Removing url fragment from NSURL - cocoa

Question

I'm writing a Cocoa application, which uses NSURLs -- I need to remove the fragment portion of the URL (the #BLAH part).
example: http://example.com/#blah should end up as http://example.com/
I found some code in WebCore that seems to do it by using CFURL functionality, but it never finds the fragment portion in the URL. I've encapsulated it in a extension category:
-(NSURL *)urlByRemovingComponent:(CFURLComponentType)component {
CFRange fragRg = CFURLGetByteRangeForComponent((CFURLRef)self, component, NULL);
// Check to see if a fragment exists before decomposing the URL.
if (fragRg.location == kCFNotFound)
return self;
UInt8 *urlBytes, buffer[2048];
CFIndex numBytes = CFURLGetBytes((CFURLRef)self, buffer, 2048);
if (numBytes == -1) {
numBytes = CFURLGetBytes((CFURLRef)self, NULL, 0);
urlBytes = (UInt8 *)(malloc(numBytes));
CFURLGetBytes((CFURLRef)self, urlBytes, numBytes);
} else
urlBytes = buffer;
NSURL *result = (NSURL *)CFMakeCollectable(CFURLCreateWithBytes(NULL, urlBytes, fragRg.location - 1, kCFStringEncodingUTF8, NULL));
if (!result)
result = (NSURL *)CFMakeCollectable(CFURLCreateWithBytes(NULL, urlBytes, fragRg.location - 1, kCFStringEncodingISOLatin1, NULL));
if (urlBytes != buffer) free(urlBytes);
return result ? [result autorelease] : self;
}
-(NSURL *)urlByRemovingFragment {
return [self urlByRemovingComponent:kCFURLComponentFragment];
}
This is used as such:
NSURL *newUrl = [[NSURL URLWithString:#"http://example.com/#blah"] urlByRemovingFragment];
unfortunately, newUrl ends up being "http://example.com/#blah" because the first line in urlByRemovingComponent always returns kCFNotFound
I'm stumped. Is there a better way of going about this?
Working Code, thanks to nall
-(NSURL *)urlByRemovingFragment {
NSString *urlString = [self absoluteString];
// Find that last component in the string from the end to make sure to get the last one
NSRange fragmentRange = [urlString rangeOfString:#"#" options:NSBackwardsSearch];
if (fragmentRange.location != NSNotFound) {
// Chop the fragment.
NSString* newURLString = [urlString substringToIndex:fragmentRange.location];
return [NSURL URLWithString:newURLString];
} else {
return self;
}
}

Answer 1

How about this:
NSString* s = #"http://www.somewhere.org/foo/bar.html/#label";
NSURL* u = [NSURL URLWithString:s];
// Get the last path component from the URL. This doesn't include
// any fragment.
NSString* lastComponent = [u lastPathComponent];
// Find that last component in the string from the end to make sure
// to get the last one
NSRange fragmentRange = [s rangeOfString:lastComponent
options:NSBackwardsSearch];
// Chop the fragment.
NSString* newURLString = [s substringToIndex:fragmentRange.location + fragmentRange.length];
NSLog(#"%#", s);
NSLog(#"%#", newURLString);

Answer 2

This is quite an old question, and it has already been answered, but for another simple option this is how I did it:
NSString* urlAsString = [myURL absoluteString];
NSArray* components = [urlAsString componentsSeparatedByString:#"#"];
NSURL* myURLminusFragment = [NSURL URLWithString: components[0]];
if there is no fragment, urlMinusFragment will be the same as myURL

Answer 3

Swift 3.0
this will remove the fragment
if let fragment = url.fragment{
url = URL(string: url.absoluteString.replacingOccurrences(of: "#\(fragment)", with: "")!
}