I have my archive at location myProject/unzip and need to:
Zip the contents within the unzip folder and create a zip file with some name at any location within the project.
Using gradle 2.3.
Can anyone help me for this?
I am not sure what you are doing differently than the examples in the documentation from the link I gave in the comments. But this works for me with Gradle 2.3:
task myZip(type: Zip){
from "$projectDir/unzip"
archiveName = "my-zip.zip"
destinationDir = buildDir
}
The input folder is called unzip and needs to present as a child in the project folder. It outputs a file my-zip.zip in the build folder.
Be sure that there actually are some resources located in the from path, or Gradle might skip it.
Related
Searching in vain for examples on this humble task, none worked, I need to learn how to use gradle to copy one specific file from the main directory of a gradle project (containing subprojects) and into the /build/libs folder of one of the subprojects. Structure is this:
mainProject folder
file.txt
Subproject folder
build folder
libs folder
(I want to copy file.txt here)
This copy process shall be in the build.gradle (for the Subproject) file. I am using Android Studio and the subproject is a pure java application.
Thanks for any help.
You need to implement a custom task of type Copy to copy the file to the target directory. To access the file in the root project, you may use the rootProject property of the subproject.
task copyFileFromRootProject(type: Copy) {
from "${rootProject.projectDir}/file.txt"
into 'build/libs'
}
During my gradle build, I generate a temporary buildinfo.properties file containing things like Git commit info, build time, etc. I would like to include this file in my output *.jar / *.war files as a resource. However, I do not want to put this file in my project src/ folder (this would require fiddling with .gitignore and in general it just seems unnecessary to me). Ideally, the developer shouldn't even see this file at all, it should just be contained in the output archive.
How would you include a dynamically generated text file in a Gradle build?
Add that file in a jar task (Kotin DSL):
tasks {
val jar by getting(Jar::class) {
from("build/buildinfo.properties")
}
}
It will add build/buildinfo.properties file (assuming you generate it there with another taks) to the root of your JAR.
For dynamically generated file, standard gradle way to process resources is the gradle task called processResources. You can do something like this:
processResources {
dependsOn taskThatGeneratesYourBuildinfo
from("build/buildinfo.properties") {
into("desired/path/in/jar")
}
}
I am working in an old project which was using Gradle Wrapper v3.2.1, but I want to update it to the latest version (currently v5.4.1).
I have tried updating it to v4.10.2 first but it fails too, so I guess it is something that was not backwards compatible between v3->v4.
The code we have in our build.gradle is:
task buildZip(type: Zip) {
group 'Build'
description 'Assembles a zip archive containing the main classes.'
baseName = "someName"
from compileJava
from processResources
into('lib') {
from configurations.runtime
}
}
Using gradle v3 it included all the libraries (as .jar files) in the .zip file under "lib/" folder, but if I use v4 or later, it does not fail, but it does not include the libraries neither. I have achieved to get the .class files of the dependencies, but that does not work for what I need (AWS Lambda function).
Any idea on how to get the .jar dependencies into the .zip file?
Cheers!
Francisco Robles Martin
So, thanks to Opal comment, I kept looking for a bit more and got a solution, but it seems to not be very correct as I am forcing implementation to allow be resolved:
configurations.implementation.setCanBeResolved(true)
task buildZip(type: Zip) {
group 'Build'
description 'Assembles a zip archive containing the main classes.'
baseName = "someName"
from compileJava
from processResources
into('lib') {
from configurations.implementation
}
}
It works, but I guess there should be a better way to do it without the first line.
By default, Gradle puts all WAR files that it creates in build/libs when I run gradle build on a Java project. How do I instruct Gradle to create a directory called dist under build and put all WAR files in that directory (i.e. build/dist)?
I created a new task called moveWar that accomplished what I wanted:
task moveWar(type: Copy) {
from 'build/libs'
into 'build/dist'
}
Then I used build.finalizedBy moveWar to move the WAR file in libs to dist after the build is finished.
Another approach I found:
war.destinationDir = file "$buildDir/dist"
task fullZip(type: Zip) {
baseName = 'fullZip'
from projectDir.parentFile
exclude 'build'
}
Looking to zip complete project, with the entire subprojects/modules.
Gradle task never completes and the size of the zip is building up to enormous size while it's a small project in general.
This zip task is part of gradle file in one of the module.
From the half cooked zip file, I can see build directories, which should have been excluded are present.
You need to use exclude **/build/*.