What are $# and $< in a Makefile? [duplicate] - makefile

This question already has answers here:
What do $< and $# represent in a Makefile?
(2 answers)
Closed 7 years ago.
For example in
$(CC) $(CFLAGS) -c -o $# $<
what do they mean?

$# The file name of the target.
$< The name of the first dependency.
For more details: Makefile symbol reference

$# is the name of the target being built - the program or object file being created.
$< is the name of the file that caused it to be rebuilt is the name of the file 'whose existence allowed the inference rule to be chose for the target'.
In the example, you might have:
program.o: program.c
${CC} ${CFLAGS} -c -o $# $<
In this case, $# is 'program.o' and $< is 'program.c'. (The rule must be generating an object file because of the '-c' option.)
Beware '$<'; if there was a header that was more recent than the program, '$<' would match that instead - and then the compile line wouldn't work. As shown, it is safe enough, though.
Beta comments about '$<'...
The POSIX definition of 'make' says:
$<
In an inference rule, the $< macro shall evaluate to the filename whose existence allowed the inference rule to be chosen for the target. In the .DEFAULT rule, the $< macro shall evaluate to the current target name. The meaning of the $< macro shall be otherwise unspecified.
For example, in the .c.a inference rule, $< represents the prerequisite .c file.
So, in the example I gave, '$<' is technically 'unspecified'. And, in the correct context,
which would be:
.c.o:
${CC} ${CFLAGS} -c -o $# $<
Then '$<' is unconditionally 'progname.c' when 'progname.o' is being built.
Some versions of 'make' used to do weird things with it; both GNU Make (3.81) and Solaris 10 make seem to behave sanely. I'm caught in a time-warp, I suspect. I used the following makefile:
all: x.o
x.o: x.c
${CC} ${CFLAGS} -c -o $# $<
x.o: x.h
I used 'echo "int main(){return 0;}" > x.c' and 'echo > x.h' to create the code. It didn't matter which file was touched out of 'x.c' and 'x.h'; either way, the compilation was 'correct'. I have an old make-derivative which was, circa 1992, compatible with Sun MAKE of the time in most respects, that mishandles it.
The 7th Edition UNIX Programmer's Manual says:
The rule to create a file with suffix s2 that depends on a similarly named file with suffix s1 is specified
as an entry for the ‘target’ s1s2. In such an entry, the special macro $* stands for the target name with
suffix deleted, $# for the full target name, $< for the complete list of prerequisites, and $? for the list
of prerequisites that are out of date.
It doesn't say anything about what it means outside that context. I note that 7th Edition 'make' would list both 'x.c' and 'x.h' for '$<' - but POSIX says that is incorrect.
The SUN "make User's Guide" (Revision A of 16 March 1987) says:
$< The name of the dependency file, as if selected by make for use with an implicit rule.
That more or less conforms to what you now see.
Oh well, such is life; things change around you. Sometimes you spot it happening; sometimes you don't.

Related

GNU make generate assembly first, them compile them to .o and link

SOURCE=a.c b.c c.c
ASM=$(patsubst %.c,%.s, $(SOURCE))
all:%.o
gcc -o test $^
$(ASM):%.c
gcc -S -o $# $<
%.o:%.s
gcc -c -o$# $<
I want to generate assembly code (.s) first, then compile the assembly code to object (.o), then link them.
But it seems above makefile code does not work. What is the correct code?
When asking questions, does not work is never very useful... if it worked you probably wouldn't be asking a question! :-) Instead you should always show the command you ran and the output you received (or at least the failing part of the output if it's long). Please cut and paste the actual text rather than paraphrasing messages. Also, including the version of the make program you're using (make --version) and the platform you're running on is often helpful.
Luckily this time we can figure out the problem without this information:
This:
$(ASM):%.c
gcc -S -o $# $<
where ASM is a.s b.s c.s, is not a pattern rule because the targets don't contain a pattern character %. That means the prerequisite %.c is not treated as a pattern, but as an actual file name, literally %.c which obviously doesn't exist.
Similarly, this:
all: %.o
has the same problem: all is a target, so this depends on the literal file named %.o which doesn't exist, and can't be created.
Also as a general rule every recipe that creates a target must create the actual target you told make it would, so this all rule is wrong because the target name is all but the recipe creates the target test.
Finally, it's a very bad idea to name your program test because test is a common UNIX program and a shell built-in, so if you run test it won't do the right thing (if you run ./test it will work).
You want to have all depend on the program you want to build, say mytest, and mytest should depend on the actual .o files:
all: mytest
mytest: $(SOURCE:.c=.o)
gcc -o $# $^
Next, you need to define a pattern rule that knows how to create an assembly file from a source file:
%.s : %.c
gcc -S -o $# $<
That, along with your other pattern rules, is all you need: make will figure it all out from that.
Finally, make has a built-in rule that tells it how to build object files directly from source files. It's best to get rid of this to force make to use your rules; add this to your makefile to delete it:
%.o : %.c

Makefile Syntax unclear

This is my first Makefile, and I am can't figure out some of the syntax used. The questions are marked below.
$(BUILD_DIR)/%.o: %.c $(BUILD_DIR)
$(CC) -c $(CFLAGS) -Wa,-a,-ad,-alms=$(BUILD_DIR)/$(notdir $(<:.c=.lst)) $< -o $#
What is the usage of "$(BUILD_DIR)" in the dependency?
What is the meaning of "$(BUILD_DIR)/$(notdir $(<:.c=.lst)) $< -o $#" in the role?
As with most computer languages the syntax of make cannot be clear if you don't know it. If you are using GNU make the GNU make manual is your friend. In the following explanations I will assume that BUILD_DIR = build and that one of the source files is bar/foo.c.
$(BUILD_DIR) in the list of prerequisites (dependencies) tells make that the build directory (in which object files are supposed to go) must exist before the recipe is executed; logical. There must be another rule somewhere to create the directory if it does not exist yet. Something like:
$(BUILD_DIR):
mkdir -p $#
But unless you forgot to copy an important character, this dependency is terribly sub-optimal. As the last modification time of a directory changes each time its content changes (files or sub-directories added or removed), it will force the re-compilation of all source files every time the directory changes, which is not what you want. A better dependency would be order-only:
$(BUILD_DIR)/%.o: %.c | $(BUILD_DIR)
that tells make to consider only the existence of $(BUILD_DIR), not its last modification time, when deciding to re-build or not.
$(BUILD_DIR)/$(notdir $(<:.c=.lst)) $< -o $# is just a combination of make automatic variables and functions.
$< and $# expand as the first prerequisite (bar/foo.c) and the target (build/bar/foo.o) respectively.
$(<:.c=.lst) replaces .c by .lst in $<: bar/foo.lst.
$(notdir $(<:.c=.lst)) removes the directory part: foo.lst.
All in all, for a bar/foo.c source file, and with BUILD_DIR = build, the pattern rule would be equivalent to:
build/bar/foo.o: bar/foo.c | build
$(CC) -c $(CFLAGS) -Wa,-a,-ad,-alms=build/foo.lst bar/foo.c -o build/bar/foo.o
Note that there are two different situations to consider:
All your source files are in the same directory as the Makefile (no bar/foo.c, just foo.c). Then you can simplify your recipe:
$(CC) -c $(CFLAGS) -Wa,-a,-ad,-alms=$(BUILD_DIR)/$(<:.c=.lst) $< -o $#
because the $(notdir...) is useless.
Your source files can be in sub-directories (bar/foo.c). Then you need the $(notdir...) in your recipe. But be warned that if you have two source files with the same base name (bar/foo.c and baz/foo.c) you will have a name conflict for $(BUILD_DIR)/foo.lst and your Makefile will not work as expected. Moreover, the order-only prerequisite of the rule should be equivalent to build/bar (or build/baz), not just build. And there should be a rule to create it if needed. If it is your case I suggest to change your pattern rule for:
$(BUILD_DIR)/%.o: %.c
mkdir -p $(dir $#)
$(CC) -c $(CFLAGS) -Wa,-a,-ad,-alms=$(BUILD_DIR)/$(notdir $(<:.c=.lst)) $< -o $#
There are other solutions (secondary expansion...) but there are a bit too complicated for this already too long answer.

Assignment of variable in GNU Makefile

I am new in GNU make. I have a problem understanding Makefile program inside NETAL software (it can be downloaded from here).
Inside folder NETAL, there is a file Makefile which includes other files such as make.inc and make.headers.
I understand most of the rules in Makefile inside folder NETAL, except for these:
Line 16 and 22. $(LINK.o) $^ $(LDLIBS) $(OUTPUT_OPTION)
What does $(LINK.o) and $(OUTPUT_OPTION) refer to? I cannot find a definition/assignment of these variable anywhere (neither in make.inc and make.headers).
Line 26 and 30. $(COMPILE.c) $< $(OUTPUT_OPTION)
Same problem with variable $(COMPILE.c). I can't find its assignment anywhere, and what it refers to. Also I don't understand the meaning of $< (and why "<" has to be preceded by a dollar sign "$"). I know dollar sign is for variable, just like in PHP.
I have knocked myself out reading the manual (RTFM, I know): GNU make manual
And this is the result of my reading: In Chapter 4.3 Types of Prerequisites, I found an example which similar with what I am looking for:
OBJDIR := objdir
OBJS := $(addprefix $(OBJDIR)/,foo.o bar.o baz.o)
$(OBJDIR)/%.o : %.c
$(COMPILE.c) $(OUTPUT_OPTION) $<
all: $(OBJS)
$(OBJS): | $(OBJDIR)
$(OBJDIR):
mkdir $(OBJDIR)
Unfortunately, there is no explanation about what is "$(COMPILE.c)", "$(OUTPUT_OPTION)", and "$<" .
Can someone explain it to me in a way that is easier for me to understand?
Or give me a link/keyword so that I can Google further.
These are prefedined make variables. From the GNU make manual:
Every rule that produces an object file uses the variable OUTPUT_OPTION. make defines this variable either to contain ‘-o $#’, or to be empty, depending on a compile-time option.
and
make follows the convention that the rule to compile a .x source file uses the variable COMPILE.x. Similarly, the rule to produce an executable from a .x file uses LINK.x; and the rule to preprocess a .x file uses PREPROCESS.x.

What is the syntax for copying in makefile [duplicate]

CC=g++
CFLAGS=-c -Wall
LDFLAGS=
SOURCES=main.cpp hello.cpp factorial.cpp
OBJECTS=$(SOURCES:.cpp=.o)
EXECUTABLE=hello
all: $(SOURCES) $(EXECUTABLE)
$(EXECUTABLE): $(OBJECTS)
$(CC) $(LDFLAGS) $(OBJECTS) -o $#
.cpp.o:
$(CC) $(CFLAGS) $< -o $#
What do the $# and $< do exactly?
$# is the name of the target being generated, and $< the first prerequisite (usually a source file). You can find a list of all these special variables in the GNU Make manual.
For example, consider the following declaration:
all: library.cpp main.cpp
In this case:
$# evaluates to all
$< evaluates to library.cpp
$^ evaluates to library.cpp main.cpp
From Managing Projects with GNU Make, 3rd Edition, p. 16 (it's under GNU Free Documentation License):
Automatic variables are set by make after a rule is matched. They
provide access to elements from the target and prerequisite lists so
you don’t have to explicitly specify any filenames. They are very
useful for avoiding code duplication, but are critical when defining
more general pattern rules.
There are seven “core” automatic variables:
$#: The filename representing the target.
$%: The filename element of an archive member specification.
$<: The filename of the first prerequisite.
$?: The names of all prerequisites that are newer than the target,
separated by spaces.
$^: The filenames of all the prerequisites, separated by spaces. This
list has duplicate filenames removed since for most uses, such as
compiling, copying, etc., duplicates are not wanted.
$+: Similar to $^, this is the names of all the prerequisites separated
by spaces, except that $+ includes duplicates. This variable was
created for specific situations such as arguments to linkers where
duplicate values have meaning.
$*: The stem of the target filename. A stem is typically a filename
without its suffix. Its use outside of pattern rules is
discouraged.
In addition, each of the above variables has two variants for
compatibility with other makes. One variant returns only the directory
portion of the value. This is indicated by appending a “D” to the
symbol, $(#D), $(<D), etc. The other variant returns only the file
portion of the value. This is indicated by appending an “F” to the
symbol, $(#F), $(<F), etc. Note that these variant names are more than
one character long and so must be enclosed in parentheses. GNU make
provides a more readable alternative with the dir and notdir
functions.
The $# and $< are called automatic variables. The variable $# represents the name of the target and $< represents the first prerequisite required to create the output file.
For example:
hello.o: hello.c hello.h
gcc -c $< -o $#
Here, hello.o is the output file. This is what $# expands to. The first dependency is hello.c. That's what $< expands to.
The -c flag generates the .o file; see man gcc for a more detailed explanation. The -o specifies the output file to create.
For further details, you can read this article on linoxide about Linux Makefiles.
Also, you can check the GNU make manuals. It will make it easier to make Makefiles and to debug them.
If you run this command, it will output the makefile database:
make -p
The $# and $< are special macros.
Where:
$# is the file name of the target.
$< is the name of the first dependency.
The Makefile builds the hello executable if any one of main.cpp, hello.cpp, factorial.cpp changed. The smallest possible Makefile to achieve that specification could have been:
hello: main.cpp hello.cpp factorial.cpp
g++ -o hello main.cpp hello.cpp factorial.cpp
pro: very easy to read
con: maintenance nightmare, duplication of the C++ dependencies
con: efficiency problem, we recompile all C++ even if only one was changed
To improve on the above, we only compile those C++ files that were edited. Then, we just link the resultant object files together.
OBJECTS=main.o hello.o factorial.o
hello: $(OBJECTS)
g++ -o hello $(OBJECTS)
main.o: main.cpp
g++ -c main.cpp
hello.o: hello.cpp
g++ -c hello.cpp
factorial.o: factorial.cpp
g++ -c factorial.cpp
pro: fixes efficiency issue
con: new maintenance nightmare, potential typo on object files rules
To improve on this, we can replace all object file rules with a single .cpp.o rule:
OBJECTS=main.o hello.o factorial.o
hello: $(OBJECTS)
g++ -o hello $(OBJECTS)
.cpp.o:
g++ -c $< -o $#
pro: back to having a short makefile, somewhat easy to read
Here the .cpp.o rule defines how to build anyfile.o from anyfile.cpp.
$< matches to first dependency, in this case, anyfile.cpp
$# matches the target, in this case, anyfile.o.
The other changes present in the Makefile are:
Making it easier to changes compilers from g++ to any C++ compiler.
Making it easier to change the compiler options.
Making it easier to change the linker options.
Making it easier to change the C++ source files and output.
Added a default rule 'all' which acts as a quick check to ensure all your source files are present before an attempt to build your application is made.
in exemple if you want to compile sources but have objects in an different directory :
You need to do :
gcc -c -o <obj/1.o> <srcs/1.c> <obj/2.o> <srcs/2.c> ...
but with most of macros the result will be all objects followed by all sources, like :
gcc -c -o <all OBJ path> <all SRC path>
so this will not compile anything ^^ and you will not be able to put your objects files in a different dir :(
the solution is to use these special macros
$# $<
this will generate a .o file (obj/file.o) for each .c file in SRC (src/file.c)
$(OBJ):$(SRC)
gcc -c -o $# $< $(HEADERS) $(FLAGS)
it means :
$# = $(OBJ)
$< = $(SRC)
but lines by lines INSTEAD of all lines of OBJ followed by all lines of SRC

What do the makefile symbols $# and $< mean?

CC=g++
CFLAGS=-c -Wall
LDFLAGS=
SOURCES=main.cpp hello.cpp factorial.cpp
OBJECTS=$(SOURCES:.cpp=.o)
EXECUTABLE=hello
all: $(SOURCES) $(EXECUTABLE)
$(EXECUTABLE): $(OBJECTS)
$(CC) $(LDFLAGS) $(OBJECTS) -o $#
.cpp.o:
$(CC) $(CFLAGS) $< -o $#
What do the $# and $< do exactly?
$# is the name of the target being generated, and $< the first prerequisite (usually a source file). You can find a list of all these special variables in the GNU Make manual.
For example, consider the following declaration:
all: library.cpp main.cpp
In this case:
$# evaluates to all
$< evaluates to library.cpp
$^ evaluates to library.cpp main.cpp
From Managing Projects with GNU Make, 3rd Edition, p. 16 (it's under GNU Free Documentation License):
Automatic variables are set by make after a rule is matched. They
provide access to elements from the target and prerequisite lists so
you don’t have to explicitly specify any filenames. They are very
useful for avoiding code duplication, but are critical when defining
more general pattern rules.
There are seven “core” automatic variables:
$#: The filename representing the target.
$%: The filename element of an archive member specification.
$<: The filename of the first prerequisite.
$?: The names of all prerequisites that are newer than the target,
separated by spaces.
$^: The filenames of all the prerequisites, separated by spaces. This
list has duplicate filenames removed since for most uses, such as
compiling, copying, etc., duplicates are not wanted.
$+: Similar to $^, this is the names of all the prerequisites separated
by spaces, except that $+ includes duplicates. This variable was
created for specific situations such as arguments to linkers where
duplicate values have meaning.
$*: The stem of the target filename. A stem is typically a filename
without its suffix. Its use outside of pattern rules is
discouraged.
In addition, each of the above variables has two variants for
compatibility with other makes. One variant returns only the directory
portion of the value. This is indicated by appending a “D” to the
symbol, $(#D), $(<D), etc. The other variant returns only the file
portion of the value. This is indicated by appending an “F” to the
symbol, $(#F), $(<F), etc. Note that these variant names are more than
one character long and so must be enclosed in parentheses. GNU make
provides a more readable alternative with the dir and notdir
functions.
The $# and $< are called automatic variables. The variable $# represents the name of the target and $< represents the first prerequisite required to create the output file.
For example:
hello.o: hello.c hello.h
gcc -c $< -o $#
Here, hello.o is the output file. This is what $# expands to. The first dependency is hello.c. That's what $< expands to.
The -c flag generates the .o file; see man gcc for a more detailed explanation. The -o specifies the output file to create.
For further details, you can read this article on linoxide about Linux Makefiles.
Also, you can check the GNU make manuals. It will make it easier to make Makefiles and to debug them.
If you run this command, it will output the makefile database:
make -p
The $# and $< are special macros.
Where:
$# is the file name of the target.
$< is the name of the first dependency.
The Makefile builds the hello executable if any one of main.cpp, hello.cpp, factorial.cpp changed. The smallest possible Makefile to achieve that specification could have been:
hello: main.cpp hello.cpp factorial.cpp
g++ -o hello main.cpp hello.cpp factorial.cpp
pro: very easy to read
con: maintenance nightmare, duplication of the C++ dependencies
con: efficiency problem, we recompile all C++ even if only one was changed
To improve on the above, we only compile those C++ files that were edited. Then, we just link the resultant object files together.
OBJECTS=main.o hello.o factorial.o
hello: $(OBJECTS)
g++ -o hello $(OBJECTS)
main.o: main.cpp
g++ -c main.cpp
hello.o: hello.cpp
g++ -c hello.cpp
factorial.o: factorial.cpp
g++ -c factorial.cpp
pro: fixes efficiency issue
con: new maintenance nightmare, potential typo on object files rules
To improve on this, we can replace all object file rules with a single .cpp.o rule:
OBJECTS=main.o hello.o factorial.o
hello: $(OBJECTS)
g++ -o hello $(OBJECTS)
.cpp.o:
g++ -c $< -o $#
pro: back to having a short makefile, somewhat easy to read
Here the .cpp.o rule defines how to build anyfile.o from anyfile.cpp.
$< matches to first dependency, in this case, anyfile.cpp
$# matches the target, in this case, anyfile.o.
The other changes present in the Makefile are:
Making it easier to changes compilers from g++ to any C++ compiler.
Making it easier to change the compiler options.
Making it easier to change the linker options.
Making it easier to change the C++ source files and output.
Added a default rule 'all' which acts as a quick check to ensure all your source files are present before an attempt to build your application is made.
in exemple if you want to compile sources but have objects in an different directory :
You need to do :
gcc -c -o <obj/1.o> <srcs/1.c> <obj/2.o> <srcs/2.c> ...
but with most of macros the result will be all objects followed by all sources, like :
gcc -c -o <all OBJ path> <all SRC path>
so this will not compile anything ^^ and you will not be able to put your objects files in a different dir :(
the solution is to use these special macros
$# $<
this will generate a .o file (obj/file.o) for each .c file in SRC (src/file.c)
$(OBJ):$(SRC)
gcc -c -o $# $< $(HEADERS) $(FLAGS)
it means :
$# = $(OBJ)
$< = $(SRC)
but lines by lines INSTEAD of all lines of OBJ followed by all lines of SRC

Resources