I have a string that contains digits inside. For example, "adf20j83n,m3jh2k9". Is there a direct way to count the number of digits inside the string. As in my example, it should give me "7" as an output.
Also, I have tried RegExp but it's not working in VBScript in QTP.
Btw, I'm not looking for loops and stuff like that. Just a direct way, or a suggestion to make this RegExp work in QTP.
You'll probably need to create the COM object via its ProgId:
Dim re
Set re = CreateObject("VBScript.RegExp")
re.Pattern = "\d"
re.Global = True
MsgBox "Digits: " & re.Execute("adf20j83n,m3jh2k9").Count
Output:
Digits: 7
I know it's techically what you said but it's a good way nonetheless
Try using this function:
Public Sub CountNumeric(ByVal input As String)
Dim numericCount As Integer = 0
For Each c As Char In input
If Char.IsDigit(c) Then numericCount += 1
Next
MessageBox.Show(String.Format("Number of numerics : {0}", numericCount)
End Sub
EDIT:
You could also try this:
Dim charColl As MatchCollection = Regex.Matches(input , "^\d+$")
Console.WriteLine(charColl.Count.ToString())
Related
I tried almost all the methods (CLEAN,TRIM,SUBSTITUTE) trying to remove the character hiding in the beginning and the end of a text. In my case, I downloaded the bill of material report from oracle ERP and found that the item codes are a victim of hidden characters.
After so many findings, I was able to trace which character is hidden and found out that it's a question mark'?' (via VBA code in another thread) both at the front and the end. You can take this item code: 11301-21
If you paste the above into your excel and see its length =LEN(), you can understand my problem much better.
I need a good solution for this problem. Therefore please help!
Thank you very much in advance.
Thanks to Gary's Student, because his answer inspired me.
Also, I used this answer for this code.
This function will clean every single char of your data, so it should work for you. You need 2 functions: 1 to clean the Unicode chars, and other one to clean your item codes_
Public Function CLEAN_ITEM_CODE(ByRef ThisCell As Range) As String
If ThisCell.Count > 1 Or ThisCell.Count < 1 Then
CLEAN_ITEM_CODE = "Only single cells allowed"
Exit Function
End If
Dim ZZ As Byte
For ZZ = 1 To Len(ThisCell.Value) Step 1
CLEAN_ITEM_CODE = CLEAN_ITEM_CODE & GetStrippedText(Mid(ThisCell.Value, ZZ, 1))
Next ZZ
End Function
Private Function GetStrippedText(txt As String) As String
If txt = "–" Then
GetStrippedText = "–"
Else
Dim regEx As Object
Set regEx = CreateObject("vbscript.regexp")
regEx.Pattern = "[^\u0000-\u007F]"
GetStrippedText = regEx.Replace(txt, "")
End If
End Function
And this is what i get using it as formula in Excel. Note the difference in the Len of strings:
Hope this helps
You have characters that look like a space character, but are not. They are UniCode 8236 & 8237.
Just replace them with a space character (ASCII 32).
EDIT#1:
Based on the string in your post, the following VBA macro will replace UniCode characters 8236 amd 8237 with simple space characters:
Sub Kleanup()
Dim N1 As Long, N2 As Long
Dim Bad1 As String, Bad2 As String
N1 = 8237
Bad1 = ChrW(N1)
N2 = 8236
Bad2 = ChrW(N2)
Cells.Replace what:=Bad1, replacement:=" ", lookat:=xlPart
Cells.Replace what:=Bad2, replacement:=" ", lookat:=xlPart
End Sub
I want to replace a particular value followed by TRN* to some other value.How to do the coding for the same?..Please provide an example.
For example :
TRN*12345*34444~
This is a segment in my file(like this I have many TRN* segments in my file).I want to replace the segment after TRN* and before next * (ie.12345)with some other value.
Is there any way to do this by using vbscript?
Thanks in advance
The regular expression way of safetyOtter is the way to go, you only have to fiddle with the pattern and replacement string:
originalString = "TRN*12345*34444~"
replaceValue = "78910"
Set re = new RegExp
re.Pattern = "(.*TRN\*)([^*]+)(.*)"
re.IgnoreCase = False
' This keeps the first and last part between parenthesis, but replaces the middle part
newString = re.Replace(originalString, "$1" & replaceValue & "$3")
msgbox newString
' result: TRN*78910*34444~
Something like this should work, may have to tweak, can't test it at the moment
Set regEx = New RegExp
regEx.Pattern = "TRN\*.*?\*"
regEx.IgnoreCase = True
replStr = "TRN*" & SomeOtherValue& "*"
ReplaceTest = regEx.Replace(YourStringHere, replStr)
Edit:
if you are looking to replace a specific number with another, a simple:
YourStringHere = Replace(YourStringHere,"TRN*12345*","TRN*67890*")
Is enough
I'd like to know how can i find out if a substring is contained in another string?
In VB.net I used to write something like:
Dim s as string = textbox1.text
if s.contains("http://youtube.com/watch?v=")
//instructions
end if
Basically, this is want I want to do but it doesn't work the same way in RealBasic, so how can I translate this?
You can do the same thing by using:
Dim s as string = textbox1.text
if s.instr("http://youtube.com/watch?v=") > 0 then
//instructions
end
I have 6400+ records which I am looping through. For each of these: I check that the address is valid by testing it against something similar to what the Post Office uses (find address). I need to double check that the postcode I have pulled back matches.
The only problem is that the postcode may have been inputted in a number of different formats for example:
OP6 6YH
OP66YH
OP6 6YH.
If Replace(strPostcode," ","") = Replace(xmlAddress.selectSingleNode("//postcode").text," ","") Then
I want to remove all spaces from the string. If I do the Replace above, it removes the space for the first example but leave one for the third.
I know that I can remove these using a loop statement, but believe this will make the script run really slow as it will have to loop through 6400+ records to remove the spaces.
Is there another way?
I didn't realise you had to add -1 to remove all spaces
Replace(strPostcode," ","",1,-1)
Personally I've just done a loop like this:
Dim sLast
Do
sLast = strPostcode
strPostcode = Replace(strPostcode, " ", "")
If sLast = strPostcode Then Exit Do
Loop
However you may want to use a regular expression replace instead:
Dim re : Set re = New RegExp
re.Global = True
re.Pattern = " +" ' Match one or more spaces
WScript.Echo re.Replace("OP6 6YH.", "")
WScript.Echo re.Replace("OP6 6YH.", "")
WScript.Echo re.Replace("O P 6 6 Y H.", "")
Set re = Nothing
The output of the latter is:
D:\Development>cscript replace.vbs
OP66YH.
OP66YH.
OP66YH.
D:\Development>
This is the syntax Replace(expression, find, replacewith[, start[, count[, compare]]])
it will default to -1 for count and 1 for start. May be some dll is corrupt changing the defaults of Replace function.
String.Join("", YourString.Split({" "}, StringSplitOptions.RemoveEmptyEntries))
Because you get all strings without spaces and you join them with separator "".
Is there something like this, that only leaves numbers, letters and underscore for spaces?
Server.URLEncode isn't quite what i'm looking for.
There is no an integrated function as you described in ASP.
But you can do with regular expressions.
May be as follows:
Function FileNameEncode(ByVal strFileName)
Dim oReg
Set oReg = New RegExp
oReg.IgnoreCase = True
oReg.Global = True
oReg.Pattern = "[^a-z\d\s.]+"
FileNameEncode = Replace(oreg.Replace(strFileName, ""), " ", "_")
Set oReg = Nothing
End Function
'FileNameEncode("letters é$- 123ÖÇ.bat") returns "letters__123.bat"
If you pass filename without extension as parameter, you could remove the dot char from pattern.