Using OS X, I need a one line bash script to look at a client mac hostname like:
12345-BA-PreSchool-LT.local
Where the first 5 digits are an asset serial number, and the hyphens separate a business unit code from a department name followed by something like 'LT' to denote a laptop.
I guess I need to echo the hostname and use a combination of sed, awk and perhaps cut to strip characters out to leave me with:
"BA PreSchool"
Any help much appreciated. This is what I have so far:
echo $HOSTNAME | sed 's/...\(...\)//' | sed 's/.local//'
echo "12345-BA-PreSchool-LT.local" | cut -d'-' -f2,3 | sed -e 's/-/ /g'
(Not on OSX, so not sure if cut is defined)
I like to keep things simple :)
You could do it with just cut:
echo 12345-BA-PreSchool-LT.local | cut -d"-" -f2,3
BA-PreSchool
If you want to remove the hyphen you can use tr
echo 12345-BA-PreSchool-LT.local | cut -d"-" -f2,3 | tr "-" " "
BA PreSchool
How about
echo $HOSTNAME | awk 'BEGIN { FS = "-" } ; { print $2, $3 }'
Awk can solve your question easily.
echo "12345-BA-PreSchool-LT.local" | awk -F'-' '$0=$2" "$3'
BA PreSchool
bash$ string="12345-BA-PreSchool-LT.local"
bash$ IFS="-"
bash$ set -- $string
bash$ echo $2-$3
BA-PreSchool
Related
Heyo guys. I am using bash script to get current location of my mouse, but I stuck with this. when I do:
xdotool getmouselocation
x:688 y:411 screen:0 window:98568199
I got my output as a string, I am kinda newbie. How can I get values of x and y into some variables, so I can use them further. Thank you.
The x coordinate is the first word in the output (taking for granted that the space is the word separator). y coordinate is the second one. So:
#!/bin/bash
#
output=$(xdotool getmouselocation)
x=$(echo $output | awk '{print $1}' | cut -d":" -f2)
y=$(echo $output | awk '{print $2}' | cut -d":" -f2)
echo "X= $x"
echo "Y= $y"
The awk prints the word you asked for ($1 or $2) and cut gives you what follows the ':' character.
I have a variable with value like:
#capability_ids type="list">[LOADBALANCER]</capability_ids>#
And need to extract from this string type of equipment ( LOADBALANCER ).
I've tried to use cut, but don't know how write cut command with different delimiters.
DeviceType=$( echo $DeviceTypeDirty | cut -d'[' -f1)
Can enywone help me with right solution on bash?
use awk with regular expression: awk -F '[\\[\\]]' '{print $2}'
$ echo '#capability_ids type="list">[L3SWITCH]/capability_ids>#'|awk -F '[\\[\\]]' '{print $2}'
$ L3SWITCH
$ DeviceType=$( echo "$DeviceTypeDirty" | awk -F '[\\[\\]]' '{print $2}')
I tried and got to extract "LOADBALANCER"
Administrators-MacBook-Pro:~$ echo "\"list\">[LOADBALANCER]
</capability_ids>#"|awk -F '[][]' '{print $2}'
LOADBALANCER
Administrators-MacBook-Pro:~$
Hope that helps!
Using cut:
DeviceTypeDirty="#capability_ids type="list">[LOADBALANCER]</capability_ids>#"
DeviceType="$(echo "$DeviceTypeDirty" | cut -d'[' -f2 | cut -d']' -f1)"
Output:
echo "$DeviceType"
LOADBALANCER
In my script I have a variable $var which will hold a value "00135 00136 00137". I want to generate three files based on the values available in $var - if possible without using a loop.
For example, I need touch files with these names:
test.00136.txt
test.00137.txt
test.00138.txt
Avioding a while loop is possible with xargs.
First split the var into lines, use the string num as a placeholder and touch the files:
var="000135 00136 00137 00138 00139"
echo "${var}" | tr " " "\n" | xargs -I num touch test.num.txt
Edit:
Avoid tr with
echo -n "$var" | xargs -d' ' -n1 -Inum echo test.num.txt
The awk utility makes processing columnar data quite simple:
var="00135 00136 00137"
var1=$(echo "$var" | awk '{print $1}')
var2=$(echo "$var" | awk '{print $2}')
var3=$(echo "$var" | awk '{print $3}')
touch "test.${var1}.txt"
touch "test.${var2}.txt"
touch "test.${var3}.txt"
I have a String like this
//ABC/REC/TLC/SC-prod/1f9/20/00000000957481f9-08d035805a5c94bf
and want to get last part of
00000000957481f9-08d035805a5c94bf
Let's say you have
text="//ABC/REC/TLC/SC-prod/1f9/20/00000000957481f9-08d035805a5c94bf"
If you know the position, i.e. in this case the 9th, you can go with
echo "$text" | cut -d'/' -f9
However, if this is dynamic and your want to split at "/", it's safer to go with:
echo "${text##*/}"
This removes everything from the beginning to the last occurrence of "/" and should be the shortest form to do it.
For more information on this see: Bash Reference manual
For more information on cut see: cut man page
The tool basename does exactly that:
$ basename //ABC/REC/TLC/SC-prod/1f9/20/00000000957481f9-08d035805a5c94bf
00000000957481f9-08d035805a5c94bf
I would use bash string function:
$ string="//ABC/REC/TLC/SC-prod/1f9/20/00000000957481f9-08d035805a5c94bf"
$ echo "${string##*/}"
00000000957481f9-08d035805a5c94bf
But following are some other options:
$ awk -F'/' '$0=$NF' <<< "$string"
00000000957481f9-08d035805a5c94bf
$ sed 's#.*/##g' <<< "$string"
00000000957481f9-08d035805a5c94bf
Note: <<< is herestring notation. They do not create a subshell, however, they are NOT portable to POSIX sh (as implemented by shells such as ash or dash).
In case you want more than just the last part of the path,
you could do something like this:
echo $PWD | rev | cut -d'/' -f1-2 | rev
You can use this BASH regex:
s='//ABC/REC/TLC/SC-prod/1f9/20/00000000957481f9-08d035805a5c94bf'
[[ "$s" =~ [^/]+$ ]] && echo "${BASH_REMATCH[0]}"
00000000957481f9-08d035805a5c94bf
This can be done easily in awk:
string="//ABC/REC/TLC/SC-prod/1f9/20/00000000957481f9-08d035805a5c94bf"
echo "${string}" | awk -v FS="/" '{ print $NF }'
Use "/" as field separator and print the last field.
You can try this...
echo //ABC/REC/TLC/SC-prod/1f9/20/00000000957481f9-08d035805a5c94bf |awk -F "/" '{print $NF}'
In shell,
s="abc\tdef\tghi" # 3 words separated by \t
What if I want to get the second word which is def?
PS
I know cut can do the job, but any way else just like variable substitution?
How about cut ?
[cnicutar#ariel ~]$ echo -e $s | cut -f2
def
Or maybe awk:
echo -e $s | awk '{print $2}'
Maybe you're looking for this.
s="abc\tdef\tghi"
s=${s#*\t}
s=${s%\\t*}
echo $s