grep pipe with sed - bash

Question

This is my bash command
grep -rl "System.out.print" Project1/ |
xargs -I{} grep -H -n "System.out.print" {} |
cut -f-2 -d: |
sed "s/\(.*\):\(.*\)/filename is \1 and line number is \2/
What I'm trying to do here is,I'm trying to iterate through sub folders and check what files contains "System.out.print" (using grep)
using 2nd grep trying to get file names and line numbers
using sed command I display those to console.
from here I want to remove "System.out.print" with "XXXXX" how I can pipe sed command to this?
pls help me
thanxx

Answer 1

GNU sed has an option to change files in place:
find Project1/ -type f | xargs sed -i 's/System\.out\.print/XXXXX/g'
Btw, your script could be written as:
grep -rsn 'root' /etc/ |
awk -F: '{ print "filename is", $1, "and line number is", $2 }'

Answer 2

I'm just building on hop's answer, which I found to be more useful than find -exec. I had search_text dispersed all over my computer, in logs, config files and so on, but I didn't want to search (or especially change) anything in /dev, /sys, /proc, and so on. One note, read man xargs; it doesn't like file names with spaces.
grep -HriIl --exclude-dir=dev --exclude-dir=proc --exclude-dir=sys search_text / | xargs sed -i 's/search_text/replace_text/g'