Configure a JMS (ActiveMQ) queue so that it only contains the last message - jms

We have quartz process that polls a ActiveMQ JMS queue.
We know that we could get several messages a minute would like to only respond to the most current message at a configured polling rate of a minute or more.
We don't need to process any of the previous messages.
Is there a way to configure the queue to get this behavior?
Its seems like a topic has the ability to do this via the subscription recovery policy using a count of 1. We would like to do this using a queue to guarantee (more or less) a single delivery of the message.
Or is there a conceptual flaw in our assumptions...
Thanks

In my opinion there is no standard operation for this, so you will have to write some code....
One possible solution would be to use a QueueBrowser together with a QueueReceiver:
Through the QueueReceiver you would get an Enumeration of the messages in the queue. For each message you can now perform a receive with a MessageSelector on the JMSMessageID as long as hasMoreElements() returns true. The last message will be the one you want to have....

When using activemq, you can use "image caching" on topics. One of the settings there is to always keep the last mesage sent..
Take a look at the Subscription recovery Policy settings:
http://activemq.apache.org/subscription-recovery-policy.html

Related

ActiveMQ - Competing Consumers with Selector - messages starve in the queue

ActiveMQ 5.15.13
Context: I have a single queue with multiple Consumers. I want to stop some consumers from processing certain messages. This has to be dynamic, I don't want to create separate queues for this. This works without any problems. e.g. Consumer1 ignores Stocks -> Consumer1 can process all invoices and Consumer2 can process all Stocks
But if there is a large number of messages already in the Queue (of one type, e.g. stocks) and I send a message of another type (e.g. invoices), Consumer1 won't process the message of type invoices. It will instead be idle until Consumer2 has processed all Stocks messages. It does not happen every time, but quite often.
Is there any option to change the order of the new messages coming into the queue, such that an idle consumer with matching selector picks up the new message?
Things I've already tried:
using a PendingMessageLimitStrategy -> it seems like it does not work for queues
increasing the maxPageSize and maxBrowsePageSize in the hope that once all Messages are in RAM, the Consumers will search for their messages.
Exclusive Consumers aren't an option since I want to be able to use more than one Consumer per message type.
Im pretty sure that there is some configuration which allows this type of usage. I'm aware that there are better solutions for this issue, but sadly I can't use them easily due to other constraints.
Thanks a lot in advance!
EDIT: I noticed that when I'm refreshing on the localhost queue browser, the stuck messages get executed immediately. It seems like this action performs some sort of queue refresh where the messages get filtered based on their selector again. So I just need this action whenever a new message enters the queue...
This is a 'window' problem where the next set of 'stocks' data needs to be processed before the 'invoicing' data can be processed.
The gotcha with window problems like this is that you need to account for the fact that some messages may never come through, or a consumer may never come back online either. Also, eventually you will be asked 'how many invoices or stocks are left to be processed'-- aka observability.
ActiveMQ has you covered-- check out wild-card destinations and consumers.
Produce 'stocks' to:
queue://data.stocks.input
Produce 'invoices' to:
queue://data.invoices.input
You then setup consumes to connect:
queue://data.*.input
note: the wildard '*'.
ActiveMQ will match queues based on the wildcard pattern, and then process data accordingly. As a bonus, you can still use a selector.

how to use same rabbitmq queue in different java microservice [duplicate]

I have implemented the example from the RabbitMQ website:
RabbitMQ Example
I have expanded it to have an application with a button to send a message.
Now I started two consumer on two different computers.
When I send the message the first message is sent to computer1, then the second message is sent to computer2, the thrid to computer1 and so on.
Why is this, and how can I change the behavior to send each message to each consumer?
Why is this
As noted by Yazan, messages are consumed from a single queue in a round-robin manner. The behavior your are seeing is by design, making it easy to scale up the number of consumers for a given queue.
how can I change the behavior to send each message to each consumer?
To have each consumer receive the same message, you need to create a queue for each consumer and deliver the same message to each queue.
The easiest way to do this is to use a fanout exchange. This will send every message to every queue that is bound to the exchange, completely ignoring the routing key.
If you need more control over the routing, you can use a topic or direct exchange and manage the routing keys.
Whatever type of exchange you choose, though, you will need to have a queue per consumer and have each message routed to each queue.
you can't it's controlled by the server check Round-robin dispatching section
It decides which consumer turn is. i'm not sure if there is a set of algorithms you can pick from, but at the end server will control this (i think round robin algorithm is default)
unless you want to use routing keys and exchanges
I would see this more as a design question. Ideally, producers should create the exchanges and the consumers create the queues and each consumer can create its own queue and hook it up to an exchange. This makes sure every consumer gets its message with its private queue.
What youre doing is essentially 'worker queues' model which is used to distribute tasks among worker nodes. Since each task needs to be performed only once, the message is sent to only one node. If you want to send a message to all the nodes, you need a different model called 'pub-sub' where each message is broadcasted to all the subscribers. The following link shows a simple pub-sub tutorial
https://www.rabbitmq.com/tutorials/tutorial-three-python.html

read messages from JMS MQ or In-Memory Message store by count

I want to read messages from JMS MQ or In-memory message store based on count.
Like I want to start reading the messages when the message count is 10, until that i want the message processor to be idle.
I want this to be done using WSO2 ESB.
Can someone please help me?
Thanks.
I'm not familiar with wso2, but from an MQ perspective, the way to do this would be to trigger the application to run once there are 10 messages on the queue. There are trigger settings for this, specifically TRIGTYPE(DEPTH).
To expand on Morag's answer, I doubt that WS02 has built-in triggers that would monitor the queue for depth before reading messages. I suspect it just listens on a queue and processes messages as they arrive. I also doubt that you can use MQ's triggering mechanism to directly execute the flow conveniently based on depth. So although triggering is a great answer, you need a bit of glue code to make that work.
Conveniently, there's a tutorial that provides almost all the information necessary to do this. Please see Mission:Messaging: Easing administration and debugging with circular queues for details. That article has the scripts necessary to make the Q program work with MQ triggering. You just need to make a couple changes:
Instead of sending a command to Q to delete messages, send a command to move them.
Ditch the math that calculates how many messages to delete and either move them in batches of 10, or else move all messages until the queue drains. In the latter case, make sure to tell Q to wait for any stragglers.
Here's what it looks like when completed: The incoming messages land on some queue other than the WS02 input queue. That queue is triggered based on depth so that the Q program (SupportPac MA01) copies the messages to the real WS02 input queue. After the messages are copied, the glue code resets the trigger. This continues until there are less than 10 messages on the queue, at which time the cycle idles.
I got it by pushing the message to db and get as per the count required as in this answer of me take a look at my answer

Camel JMS ensuring ordering when unsidelining from dead letter channel

I am using camel to integrate with ActiveMQ JMS. I am receiving prices for products on this queue. I am using JMSXGroupID on productId to ensure ordering across a productId. Now if I fail to process this message I move it to a DeadLetterQueue. This could be because of a connection error on a dependent service or because of error with the message itself.
In case of the former I would have to manually remove it from the DLQ and put it back into the JMS queue.
Now the problem is that I dont know if any other message on that groupId has been received and processed or not. And hence unsidelining from DLQ will disrupt the order. On the other hand if I dont unsideline it and no other message has been received the product Id will not get the correct price.
1 solution that I have in mind is to use a fast key-value store(Redis) to store the last messageId or JMSTimestamp against a productId(message group). This is updated everytime I dequeue a message. Any other solution for this?
Relying on message order in JMS is a risky business - at best.
The best thing to do is to make the receiver handle messages out of sequence as a special case (but may take advantage message order during normal operation).
You may also want to distinguish between two errors: posion messages and temporary connection problems, maybe even use two different error queues for them. In the case of a posion message (invalid payload etc.) then there is nothing you can really do about it except starting a bug investigation. In such cases, you can probably send along "something else", such as dummy message to not interfere with order.
For the issues with connection problems, you can have another strategy - ActiveMQ Redelivery Policies. If there is network trouble, it's usually no use in trying to process the second message until the first has been handled. A Redelivery Policy ensures that (given you have a single consumer, that is). There is another question at SO where the poster actually has a solution to your problem and wants to avoid it. Read it. :)

Delayed Message Queue Best Practice

I'm looking into a message queue solution where some messages need to be delivered without delay, and other messages need to be delivered at a specified time. The delay is anywhere from hours to a week or two. I have access to a JMS message Queue, but I'm questioning whether it is a good idea to put messages on the queue with long delays.
Is delaying messages a common practice?
Is using the QueueBrowser to peek at the messages and cherry picking the messages at the right time a viable solution (assuming the message as the delivery date in it)?
Is there another solution (other than putting the messages in the database with a time stamp) and periodically querying the database?
JMS 2.0 supports message delaying; see the spec, section 7.9: You can call setDeliveryDelay on the JMSProducer with the number of milliseconds you want messages to be delayed. (Note that, confusing as it is, you can not use the setJMSDeliveryTime method on the Message object.) In JMS 1.1, some JMS implementations support proprietary headers for the same effect.
It's a quite common practice, but it has a major drawback in practical use, when the delay is longer: There's no (standardized) way to access the delayed messages: The QueueBrowser doesn't return them until their time has come. If you need more control, you're better off with polling a database.

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