I have ./lib directory in my project, how can i copy dependencies to this directory in buildr?
You can get the tasks representing the dependencies for a project using project.compile.dependencies. You can get the path from a file task using #to_s. So you should be able to do something like this:
cp project.compile.dependencies.collect { |t| t.to_s }, project.path_to('lib')
Related
I have my archive at location myProject/unzip and need to:
Zip the contents within the unzip folder and create a zip file with some name at any location within the project.
Using gradle 2.3.
Can anyone help me for this?
I am not sure what you are doing differently than the examples in the documentation from the link I gave in the comments. But this works for me with Gradle 2.3:
task myZip(type: Zip){
from "$projectDir/unzip"
archiveName = "my-zip.zip"
destinationDir = buildDir
}
The input folder is called unzip and needs to present as a child in the project folder. It outputs a file my-zip.zip in the build folder.
Be sure that there actually are some resources located in the from path, or Gradle might skip it.
During my gradle build, I generate a temporary buildinfo.properties file containing things like Git commit info, build time, etc. I would like to include this file in my output *.jar / *.war files as a resource. However, I do not want to put this file in my project src/ folder (this would require fiddling with .gitignore and in general it just seems unnecessary to me). Ideally, the developer shouldn't even see this file at all, it should just be contained in the output archive.
How would you include a dynamically generated text file in a Gradle build?
Add that file in a jar task (Kotin DSL):
tasks {
val jar by getting(Jar::class) {
from("build/buildinfo.properties")
}
}
It will add build/buildinfo.properties file (assuming you generate it there with another taks) to the root of your JAR.
For dynamically generated file, standard gradle way to process resources is the gradle task called processResources. You can do something like this:
processResources {
dependsOn taskThatGeneratesYourBuildinfo
from("build/buildinfo.properties") {
into("desired/path/in/jar")
}
}
I have a multi-project gradle project with following directory structure:
+ project_root
+ module1
+ src
build.gradle
+ module2
+ src
build.gradle
+ web
..
build.gradle
settings.gradle
In module1/build.gradle among other things I have specified:
compileKotlin2Js.kotlinOptions {
outputFile = "web/script.js"
}
It is a special Kotlin JS setting that specifies output file path of compiled JS file.
Now my problem is, that when I build the whole project (project_root/build.gradle) the file ends up in the right directory (project_root/web), but when I accidentally run build on the module alone the file is saved in module directory (project_root/module1/web).
How can I fix paths in my build scripts, so file output will be saved in exactly the same directory no matter which build script I run (without specifying full path, I want a relative path)?
I don't know what Gradle plugin requires the path parameter in your code example, but all regular (non-3rd-party) Gradle plugins evaluate path parameters via Project.files(Object...) to avoid different locations when calling Gradle from various working directories.
I would suggest to use the above method (or its single file version Project.file(Object)) as well. You can even omit the project part, because the build.gradle file gets executed in the project scope:
compileKotlin2Js.kotlinOptions {
outputFile = file('web/script.js')
}
This will always evaluate the path relative to the project directory of the project your build.gradle belongs to. To evaluate a file relative to the project directory of the root project, use rootProject.files(Object...), for a path relative to the project directory of a subproject or any project in the build, use project(':path:to:project').files(Object...).
By default, Gradle puts all WAR files that it creates in build/libs when I run gradle build on a Java project. How do I instruct Gradle to create a directory called dist under build and put all WAR files in that directory (i.e. build/dist)?
I created a new task called moveWar that accomplished what I wanted:
task moveWar(type: Copy) {
from 'build/libs'
into 'build/dist'
}
Then I used build.finalizedBy moveWar to move the WAR file in libs to dist after the build is finished.
Another approach I found:
war.destinationDir = file "$buildDir/dist"
How can I package a jar file (packaged via buildr) and script files into a zip file? The jar file is created as per the buildfile:
define "myapp" do
...
package(:jar)
...
end
I tried Zip Task, but it didn't work.
You can use this:
package(:zip).include(package(:jar), :path => "distrib")
Or you can define a subproject for the distrib, see this example.