I am having a problem in matlab and the problem is described as follows:
When i try to read an image ( I have several images) and write them to a specific folder, the matlab triggers an error saying
Error using ==> imwrite at 394
Can't open file "\Temp\\inim735282.4716703009300000.jpg" for writing.
You may not have write permission.
May I know why this is happening?
this is the code where the problem occurs
mkdir('.\Temp');
temp_name = sprintf('%.16f',now);
corner_file = ['\Temp\corners', temp_name,'.in'];
image_file = ['\Temp\inim', temp_name,'.jpg'];
out_file = ['\Temp\out', temp_name,'.desc'];
out_imname = ['\Temp\out', temp_name,'.desc.jpg'];
I tried to change it by omitting
mkdir('.\Temp');
moreoever, i direct the path in the folder to the folder by doing this
binary_path = 'C:\Users\cool\Documents\MATLAB\Experment\experiments\bag_of_words\Temp';
to read and and write in and out of the folder.
Can someone please help me figure out this problem?
Thank you guys
Open MatLAB with admin privileges.
A few suggestions:
To generate a temporary output name use the command tempname.
temp_name = tempname();
To concatenate paths and file names use fullfile.
conrner_file = fullfile( '\', 'Temp', 'corners', [temp_name, '.in'] );
You should be careful not to mix '\Temp' and '.\Temp': as the first is an absolute path, while the second is a relative path to cwd.
EDIT:
How about:
temp_name = tempname(); % temp name + folder name in TEMP
corner_file = [ temp_name,'.in'];
image_file = [ temp_name,'.jpg'];
out_file = [temp_name,'.desc'];
out_imname = [temp_name,'.desc.jpg'];
Is it working now?
Related
I have to perform the following steps on set of images via matlab GUI:
Read multiple images from directory
Process them (Apply imadjust on each image)
Store them in user specified or same directory while renaming them
Can someone kindly provide me the code for the same? I am stuck after this:
[filename, pathname,~] = uigetfile( ...
{'*.jpg;*.jpeg;',...
'JPEG Files (*.jpg,*.jpeg)';
'*.png', 'PNG files (*.png)'; ...
'*.bmp','BMP File (*.bmp)'; ...
'*.tiff;*.tif','TIFF Files (*.tiff,*.tif)'; ...
'*.*', 'All Files (*.*)'}, ...
'Pick a file',...
'Multiselect','on');
set(handles.inputpathtext,'String',pathname);
[file_name_list, pathname] = uigetfile({'your filter spec','Multiselect','on');
The line above should give you a cell array containing the names of the files you selected. The following code loops through the cell array, read image, perform some adjustement, and save them with 'processed_' prefix added to the file name in the same folder specified by pathname.
for ii = 1:length(file_name_list)
if iscell(file_name_list)
filename = file_name_list{ii};
else
filename = file_name_list;
end
img = imread(fullfile(pathname, filename));
img = imadjust(img); % Do something to the image
imwrite(img, fullfile(pathname, ['processed_', filename])
end
I need to import multiple images (10.000) in Matlab (2013b) from a subdirectory of the predefined directory of Matlab.
I don't know the exact names of the images.
I tried this:
file = dir('C:\Users\user\Documents\MATLAB\train');
NF = length(file);
for k = 1 : NF
img = imread(fullfile('C:\Users\user\Documents\MATLAB\train', file(k).name));
end
But it throws this error though I ran it with the Admin privileges:
Error using imread (line 347)
Can't open file "C:\Users\user\Documents\MATLAB\train\." for reading;
you may not have read permission.
The "dir" command returns the virtual directory elements "." (self directory) and ".." parent, as your error message shows.
A simple fix is to use a more specific dir call, based on your image types, perhaps:
file = dir('C:\Users\user\Documents\MATLAB\train\*.jpg');
Check the output of dir. The first two "files" are . and .., which is similar to the behaviour of the windows dir command.
file = dir('C:\Users\user\Documents\MATLAB\train');
NF = length(file);
for k = 3 : NF
img = imread(fullfile('C:\Users\user\Documents\MATLAB\train', file(k).name));
end
In R2013b you would have to do
file = dir('C:\Users\user\Documents\MATLAB\train\*.jpg');
If you have R2014b with the Computer Vision System Toolbox then you can use imageSet:
images = imageSet('C:\Users\user\Documents\MATLAB\train\');
This will create an object containing paths to all image files in the train directory, regardless of format. Then you can read the i-th image like this:
im = read(images, i);
I have vtk example which can read vtk file if it present, but I don't know where I to put vtp file?
If only the file name is passed to a reader, it should look in the current working directory (the same directory that your executable is created in).
To read and print to video a .vtp file use a piece of code like this:
filename = 'filename'
reader = vtk.vtkXMLPolyDataReader()
reader.setFileName(filename)
mapper = vtk.vtkPolyDataMapper()
mapper.SetInputConnection(reader.GetOutputPort())
actor = vtkActor()
actor.SetMapper(mapper)
renderer = vtkRenderer()
renderer.AddActor(actor)
renderWindow = vtk.vtkRenderWindow()
renderWindow.AddRenderer(renderer)
renderWindowInteractor = vtk.vtkRenderWindowInteractor()
renderWindowInteractor.SetRenderWindow(renderWindow)
renderer.ResetCamera()
renderWindow.Render()
renderWindowInteractor.Initialize()
renderWindowInteractor.Start()
Obviously substitute the 'filename' with the name of your .vtp file, like this
filename = 'example.vip'
I have downloaded a set of html files and saved the file paths which I saved them to in a .txt file. It has each path on a new line. I wanted to look at the first file in the list and then itterate through the whole list, opening the files and extracting data before going on to the next file.
My code works fine with a single path put in directly (for the first file) as:
path = r'C:\path\to\file.html'
and works if I itterate through the text file using:
file_list_fp = r'C:\path\to\file_with_pathlist.txt'
with open(file_list_fp, 'r') as file_list:
for filepath in file_list:
pathend = filepath.find('\n')
path = file[:pathend]
q = open(path, 'r').read()
but it fails when I try getting a single path using either:
with open(file_list_fp, 'r') as file_list:
path_n = file_list.readline()
end = path_n.find('\n')
path_bad1 = path_n[:end]
or:
with open(file_list_fp, 'r') as file_list:
path_bad2 = file_list.readline().split('\n')[0]
With these two my code exits just after that point. I can't figure out why. Any pointers very welcome. (I'm using Python 3.3.1 on windows.)
I'm trying to make a script in photoshop that will modify some layers and than export them as a PNG image. I've copied the following code from another place:
function SavePNG(saveFile){
var pngOpts = new ExportOptionsSaveForWeb;
pngOpts.format = SaveDocumentType.PNG
pngOpts.PNG8 = false;
pngOpts.transparency = true;
pngOpts.interlaced = true;
pngOpts.quality = 100;
activeDocument.exportDocument(saveFile,ExportType.SAVEFORWEB,pngOpts);
}
The function export the active document of photoshop to the file specified by the saveFile parameter.
It's working fine with simple paths like "C:\images\result.png" but when trying with different paths like "~/Desktop/" or paths with some special characters the file isn't exported, and a "destination folder does not exist" error message appears.
Any idea how can I solve it?
Well, I'm not sure why this is occur but you could try the following modification:
function SavePNG(saveFile){
var tmpFile = "./tmp.png";
tmpFile = new File(tmpFile);
var pngOpts = new ExportOptionsSaveForWeb;
pngOpts.format = SaveDocumentType.PNG
pngOpts.PNG8 = false;
pngOpts.transparency = true;
pngOpts.interlaced = true;
pngOpts.quality = 100;
activeDocument.exportDocument(tmpFile,ExportType.SAVEFORWEB,pngOpts);
tmpFile.rename (saveFile);
tmpFile.changePath(saveFile);
}
it'll export the file into a temporary file and then rename & move it to the requested path, should solve the path problem.
exportDocument expects a full file name, not a folder path.
This works:
activeDocument.exportDocument(new File("~/foo/foo.png"), ExportType.SAVEFORWEB, pngOpts);
This doesn't work and gives the 'destination folder does not exist' error message:
activeDocument.exportDocument(new File("~/foo/"), ExportType.SAVEFORWEB, pngOpts);
For people having this error and not using photoshop-script.
The error might be unbound to the destination folder, but occurs because the folder, which was used for the export step, is deleted. So either
recreate the folder, which was used during recording, or
recreate the export step