I am trying to insert nvarchar2 values into my oracle Date field. When my source nvarchar2 value is '20701130', I want to save it as '30/11/2070' in my oracle column. And, if the source value is '21150529', I want to save it as '29/05/2115'.
I tried different formatting options to achieve this, but the year is always getting saved as two digits and is not indicating the correct century.
One of my Queries:
INSERT INTO MY_TABLE (MY_DATE_FIELD)
VALUES(TO_DATE('21061030', 'RRRR-MM-DD'));
Now, when I select after the above query, I get the result as 30/10/06 which is not we want, it should be '30/10/2106'.
You can go about it in many ways:
You alter the session date format itself to a format you want to achieve like :
ALTER SESSION SET NLS_DATE_FORMAT = 'RRRR-MM-DD';
Another approach is once you have achieved a date from a string passed using to_date then you can again add to_char to display the date in a format you want.
To_date will convert your string to a date using the format you have provided but while selecting it will still display the date as per the format provided in the session that's why we use To_char to change it to a format we want to display it into.
select to_char(TO_DATE('21061030', 'RRRR-MM-DD'),'RRRR-MM-DD') "DATE" from dual;
Thanks for the help.
I have pasted my SQL below if anyone is interested.
-- To insert into table
UPDATE MY_TABLE SET MY_DATE_FLD = TO_CHAR(TO_DATE('21061030', 'RRRR-MM-DD'),'DD-MM-YYYY') ;
-- To read from the table, this gave me the result 30/01/2106
select TO_CHAR(DATE_FLD,'DD/MM/YYY') AS START_DATE from MY_TABLE;
Appreciate the help.
Kiran.
Related
I need to load a table with a .csv file which contains date "20140825145416".
I have tried using (DT date "yyyymmdd hh24:mm:ss") in my control file.
It throws an error as ORA-01821: date format not recognized
I require the data in table as "MM/DD/YYYY HH:MM:SS".
Sample data : 20140825145416
thanks in advance.
Well, I would be remiss if I did not point out that the correct answer is to never store dates as VARCHAR2 data, but make it a proper DATE column and load it like this:
DT DATE "YYYYMMDDHH24MISS"
Formatting is done when selecting. It will make your life so much easier if you ever need to use that date in a calculation.
That out of the way, If you have no control over the database and have to store it as a VARCHAR2, first convert to a date, then use to_char to format it before inserting:
DT CHAR "to_char(to_date(:DT, 'YYYYMMDDHH24MISS'), 'MM/DD/YYYY HH24:MI:SS')"
Note 'MI' is used for minutes. You had a typo where you used 'MM' (months) again for minutes.
I know it's already been said in the previous answer, but it's so important, it's worth repeating. Do not store dates as varchars !!
If your DT column is timestamp then this might work
DT CHAR(25) date_format TIMESTAMP mask "yyyymmddhhmiss"
I used something like this in external tables. Maybe this might help
https://docs.oracle.com/cd/B19306_01/server.102/b14215/et_concepts.htm
and
https://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:8128892010789
I have the following date which is in varchar2(11) column in database:
select valid_untill from SALES_ORDERS_V where header_id = 7999410;
30-May-2016
Using rtf template and xml source, the report output (PDF) is:
4950-11-19 04:45:49:0
I don't know its equal to "30-May-2016".
Why this is showing this, as I did not do any formating in rtf?
Not familiar with either RTF or XML-Publisher, but whenever you retrieve a date saved in string format, IF you use it as a date in your code and not as a string, you must make sure you retrieve it correctly.
In this case, with your select statement: it shouldn't be select valid-until from... (or is it really misspelled, with two l at the end: valid_until?) If it is meant to be used as a date, it should be
select to_date(valid_until, 'dd-Mon-yyyy') from ...
Really the problem here is that the date is stored as a string and not in the date datatype. Good luck!
I have a requirement to globalize the application based on culture specified in config file.
I have Amounts and date values .I decided to convert them in query itself.Like below
For Spanish Chile Es-CL:
for Date format is "dd-mm-yyyy" I will use Select TO_CHAR(busdate,'dd-mm-yyyy') from itemTable.
Similarly i want to use same for the amounts Select to_char(Amount,'99.999.99,00') from table1.
But its in vain.
Please suggest me the right way to achive my requirement.
These amounts and date formats can be available.but need to know how to convert them.
I thought to use in On_Data_bound event for datagrids ,but still this will be a performance issue.
You would use the NLS_NUMERIC_CHARACTERS session variable, along with globalized format model:
SQL> alter session set NLS_NUMERIC_CHARACTERS='.,';
Session altered
SQL> select to_char(123456789.01, 'fm999G999G990D00') from dual;
TO_CHAR(123456789.01,
---------------------
123,456,789.01
SQL> alter session set NLS_NUMERIC_CHARACTERS=', ';
Session altered
SQL> select to_char(123456789.01, 'fm999G999G990D00') from dual;
TO_CHAR(123456789.01,
---------------------
123 456 789,01
I am using Oracle10g database in which a table contains a Column with Date DataType. I am using the following query to get the record:
select to_char(START_TIME, 'YYMMDD HH24:MI:SS') from table;
So from above query, the result will be of type VARCHAR. I have tried to_Date() method but resulted in displaying only DATE. Can i convert VARCHAR to DATETIME format? The result should be of type DATETIME. Please help me how to resolve this problem.
an Oracle date contains both date and time so you can consider it a datetime (there is no datatype of datetime in Oracle). how is DISPLAYS when you select it is entirely up to your client. the default display setting is controlled by the NLS_DATE_FORMAT parameter. If you're just using the date in your pl/sql block then just assign it into a date datatype and select into that variable without to_char and it will work just fine and contain whatever time component is present in your table.
to control the display, for example using nls_date_format:
SQL> select a from datetest;
A
---------
19-FEB-13
SQL> alter session set nls_date_format='YYMMDD HH24:MI:SS';
Session altered.
SQL> select a from datetest;
A
---------------
130219 07:59:38
but again, this is only for display.
Oracle's Date type fields contain date/time values, therefore converting it to Datetime does not make any sense (it's already datetime)
Read more about oracle date types here
Yeah the Date datatype will meet your needs but you will have to jump through some hoops every time to get the exact time out of it. Definitely use the Timestamp datatype.
I'm reading a pipe delimited file with SQL Loader and want to populate a LAST_UPDATED field in the table I am populating. My Control File looks like this:
LOAD DATA
INFILE SampleFile.dat
REPLACE
INTO TABLE contact
FIELDS TERMINATED BY '|'
OPTIONALLY ENCLOSED BY '"'
(
ID,
FIRST_NAME,
LAST_NAME,
EMAIL,
DEPARTMENT_ID,
LAST_UPDATED SYSTIMESTAMP
)
For the LAST_UPDATED field I've tried SYSTIMESTAMP and CURRENT_TIMESTAMP and neither work. SYSDATE however works fine but doesn't give me the time of day.
I am brand new to SQL Loader so I really know very little about what it is or isn't capable of. Thanks.
Have you tried the following:
CURRENT_TIMESTAMP [ (precision) ]
select current_timestamp(3) from dual;
CURRENT_TIMESTAMP(3)
-----------------------------
10-JUL-04 19.11.12.686 +01:00
To do this in SQLLDR, you will need to use EXPRESSION in the CTL file so that SQLLDR knows to treat the call as SQL.
Replace:
LAST_UPDATED SYSTIMESTAMP
with:
LAST_UPDATED EXPRESSION "current_timestamp(3)"
I accepted RC's answer because ultimately he answered what I was asking but my unfamiliarity with some of Oracle's tools led me to make this more difficult than it needed to be.
I was trying to get SQL*Loader to record a timestamp instead of just a date. When I used SYSDATE, and then did a select on the table it was only listing the the date (05-AUG-09).
Then, I tried RC's method (in the comments) and it worked. However, still, when I did a select on the table I got the same date format. Then it occurred to me it could just be truncating the remainder for display purposes. So then I did a:
select TO_CHAR(LAST_UPDATED,'MMDDYYYY:HH24:MI:SS') from contact;
And it then displayed everything. Then I went back to the control file and changed it back to SYSDATE and ran the same query and sure enough, the HH:MI:SS was there and accurate.
This is all being done in SqlDeveloper. I don't know why it defaults to this behavior. Also what threw me off are the following two statements in sqldeveloper.
SELECT CURRENT_TIMESTAMP FROM DUAL; //returns a full date and time
SELECT SYSDATE FROM DUAL; // returns only a date
If you want to use the table defined default you can use:
ROWDATE EXPRESSION "DEFAULT"
In Sql Developer run:
ALTER SESSION SET NLS_DATE_FORMAT='YYYY-MM-DD HH24:MI:SS'
and then check it with
SELECT SYSDATE FROM DUAL