According to Spring framework API
UrlFilenameViewController's purpose is:
Transforms the virtual path of a URL into a view name and returns that view
If i request for /info.xhtml, its logical view name is info
See UrlFilenameViewController documentation
Both web.xml and controller is mapped according to
/WEB-INF/web.xml
<?xml version="1.0" encoding="UTF-8">
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>smac</display-name>
<servlet>
<servlet-name>controller</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>controller</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
</web-app>
/WEB-INF/controller-servlet.xml
<?xml version="1.0" encoding="UTF-8">
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
<bean class="org.springframework.web.servlet.view.InternalViewResolver">
<property name="prefix" value="/WEB-INF/output/"/>
<property name="suffix" value=".jsp"/>
</bean>
<bean class="org.springframework.web.servlet.mvc.UrlFilenameViewController"/>
</beans>
My smac app deploys fine.
So, if i request for http://127.0.0.1:8080/smac/info.xhtml, Spring-MVC should return /WEB-INF/output/info.jsp. But i have seen in console the following:
No mapping found for HTTP request with URI [/smac/info.xhtml] in DispatcherServlet with name 'controller'
Could anyone help me ?
regards,
You need to configure a HandlerMapping. Default one is BeanNameUrlHandlerMapping which will only do what you want if you bind your controller bean under the name matching your URI. You probably want the SimpleUrlHandlerMapping instead:
<bean name="myController" class="org.springframework.web.servlet.mvc.UrlFilenameViewController"/>
<bean class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<value>
/**/*.xhtml=myController
</value>
</property>
</bean>
Related
I am trying to implement SimpleUrlHandlerMapping in Spring. I am using Spring 4.2.5 version.
Following is my mapping
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">
.....
<bean class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="/hello1.dsm">hc</prop>
</props>
</property>
</bean>
<bean id="hc" class="com.vaannila.HelloWorldController" >
<property name="message" value="Hello World!" />
</bean>
....
</beans>
When I run tomcat, I get the info message on console saying
org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler
INFO: Mapped URL path [/hello1.dsm] onto handler 'hc'
But When I hit the url "http://localhost:8080/SpringExample5/hello1.dsm" in my browser I get the requested resource is not available error i.e 404.
Later when I change key to "/hello1.htm", it worked fine with respective url. I am wondering is there any rule on url extention while mapping url to controller.
In web.xml, The dispatcher servlet url pattern is configured to .htm extention
<?xml version="1.0" encoding="UTF-8"?>
............
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>............
and hence It is working fine for ".htm" extention.
To make it work for other extentions we need to set corresponding url-pattern in web.xml file.
I try run a basic Java EE Spring project on eclipse(jboss 7.1.1 server, Spring 3.1.2 released), but when it always print that the configuration file do not find but I Actually put the configuration file in right place. I do not configure the welcome-file, but mvc:view-controller instead.
this is the web.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee /web-app_3_0.xsd">
<display-name>springupload</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/web-application-config.xml</param-value>
</context-param>
<!-- Loads the Spring web application context -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value/>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<!-- Map all *.spring requests to the DispatcherServlet for handling -->
<servlet-mapping>
<servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
This is the web-application-config.xml file
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<!-- Scans for application #Components to deploy -->
<context:component-scan base-package="com.pack" />
<!-- Imports the configurations of the different infrastructure systems of the application -->
<import resource="webmvc-config.xml" />
<!-- <import resource="webflow-config.xml" /> -->
<!-- <import resource="data-access-config.xml" /> -->
<bean class="org.springframework.web.multipart.commons.CommonsMultipartResolver" id="multipartResolver">
<property name="maxUploadSize" value="1000000"></property>
</bean>
</beans>
This is webmvc-config.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:aop="http://www.springframework.org/schema/aop"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd">
<!-- Enables controllers mapped with #RequestMapping annotations, formatting annotations #NumberFormat #DateTimeFormat, and JSR 303 style validation -->
<mvc:annotation-driven/>
<mvc:resources mapping="/res/**" location="/, classpath:/META-INF/web-resources/" />
<mvc:view-controller path="/" view-name="hello"/>
<mvc:default-servlet-handler />
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" id="jspre">
<property name="prefix" value="/WEB-INF/"/>
<property name="suffix" value=".jsp"/>
</bean>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" id="htmlre">
<property name="prefix" value="/WEB-INF/"/>
<property name="suffix" value=".html"/>
</bean>
</beans>
The error you can see in the picture:
HTTP Status 404 - /springupload/WEB-INF/webmvc-config.xml
type Status report
message /springupload/WEB-INF/webmvc-config.xml
description The requested resource (/springupload/WEB-INF/webmvc-config.xml) is not available.
JBoss Web/7.0.13.Final
I really do not know why I configure the html and jsp page, while it should some configuration file as my start page?
Your configuration is not far from being OK.
One thing I notice is that the hello.html file is in your root WebContent folder. I suppose this is the view you want rendered when you access http://localhost:8080/springupload/ because of this line in the configuration:
<mvc:view-controller path="/" view-name="hello"/>
If this is so, then Spring is trying to resolve to /WEB-INF/hello.html because of the prefix and suffix on this viewResolver :
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" id="htmlre">
<property name="prefix" value="/WEB-INF/"/>
<property name="suffix" value=".html"/>
</bean>
However, you have two view resolvers with no order in them, and Spring is taking only the first one which resolves to /WEB-INF/hello.jsp, hence the 404 Not found
To wrap it up your solution is to move hello.html to /WEB-INF/ and to change your viewResolver configuration in webmvc-config.xml like so
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" id="jspre">
<property name="order" value="2" />
<property name="prefix" value="/WEB-INF/"/>
<property name="suffix" value=".jsp"/>
</bean>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" id="htmlre">
<property name="order" value="1" />
<property name="prefix" value="/WEB-INF/"/>
<property name="suffix" value=".html"/>
</bean>
Last, you're not supposed to access directly content in the http://localhost:8080/WEB-INF/* URL, so everything you try here will result in a 404 Not found.
change your configuration file name to [dispatcher servlet name]-servlet.xml
http://static.springsource.org/spring/docs/3.0.x/reference/mvc.html
I need to know the basic XML configuration files to put in my Web-inf folder, like web.XML, and where to write view resolver bean.
How do I register the controller?
When I run my application I get the error "could not open servlet context resource". What is servlet context resource and where do I mention it?
My web.xml is:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<servlet>
<servlet-name>springmvc</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springmvc</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>
jsp/index.jsp
</welcome-file>
</welcome-file-list>
</web-app>
My springmvc is:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
<bean name="/hello_world.html" class="springmvc.web.HelloWorldController"/>
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
<property name="prefix" value="/jsp/"/>
<property name="suffix" value=".jsp"/>
</bean>
</beans>
I have these two xml files only.
I know I need a spring configuration file too. I don't know what details I need to put in that.
If you use STS (Spring Tool Suite) then you can create a Spring Template Project.
(New Project/SpringSource Tool Suite/Spring Template Project/-Spring MVC Project)
This contains all the files you need to start.
I am really confused how does the address of my spring application come from.
I followed the tutorial, but now I am trying to change the address, but I can't find the spot.
At the moment address is this : http://localhost:8080/HelloWorld/
Where can I change HelloWorld to something else?
I will provide you with any code you need. I have two conf files : web.xml, spring-servlet.xml, but there is nothing in them that contains HelloWorld.
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="hello.spring3.controller" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView"/>
<property name="prefix" value="/WEB-INF/jsp/"/>
<property name="suffix" value=".jsp" />
</bean>
</beans>
and web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="spring3" version="3.0">
<display-name>Spring display name</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
</web-app>
Actually this is not issue unless you deploy it on production environament.
When you deploy it there you should create new HOST in TOMCAT_HOME/conf/server.xml file
it should look something like:
<Host name="www.mysite.com" appBase="www"
unpackWARs="true" autoDeploy="true"
xmlValidation="false" xmlNamespaceAware="false">
</Host>
Second option is to deploy your war file in ROOT directory, but in my opinion the first option is more suitable.
Update: No problem, If you are using eclipse, please click right mouse button on your project, Select Properties - > Web Project Settings.
and change name of your "HelloWorld" directory.
It's the name of your war file.
I recently switched one of my static html files to a Spring controller that uses a JSP to render its view. I use jetty to test locally and local testing shows the page rendering fine. Upon deploying to our test server, which uses Tomcat 6.0.26, I get the following exception:
javax.servlet.ServletException: Could not get RequestDispatcher for [/WEB-INF/jsp/index.jsp]: check that this file exists within your WAR
org.springframework.web.servlet.view.InternalResourceView.renderMergedOutputModel(InternalResourceView.java:219)
org.springframework.web.servlet.view.AbstractView.render(AbstractView.java:250)
org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1060)
org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:798)
org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:716)
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:644)
org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:549)
javax.servlet.http.HttpServlet.service(HttpServlet.java:617)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
I have confirmed that the JSP exists in the war I deploy and the exploded directory that tomcat creates upon deployment. Here is what my web.xml and front-controller-servlet.xml files look like respectively (web.xml shorted slightly):
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="
http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- Initialize the Spring DispatcherServlet -->
<servlet>
<servlet-name>gwtrpc</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<!-- Map the DispatcherServlet to only intercept RPC requests -->
<servlet-mapping>
<servlet-name>gwtrpc</servlet-name>
<url-pattern>*.gwtrpc</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>front-controller</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>front-controller</servlet-name>
<url-pattern>/search.html</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>front-controller</welcome-file>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
front-controller-servlet.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.0.xsd">
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="/search.html">indexController</prop>
</props>
</property>
</bean>
<bean id="indexController" class="com.company.search.web.server.controller.IndexController" />
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp"/>
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView" />
</bean>
</beans>
The difference between my dev instance and test instance is that the dev instance is deployed to the root (localhost/search.html) whereas the test instance is deployed to server.com/appname/search.html. Appname is the name of the *.war file I deploy. I have tried adding the full path as the prefix to the jps files (/appname/WEB-INF/jsp/) and a number of other combinations with no luck. I have verified that the jsp-api jars are in the tomcat lib directory. My tomcat install is the basic/default install.
The issue was caused by the default jsp servlet being removed from the default web.xml of the tomcat install. This had been done by a former co-worker and not to my knowledge. Replacing the test server's web.xml with the default web.xml (which included url-patterns/servlets for handling jsp files) corrected the issue.