives the error: AttributeError: type object 'QTextDocument' has no attribute 'ImageResource'
I found a solution that works, and I think, either the QT6 documentation needs to be updated, or the PyQt6 implementation of the documentation needs to be developed.
The required Integer is stored in the value attribute:
document.addResource(QtGui.QTextDocument.ResourceType.ImageResource.value, url, QtCore.QVariant(image))
QVariant method is not required, simpler code below:
document.addResource(QtGui.QTextDocument.ResourceType.ImageResource.value, url, image)
I came across a strange issue while reading files from Ti.Filesystem.applicationDataDirectory. Whenever I want to access the text property of the Ti.Blob returned by Ti.Filesystem.File.read() I get null
var f = Ti.Filesystem.getFile(Ti.Filesystem.applicationDataDirectory,'foo.key');
var contents = f.read();
Ti.API.debug('contents: ' + JSON.stringify(contents));
var text = contents.text;
Ti.API.debug('text: ' + JSON.stringify(text)); // is NULL
The file was created like so
var f = Ti.Filesystem.getFile(Ti.Filesystem.applicationDataDirectory,'foo.key');
f.write(JSON.stringify({foo: 'bar'});
I'm developing on Android by the way with 6.0.1.GA
TL;DR it's the file extension that's causing the problem
When looking at the Ti.Blob more thoroughly I found that it says mimeType : application/gpg-keys. After updating my code above so it uses foo.json as filename everything works as expected.
I want to retrieve bibtex data (for building a bibliography) by sending a DOI (Digital Object Identifier) to http://www.crossref.org from within matlab.
The crossref API suggests something like this:
curl -LH "Accept: text/bibliography; style=bibtex" http://dx.doi.org/10.1038/nrd842
based on this source.
Another example from here suggests the following in ruby:
open("http://dx.doi.org/10.1038/nrd842","Accept" => "text/bibliography; style=bibtex"){|f| f.each {|line| print line}}
Although I've heard ruby rocks I want to do this in matlab and have no clue how to translate the ruby message or interpret the crossref command.
The following is what I have so far to send a doi to crossref and retrieve data in xml (in variable retdat), but not bibtex, format:
clear
clc
doi = '10.1038/nrd842';
URL_PATTERN = 'http://dx.doi.org/%s';
fetchurl = sprintf(URL_PATTERN,doi);
numinputs = 1;
www = java.net.URL(fetchurl);
is = www.openStream;
%Read stream of data
isr = java.io.InputStreamReader(is);
br = java.io.BufferedReader(isr);
%Parse return data
retdat = [];
next_line = toCharArray(br.readLine)'; %First line contains headings, determine length
%Loop through data
while ischar(next_line)
retdat = [retdat, 13, next_line];
tmp = br.readLine;
try
next_line = toCharArray(tmp)';
if strcmp(next_line,'M END')
next_line = [];
break
end
catch
break;
end
end
%Cleanup java objects
br.close;
isr.close;
is.close;
Help translating the ruby statement to something matlab can send using a script such as that posted to establish the communication with crossref would be greatly appreciated.
Edit:
Additional constraints include backward compatibility of the code (back at least to R14) :>(. Also, no use of ruby, since that solves the problem but is not a "matlab" solution, see here for how to invoke ruby from matlab via system('ruby script.rb').
You can easily edit urlread for what you need. I won't post my modified urlread function code due to copyright.
In urlread, (mine is at C:\Program Files\MATLAB\R2012a\toolbox\matlab\iofun\urlread.m), as the least elegant solution:
Right before "% Read the data from the connection." I added:
urlConnection.setRequestProperty('Accept','text/bibliography; style=bibtex');
The answer from user2034006 lays the path to a solution.
The following script works when urlread is modified:
URL_PATTERN = 'http://dx.doi.org/%s';
doi = '10.1038/nrd842';
fetchurl = sprintf(URL_PATTERN,doi);
method = 'post';
params= {};
[string,status] = urlread(fetchurl,method,params);
The modification in urlread is not identical to the suggestion of user2034006. Things worked when the line
urlConnection.setRequestProperty('Content-Type','application/x-www-form-urlencoded');
in urlread was replaced with
urlConnection.setRequestProperty('Accept','text/bibliography; style=bibtex');
I am having a problem in matlab and the problem is described as follows:
When i try to read an image ( I have several images) and write them to a specific folder, the matlab triggers an error saying
Error using ==> imwrite at 394
Can't open file "\Temp\\inim735282.4716703009300000.jpg" for writing.
You may not have write permission.
May I know why this is happening?
this is the code where the problem occurs
mkdir('.\Temp');
temp_name = sprintf('%.16f',now);
corner_file = ['\Temp\corners', temp_name,'.in'];
image_file = ['\Temp\inim', temp_name,'.jpg'];
out_file = ['\Temp\out', temp_name,'.desc'];
out_imname = ['\Temp\out', temp_name,'.desc.jpg'];
I tried to change it by omitting
mkdir('.\Temp');
moreoever, i direct the path in the folder to the folder by doing this
binary_path = 'C:\Users\cool\Documents\MATLAB\Experment\experiments\bag_of_words\Temp';
to read and and write in and out of the folder.
Can someone please help me figure out this problem?
Thank you guys
Open MatLAB with admin privileges.
A few suggestions:
To generate a temporary output name use the command tempname.
temp_name = tempname();
To concatenate paths and file names use fullfile.
conrner_file = fullfile( '\', 'Temp', 'corners', [temp_name, '.in'] );
You should be careful not to mix '\Temp' and '.\Temp': as the first is an absolute path, while the second is a relative path to cwd.
EDIT:
How about:
temp_name = tempname(); % temp name + folder name in TEMP
corner_file = [ temp_name,'.in'];
image_file = [ temp_name,'.jpg'];
out_file = [temp_name,'.desc'];
out_imname = [temp_name,'.desc.jpg'];
Is it working now?