Codeigniter: simple form function - codeigniter

I'm stuck writing a simple form...I feel dumb.
Here's my controller:
function welcome_message(){
//Update welcome message
$id = $this->session->userdata('id');
$profile['welcome_message'] = $this->input->post('welcome_message');
$this->db->update('be_user_profiles',$profile, array('user_id' => $id));
}
And the html:
<?php print form_open('home/welcome_message')?>
<input type="checkbox" value="0" checked="false">Don't show me this again</input>
<p>
<input class="button submit" type="submit" class="close-box" value="Close" />
</p>
<?php print form_close()?>
Edit
I simply need it to submit to a private function and return to the home page (page submitted from).

You have to name your input...?
<input type="checkbox" value="0" name="welcome_message" checked="false">
Don't show me this again
</input>
EDIT: You can't submit to a private function via the URL (in a default CI installation, anyway).
Do it like this:
function welcome_message()
{
if(isset($_POST['welcome_message']))
{
$this->_my_private_function();
}
}
private function _my_private_function()
{
// do your thing with the $_POST data
redirect('your/uri', 'location');
}
But you really don't have to redirect if your returning to the same page (controller method) that called the private function in the first place. Would be a waste.

Related

GET Data empty in Laravel

Hi I am new to Laravel and so far I made good progress. Right now my head is blocked now and I need some direction or help, please.
I am getting data from radio button but GET Data is empty. I need to fill-in this data (pay) into an exist DB and I am getting "Creating default object from empty value" and I agree with Laravel :) I guess, my lack of knowledge is blocking me here.
Thanks.
This is the GET and POST data
GET Data empty
POST Data
_token = "72nrnI7Y7xuIQJe6LZPLGLzNsAv6ZZbY29zkjcIr"
pay = "CC"`
This is the Model
namespace App;
use Illuminate\Database\Eloquent\Model;
use DB;
use Auth;
class DAddress extends Model
{
protected $table='dAddress';
protected $fillable = ['payment_method'];
public function createPay()
{
$user = Auth::user();
$order = $user->daddress()->create([
'payment_method' => paymentMethod()
]);
}
}
This is the Controller
public function paymentMethod(Request $request) {
$address->payment_method = $request->pay;
DAddress::createPay();
Cart::destroy();
return redirect('abc');
}
This is where I get the HTML data
<form action="{{url('/paymentMethod')}}" method="post">
<input type="hidden" value="{{csrf_token()}}" name="_token"/>
<div class="form-group">
<div class="col-md-6">
<!-- First name -->
<input type="radio" class="form-control" name="pay"
value="CC"><i class="fa fa-credit-card"></i> Credit Card
<br> <br>
<input type="radio" class="form-control" name="pay"
value="PP"><i class="fa fa-paypal"></i> Paypal
<br> <br>
<input type="radio" class="form-control" name="pay"
value="BT"><i class="fa fa-university"></i> Bank Transfer
</div>
</div>
<input type="submit" class="btn btn-primary" value="Move to Last Page" />
This is the User.php I added below function.
public function daddress()
{
return $this->hasMany(DAddress::class);
}
i do not understand what you are trying to do with this line $address->payment_method = $request->pay;
when you say $address->payment_method, what is the $address object holding and where is payment_method you are trying to access, why not do something like this $payment_method = $request->pay, except is you are setting $payment_method as a global variable
if you are using the laravel create method you could do something like this $payment_method= App\createPay::create(['payment_method' => $request->pay]);
else you could instantiate you model like
$pay =createPay();
$pay->payment_method=$request->pay;
$pay->save();
i would have love you logic to be in the controller, i would have done something like this in my controller
public function createPay(Request $request){
$user = Auth::user();
$id=$user->id;
$payment=createPay::find($id);
$payment->payment_method=$request->pay;
$payment->save();
return redirect('abc');
}
i used laravel eloquent here, that is if you want to update a record, i don't know if this is close to what you want.

Laravel - Upload to Existing Model Record

Maybe it's because I'm tired, but I can't seem to get a simple upload working for one of my models.
On the show details page of my customers (who are NOT users) model, I have a simple form where a user can upload the logo of the customer.
The form:
<form enctype="multipart/form-data" action="/customers/i/{{$customer->url_string}}" method="POST">
<input type="file" name="logoUpload">
<input type="hidden" name="_token" value="{{csrf_token()}}">
<input type="submit" class="pull-right btn btn-sm btn-primary" value="Upload">
</form>
The Controller:
public function logoUpload(Request $request){
if($request->hasFile('logoUpload')){
$path = Storage::putFile('public/customer/uploads', new File(request('logoUpload')));
$customer->car_logo = $path;
$customer->save();
return back();
}
}
I know the issue is that I haven't defined $customer in the controller since the file does actually store itself in the correct folder after I click submit, but it does not hit the database at all.
Update
The current customer details url:
http://localhost:8000/customers/i/dsdado9a98w78721
The web definition for the post route:
Route::post('/customers/i/{customer}', 'CustomerController#logoUpload');
You have to create a hidden field in your form that contains the customer id and then use it in your controller to update it with the new file path, here is an example:
View
<form enctype="multipart/form-data" action="/customers/i/{{$customer->url_string}}" method="POST">
<input type="file" name="logoUpload">
<input type="hidden" name="_token" value="{{csrf_token()}}">
<!-- customer_id field -->
<input type="hidden" name="customer_id" value="{{$customer->id}}">
<input type="submit" class="pull-right btn btn-sm btn-primary" value="Upload">
</form>
Controller
public function logoUpload(Request $request){
if($request->hasFile('logoUpload')){
$path = Storage::putFile('public/customer/uploads', new File(request('logoUpload')));
// get customer
$customer = Customer::find($request->customer_id);
$customer->car_logo = $path;
$customer->save();
return back();
}
}
You have some options, here is a simple one, with only adjusting that controller method:
public function logoUpload(Request $request, $customer)
{
$customer = Customer::where('url_string', $customer)->firstOrFail();
if($request->hasFile('logoUpload')){
$path = Storage::putFile('public/customer/uploads', new File(request('logoUpload')));
$customer->car_logo = $path;
$customer->save();
return back();
}
...
}
We have added a parameter to the method signature to accept the route parameter. We then find the model via url_string matching that parameter.
You also could setup route model binding as well to do the resolving of that model based on the route parameter for you.

How can I pass my search keyword to my Controller?

I'm learning laravel 5.4 and i'm doing a sample project. In that I need to do a search from my DB. Below i have attached a screenshot of my interface.
As you can see in the searchbox i have given i need to search "malabe". And i need to get results for that. i have implemented Controller and needed views too. below i have attached my controller
class SearchController extends Controller
{
//search controller
public function search($keydown){
$searchDetails = DB::table('van_Services')
->where('vs_RouteTo','like','%'.$keydown.'%')
->orwhere('vs_RouteFrom','like','%'.$keydown.'%')
->orwhere('vs_Description','like','%'.$keydown.'%')
->orderBy('created_at', 'DESC')
->paginate(12);
return view('search.search', compact('searchDetails'));
}
}
route code
Route::get('/search/{key}','SearchController#search');
here is the div of my search box code,
<div class="col-xs-6 col-sm-2 col-md-2">
<div class="search_box pull-right">
{{--Search Button--}}
<input type="text" name="search" id="search" laceholder="Search"/>
</div>
</div>
My route and code works if i do the url manual,
my problem is how can i make my search box work? any tutorials or tips?
1. If you really need to use URL link.
JS solution is:
// q => Your search word
function redirectSearch(q) {
location.href = '/search/'+q;
}
pass search field value to this function and page redirect automatically.
.
2. You can send GET params to controller.
Front code:
<div class="col-xs-6 col-sm-2 col-md-2">
<div class="search_box pull-right">
<form action="/search" method="GET">
{{--Search Button--}}
<input type="text" name="search" id="search" placeholder="Search"/>
</form>
</div>
Controller code:
public function search(Request $request){
$search = $request->search;
... Your code ...
}
If you use method with request don`t forget about
use Illuminate\Http\Request;
Route:
Route::get('/search','SearchController#search');
My route and code works if i do the url manual,
I assume it's already working and redirection is just your problem.
Just simply use JS/jQuery.
// when ENTER is pressed
$(document).keypress(function (e) {
if (e.which == 13) {
e.preventDefault();
window.location = APP_URL + "/search/" + $('#search').val();
}
});
Goodluck.

Hot Towel Angular data-ng-show not working during validation

Hello anyone has anyone tried doing a validation using angularjs in a with Hot Towel template?
Basically i have a property in my angular controller which is binded(two way) in my view.
I just want to do a simple required validation, and then show a <span> element with the message.
here is my controller code
(function () {
'use strict';
var controllerId = 'login';
angular.module('app').controller(controllerId, ['$scope', 'common', 'userservice','$location', login]);
function login($scope, common, userservice, $location) {
var getLogFn = common.logger.getLogFn;
var log = getLogFn(controllerId);
var vm = this;
vm.title = 'Login';
//view model for credentials
vm.email = null;
activate();
function activate() {
common.activateController([], controllerId)
.then(function () { log('Activated Login View'); });
}
}
})();
and this is my view
<div data-ng-controller="login as vm">
<form name="loginform" id="loginform" novalidate data-ng-submit="loginuser()">
<fieldset>
<legend>Login</legend>
<p>
<label>Email</label>
<input type="email" data-ng-model="email" placeholder="Email" required />
<span data-ng-show="loginform.email.$error.required">*</span>
</p>
</fieldset>
</form>
</div>
i dont know what the problem is, but the <span> just wont show. am i missing something?
You have to set 'name' attribute to your input email :
<input type="email" name="email" data-ng-model="email" placeholder="Email" required />
For each field of your form, angularjs will set a value like: loginform[name-attribute].
For your information, your span will be visible only when required error is triggered (when your email is not empty, your span will be hidden).
[EDIT] See this fiddle: http://jsfiddle.net/k82at

How can I upload a picture using Codeigniter

I want to know how I can upload an image and save its name in a database when using Codeigniter.
I am using a simple form tag for this, like:
<form action="./myaccount/index/" method="post" enctype="multipart/form-data">
<div>
<label for="pic">picture</label>
<input type="file" id="pic" name="pic" />
</div>
<input id="register-btn" name="register" type="submit" value="ok" class="input-text custom-btn">
</form>
Here's my controller:
public function index() {
$user = new User($_SESSION['user_id']);
if($this->input->post()){
$user->pic = $this->input->post('pic');
if($this->input->post('password') == $this->input->post('confirm')){
$user->password=md5(sha1(sha1($this->input->post('password'))));
$user->save();
$this->data['success'] = "done";
}else{
$this->errors[] = "error";
}
}
$this->data['user'] = $user;
$this->data['errors'] = $this->errors;
$this->template->set_layout('myaccount');
$this->template->build('profile',$this->data);
}
I checked the manual but I can't understand what they are doing.
Im' trying to make a controler function for this that will insert all the values in the database and also upload the image file.

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