Im working on a vbscript that is pulling data from excel to text. I currently have a column in an excel sheet with values like:
305 ABCDE
23 FTPXX
N3 TOY
3321 APPLE
I want to get the 2nd values to only show so that the data would look like
ABCDE
FTPXX
TOY
APPLE
I was thinking of trying to split the values and then replacing the first part of the value as "spaces" and just trimming the results.
Can someone help me with this or know a better way to do this?
Thanks in advance.
s1 = "305 ABCDE 23 FTPXX N3 TOY 3321 APPLE"
s2 = Split(s1, " ")
For i = 0 To UBound(s2) Step 2
s2(i) = " "
Next
s3 = trim(Join(s2, ""))
WScript.Echo s3
set myregexp = new RegExp
myregexp.IgnoreCase = True
myRegExp.Global = True
myRegExp.Pattern = "([a-zA-Z]+)"
Set myMatches = myRegExp.Execute(subjectString)
myMatches will hold any matches found within subjectString
Related
I tried almost all the methods (CLEAN,TRIM,SUBSTITUTE) trying to remove the character hiding in the beginning and the end of a text. In my case, I downloaded the bill of material report from oracle ERP and found that the item codes are a victim of hidden characters.
After so many findings, I was able to trace which character is hidden and found out that it's a question mark'?' (via VBA code in another thread) both at the front and the end. You can take this item code: 11301-21
If you paste the above into your excel and see its length =LEN(), you can understand my problem much better.
I need a good solution for this problem. Therefore please help!
Thank you very much in advance.
Thanks to Gary's Student, because his answer inspired me.
Also, I used this answer for this code.
This function will clean every single char of your data, so it should work for you. You need 2 functions: 1 to clean the Unicode chars, and other one to clean your item codes_
Public Function CLEAN_ITEM_CODE(ByRef ThisCell As Range) As String
If ThisCell.Count > 1 Or ThisCell.Count < 1 Then
CLEAN_ITEM_CODE = "Only single cells allowed"
Exit Function
End If
Dim ZZ As Byte
For ZZ = 1 To Len(ThisCell.Value) Step 1
CLEAN_ITEM_CODE = CLEAN_ITEM_CODE & GetStrippedText(Mid(ThisCell.Value, ZZ, 1))
Next ZZ
End Function
Private Function GetStrippedText(txt As String) As String
If txt = "–" Then
GetStrippedText = "–"
Else
Dim regEx As Object
Set regEx = CreateObject("vbscript.regexp")
regEx.Pattern = "[^\u0000-\u007F]"
GetStrippedText = regEx.Replace(txt, "")
End If
End Function
And this is what i get using it as formula in Excel. Note the difference in the Len of strings:
Hope this helps
You have characters that look like a space character, but are not. They are UniCode 8236 & 8237.
Just replace them with a space character (ASCII 32).
EDIT#1:
Based on the string in your post, the following VBA macro will replace UniCode characters 8236 amd 8237 with simple space characters:
Sub Kleanup()
Dim N1 As Long, N2 As Long
Dim Bad1 As String, Bad2 As String
N1 = 8237
Bad1 = ChrW(N1)
N2 = 8236
Bad2 = ChrW(N2)
Cells.Replace what:=Bad1, replacement:=" ", lookat:=xlPart
Cells.Replace what:=Bad2, replacement:=" ", lookat:=xlPart
End Sub
I have a string that contains digits inside. For example, "adf20j83n,m3jh2k9". Is there a direct way to count the number of digits inside the string. As in my example, it should give me "7" as an output.
Also, I have tried RegExp but it's not working in VBScript in QTP.
Btw, I'm not looking for loops and stuff like that. Just a direct way, or a suggestion to make this RegExp work in QTP.
You'll probably need to create the COM object via its ProgId:
Dim re
Set re = CreateObject("VBScript.RegExp")
re.Pattern = "\d"
re.Global = True
MsgBox "Digits: " & re.Execute("adf20j83n,m3jh2k9").Count
Output:
Digits: 7
I know it's techically what you said but it's a good way nonetheless
Try using this function:
Public Sub CountNumeric(ByVal input As String)
Dim numericCount As Integer = 0
For Each c As Char In input
If Char.IsDigit(c) Then numericCount += 1
Next
MessageBox.Show(String.Format("Number of numerics : {0}", numericCount)
End Sub
EDIT:
You could also try this:
Dim charColl As MatchCollection = Regex.Matches(input , "^\d+$")
Console.WriteLine(charColl.Count.ToString())
I've written a lot of IF statements in VBScript, but haven't gone much beyond that so apologize for my lack of experience. I hope what I'm asking is simple to do.
I want to output item identifiers created by three combined recordset field values and add "B" "C" "D" etc., to any duplicates. Duplicates are rare, but do happen occasionally. I want to do this for meaningful item identification which autonumbers do not provide.
The following example works to combine fields, but then I need to include script to loop and find the duplicates and add the appropriate alpha character.
FYI: a = alpha character, b = alpha character, c = reformatted date
<% Dim idCode
a = (rs_table.Fields.Item("CodeA").Value)
b = (rs_table.Fields.Item("CodeB").Value)
c = (fixedDate(rs_table.Fields.Item("Date").Value))
idCode = (a) & (b) & (c)
Response.write idCode
%>
example output: LC032414
example dupe output: LC032414B
Thanks, I'm almost afraid to ask and may find this more pain than what it's worth!
I would probably use a Dictionary to store the ID's, since you can add each as a key (which must be unique) and test the Dictionary for its existence. Something like this:
' Early on... create a dictionary...
Set d = CreateObject("Scripting.Dictionary")
' Loop through your records...
Do Until rs_table.EOF
' Determine your ID...
idCode = rs_table("CodeA") & rs_table("CodeB") & fixedDate(rs_table("Date"))
' Check for existence in the dictionary...
If d.Exists(idCode) Then
' ID already exists. Keep testing suffixes until we find an availability...
strLetter = "B"
Do While d.Exists(idCode & strLetter)
strLetter = Chr(Asc(strLetter) + 1)
Loop
d.Add idCode & strLetter, "" ' Add the ID/key. The value is unimportant.
Else
' This ID doesn't exist yet. Just add it.
d.Add idCode, "" ' Add the ID/key. The value is unimportant.
End If
rs_table.MoveNext
Loop
When it comes time to print your ID's, you can just iterate the dictionary's Keys collection:
For Each k In d.Keys
Response.Write k
Next
I know I can split a string into multiple substrings by giving a delimiter. I know I can also choose a substring based on character position like this:
sAddressOverflow = Right(sAddressLine1,5)
What I would like to do though is split an input string like this:
"123 South Main Street Apt. 24B"
But I only want to end up with two substrings which are split based on the first space to the left of the 25th character. So my desired output using the above input would be:
Substring1 = "123 South Main Street"
Substring2 = "Apt. 24B"
Is this possible?
Regular expressions have the advantage that you can configure your pattern independently from the location where you use it and that they are highly adaptable, so I prefer to do string manipulation with regular expressions. Unfortunately the pattern of Ansgar Wiechers does not exactly match your requirement. Here is one that does:
myString = "1234 6789A 234567 9B12 4567 890"
Set re = new RegExp
re.Pattern = "^(.{1,25}) (.*)$"
Set matches = re.Execute(myString)
wscript.echo "leftpart: " & matches(0).submatches(0)
wscript.echo "rightpart: " & matches(0).submatches(1)
There is no such inbuilt function available,
but you might want to try this,
add = "123 South Main Street Apt. 24B"
valid = Left(add,25)
arr = Split(valid)
char= InStrRev(add,arr(UBound(arr)))-1
address1 = Left(add,char)
address2= Right(add,Len(add)-char)
Wscript.echo address1
Wscript.echo address2
this might not be the perfect way, but it works !!!
You can do this with a regular expression, but you need a well defined format:
addr = "123 South Main Street Apt. 24B"
Set re = New RegExp
re.Pattern = "^(\d+ .*) +(apt\. +\d+(.*?))$"
re.IgnoreCase = True
Set m = re.Execute(addr)
If m.Count > 0 Then
WScript.Echo m(0).SubMatches(0)
WScript.Echo m(0).SubMatches(1)
End If
By "well-defined format" I mean that you need some "anchors" (or fix points) in your expression to identify the parts in the string. In the example the anchor is the substring "apt." followed by one or more digits.
I have 6400+ records which I am looping through. For each of these: I check that the address is valid by testing it against something similar to what the Post Office uses (find address). I need to double check that the postcode I have pulled back matches.
The only problem is that the postcode may have been inputted in a number of different formats for example:
OP6 6YH
OP66YH
OP6 6YH.
If Replace(strPostcode," ","") = Replace(xmlAddress.selectSingleNode("//postcode").text," ","") Then
I want to remove all spaces from the string. If I do the Replace above, it removes the space for the first example but leave one for the third.
I know that I can remove these using a loop statement, but believe this will make the script run really slow as it will have to loop through 6400+ records to remove the spaces.
Is there another way?
I didn't realise you had to add -1 to remove all spaces
Replace(strPostcode," ","",1,-1)
Personally I've just done a loop like this:
Dim sLast
Do
sLast = strPostcode
strPostcode = Replace(strPostcode, " ", "")
If sLast = strPostcode Then Exit Do
Loop
However you may want to use a regular expression replace instead:
Dim re : Set re = New RegExp
re.Global = True
re.Pattern = " +" ' Match one or more spaces
WScript.Echo re.Replace("OP6 6YH.", "")
WScript.Echo re.Replace("OP6 6YH.", "")
WScript.Echo re.Replace("O P 6 6 Y H.", "")
Set re = Nothing
The output of the latter is:
D:\Development>cscript replace.vbs
OP66YH.
OP66YH.
OP66YH.
D:\Development>
This is the syntax Replace(expression, find, replacewith[, start[, count[, compare]]])
it will default to -1 for count and 1 for start. May be some dll is corrupt changing the defaults of Replace function.
String.Join("", YourString.Split({" "}, StringSplitOptions.RemoveEmptyEntries))
Because you get all strings without spaces and you join them with separator "".