I have to query all_objects table where last_ddl_time='01 jan 2010' but it refuses the date format...
Any body give me the exact format to query?
As AKF said, you should be using Trunc unless you know the exact time the DDL was modified. Your query you added in the comments is looking for any objects where the DDL changed at 1/1/2010 00:00:00. Try:
SELECT *
FROM all_objects
WHERE trunc(last_ddl_time) = to_date('01-01-2010','dd-mm-yyyy');
I suggest you to use de date literal:
where trunc(last_ddl_time) = date '2010-01-01'
You can use the to_date function to format your date. If you enter a literal string, Oracle will attempt to convert that string using to_date with a default format 'DD-MON-YY', so your date would look like "01-JAN-10". As Oracle will be using this same function, you might want to put it in yourself and enjoy the finer granularity that custom formatting can provide.
It would be good to note that the dates stored in that column most likely have more precise dates, including hours and minutes, etc. Though you will be taking a bit of a performance hit, you might be better served using trunc(last_ddl_time) if you are testing with =.
There is some good info on Dates in Oracle at this link.
SELECT *
FROM all_objects t
WHERE trunc(t.last_ddl_time, 'DD') = to_date('2010-JAN-01', 'YYYY-MON-DD');
Related
There are records in table for particular date. But when I query with that value, I am unable to filter the records.
select * from TBL_IPCOLO_BILLING_MST
where LAST_UPDATED_DATE = '03-09-21';
The dates are in dd-mm-yy format.
To the answer by Valeriia Sharak, I would just add a few things since your question is tagged Oracle. I was going to add this as a comment to her answer, but it's too long.
First, it is bad practice to compare dates to strings. Your query, for example, would not even execute for me -- it would end with ORA-01843: not a valid month. That is because Oracle must do an implicit type conversion to convert your string "03-09-21" to a date and it uses the current NLS_DATE_FORMAT setting to do that (which in my system happens to be DD-MON-YYYY).
Second, as was pointed out, your comparison is probably not matching rows due LAST_UPDATED_DATE having hours, minutes, and seconds. But a more performant solution for that might be:
...
WHERE last_update_date >= TO_DATE('03-09-21','DD-MM-YY')
AND last_update_date < TO_DATE('04-09-21','DD-MM-YY')
This makes the comparison without wrapping last_update_date in a TRUNC() function. This could perform better in either of the following circumstances:
If there is an index on last_update_date that would be useful in your query
If the table with last_update_date is large and is being joined to other tables (because it makes it easier for Oracle to estimate the number of rows from your table that are inputs to the join).
Your column might contain hours and seconds, but they can be hidden.
So when you filter on the date, oracle implicitly adds time to the date. So basically you are filtering on '03-09-21 00:00:00'
Try to trunc your column:
select * from TBL_IPCOLO_BILLING_MST
where trunc(LAST_UPDATED_DATE) = '03-09-21';
Hope, I understood your question correctly.
Oracle docs
I have a varchar column called begin_time that stores the 24-hour time as a varchar with no time formatting, ie 1330
I need to convert this varchar to a usable timestamp, datetime, etc. where I can easily convert the varchar to a standard time format (1:30 PM)
The end format type doesn't matter as long as I can convert the varchar into a format that I can manipulate to a standard format.
I've tried looking into Cognos-specific format tricks (These functions are for Metric Designer, and I'm using Report Studio) to no avail. The methods I found when looking for oracle-specific tricks seemed to be way too convoluted (using insanely long regex rules) for what I need.
If I need to have a date involved, I can use the column start_date and append the varchar time.
Note: start_date is in the date format
Example
select
to_date('08/27/2018','MM/DD/YYYY') as start_date
, '1300' as begin_time
from dual
What I ultimately need is just to be able to output the time as 1:00 PM
Any help would be appreciated. I'm beating my head against the wall on this... I'm used to using proprietary codes for periods of time and don't have a lot of experience with the true datetime formats.
Updates answering questions
Alex Poole, I make no claims that this system is the best... It's vendor-provided. :)
The BEGIN_TIME is always 4 characters
It does look like I was overthinking it quite a bit... Littlefoot may have nailed it on the head, but I unfortunately won't have a chance to test that until tomorrow.
Thank you all for the fast responses. I might have hair left when this request is over now :)
Final Thought
My lesson learned from this is simple: If you're dealing with time formats, don't throw out the idea of using a Date format function.
Looking for this?
SQL> with test (col) as
2 (select '1330' from dual)
3 select to_char(to_date(col, 'hh24mi'), 'hh:mi am') result
4 from test;
RESULT
--------
01:30 PM
SQL>
What does it do?
TO_DATE converts string you have (such as 1330) into a valid DATE value. By default, it'll be a date value truncated to the first of current month:
SQL> alter session set nls_Date_format = 'dd.mm.yyyy hh24:Mi';
Session altered.
SQL> select to_date('1330', 'hh24mi') res1 from dual;
RES1
----------------
01.04.2019 13:30
SQL>
applying TO_CHAR to it, again with the appropriate format mask, returns the desired result
I am trying to insert nvarchar2 values into my oracle Date field. When my source nvarchar2 value is '20701130', I want to save it as '30/11/2070' in my oracle column. And, if the source value is '21150529', I want to save it as '29/05/2115'.
I tried different formatting options to achieve this, but the year is always getting saved as two digits and is not indicating the correct century.
One of my Queries:
INSERT INTO MY_TABLE (MY_DATE_FIELD)
VALUES(TO_DATE('21061030', 'RRRR-MM-DD'));
Now, when I select after the above query, I get the result as 30/10/06 which is not we want, it should be '30/10/2106'.
You can go about it in many ways:
You alter the session date format itself to a format you want to achieve like :
ALTER SESSION SET NLS_DATE_FORMAT = 'RRRR-MM-DD';
Another approach is once you have achieved a date from a string passed using to_date then you can again add to_char to display the date in a format you want.
To_date will convert your string to a date using the format you have provided but while selecting it will still display the date as per the format provided in the session that's why we use To_char to change it to a format we want to display it into.
select to_char(TO_DATE('21061030', 'RRRR-MM-DD'),'RRRR-MM-DD') "DATE" from dual;
Thanks for the help.
I have pasted my SQL below if anyone is interested.
-- To insert into table
UPDATE MY_TABLE SET MY_DATE_FLD = TO_CHAR(TO_DATE('21061030', 'RRRR-MM-DD'),'DD-MM-YYYY') ;
-- To read from the table, this gave me the result 30/01/2106
select TO_CHAR(DATE_FLD,'DD/MM/YYY') AS START_DATE from MY_TABLE;
Appreciate the help.
Kiran.
I need to load a table with a .csv file which contains date "20140825145416".
I have tried using (DT date "yyyymmdd hh24:mm:ss") in my control file.
It throws an error as ORA-01821: date format not recognized
I require the data in table as "MM/DD/YYYY HH:MM:SS".
Sample data : 20140825145416
thanks in advance.
Well, I would be remiss if I did not point out that the correct answer is to never store dates as VARCHAR2 data, but make it a proper DATE column and load it like this:
DT DATE "YYYYMMDDHH24MISS"
Formatting is done when selecting. It will make your life so much easier if you ever need to use that date in a calculation.
That out of the way, If you have no control over the database and have to store it as a VARCHAR2, first convert to a date, then use to_char to format it before inserting:
DT CHAR "to_char(to_date(:DT, 'YYYYMMDDHH24MISS'), 'MM/DD/YYYY HH24:MI:SS')"
Note 'MI' is used for minutes. You had a typo where you used 'MM' (months) again for minutes.
I know it's already been said in the previous answer, but it's so important, it's worth repeating. Do not store dates as varchars !!
If your DT column is timestamp then this might work
DT CHAR(25) date_format TIMESTAMP mask "yyyymmddhhmiss"
I used something like this in external tables. Maybe this might help
https://docs.oracle.com/cd/B19306_01/server.102/b14215/et_concepts.htm
and
https://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:8128892010789
I've had some brilliant help before and I'm hoping you can get me out of a hole again.
I've got a date coming in from a web service in this format:
2009-02-13T11:46:40+00:00
which to me looks like standard UTC format.
I need to insert it into an Oracle database, so I'm using to_date() on the insert. Problem is, I cant get a matching formatting string for it and keep getting "ORA-01861: literal does not match format string" errors.
I know its a fairly trivial problem but for some reason I cannot get it to accept the right format string. Any help appreciated.
Thanks :)
Gareth
You can directly convert it to a TIMESTAMP_WITH_TIME_ZONE datatype.
select
to_timestamp_tz('2009-02-13T11:46:40+00:00','YYYY-MM-DD"T"HH24:MI:SSTZH:TZM')
from
dual
TO_TIMESTAMP_TZ('2009-02-13T11:46:40+00:00','YYYY-MM-DD"T"HH24:MI:SSTZH:TZM
---------------------------------------------------------------------------
13-FEB-09 11.46.40.000000000 AM +00:00
(I'm assuming the input string is using a 24-hour clock since there is no AM/PM indicator.)
If you want to convert that to a simple DATE, you can, but it will lose the time zone information.
SELECT CAST(TO_TIMESTAMP_TZ(REPLACE('2009-02-13T11:46:40+00:00', 'T', ''), 'YYYY-MM-DD HH:MI:SS TZH:TZM') AS DATE)
FROM dual
To import date in specified format you can set nls_date_format.
Example:
alter session set nls_date_format='YYYY-MM-DD HH24:MI:SS'
This way your SQL statements can be shorter (no casts). For various mask look at Datetime Format Models